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CN111818581A - A user access method and access network equipment - Google Patents

A user access method and access network equipment Download PDF

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CN111818581A
CN111818581A CN202010754626.7A CN202010754626A CN111818581A CN 111818581 A CN111818581 A CN 111818581A CN 202010754626 A CN202010754626 A CN 202010754626A CN 111818581 A CN111818581 A CN 111818581A
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bandwidth
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private network
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CN111818581B (en
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杨艳
冯毅
张涛
张忠皓
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China United Network Communications Group Co Ltd
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    • HELECTRICITY
    • H04ELECTRIC COMMUNICATION TECHNIQUE
    • H04WWIRELESS COMMUNICATION NETWORKS
    • H04W48/00Access restriction; Network selection; Access point selection
    • H04W48/16Discovering, processing access restriction or access information
    • HELECTRICITY
    • H04ELECTRIC COMMUNICATION TECHNIQUE
    • H04WWIRELESS COMMUNICATION NETWORKS
    • H04W28/00Network traffic management; Network resource management
    • H04W28/02Traffic management, e.g. flow control or congestion control
    • H04W28/08Load balancing or load distribution
    • HELECTRICITY
    • H04ELECTRIC COMMUNICATION TECHNIQUE
    • H04WWIRELESS COMMUNICATION NETWORKS
    • H04W28/00Network traffic management; Network resource management
    • H04W28/16Central resource management; Negotiation of resources or communication parameters, e.g. negotiating bandwidth or QoS [Quality of Service]
    • H04W28/18Negotiating wireless communication parameters
    • H04W28/20Negotiating bandwidth
    • HELECTRICITY
    • H04ELECTRIC COMMUNICATION TECHNIQUE
    • H04WWIRELESS COMMUNICATION NETWORKS
    • H04W28/00Network traffic management; Network resource management
    • H04W28/16Central resource management; Negotiation of resources or communication parameters, e.g. negotiating bandwidth or QoS [Quality of Service]
    • H04W28/24Negotiating SLA [Service Level Agreement]; Negotiating QoS [Quality of Service]
    • HELECTRICITY
    • H04ELECTRIC COMMUNICATION TECHNIQUE
    • H04WWIRELESS COMMUNICATION NETWORKS
    • H04W48/00Access restriction; Network selection; Access point selection
    • H04W48/18Selecting a network or a communication service
    • YGENERAL TAGGING OF NEW TECHNOLOGICAL DEVELOPMENTS; GENERAL TAGGING OF CROSS-SECTIONAL TECHNOLOGIES SPANNING OVER SEVERAL SECTIONS OF THE IPC; TECHNICAL SUBJECTS COVERED BY FORMER USPC CROSS-REFERENCE ART COLLECTIONS [XRACs] AND DIGESTS
    • Y02TECHNOLOGIES OR APPLICATIONS FOR MITIGATION OR ADAPTATION AGAINST CLIMATE CHANGE
    • Y02DCLIMATE CHANGE MITIGATION TECHNOLOGIES IN INFORMATION AND COMMUNICATION TECHNOLOGIES [ICT], I.E. INFORMATION AND COMMUNICATION TECHNOLOGIES AIMING AT THE REDUCTION OF THEIR OWN ENERGY USE
    • Y02D30/00Reducing energy consumption in communication networks
    • Y02D30/70Reducing energy consumption in communication networks in wireless communication networks

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  • Computer Networks & Wireless Communication (AREA)
  • Signal Processing (AREA)
  • Quality & Reliability (AREA)
  • Computer Security & Cryptography (AREA)
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Abstract

本发明提供了一种用户接入方法和接入网设备,涉及通信技术领域,解决了共建后的共享基站如何在资源有限的情况下,尽可能满足不同运营商的2B(可以理解为专网)用户和2C(可以理解为公网)用户接入诉求成为了一个亟待解决的问题。该方法包括,获取N个运营商中每个运营商的目标业务在当前单位时间的网络数据;确定第n个运营商的第k个专网业务的RRC连接数大于第一阈值,和/或第k个专网业务的数传连接数大于第二阈值时,根据N个运营商的网络数据确定第k个专网业务在当前单位时间的带宽需求量;确定第n个运营商的剩余带宽大于带宽需求量时,在当前单位时间允许第k个专网业务的新用户接入第k个专网业务对应的核心网设备。

Figure 202010754626

The present invention provides a user access method and access network equipment, relates to the field of communications technology, and solves the problem of how a shared base station after co-construction can meet the 2B requirements of different operators as much as possible under the condition of limited resources (which can be understood as a special Internet) users and 2C (can be understood as public network) users' access demands have become an urgent problem to be solved. The method includes: acquiring network data of the target service of each operator among the N operators in the current unit time; determining that the number of RRC connections of the kth private network service of the nth operator is greater than a first threshold, and/or When the number of data transmission connections of the kth private network service is greater than the second threshold, determine the bandwidth demand of the kth private network service in the current unit time according to the network data of the N operators; determine the remaining bandwidth of the nth operator When the bandwidth requirement is greater than the bandwidth requirement, new users of the k-th private network service are allowed to access the core network equipment corresponding to the k-th private network service in the current unit time.

Figure 202010754626

Description

一种用户接入方法和接入网设备A user access method and access network equipment

技术领域technical field

本发明涉及通信技术领域,尤其涉及一种用户接入方法和接入网设备。The present invention relates to the field of communication technologies, and in particular, to a user access method and access network equipment.

背景技术Background technique

第五代移动通信技术(5th-generation,5G)网络提供了多种切片模式,能够同时满足消费者(customer to customer,2C)和企业(business to business,2B)的需求。The fifth-generation mobile communication technology (5th-generation, 5G) network provides a variety of slicing modes, which can meet the needs of consumers (customer to customer, 2C) and enterprises (business to business, 2B) at the same time.

5G网络中的收发设备(如接入网设备)通常为多天线设备,如:64收发(transmitter and receiver,TR)设备,导致建网成本极高。因此,运营商开始寻求一种多家运营商共建基站,并利用共建后的基站进行网络部署的方案。共建基站是指一个基站可以满足多家运营商的需求,并不是将多个运营商的设备集中在同一个基站中。The transceiver equipment (such as access network equipment) in the 5G network is usually multi-antenna equipment, such as: 64 transceiver (transmitter and receiver, TR) equipment, resulting in extremely high network construction costs. Therefore, operators have begun to seek a solution in which multiple operators jointly build base stations and use the co-built base stations for network deployment. Co-construction of base stations means that one base station can meet the needs of multiple operators, rather than concentrating the equipment of multiple operators in the same base station.

共建后的共享基站如何在资源有限的情况下,尽可能满足不同运营商的2B(可以理解为专网)用户和2C(可以理解为公网)用户接入诉求成为了一个亟待解决的问题。How to meet the access demands of 2B (can be understood as private network) users and 2C (can be understood as public network) users of different operators as much as possible in the case of limited resources has become an urgent problem to be solved. .

发明内容SUMMARY OF THE INVENTION

本发明提供一种用户接入方法和接入网设备,解决了共建后的共享基站如何在资源有限的情况下,尽可能满足不同运营商的2B(可以理解为专网)用户和2C(可以理解为公网)用户接入诉求成为了一个亟待解决的问题。The present invention provides a user access method and access network equipment, which solves how the shared base station after co-construction can satisfy 2B (can be understood as private network) users and 2C (2C (private network) users of different operators as much as possible under the condition of limited resources It can be understood as the public network) user access demands have become an urgent problem to be solved.

为达到上述目的,本发明采用如下技术方案:To achieve the above object, the present invention adopts the following technical solutions:

第一方面,本发明实施例提供一种用户接入方法,应用于接入网设备,接入网设备通过一路载波为一个运营商的公网业务和专网业务提供支持,包括:获取N个运营商中每个运营商的目标业务在当前单位时间的网络数据。其中,目标业务包括K个专网业务,网络数据至少包括RRC连接数和数传连接数,N为大于或等于2的整数,K为大于或等于1的整数。确定第n个运营商的第k个专网业务的RRC连接数大于第一阈值,和/或第k个专网业务的数传连接数大于第二阈值时,根据N个运营商的网络数据确定第k个专网业务在当前单位时间的带宽需求量。其中,n∈[1,N],且n为整数,k∈[1,K],且k为整数。确定第n个运营商的剩余带宽大于带宽需求量时,在当前单位时间允许第k个专网业务的新用户接入第k个专网业务对应的核心网设备。In a first aspect, an embodiment of the present invention provides a user access method, which is applied to an access network device. The access network device provides support for an operator's public network services and private network services through a carrier, including: acquiring N Network data of the target service of each operator in the current unit time. The target service includes K private network services, the network data includes at least the number of RRC connections and the number of data transmission connections, N is an integer greater than or equal to 2, and K is an integer greater than or equal to 1. When it is determined that the number of RRC connections of the kth private network service of the nth operator is greater than the first threshold, and/or the number of data transmission connections of the kth private network service is greater than the second threshold, according to the network data of the N operators Determine the bandwidth demand of the kth private network service in the current unit time. where n∈[1,N], and n is an integer, k∈[1,K], and k is an integer. When it is determined that the remaining bandwidth of the nth operator is greater than the bandwidth demand, the new user of the kth private network service is allowed to access the core network equipment corresponding to the kth private network service in the current unit time.

可以看出,接入网设备可以根据当前单位时间的网络数据,确定第n个运营商的第k个专网业务的RRC连接数是否大于第一阈值,和/或该第k个专网业务的数传连接数是否大于第二阈值的第k个专网业务,从而确定当前单位时间该第k个专网业务的新用户是否可以接入该第k个专网业务对应的核心网设备。当确定第n个运营商的第k个专网业务的RRC连接数大于第一阈值,和/或第k个专网业务的数传连接数大于第二阈值时,说明此时该第k个专网业务在当前单位时间的请求接入的新用户较多,因此需要确定该第k个专网业务在当前单位时间的带宽需求量。当确定第n个运营商的剩余带宽大于带宽需求量时,在当前单位时间允许第k个专网业务的新用户接入第k个专网业务对应的核心网设备。从而解决了共建后的共享基站如何在资源有限的情况下,尽可能满足不同运营商的2B(可以理解为专网)用户和2C(可以理解为公网)用户接入诉求的问题。It can be seen that the access network device can determine whether the number of RRC connections of the kth private network service of the nth operator is greater than the first threshold according to the network data of the current unit time, and/or the kth private network service Whether the number of data transmission connections is greater than the kth private network service of the second threshold, so as to determine whether new users of the kth private network service can access the core network equipment corresponding to the kth private network service in the current unit time. When it is determined that the number of RRC connections of the kth private network service of the nth operator is greater than the first threshold, and/or the number of data transmission connections of the kth private network service is greater than the second threshold, it means that the kth private network service at this time is There are many new users requesting access to the private network service in the current unit time, so it is necessary to determine the bandwidth demand of the kth private network service in the current unit time. When it is determined that the remaining bandwidth of the nth operator is greater than the bandwidth requirement, the new user of the kth private network service is allowed to access the core network equipment corresponding to the kth private network service in the current unit time. This solves the problem of how the co-constructed shared base station can meet the access demands of 2B (can be understood as private network) users and 2C (can be understood as public network) users of different operators as much as possible under the condition of limited resources.

第二方面,本发明提供一种接入网设备,该接入网设备通过一路载波为一个运营商的公网业务和专网业务提供支持,该接入网设备包括用于执行第一方面的用户接入方法的各个模块。In a second aspect, the present invention provides an access network device, the access network device provides support for an operator's public network services and private network services through a carrier, and the access network device includes a method for performing the first aspect. Each module of the user access method.

具体的,该接入网设备包括:获取单元和处理单元。上述获取单元,用于获取N个运营商中每个运营商的目标业务在当前单位时间的网络数据;其中,目标业务包括K个专网业务,网络数据至少包括RRC连接数和数传连接数,N为大于或等于2的整数,K为大于或等于1的整数。上述处理单元,用于确定获取单元获取的第n个运营商的第k个专网业务的RRC连接数大于第一阈值,和/或获取单元获取的第k个专网业务的数传连接数大于第二阈值时,根据获取单元获取的N个运营商的网络数据确定第k个专网业务在当前单位时间的带宽需求量。其中,n∈[1,N],且n为整数,k∈[1,K],且k为整数。上述处理单元,还用于确定第n个运营商的剩余带宽大于带宽需求量时,在当前单位时间允许第k个专网业务的新用户接入第k个专网业务对应的核心网设备。Specifically, the access network device includes: an acquisition unit and a processing unit. The above-mentioned obtaining unit is used to obtain the network data of the target service of each operator in the N operators at the current unit time; wherein, the target service includes K private network services, and the network data at least includes the number of RRC connections and the number of data transmission connections , N is an integer greater than or equal to 2, and K is an integer greater than or equal to 1. The above processing unit is used to determine that the number of RRC connections of the kth private network service of the nth operator acquired by the acquisition unit is greater than the first threshold, and/or the number of data transmission connections of the kth private network service acquired by the acquisition unit When the value is greater than the second threshold, the bandwidth demand of the kth private network service in the current unit time is determined according to the network data of the N operators acquired by the acquiring unit. where n∈[1,N], and n is an integer, k∈[1,K], and k is an integer. The above processing unit is further configured to allow new users of the kth private network service to access the core network equipment corresponding to the kth private network service in the current unit time when the remaining bandwidth of the nth operator is greater than the bandwidth demand.

第三方面,本发明提供一种接入网设备,包括:通信接口、处理器、存储器、总线;存储器用于存储计算机执行指令,处理器与存储器通过总线连接。当接入网设备运行时,处理器执行存储器存储的计算机执行指令,以使接入网设备执行如上述第一方面提供的用户接入方法。In a third aspect, the present invention provides an access network device, including: a communication interface, a processor, a memory, and a bus; the memory is used to store computer execution instructions, and the processor and the memory are connected through a bus. When the access network device is running, the processor executes the computer execution instructions stored in the memory, so that the access network device executes the user access method provided in the first aspect above.

第四方面,本发明提供一种计算机可读存储介质,包括指令。当所述指令在计算机上运行时,使得计算机执行如上述第一方面提供的用户接入方法。In a fourth aspect, the present invention provides a computer-readable storage medium comprising instructions. When the instructions are executed on the computer, the computer is caused to execute the user access method provided by the above-mentioned first aspect.

第五方面,本发明提供一种计算机程序产品,当所述计算机程序产品在计算机上运行时,使得所述计算机执行如第一方面的设计方式所述的用户接入方法。In a fifth aspect, the present invention provides a computer program product, which, when the computer program product runs on a computer, causes the computer to execute the user access method described in the design manner of the first aspect.

需要说明的是,上述计算机指令可以全部或者部分存储在第一计算机可读存储介质上。其中,第一计算机可读存储介质可以与接入网设备的处理器封装在一起的,也可以与接入网设备的处理器单独封装,本发明对此不作限定。It should be noted that the above computer instructions may be stored in whole or in part on the first computer-readable storage medium. The first computer-readable storage medium may be packaged together with the processor of the access network device, or may be packaged separately with the processor of the access network device, which is not limited in the present invention.

本发明中第二方面、第三方面、第四方面以及第五方面的描述,可以参考第一方面的详细描述;并且,第二方面、第三方面、第四方面以及第五方面的描述的有益效果,可以参考第一方面的有益效果分析,此处不再赘述。For the description of the second, third, fourth and fifth aspects of the present invention, reference may be made to the detailed description of the first aspect; and, for the description of the second, third, fourth and fifth aspects For the beneficial effects, reference may be made to the analysis of the beneficial effects of the first aspect, which will not be repeated here.

在本发明中,上述接入网设备的名字对设备或功能模块本身不构成限定,在实际实现中,这些设备或功能模块可以以其他名称出现。只要各个设备或功能模块的功能和本发明类似,属于本发明权利要求及其等同技术的范围之内。In the present invention, the names of the above-mentioned access network devices do not limit the devices or functional modules themselves, and in actual implementation, these devices or functional modules may appear with other names. As long as the functions of various devices or functional modules are similar to the present invention, they fall within the scope of the claims of the present invention and their equivalents.

本发明的这些方面或其他方面在以下的描述中会更加简明易懂。These and other aspects of the present invention will become apparent from the following description.

附图说明Description of drawings

为了更清楚地说明本发明实施例或现有技术中的技术方案,下面将对实施例或现有技术描述中所需要使用的附图作简单地介绍,显而易见地,下面描述中的附图仅仅是本发明的一些实施例,对于本领域普通技术人员来讲,在不付出创造性劳动的前提下,还可以根据这些附图获得其他的附图。In order to explain the embodiments of the present invention or the technical solutions in the prior art more clearly, the following briefly introduces the accompanying drawings that need to be used in the description of the embodiments or the prior art. Obviously, the accompanying drawings in the following description are only These are some embodiments of the present invention. For those of ordinary skill in the art, other drawings can also be obtained according to these drawings without creative efforts.

图1为本发明实施例提供的一种用户接入方法应用于的系统架构示意图;1 is a schematic diagram of a system architecture to which a user access method provided by an embodiment of the present invention is applied;

图2为本发明实施例提供的另一种用户接入方法应用于的系统架构示意图;2 is a schematic diagram of a system architecture to which another user access method provided by an embodiment of the present invention is applied;

图3为本发明实施例提供的一种接入网设备的结构示意图;3 is a schematic structural diagram of an access network device according to an embodiment of the present invention;

图4为本发明实施例提供的一种用户接入方法的流程示意图之一;FIG. 4 is one of the schematic flowcharts of a user access method according to an embodiment of the present invention;

图5为本发明实施例提供的一种用户接入方法的流程示意图之二;FIG. 5 is a second schematic flowchart of a user access method according to an embodiment of the present invention;

图6为本发明实施例提供的一种用户接入方法的流程示意图之三;FIG. 6 is a third schematic flowchart of a user access method according to an embodiment of the present invention;

图7为本发明实施例提供的一种用户接入方法的流程示意图之四;FIG. 7 is a fourth schematic flowchart of a user access method according to an embodiment of the present invention;

图8为本发明实施例提供的一种用户接入方法的流程示意图之五;FIG. 8 is a fifth schematic flowchart of a user access method according to an embodiment of the present invention;

图9为本发明实施例提供的一种用户接入方法的流程示意图之六;FIG. 9 is a sixth schematic flowchart of a user access method according to an embodiment of the present invention;

图10为本发明实施例提供的一种用户接入方法的流程示意图之七;FIG. 10 is a seventh schematic flowchart of a user access method according to an embodiment of the present invention;

图11为本发明实施例提供的一种基站的结构示意图之一;FIG. 11 is one of schematic structural diagrams of a base station according to an embodiment of the present invention;

图12为本发明实施例提供的一种基站的结构示意图之二;FIG. 12 is a second schematic structural diagram of a base station according to an embodiment of the present invention;

图13为本发明实施例提供的用户接入方法的计算机程序产品的结构示意图。FIG. 13 is a schematic structural diagram of a computer program product of a user access method provided by an embodiment of the present invention.

具体实施方式Detailed ways

下面结合附图,对本发明的实施例进行描述。Embodiments of the present invention will be described below with reference to the accompanying drawings.

下面将结合本发明实施例中的附图,对本发明实施例中的技术方案进行清楚、完整地描述,显然,所描述的实施例仅仅是本发明一部分实施例,而不是全部的实施例。基于本发明中的实施例,本领域普通技术人员在没有做出创造性劳动前提下所获得的所有其他实施例,都属于本发明保护的范围。The technical solutions in the embodiments of the present invention will be clearly and completely described below with reference to the accompanying drawings in the embodiments of the present invention. Obviously, the described embodiments are only a part of the embodiments of the present invention, but not all of the embodiments. Based on the embodiments of the present invention, all other embodiments obtained by those of ordinary skill in the art without creative efforts shall fall within the protection scope of the present invention.

为了便于清楚描述本发明实施例的技术方案,在本发明的实施例中,采用了“第一”、“第二”等字样对功能和作用基本相同的相同项或相似项进行区分,本领域技术人员可以理解“第一”、“第二”等字样并不对数量和执行次序进行限定。In order to clearly describe the technical solutions of the embodiments of the present invention, in the embodiments of the present invention, words such as "first" and "second" are used to distinguish the same items or similar items with basically the same functions and functions. A skilled person can understand that words such as "first" and "second" do not limit the quantity and execution order.

针对上述问题,本发明实施例提供一种用户接入方法,能够基于无线资源控制(radio resource control,RRC)连接数和数传连接数(表示有数传的RRC连接数)满足不同运营商共建的共享基站(接入网设备)承载的不同业务对应的用户终端的接入诉求。该方法应用于如图1所示的系统架构中,该系统可以包括:终端01、接入网设备02和至少一个核心网设备03(03-1、03-2、03-3和03-4),每一个核心网设备03对应一个运营商核心网(专网核心网(支持2B业务)或公网核心网(支持2C业务))。示例性的,参照图1所示,03-1可以对应运营商A的公网核心网,03-2可以对应运营商A的专网核心网,03-3可以对应运营商B的公网核心网,03-4可以对应运营商B的专网核心网。终端01接入网设备02与接入网设备产生连接后可以通过不同核心网设备03接入相应的运营商的公网核心网或专网核心网。当然实际中也可以仅存在一个核心网设备03,可以完成上述多个核心网设备的功能。In view of the above problems, embodiments of the present invention provide a user access method, which can meet the requirements of co-construction by different operators based on the number of radio resource control (RRC) connections and the number of data transmission connections (indicating the number of RRC connections with data transmission). Access requirements of user terminals corresponding to different services carried by the shared base station (access network equipment). The method is applied to the system architecture shown in FIG. 1 , and the system may include: a terminal 01, an access network device 02, and at least one core network device 03 (03-1, 03-2, 03-3, and 03-4). ), each core network device 03 corresponds to an operator core network (private network core network (supporting 2B services) or public network core network (supporting 2C services)). Exemplarily, as shown in FIG. 1 , 03-1 may correspond to the public network core network of operator A, 03-2 may correspond to the private network core network of operator A, and 03-3 may correspond to the public network core network of operator B network, 03-4 can correspond to the core network of the private network of operator B. After the access network device 02 of the terminal 01 is connected to the access network device, it can access the public network core network or private network core network of the corresponding operator through different core network devices 03 . Of course, in practice, there may be only one core network device 03, which can perform the functions of the above-mentioned multiple core network devices.

需要说明的是,本发明中,公网业务(2C业务)指公网中的所有业务,专网业务(2B业务)指专网中的所有业务。It should be noted that, in the present invention, public network services (2C services) refer to all services in the public network, and private network services (2B services) refer to all services in the private network.

示例性的,参照图2所示,核心网设备03中的功能模块可以包括有业务分布需求收集模块031、业务依赖度分析模块032、关键用户数参数定制模块033和运营商载波带宽定制模块034。其中,业务分布需求收集模块031可以对其连接的接入网设备02(例如基站)的对应运营商的专网业务或公网业务的网络数据进行采集。网络数据可以包括:网络对应的业务的相关数据(每单位时间(例如小时)的平均RRC连接数/平均有数传的RRC连接数、每单位时间(例如小时)的最大RRC连接数/最大有数传的RRC连接数)、业务的流量或用户数等。Exemplarily, as shown in FIG. 2 , the functional modules in the core network device 03 may include a service distribution requirement collection module 031, a service dependency analysis module 032, a key user number parameter customization module 033, and an operator carrier bandwidth customization module 034. . The service distribution requirement collection module 031 may collect network data of the corresponding operator's private network service or public network service of the connected access network device 02 (eg, base station). The network data may include: related data of services corresponding to the network (the average number of RRC connections per unit time (for example, hours)/the average number of RRC connections with data transmission, the maximum number of RRC connections per unit time (for example, hours)/the maximum number of data transmissions number of RRC connections), service traffic or number of users, etc.

业务依赖度分析模块032,可以通过与其连接的接入网设备02对应的其他核心网设备中的业务依赖度分析模块032配合,利用其对应的业务分布需求收集模块031获取的网络数据,通过一定的计算确定该网络数据对应的实际场景中的业务是否主要依赖于RRC连接数和有数传的RRC连接数。当然,若所有核心网对应同一核心网设备时,则其包括的业务依赖度分析模块则独立完成上述计算过程。The service dependency analysis module 032 can cooperate with the service dependency analysis module 032 in other core network devices corresponding to the access network device 02 connected to it, and use the network data obtained by the corresponding service distribution requirement collection module 031, through a certain The calculation of , determines whether the service in the actual scenario corresponding to the network data mainly depends on the number of RRC connections and the number of RRC connections with data transmission. Of course, if all the core networks correspond to the same core network device, the service dependency analysis module included in the core network can independently complete the above calculation process.

关键用户数参数定制模块033,用于可以通过与其连接的接入网设备02对应的其他核心网设备中的关键用户数参数定制模块033配合,根据其各自对应业务分布需求收集模块031获取的网络数据计算得出为不同运营商的公网业务和专网业务推荐的每目标单位时间的约定的RRC连接数(第一阈值)以及约定的有数传RRC连接数(第二阈值)。当然,若所有核心网对应同一核心网设备时,则其包括的关键容量定制模块则独立完成上述计算过程。The key user number parameter customization module 033 is used to cooperate with the key user number parameter customization module 033 in other core network devices corresponding to the access network device 02 connected to it, and collect the network obtained by the module 031 according to their respective corresponding service distribution requirements The data is calculated to obtain the agreed number of RRC connections per target unit time recommended for public network services and private network services of different operators (the first threshold) and the agreed number of RRC connections with data transmission (the second threshold). Of course, if all the core networks correspond to the same core network device, the key capacity customization module included in the core network can independently complete the above calculation process.

示例性的,以单位时间为1秒,目标单位时间为1小时为例,专网业务的第一阈值和第二阈值可以由以下公式计算得出:Exemplarily, taking the unit time of 1 second and the target unit time of 1 hour as an example, the first threshold and the second threshold of the private network service can be calculated by the following formulas:

Figure BDA0002611117520000061
Figure BDA0002611117520000061

Figure BDA0002611117520000062
Figure BDA0002611117520000062

其中,

Figure BDA0002611117520000063
表示约定的每秒专网用户接入数,
Figure BDA0002611117520000064
表示约定的每秒专网有数传的用户接入数,
Figure BDA0002611117520000065
表示专网每小时最大RRC连接数,
Figure BDA0002611117520000066
表示专网每小时平均RRC连接数,
Figure BDA0002611117520000067
表示专网每小时最大有数传的RRC连接数,
Figure BDA0002611117520000068
表示专网每小时平均有数传的RRC连接数。in,
Figure BDA0002611117520000063
Indicates the agreed number of private network user access per second,
Figure BDA0002611117520000064
Indicates the agreed number of users accessing the private network with data transmission per second,
Figure BDA0002611117520000065
Indicates the maximum number of RRC connections per hour on the private network,
Figure BDA0002611117520000066
Indicates the average number of RRC connections per hour on the private network,
Figure BDA0002611117520000067
Indicates the maximum number of RRC connections with data transmission per hour on the private network.
Figure BDA0002611117520000068
Indicates the average number of RRC connections per hour for data transmission on the private network.

运营商载波带宽定制模块034,用于获取拟部署基站的区域内不同运营商的RRC连接数和有数传的RRC连接数,确定每个载波的初始带宽。The carrier carrier bandwidth customization module 034 is configured to acquire the number of RRC connections of different carriers and the number of RRC connections with data transmission in the area where the base station is to be deployed, and determine the initial bandwidth of each carrier.

其中,初始带宽满足Among them, the initial bandwidth satisfies

Figure BDA0002611117520000069
Figure BDA0002611117520000069

其中,i表示载波i,j为载波i下第j个专网,W为基站支持的总带宽,floor表示计算值向下取整。Among them, i represents carrier i, j represents the jth private network under carrier i, W represents the total bandwidth supported by the base station, and floor represents the calculated value rounded down.

示例性的,参照图2所示,接入网设备02中包括用户数实时监控模块021、用户数判别模块022、网络负载均衡模块023。其中,用户数实时监控模块021可以以单位时间(1秒)的时间粒度采集个运营商的专网业务和公网业务的RRC连接数和有数传的RRC连接数。用户数判别模块022可以根据业务分布需求收集模块031采集的RRC连接数和有数传的RRC连接数,确定是否需要后续的网络负载均衡模块023对各业务的用户终端的接入请求拒绝或允许等。Exemplarily, as shown in FIG. 2 , the access network device 02 includes a user number real-time monitoring module 021 , a user number determining module 022 , and a network load balancing module 023 . The real-time monitoring module 021 for the number of users can collect the number of RRC connections and the number of RRC connections with data transmission for private network services and public network services of each operator with the time granularity of a unit time (1 second). The number of users judging module 022 can determine whether the subsequent network load balancing module 023 needs to reject or allow the access requests of the user terminals of each service according to the number of RRC connections collected by the service distribution requirement collection module 031 and the number of RRC connections with data transmission. .

示例性的,以5G通信网络为例,参照图3所示,接入网设备02中的实际装置可以包括射频单元和基带处理单元。其中,射频单元通过通用公共无线电接口(common publicradio interface,CPRI(eCRPI))与基带处理单元连接,运营商A的公网核心网(5GC1)、运营商B的公网核心网(5GC2)、运营商A的专网核心网(5GC3)和运营商B的专网核心网(5GC4)均通过NG接口与接入网设备2的基带处理单元相连接。Exemplarily, taking a 5G communication network as an example, as shown in FIG. 3 , the actual device in the access network device 02 may include a radio frequency unit and a baseband processing unit. The radio frequency unit is connected to the baseband processing unit through a common public radio interface (CPRI (eCRPI)), and the public network core network (5GC1) of operator A, the public network core network (5GC2) of operator B, Both the private network core network (5GC3) of the operator A and the private network core network (5GC4) of the operator B are connected to the baseband processing unit of the access network device 2 through the NG interface.

5G基带处理单元包括控制面(control plane,CP)和用户面(user plane,UP)。控制面中存在有对不同运营商的专网核心网、公网核心网入的识别模块(具体可通过PLMN(public land mobile network,公共陆地移动网)、APN(access point name,接入点名称)、DNN(data network name,数据网络名称)等判断),从而实现不同运营商下公网核心网和专网核心网的区分。上述的用户数实时监控模块021、用户数判别模块022、网络负载均衡模块023也可以均设置在该CP中。The 5G baseband processing unit includes a control plane (CP) and a user plane (UP). In the control plane, there are identification modules for accessing the private network core network and public network core network of different operators (specifically, PLMN (public land mobile network, public land mobile network), APN (access point name, access point name) ), DNN (data network name, data network name), etc.), so as to realize the distinction between the public network core network and the private network core network under different operators. The above-mentioned real-time monitoring module 021 for the number of users, the determining module 022 for the number of users, and the network load balancing module 023 may all be set in the CP.

5G射频单元包括天线单元、开关、第一合路器、第二合路器、第一收发器和第二收发器。其中,每个收发器包括数字上变频(digital up conversion,DUC)、数字模拟转换器(digital to analog converter,DAC)、发送天线(transport,TX)、接收天线(receive,RX)、模拟数字转换器(analog to digital converter,ADC)和数字下变频(digital downconversion,DDC)。The 5G radio frequency unit includes an antenna unit, a switch, a first combiner, a second combiner, a first transceiver and a second transceiver. Wherein, each transceiver includes a digital up conversion (DUC), a digital to analog converter (DAC), a transmitting antenna (transport, TX), a receiving antenna (receive, RX), an analog-to-digital conversion converter (analog to digital converter, ADC) and digital downconversion (digital downconversion, DDC).

具体的,本发明提供的技术方案中,接入网设备02为每个运营商分配一条载波承载该运营商的公网业务和专网业务。每条载波包括上行载波和下行载波,上行载波对应的通信链路由图3中的天线单元、开关、RX、ADC、DDC、5G基带处理单元组成,下行载波对应的通信链路由图3中的天线单元、开关、TX、DAC、DUC、5G基带处理单元组成。Specifically, in the technical solution provided by the present invention, the access network device 02 allocates a carrier to each operator to carry the operator's public network services and private network services. Each carrier includes an uplink carrier and a downlink carrier. The communication link corresponding to the uplink carrier is composed of the antenna unit, switch, RX, ADC, DDC, and 5G baseband processing unit in Figure 3. The communication link corresponding to the downlink carrier is composed of Figure 3. It is composed of antenna unit, switch, TX, DAC, DUC, and 5G baseband processing unit.

示例性的,如图3所示,当接入网设备内接入2个运营商(分别为运营商A和运营商B)时,运营商A的用户终端在发起专网业务或公网业务时,可以通过第一载波传输,运营商B的用户终端在发起专网业务或公网业务时,可以通过第二载波传输。其中,第一载波包括第一收发器、第一合路器、开关和天线单元;第二载波包括第二收发器、第二合路器、开关和天线单元。Exemplarily, as shown in FIG. 3 , when two operators (operator A and operator B, respectively) are connected to the access network device, the user terminal of operator A is initiating private network services or public network services. When the user terminal of operator B initiates a private network service or a public network service, it can be transmitted through the second carrier. Wherein, the first carrier includes a first transceiver, a first combiner, a switch and an antenna unit; the second carrier includes a second transceiver, a second combiner, a switch and an antenna unit.

在本发明实施例中,接入网设备02可以是全球移动通信系统(globalsystemformobilecommunication,GSM),码分多址(code division multiple access,CDMA)中的接入网设备(basetransceiver station,BTS),宽带码分多址(wideband code divisionmultiple access,WCDMA)中的接入网设备(node B,NB),长期演进(Long Term Evolution,LTE)中的接入网设备(evolvedNode B,eNB),物联网(internet of things,IoT)或者窄带物联网(narrow band-internetof things,NB-IoT)中的eNB,未来5G移动通信网络或者未来演进的公共陆地移动网络(public land mobile network,PLMN)中的接入网设备,本发明实施例对此不作任何限制。In this embodiment of the present invention, the access network device 02 may be a global system for mobile communication (GSM), an access network device (base transceiver station, BTS) in code division multiple access (code division multiple access, CDMA), a broadband Access network equipment (node B, NB) in code division multiple access (wideband code division multiple access, WCDMA), access network equipment (evolved Node B, eNB) in Long Term Evolution (Long Term Evolution, LTE), Internet of Things ( eNB in internet of things (IoT) or narrow band-internet of things (NB-IoT), access in future 5G mobile communication network or future evolved public land mobile network (PLMN) network equipment, which is not limited in this embodiment of the present invention.

示例性的,本发明实施例中的终端01不同的名称,例如用户设备(userequipment,UE)、接入终端、终端单元、终端站、移动站、移动台、远方站、远程终端、移动设备、无线通信设备、车辆用户设备、终端代理或终端装置等。其具体可以是手机、平板电脑、桌面型、膝上型、手持计算机、笔记本电脑、超级移动个人计算机(ultra-mobile personalcomputer,UMPC)、上网本,以及蜂窝电话、个人数字助理(personal digital assistant,PDA)、增强现实(augmented reality,AR)\虚拟现实(virtual reality,VR)设备等可以与基站进行通信的设备,本发明实施例对该终端的具体形态不作特殊限制。Exemplarily, the terminal 01 in the embodiment of the present invention has different names, such as user equipment (user equipment, UE), access terminal, terminal unit, terminal station, mobile station, mobile station, remote station, remote terminal, mobile equipment, Wireless communication equipment, vehicle user equipment, terminal agents or terminal devices, etc. Specifically, it can be a mobile phone, a tablet computer, a desktop, a laptop, a handheld computer, a notebook computer, an ultra-mobile personal computer (UMPC), a netbook, as well as a cellular phone, a personal digital assistant (PDA) ), augmented reality (AR)\virtual reality (virtual reality, VR) devices and other devices that can communicate with the base station, the specific form of the terminal is not particularly limited in this embodiment of the present invention.

以下结合图1示出的通信系统,以接入网设备02为基站为例,对本发明实施例所提供的用户接入方法进行介绍。The following describes the user access method provided by the embodiment of the present invention with reference to the communication system shown in FIG. 1 , taking the access network device 02 as a base station as an example.

如图4所示,本发明实施例提供的用户接入方法,应用于基站,基站通过一路载波为一个运营商的公网业务和专网业务提供支持,包括:As shown in FIG. 4 , the user access method provided by the embodiment of the present invention is applied to a base station, and the base station provides support for an operator's public network services and private network services through one carrier, including:

S11、基站获取N个运营商中每个运营商的目标业务在当前单位时间的网络数据。其中,目标业务包括K个专网业务,网络数据至少包括RRC连接数和数传连接数,N为大于或等于2的整数,K为大于或等于1的整数。S11. The base station acquires the network data of the target service of each operator among the N operators in the current unit time. The target service includes K private network services, the network data includes at least the number of RRC connections and the number of data transmission connections, N is an integer greater than or equal to 2, and K is an integer greater than or equal to 1.

示例性的,为了保证及时基于RRC连接数和数传连接数(也称为有数传的RRC连接数)对用户终端的接入请求进行处理,这里的单位时间可以为一秒。当然,实际中技术允许的条件下,还可以为更小的单位时间,此处不做具体限制。Exemplarily, in order to ensure timely processing of the access request of the user terminal based on the number of RRC connections and the number of data transmission connections (also referred to as the number of RRC connections with data transmission), the unit time here may be one second. Of course, under the condition permitted by the technology in practice, it can also be a smaller unit time, which is not specifically limited here.

示例性的,实际中S11可以由前述的流量实时监控模块执行,其采集数据后的记录如下表1:Exemplarily, in practice, S11 can be executed by the aforementioned real-time traffic monitoring module, and the records after the data are collected are as follows in Table 1:

表1Table 1

Figure BDA0002611117520000091
Figure BDA0002611117520000091

其中,YY代表年份,MM代表月份,DD代表MM月的第几天,HH:SS代表时分秒。Among them, YY represents the year, MM represents the month, DD represents the day of the MM month, and HH:SS represents the hour, minute, and second.

可选的,参照图5所示,因为本发明实施例提供的技术方案是基于RRC连接数和有数传的RRC连接数来决定各业务的用户终端是否可接入的,而如果本身各个业务需要的RRC连接数和有数传的RRC连接数都不大,完全不影响共建共享基站的性能,则不需要执行该技术方案,所以在S11步骤前核心网设备03还需要执行如下步骤:Optionally, as shown in FIG. 5 , because the technical solution provided by the embodiment of the present invention is based on the number of RRC connections and the number of RRC connections with data transmission to determine whether the user terminals of each service can be accessed, and if each service needs to be accessed. The number of RRC connections and the number of RRC connections with data transmission are not large, and the performance of the co-construction and sharing base station is not affected at all, so this technical solution does not need to be implemented. Therefore, before step S11, the core network device 03 also needs to perform the following steps:

S1、核心网设备03获取基站承载的每一个业务在当前单位时间之前,预设时间段内属于忙时的每一目标单位时间的平均RRC连接数和平均有数传的RRC连接数。S1. The core network device 03 obtains the average number of RRC connections per target unit time and the average number of RRC connections with data transmission in a preset time period before the current unit time for each service carried by the base station.

示例性的,目标单位时间可以为1小时;为了在节省计算资源的同时保证收集的数据可以反映基站承载的各业务的RRC连接数和有数传的RRC连接数使用情况,上述预设时间段可以为连续两周的周二(任一工作日皆可)和周日(任一休息日皆可)。忙时可以为运营商根据自身对应用户的流量使用情况确定,例如在工作日可以是9:00-11:00和14:00-17:00,非工作日则可以是10:00-17:00。Exemplarily, the target unit time can be 1 hour; in order to save computing resources while ensuring that the collected data can reflect the number of RRC connections of each service carried by the base station and the usage of the number of RRC connections with data transmission, the above-mentioned preset time period can be For two consecutive Tuesdays (any working day) and Sunday (any rest day). Busy hours can be determined by the operator according to the traffic usage of its corresponding users. For example, it can be 9:00-11:00 and 14:00-17:00 on weekdays, and 10:00-17:00 on non-working days: 00.

示例性的,S1步骤主要由图2所示的核心网设备03中的业务依赖度分析模块032执行。Exemplarily, step S1 is mainly performed by the service dependency analysis module 032 in the core network device 03 shown in FIG. 2 .

S2、核心网设备03根据所有业务在预设时间段内属于忙时的每一目标单位时间的平均RRC连接数和平均有数传的RRC连接数,确定大流量目标单位时间。S2. The core network device 03 determines the high traffic target unit time according to the average number of RRC connections per target unit time and the average number of RRC connections with data transmission for all services that belong to the busy hour in the preset time period.

示例性的,当所有业务在预设时间段内属于忙时中的目标单位时间内的平均RRC连接数的和,占基站在一个目标单位时间内可以承载最大RRC连接数的占比大于第三预设占比时,确定目标单位时间为大流量目标单位时间。Exemplarily, when all services in the preset time period belong to the sum of the average number of RRC connections in the target unit time in the busy hour, the proportion of the maximum number of RRC connections that the base station can carry in one target unit time is greater than the third. When the preset ratio is set, the target unit time is determined to be the target unit time of large traffic.

当所有业务在预设时间段内属于忙时中的目标单位时间内的平均有数传的RRC连接数的和,占基站在一个目标单位时间内可以承载最大有数传的RRC连接数的占比大于第四预设占比时,确定目标单位时间为大流量目标单位时间。When all services in the preset time period belong to the average number of RRC connections with data transmission in the target unit time in the busy hour, the proportion of the maximum number of RRC connections with data transmission that the base station can carry in a target unit time is greater than When the fourth preset proportion is used, the target unit time is determined to be the high-flow target unit time.

S3、核心网设备03判断大流量目标单位时间的数量占预设时间段内忙时对应的总目标单位时间数的占比,是否大于预设百分比。S3. The core network device 03 determines whether the ratio of the quantity of the high traffic target unit time to the total target unit time corresponding to the busy time in the preset time period is greater than the preset percentage.

当大流量目标单位时间的数量占所有忙时对应的总目标单位时间数的占比,大于预设百分比时,执行S4;当大流量目标单位时间的数量占所有忙时对应的总目标单位时间数的占比,不大于预设百分比时,执行S1。When the proportion of the high traffic target unit time to the total target unit time corresponding to all busy hours is greater than the preset percentage, execute S4; when the high traffic target unit time accounts for the total target unit time corresponding to all busy hours When the proportion of the number is not greater than the preset percentage, execute S1.

示例性的,预设百分比可以为30%,也可以为其他任意可行数值,此处不做具体限制。Exemplarily, the preset percentage may be 30%, or may be any other feasible value, which is not specifically limited here.

S4、核心网设备03向基站发送相应指令以使其获取基站承载的每一个业务在当前单位时间的RRC连接数和有传输的RRC连接数。S4. The core network device 03 sends a corresponding instruction to the base station so that it acquires the number of RRC connections and the number of RRC connections with transmission in the current unit time for each service carried by the base station.

因为大流量目标单位时间所在的时间内各业务使用的流量是较多的,可以认为是非常依赖RRC连接数和有传输的RRC连接数的,而如果大流量目标单位时间占忙时总目标单位时间数的占比又超过一定比值,则表明该基站承载的各业务是比较依赖RRC连接数和有传输的RRC连接数的,需要发给基站对应的指令使基站执行本发明实施例提供的技术方案。Because the traffic used by each service in the high traffic target unit time is more, it can be considered that it is very dependent on the number of RRC connections and the number of RRC connections with transmission, and if the high traffic target unit time accounts for the total target unit of busy time If the proportion of time number exceeds a certain ratio, it indicates that each service carried by the base station is more dependent on the number of RRC connections and the number of RRC connections with transmission, and a corresponding command needs to be sent to the base station to make the base station execute the technology provided by the embodiment of the present invention. Program.

示例性的,上述S2-S4步骤由图2所示的核心网设备03中的业务依赖度分析模块032执行。Exemplarily, the above steps S2-S4 are performed by the service dependency analysis module 032 in the core network device 03 shown in FIG. 2 .

需要说明的是,实际中核心网设备也可以不执行上述S3步骤,在S2步骤后直接根据大流量目标单位时间的数量占预设时间段内忙时对应的总目标单位时间数的占比确定执行S1步骤还是发送相应指令给核心网设备以使其执行步骤S12即可。另外,大流量目标单位时间的数量占所有忙时对应的总目标单位时间数的占比等于预设百分比,可以归于大流量目标单位时间的数量占所有忙时对应的总目标单位时间数的占比大于预设百分比的情况,也可以归于大流量目标单位时间的数量占所有忙时对应的总目标单位时间数的占比小于预设百分比的情况,图5对应的实例中以其归于大流量目标单位时间的数量占所有忙时对应的总目标单位时间数的占比小于预设百分比的情况为例,但本发明并不对此做具体限制。It should be noted that, in practice, the core network equipment may not perform the above-mentioned step S3, and after the step S2, it is directly determined according to the proportion of the number of high-traffic target unit time to the total target unit time corresponding to the busy time in the preset time period. It is only necessary to perform step S1 or send a corresponding instruction to the core network device to make it perform step S12. In addition, the proportion of the high traffic target unit time to the total target unit time corresponding to all busy hours is equal to the preset percentage, which can be attributed to the proportion of the high traffic target unit time to the total target unit time corresponding to all busy hours. The situation that the ratio is greater than the preset percentage can also be attributed to the situation that the proportion of the target unit time of high traffic to the total target unit time corresponding to all busy hours is less than the preset percentage. In the example corresponding to Figure 5, it is attributed to the high traffic. The proportion of the target unit time to the total target unit time corresponding to all busy hours is less than the preset percentage is taken as an example, but the present invention does not specifically limit this.

S12、基站确定第n个运营商的第k个专网业务的RRC连接数大于第一阈值,和/或第k个专网业务的数传连接数大于第二阈值时,根据N个运营商的网络数据确定第k个专网业务在当前单位时间的带宽需求量。其中,n∈[1,N],且n为整数,k∈[1,K],且k为整数。S12. When the base station determines that the number of RRC connections of the kth private network service of the nth operator is greater than the first threshold, and/or the number of data transmission connections of the kth private network service is greater than the second threshold, according to the number of N operators Determines the bandwidth demand of the kth private network service in the current unit time. where n∈[1,N], and n is an integer, k∈[1,K], and k is an integer.

可选的,第一阈值可以为

Figure BDA0002611117520000111
第二阈值为
Figure BDA0002611117520000112
从而可以防止接入的用户对应的RRC连接数过多时,导致基站无法让新的用户接入的问题。Optionally, the first threshold can be
Figure BDA0002611117520000111
The second threshold is
Figure BDA0002611117520000112
This can prevent the problem that the base station cannot allow new users to access when the number of RRC connections corresponding to the accessing users is too large.

S13、基站确定第n个运营商的剩余带宽大于带宽需求量时,在当前单位时间允许第k个专网业务的新用户接入第k个专网业务对应的核心网设备。S13: When the base station determines that the remaining bandwidth of the nth operator is greater than the bandwidth requirement, it allows new users of the kth private network service to access the core network equipment corresponding to the kth private network service in the current unit time.

由上述可知,基站可以根据当前单位时间的网络数据,确定第n个运营商的第k个专网业务的RRC连接数是否大于第一阈值,和/或该第k个专网业务的数传连接数是否大于第二阈值的第k个专网业务,从而确定当前单位时间该第k个专网业务的新用户是否可以接入该第k个专网业务对应的核心网设备。当基站确定第n个运营商的第k个专网业务的RRC连接数大于第一阈值,和/或第k个专网业务的数传连接数大于第二阈值时,说明此时该第k个专网业务在当前单位时间的请求接入的新用户较多,因此需要确定该第k个专网业务在当前单位时间的带宽需求量。当基站确定第n个运营商的剩余带宽大于带宽需求量时,在当前单位时间允许第k个专网业务的新用户接入第k个专网业务对应的核心网设备。It can be seen from the above that the base station can determine whether the number of RRC connections of the kth private network service of the nth operator is greater than the first threshold according to the network data of the current unit time, and/or the data transmission of the kth private network service. Whether the number of connections is greater than the kth private network service of the second threshold is determined to determine whether a new user of the kth private network service can access the core network device corresponding to the kth private network service in the current unit time. When the base station determines that the number of RRC connections of the kth private network service of the nth operator is greater than the first threshold, and/or the number of data transmission connections of the kth private network service is greater than the second threshold, it indicates that at this time the kth There are many new users requesting access to the private network service in the current unit time, so it is necessary to determine the bandwidth demand of the k-th private network service in the current unit time. When the base station determines that the remaining bandwidth of the nth operator is greater than the bandwidth requirement, it allows new users of the kth private network service to access the core network equipment corresponding to the kth private network service in the current unit time.

在一种可实现的方式中,当目标业务还包括公网业务时,在此情况下,结合图4,如图6所示,本发明实施例提供的用户接入方法还包括S14。In an achievable manner, when the target service also includes a public network service, in this case, with reference to FIG. 4 , as shown in FIG. 6 , the user access method provided by the embodiment of the present invention further includes S14 .

S14、基站确定第n个运营商的公网业务的RRC连接数大于第三阈值,和/或第n个运营商的公网业务的数传连接数大于第四阈值时,在当前单位时间禁止第n个运营商的公网业务的新用户接入第n个运营商的公网业务对应的核心网设备。S14. When the base station determines that the number of RRC connections of the public network service of the nth operator is greater than the third threshold, and/or the number of data transmission connections of the public network service of the nth operator is greater than the fourth threshold, it prohibits the current unit time A new user of the public network service of the nth operator accesses the core network device corresponding to the public network service of the nth operator.

示例性的,以单位时间为1秒,目标单位时间为1小时为例,公网业务的第三阈值和第四阈值可以由以下公式计算得出:Exemplarily, taking the unit time of 1 second and the target unit time of 1 hour as an example, the third threshold and the fourth threshold of the public network service can be calculated by the following formulas:

Figure BDA0002611117520000121
Figure BDA0002611117520000121

Figure BDA0002611117520000122
Figure BDA0002611117520000122

其中,

Figure BDA0002611117520000123
表示约定的每秒公网用户接入数,
Figure BDA0002611117520000124
表示约定的每秒公网有数传的用户接入数,
Figure BDA0002611117520000125
表示公网每小时最大RRC连接数,
Figure BDA0002611117520000126
示公网每小时平均RRC连接数,
Figure BDA0002611117520000127
表示公网每小时最大有数传的RRC连接数,
Figure BDA0002611117520000128
公网每小时平均有数传的RRC连接数。in,
Figure BDA0002611117520000123
Indicates the agreed number of public network user access per second,
Figure BDA0002611117520000124
Indicates the agreed number of users accessing the public network with data transmission per second.
Figure BDA0002611117520000125
Indicates the maximum number of RRC connections per hour on the public network,
Figure BDA0002611117520000126
Shows the average number of RRC connections per hour on the public network,
Figure BDA0002611117520000127
Indicates the maximum number of RRC connections with data transmission per hour on the public network.
Figure BDA0002611117520000128
The average number of RRC connections for data transmission per hour on the public network.

示例性的,第三阈值可以为

Figure BDA0002611117520000129
第四阈值为
Figure BDA00026111175200001210
从而可以防止接入的用户对应的RRC连接数过多时,导致基站无法让新的用户接入的问题。Exemplarily, the third threshold may be
Figure BDA0002611117520000129
The fourth threshold is
Figure BDA00026111175200001210
This can prevent the problem that the base station cannot allow new users to access when the number of RRC connections corresponding to the accessing users is too large.

在一种可实施的方式中,当确定第n个运营商的第k个专网业务的RRC连接数小于或等于第一阈值,并且第n个运营商的第k个专网业务的数传连接数小于或等于第二阈值,并且确定第n个运营商的公网业务的RRC连接数小于或等于第三阈值,并且第n个运营商的公网业务的数传连接数小于或等于第四阈值时,基站正常接入第n个运营商的公网业务以及K个专网业务的新用户。其中,正常接入指维持目前的5QI(5G QoS Identifier)(用于标识5G的Qos(Quality of Service,服务质量))不变的情况,允许各业务对应的新的用户终端接入。In an implementable manner, when it is determined that the number of RRC connections of the kth private network service of the nth operator is less than or equal to the first threshold, and the data transmission of the kth private network service of the nth operator The number of connections is less than or equal to the second threshold, and it is determined that the number of RRC connections of the public network service of the nth operator is less than or equal to the third threshold, and the number of data transmission connections of the public network service of the nth operator is less than or equal to the At four thresholds, the base station normally accesses the public network services of the nth operator and K new users of private network services. Wherein, normal access refers to maintaining the current 5QI (5G QoS Identifier) (used to identify 5G QoS (Quality of Service, quality of service)) unchanged, allowing new user terminals corresponding to each service to access.

需要说明的是,在实际的应用中,由于公网业务的优先级低于专网业务的优先级,因此在基站的带宽资源紧张的情况下(如:第n个运营商的公网业务的RRC连接数大于第三阈值,和/或第n个运营商的公网业务的数传连接数大于第四阈值),通过禁止第n个运营商的公网业务的用户接入,从而可以保证第n个运营商的专网用户的用户体验。It should be noted that, in practical applications, since the priority of public network services is lower than that of private network services, under the circumstance that the bandwidth resources of the base station are tight (for example, the public network service of the nth operator has a The number of RRC connections is greater than the third threshold, and/or the number of data transmission connections of the public network service of the nth operator is greater than the fourth threshold), by prohibiting the access of users of the public network service of the nth operator, it can ensure User experience of private network users of the nth operator.

在一种可实现的方式中,结合图4,如图7所示本发明实施例提供的用户接入方法还包括S15和S16。In an achievable manner, with reference to FIG. 4 , as shown in FIG. 7 , the user access method provided by the embodiment of the present invention further includes S15 and S16 .

S15、基站确定第n个运营商的剩余带宽小于或等于带宽需求量,并且除第n个运营商之外的运营商中存在剩余带宽大于带宽需求量的运营商时,从除第n个运营商之外的运营商中剩余带宽大于带宽需求量的任一个运营商调配资源。S15. When the base station determines that the remaining bandwidth of the n-th operator is less than or equal to the bandwidth demand, and there is an operator whose remaining bandwidth is greater than the bandwidth demand among the operators other than the n-th operator, it will start the operation from the n-th operator when the remaining bandwidth is greater than the bandwidth demand. Any operator other than the operator whose remaining bandwidth is greater than the bandwidth demand allocates resources.

需要说明的是,调配资源是指基站将第j个运营商(为除第n个运营商之外的运营商中存在剩余带宽大于带宽需求量的运营商)的剩余带宽中的部分带宽资源分配给第n个运营商,从而使得第n个运营商的带宽资源在原有的基础上增加了调配的带宽资源,相应的第j个运营商的带宽资源在原有的基础上减少了调配的带宽资源。It should be noted that allocating resources means that the base station allocates part of the bandwidth resources in the remaining bandwidth of the jth operator (for operators other than the nth operator whose remaining bandwidth is greater than the bandwidth demand) For the nth operator, the bandwidth resources of the nth operator increase the allocated bandwidth resources on the original basis, and the corresponding bandwidth resources of the jth operator reduce the allocated bandwidth resources on the original basis .

在一种可实施的方式中,当第j个运营商(也称为其他运营商)在当前单位时间的带宽资源不足时,基站优先将从第j个运营商调配给第n个运营商的带宽资源重新分配回第j个运营商后,如果第j个运营商的带宽资源还是不足,则从其他运营商调配资源。其中,j与n不同,且j∈[1,N],且j为整数。In an implementable manner, when the bandwidth resources of the jth operator (also referred to as other operators) are insufficient in the current unit time, the base station preferentially allocates bandwidth resources from the jth operator to the nth operator After the bandwidth resources are reallocated back to the jth operator, if the bandwidth resources of the jth operator are still insufficient, resources are allocated from other operators. where j is different from n, and j∈[1,N], and j is an integer.

在另一种可实施的方式中,第j个运营商在当前单位时间的带宽资源不足时,基站优先将从第j个运营商调配给第n个运营商的带宽资源重新分配回第j个运营商后,如果第j个运营商的带宽资源和第n个运营商的带宽资源均不足时,优先从其他运营商给第n个运营商调配资源后,若第j个运营商的带宽资源仍不足,则从其他运营商给第j个运营商调配资源。In another implementable manner, when the bandwidth resources of the jth operator in the current unit time are insufficient, the base station preferentially re-allocates the bandwidth resources allocated from the jth operator to the nth operator back to the jth operator After the operator, if both the bandwidth resources of the jth operator and the bandwidth resources of the nth operator are insufficient, after allocating resources to the nth operator from other operators, if the bandwidth resources of the jth operator If it is still insufficient, resources are allocated to the jth operator from other operators.

在另一种可实施的方式中,第j个运营商在当前单位时间的带宽资源不足时,基站优先将从第j个运营商调配给第n个运营商的带宽资源重新分配回第j个运营商后,如果第j个运营商的带宽资源和第n个运营商的带宽资源均不足时,优先给第j个运营商从其他运营商调配资源后,再从其他运营商给第n个运营商调配资源。In another implementable manner, when the bandwidth resources of the jth operator in the current unit time are insufficient, the base station preferentially re-allocates the bandwidth resources allocated from the jth operator to the nth operator back to the jth operator After the operator, if both the bandwidth resources of the jth operator and the bandwidth resources of the nth operator are insufficient, the jth operator will be allocated resources from other operators first, and then the nth operator will be allocated from other operators. Operators allocate resources.

在另一种可实施的方式中,基站为每个运营商(如运营商A、运营商B以及运营商C)设置了不同的优先级,从而当运营商A和运营商B的剩余带宽均小于或等于带宽需求量,并且运营商C的剩余带宽大于带宽需求量时,若运营商A的优先级大于运营商B的优先级,则优先为运营商A调取资源(从运营商C的公网载波调取资源),运营商A调取完资源后,若运营商C还有剩余资源,则再给运营商B调取资源(从运营商C的公网载波调取资源)。In another implementation manner, the base station sets different priorities for each operator (eg, operator A, operator B, and operator C), so that when the remaining bandwidths of operator A and operator B are both When it is less than or equal to the bandwidth demand, and the remaining bandwidth of operator C is greater than the bandwidth demand, if the priority of operator A is higher than that of operator B, the priority is to obtain resources for operator A (from operator C's public network carrier to fetch resources), after operator A has fetched resources, if operator C has remaining resources, it will fetch resources from operator B (resources are fetched from operator C's public network carrier).

S16、基站将调配得到的资源分配给第n个运营商,并在当前单位时间允许第k个专网业务的新用户接入第k个专网业务对应的核心网设备。S16: The base station allocates the allocated resources to the nth operator, and allows new users of the kth private network service to access the core network equipment corresponding to the kth private network service in the current unit time.

需要说明的是,在实际的应用中第n个运营商从其他运营商调配资源时,可以持续预设时间(包括至少一个时刻),当其他运营商的带宽资源不足时,则将调配的资源重新分配至其他运营商。当第n个运营商的剩余带宽在减去从其他运营商调配的资源后大于带宽需求量时,则将调配的资源重新分配至其他运营商。It should be noted that in actual applications, when the nth operator allocates resources from other operators, it can continue for a preset time (including at least one moment), and when the bandwidth resources of other operators are insufficient, the allocated resources Reassign to another carrier. When the remaining bandwidth of the nth operator is greater than the bandwidth requirement after deducting resources allocated from other operators, the allocated resources are reallocated to other operators.

本发明实施例提供的用户接入方法中,每个运营商对应一个载波,因此当第n个运营商对应的载波的带宽资源小于或等于带宽需求量时,需要判别其他运营商对应的载波的是否有剩余的带宽资源,当其他运营商对应的载波的有剩余的带宽资源,通过从其他运营商调取带宽资源,从而保证第n个运营商的专网用户的用户体验,进一步地提高基站的带宽资源使用率。In the user access method provided by the embodiment of the present invention, each operator corresponds to one carrier, so when the bandwidth resource of the carrier corresponding to the nth operator is less than or equal to the bandwidth demand, it is necessary to determine the bandwidth of the carrier corresponding to other operators. Whether there are remaining bandwidth resources, when the carriers corresponding to other operators have remaining bandwidth resources, by fetching bandwidth resources from other operators, the user experience of the private network users of the nth operator is guaranteed, and the base station is further improved. bandwidth resource usage.

在一种可实现的方式中,结合图4,如图8所示本发明实施例提供的用户接入方法还包括S17。In an achievable manner, with reference to FIG. 4 , as shown in FIG. 8 , the user access method provided by the embodiment of the present invention further includes S17 .

S17、基站确定第n个运营商的剩余带宽小于或等于带宽需求量,并且除第n个运营商之外的运营商中不存在剩余带宽大于带宽需求量的运营商时,在当前单位时间禁止第k个专网业务的新用户接入第k个专网业务对应的核心网设备。S17. When the base station determines that the remaining bandwidth of the n-th operator is less than or equal to the bandwidth demand, and there is no operator whose remaining bandwidth is greater than the bandwidth demand among the operators other than the n-th operator, it prohibits the current unit time A new user of the kth private network service accesses the core network equipment corresponding to the kth private network service.

需要说明的是,在当前单位时间第n个运营商的第k个专网业务中已接入基站的用户,基站需要继续为该用户提供服务,而请求接入第n个运营商的第k个专网业务的新用户则需要禁止接入。当基站内各个运营商的剩余带宽都小于或等于带宽需求量时,此时说明各个运营商当前服务的用户数较多,因此不能从其他运营商向第n个运营商调配资源,从而保证每个运营商为各自的用户提供服务。It should be noted that, for a user who has accessed the base station in the kth private network service of the nth operator in the current unit time, the base station needs to continue to provide services for the user, and requests to access the kth operator of the nth operator. New users of private network services need to be prohibited from accessing. When the remaining bandwidth of each operator in the base station is less than or equal to the bandwidth demand, it means that each operator currently serves a large number of users, so resources cannot be allocated from other operators to the nth operator, so as to ensure that every operator Each operator provides services to their respective users.

在一种可实现的方式中,目标业务还包括公网业务,在此情况下,结合图4,如图9所示上述步骤S12可以通过步骤S120实现。In an achievable manner, the target service also includes a public network service. In this case, with reference to FIG. 4 , as shown in FIG. 9 , the above-mentioned step S12 can be implemented through step S120 .

S120、基站确定第n个运营商的第k个专网业务的RRC连接数大于第一阈值,和/或第k个专网业务的数传连接数大于第二阈值时,根据带宽需求量公式以及N个运营商中每个运营商的目标业务在当前单位时间的网络数据,确定第n个运营商的第k个专网业务在当前单位时间的带宽需求量。其中,带宽需求量公式满足:S120. When the base station determines that the number of RRC connections of the kth private network service of the nth operator is greater than the first threshold, and/or the number of data transmission connections of the kth private network service is greater than the second threshold, according to the bandwidth demand formula and the network data of the target service of each of the N operators in the current unit time, to determine the bandwidth demand of the kth private network service of the nth operator in the current unit time. Among them, the bandwidth demand formula satisfies:

Figure BDA0002611117520000151
Figure BDA0002611117520000151

其中,

Figure BDA0002611117520000152
表示带宽需求量,RCCPrAdd表示第k个专网业务在当前单位时间的RRC连接数,
Figure BDA0002611117520000153
表示第k个专网业务在当前单位时间的有数传的RRC连接数,∑RCCPU表示基站在当前单位时间全部公网业务的RRC连接数之和,∑RCCPr表示基站在当前单位时间全部专网业务的RRC连接数之和,
Figure BDA0002611117520000154
表示基站在当前单位时间全部公网业务的有数传的RRC连接数之和,
Figure BDA0002611117520000155
表示基站在当前单位时间全部专网业务的有数传的RRC连接数之和,w表示基站的总带宽。in,
Figure BDA0002611117520000152
Represents the bandwidth demand, RCC PrAdd represents the number of RRC connections of the kth private network service in the current unit time,
Figure BDA0002611117520000153
Indicates the number of RRC connections with data transmission of the kth private network service in the current unit time, ∑RCC PU indicates the sum of the RRC connections of all public network services of the base station in the current unit time, ∑RCC Pr indicates that the base station in the current unit time All private network connections The sum of the number of RRC connections for network services,
Figure BDA0002611117520000154
Indicates the sum of the number of RRC connections with data transmission for all public network services of the base station in the current unit time,
Figure BDA0002611117520000155
Indicates the sum of the number of RRC connections with data transmission for all private network services of the base station in the current unit time, and w represents the total bandwidth of the base station.

在一种可实施的方式中,当

Figure BDA0002611117520000156
大于
Figure BDA0002611117520000157
时,则
Figure BDA0002611117520000158
In one implementation, when
Figure BDA0002611117520000156
more than the
Figure BDA0002611117520000157
time, then
Figure BDA0002611117520000158

在另一种可实施的方式中,当

Figure BDA0002611117520000159
小于
Figure BDA00026111175200001510
时,则
Figure BDA00026111175200001511
In another possible implementation, when
Figure BDA0002611117520000159
less than
Figure BDA00026111175200001510
time, then
Figure BDA00026111175200001511

在另一种可实施的方式中,当

Figure BDA00026111175200001512
等于
Figure BDA00026111175200001513
Figure BDA0002611117520000161
或者
Figure BDA0002611117520000162
In another possible implementation, when
Figure BDA00026111175200001512
equal
Figure BDA00026111175200001513
but
Figure BDA0002611117520000161
or
Figure BDA0002611117520000162

在一种可实现的方式中,网络数据还包括剩余带宽,在此情况下,结合图4,如图10所示本发明实施例提供的用户接入方法还包括S18和S19。In an achievable manner, the network data also includes the remaining bandwidth. In this case, with reference to FIG. 4 , as shown in FIG. 10 , the user access method provided by the embodiment of the present invention further includes S18 and S19 .

S18、基站根据带宽公式以及N个运营商中每个运营商的目标业务在当前单位时间的网络数据,确定第n个运营商在当前单位时间已使用的带宽。其中,带宽公式满足:S18: The base station determines the bandwidth used by the nth operator in the current unit time according to the bandwidth formula and the network data of the target service of each operator in the N operators in the current unit time. Among them, the bandwidth formula satisfies:

Figure BDA0002611117520000163
Figure BDA0002611117520000163

其中,WNT表示已使用的带宽,RCCPU表示第n个运营商的公网业务在当前单位时间的RRC连接数,∑RCCPr表示第n个运营商的全部专网业务在当前单位时间的RRC连接数之和,

Figure BDA0002611117520000164
表示第n个运营商的第k个专网业务在当前单位时间的有数传的RRC连接数,
Figure BDA0002611117520000165
表示第n个运营商的全部专网业务在当前单位时间的有数传的RRC连接数之和,∑RCCPU表示基站在当前单位时间全部公网业务的RRC连接数之和,∑RCCPr表示基站在当前单位时间全部专网业务的RRC连接数之和,∑RRC数传表示基站在当前单位时间全部公网业务的有数传的RRC连接数之和,
Figure BDA0002611117520000166
表示基站在当前单位时间全部专网业务的有数传的RRC连接数之和,w表示基站的总带宽。Among them, W NT represents the used bandwidth, RCC PU represents the number of RRC connections of the public network services of the nth operator in the current unit time, and ∑ RCC Pr represents the total number of private network services of the nth operator in the current unit time. The sum of the number of RRC connections,
Figure BDA0002611117520000164
Indicates the number of RRC connections with data transmission for the kth private network service of the nth operator in the current unit time,
Figure BDA0002611117520000165
Represents the sum of the number of RRC connections with data transmission for all private network services of the nth operator in the current unit time, ∑RCC PU represents the sum of the RRC connections of all public network services of the base station in the current unit time, ∑RCC Pr Represents the base station The sum of the number of RRC connections of all private network services in the current unit time, ∑RRC data transmission represents the sum of the number of RRC connections with data transmission of all public network services of the base station in the current unit time,
Figure BDA0002611117520000166
Indicates the sum of the number of RRC connections with data transmission for all private network services of the base station in the current unit time, and w represents the total bandwidth of the base station.

S19、基站根据第n个运营商的额定带宽与第n个运营商在当前单位时间已使用的带宽,确定第n个运营商的剩余带宽。其中,a=b-c,a表示剩余带宽,b表示第n个运营商的额定带宽,c表示第n个运营商在当前单位时间已使用的带宽。S19. The base station determines the remaining bandwidth of the nth operator according to the rated bandwidth of the nth operator and the bandwidth used by the nth operator in the current unit time. where a=b-c, a represents the remaining bandwidth, b represents the rated bandwidth of the nth operator, and c represents the bandwidth used by the nth operator in the current unit time.

需要说明的是,额定带宽指初始带宽。It should be noted that the rated bandwidth refers to the initial bandwidth.

在一种可实施的方式中,当

Figure BDA0002611117520000167
大于
Figure BDA0002611117520000168
时,则
Figure BDA0002611117520000171
In one implementation, when
Figure BDA0002611117520000167
more than the
Figure BDA0002611117520000168
time, then
Figure BDA0002611117520000171

在另一种可实施的方式中,当

Figure BDA0002611117520000172
小于
Figure BDA0002611117520000173
时,则
Figure BDA0002611117520000174
In another possible implementation, when
Figure BDA0002611117520000172
less than
Figure BDA0002611117520000173
time, then
Figure BDA0002611117520000174

在另一种可实施的方式中,当

Figure BDA0002611117520000175
等于
Figure BDA0002611117520000176
时,则
Figure BDA0002611117520000177
或者
Figure BDA0002611117520000178
In another possible implementation, when
Figure BDA0002611117520000175
equal
Figure BDA0002611117520000176
time, then
Figure BDA0002611117520000177
or
Figure BDA0002611117520000178

在一种可实施的方式中,当剩余带宽小于或等于预设带宽时,执行S13。其中,预设带宽等于预设比例乘以带宽需求量。示例性的,预设比例可以为0.7。In an implementation manner, when the remaining bandwidth is less than or equal to the preset bandwidth, perform S13. The preset bandwidth is equal to the preset ratio multiplied by the bandwidth demand. Exemplarily, the preset ratio may be 0.7.

上述主要从方法的角度对本发明实施例提供的方案进行了介绍。为了实现上述功能,其包含了执行各个功能相应的硬件结构和/或软件模块。本领域技术人员应该很容易意识到,结合本文中所公开的实施例描述的各示例的单元及算法步骤,本发明能够以硬件或硬件和计算机软件的结合形式来实现。某个功能究竟以硬件还是计算机软件驱动硬件的方式来执行,取决于技术方案的特定应用和设计约束条件。专业技术人员可以对每个特定的应用来使用不同方法来实现所描述的功能,但是这种实现不应认为超出本发明的范围。The foregoing mainly introduces the solutions provided by the embodiments of the present invention from the perspective of methods. In order to realize the above-mentioned functions, it includes corresponding hardware structures and/or software modules for executing each function. Those skilled in the art should easily realize that the present invention can be implemented in hardware or a combination of hardware and computer software in conjunction with the units and algorithm steps of each example described in the embodiments disclosed herein. Whether a function is performed by hardware or computer software driving hardware depends on the specific application and design constraints of the technical solution. Skilled artisans may implement the described functionality using different methods for each particular application, but such implementations should not be considered beyond the scope of the present invention.

本发明实施例可以根据上述方法示例对基站进行功能模块的划分,例如,可以对应各个功能划分各个功能模块,也可以将两个或两个以上的功能集成在一个处理模块中。上述集成的模块既可以采用硬件的形式实现,也可以采用软件功能模块的形式实现。需要说明的是,本发明实施例中对模块的划分是示意性的,仅仅为一种逻辑功能划分,实际实现时可以有另外的划分方式。In this embodiment of the present invention, the base station can be divided into functional modules according to the above method examples. For example, each functional module can be divided corresponding to each function, or two or more functions can be integrated into one processing module. The above-mentioned integrated modules can be implemented in the form of hardware, and can also be implemented in the form of software function modules. It should be noted that, the division of modules in the embodiment of the present invention is schematic, and is only a logical function division, and there may be other division manners in actual implementation.

如图11所示,为本发明实施例提供的一种基站10的结构示意图。基站10用于获取N个运营商中每个运营商的目标业务在当前单位时间的网络数据;其中,目标业务包括K个专网业务,网络数据至少包括RRC连接数和数传连接数,N为大于或等于2的整数,K为大于或等于1的整数;确定第n个运营商的第k个专网业务的RRC连接数大于第一阈值,和/或第k个专网业务的数传连接数大于第二阈值时,根据第n个运营商的网络数据确定第k个专网业务在当前单位时间的带宽需求量;其中,n∈[1,N],且n为整数,k∈[1,K],且k为整数;确定第n个运营商的剩余带宽大于带宽需求量时,在当前单位时间允许第k个专网业务的新用户接入第k个专网业务对应的核心网设备。基站10可以包括获取单元101和处理单元102。As shown in FIG. 11 , it is a schematic structural diagram of a base station 10 according to an embodiment of the present invention. The base station 10 is used to obtain the network data of the target service of each operator among the N operators in the current unit time; wherein, the target service includes K private network services, and the network data at least includes the number of RRC connections and the number of data transmission connections, N is an integer greater than or equal to 2, and K is an integer greater than or equal to 1; it is determined that the number of RRC connections of the kth private network service of the nth operator is greater than the first threshold, and/or the number of the kth private network service When the number of connections is greater than the second threshold, determine the bandwidth demand of the kth private network service in the current unit time according to the network data of the nth operator; where, n∈[1, N], and n is an integer, k ∈[1, K], and k is an integer; when it is determined that the remaining bandwidth of the nth operator is greater than the bandwidth demand, new users of the kth private network service are allowed to access the kth private network service corresponding to the current unit time. core network equipment. The base station 10 may include an acquisition unit 101 and a processing unit 102 .

获取单元101,用于获取N个运营商中每个运营商的目标业务在当前单位时间的网络数据。例如,结合图4,获取单元101可以用于执行S11。The obtaining unit 101 is configured to obtain the network data of the target service of each operator among the N operators in the current unit time. For example, in conjunction with FIG. 4 , the obtaining unit 101 may be configured to perform S11.

处理单元102,用于确定获取单元101获取的第n个运营商的第k个专网业务的RRC连接数大于第一阈值,和/或获取单元101获取的第k个专网业务的数传连接数大于第二阈值时,根据获取单元101获取的第n个运营商的网络数据确定第k个专网业务在当前单位时间的带宽需求量。处理单元102,还用于确定第n个运营商的剩余带宽大于带宽需求量时,在当前单位时间允许第k个专网业务的新用户接入第k个专网业务对应的核心网设备。例如,结合图4,获取单元101可以用于执行S12和S13。结合图6,获取单元101可以用于执行S14。结合图7,获取单元101可以用于执行S15和S16。结合图8,获取单元101可以用于执行S17。结合图9,获取单元101可以用于执行S120。结合图10,获取单元101可以用于执行S18和S19。The processing unit 102 is configured to determine that the number of RRC connections of the kth private network service of the nth operator acquired by the acquiring unit 101 is greater than the first threshold, and/or the data transmission of the kth private network service acquired by the acquiring unit 101 When the number of connections is greater than the second threshold, the bandwidth demand of the kth private network service in the current unit time is determined according to the network data of the nth operator acquired by the acquiring unit 101 . The processing unit 102 is further configured to allow new users of the kth private network service to access the core network equipment corresponding to the kth private network service in the current unit time when the remaining bandwidth of the nth operator is greater than the bandwidth requirement. For example, in conjunction with FIG. 4 , the obtaining unit 101 may be used to perform S12 and S13. With reference to FIG. 6 , the obtaining unit 101 may be configured to perform S14. In conjunction with FIG. 7 , the obtaining unit 101 may be used to perform S15 and S16. In conjunction with FIG. 8 , the obtaining unit 101 may be configured to perform S17. With reference to FIG. 9 , the obtaining unit 101 may be configured to perform S120. In conjunction with FIG. 10 , the obtaining unit 101 may be used to perform S18 and S19.

其中,上述方法实施例涉及的各步骤的所有相关内容均可以援引到对应功能模块的功能描述,其作用在此不再赘述。Wherein, all relevant contents of the steps involved in the above method embodiments can be cited in the functional descriptions of the corresponding functional modules, and the functions thereof will not be repeated here.

当然,本发明实施例提供的基站10包括但不限于上述模块,例如基站10还可以包括存储单元103。存储单元103可以用于存储该写基站10的程序代码,还可以用于存储写基站10在运行过程中生成的数据,如写请求中的数据等。Of course, the base station 10 provided in this embodiment of the present invention includes but is not limited to the above-mentioned modules. For example, the base station 10 may further include a storage unit 103 . The storage unit 103 can be used to store the program code of the write base station 10, and can also be used to store data generated during the operation of the write base station 10, such as data in a write request.

图12为本发明实施例提供的一种基站10的结构示意图,如图12所示,该基站10可以包括:至少一个处理器51、存储器52、通信接口53和通信总线54。FIG. 12 is a schematic structural diagram of a base station 10 according to an embodiment of the present invention. As shown in FIG. 12 , the base station 10 may include: at least one processor 51 , a memory 52 , a communication interface 53 and a communication bus 54 .

下面结合图12对基站10的各个构成部件进行具体的介绍:Below in conjunction with FIG. 12 , each component of the base station 10 will be specifically introduced:

其中,处理器51是基站10的控制中心,可以是一个处理器,也可以是多个处理元件的统称。例如,处理器51是一个中央处理器(Central Processing Unit,CPU),也可以是特定集成电路(Application Specific Integrated Circuit,ASIC),或者是被配置成实施本发明实施例的一个或多个集成电路,例如:一个或多个DSP,或,一个或者多个现场可编程门阵列(Field Programmable Gate Array,FPGA)。The processor 51 is the control center of the base station 10, and may be a processor or a general term for multiple processing elements. For example, the processor 51 is a central processing unit (Central Processing Unit, CPU), may also be a specific integrated circuit (Application Specific Integrated Circuit, ASIC), or is configured to implement one or more integrated circuits in the embodiments of the present invention , for example: one or more DSPs, or, one or more Field Programmable Gate Arrays (FPGA).

在具体的实现中,作为一种实施例,处理器51可以包括一个或多个CPU,例如图12中所示的CPU0和CPU1。且,作为一种实施例,基站10可以包括多个处理器,例如图12中所示的处理器51和处理器55。这些处理器中的每一个可以是一个单核处理器(Single-CPU),也可以是一个多核处理器(Multi-CPU)。这里的处理器可以指一个或多个设备、电路、和/或用于处理数据(例如计算机程序指令)的处理核。In a specific implementation, as an embodiment, the processor 51 may include one or more CPUs, such as CPU0 and CPU1 shown in FIG. 12 . And, as an embodiment, the base station 10 may include multiple processors, such as the processor 51 and the processor 55 shown in FIG. 12 . Each of these processors can be a single-core processor (Single-CPU) or a multi-core processor (Multi-CPU). A processor herein may refer to one or more devices, circuits, and/or processing cores for processing data (eg, computer program instructions).

存储器52可以是只读存储器(Read-Only Memory,ROM)或可存储静态信息和指令的其他类型的静态存储设备,随机存取存储器(Random Access Memory,RAM)或者可存储信息和指令的其他类型的动态存储设备,也可以是电可擦可编程只读存储器(ElectricallyErasable Programmable Read-Only Memory,EEPROM)、只读光盘(Compact Disc Read-Only Memory,CD-ROM)或其他光盘存储、光碟存储(包括压缩光碟、激光碟、光碟、数字通用光碟、蓝光光碟等)、磁盘存储介质或者其他磁存储设备、或者能够用于携带或存储具有指令或数据结构形式的期望的程序代码并能够由计算机存取的任何其他介质,但不限于此。存储器52可以是独立存在,通过通信总线54与处理器51相连接。存储器52也可以和处理器51集成在一起。The memory 52 may be a Read-Only Memory (ROM) or other type of static storage device that can store static information and instructions, a Random Access Memory (RAM) or other types of information and instructions that can be stored The dynamic storage device can also be an Electrically Erasable Programmable Read-Only Memory (EEPROM), a Compact Disc Read-Only Memory (CD-ROM) or other optical disk storage, optical disk storage ( including compact discs, laser discs, compact discs, digital versatile discs, Blu-ray discs, etc.), magnetic disk storage media or other magnetic storage devices, or capable of carrying or storing desired program code in the form of instructions or data structures and capable of being stored by a computer any other medium taken, but not limited to this. The memory 52 may exist independently and be connected to the processor 51 through the communication bus 54 . The memory 52 may also be integrated with the processor 51 .

在具体的实现中,存储器52,用于存储本发明中的数据和执行本发明的软件程序。处理器51可以通过运行或执行存储在存储器52内的软件程序,以及调用存储在存储器52内的数据,执行空调器的各种功能。In a specific implementation, the memory 52 is used to store the data in the present invention and execute the software program of the present invention. The processor 51 can execute various functions of the air conditioner by running or executing software programs stored in the memory 52 and calling data stored in the memory 52 .

通信接口53,使用任何收发器一类的装置,用于与其他设备或通信网络通信,如无线接入网(Radio Access Network,RAN),无线局域网(Wireless Local Area Networks,WLAN)、终端、云端等。通信接口53可以包括接收单元实现接收功能,以及发送单元实现发送功能。The communication interface 53, using any device such as a transceiver, is used to communicate with other devices or communication networks, such as radio access network (Radio Access Network, RAN), wireless local area network (Wireless Local Area Networks, WLAN), terminal, cloud Wait. The communication interface 53 may include a receiving unit to implement a receiving function, and a transmitting unit to implement a transmitting function.

通信总线54,可以是工业标准体系结构(Industry Standard Architecture,ISA)总线、外部设备互连(Peripheral Component Interconnect,PCI)总线或扩展工业标准体系结构(Extended Industry Standard Architecture,EISA)总线等。该总线可以分为地址总线、数据总线、控制总线等。为便于表示,图12中仅用一条粗线表示,但并不表示仅有一根总线或一种类型的总线。The communication bus 54 may be an industry standard architecture (Industry Standard Architecture, ISA) bus, a peripheral component interconnect (Peripheral Component Interconnect, PCI) bus, or an extended industry standard architecture (Extended Industry Standard Architecture, EISA) bus or the like. The bus can be divided into address bus, data bus, control bus and so on. For ease of representation, only one thick line is shown in FIG. 12, but it does not mean that there is only one bus or one type of bus.

作为一个示例,结合图11,基站10中的获取单元101实现的功能与图12中的通信接口53的功能相同,处理单元102实现的功能与图12中的处理器51的功能相同,存储单元103实现的功能与图12中的存储器52的功能相同。As an example, referring to FIG. 11 , the functions implemented by the acquisition unit 101 in the base station 10 are the same as those of the communication interface 53 in FIG. 12 , the functions implemented by the processing unit 102 are the same as those of the processor 51 in FIG. 12 , and the storage unit The function implemented by 103 is the same as that of the memory 52 in FIG. 12 .

本发明另一实施例还提供一种计算机可读存储介质,该计算机可读存储介质中存储有指令,当指令在计算机上运行时,使得计算机执行上述方法实施例所示的方法。Another embodiment of the present invention further provides a computer-readable storage medium, where instructions are stored in the computer-readable storage medium, and when the instructions are executed on the computer, the computer is made to execute the method shown in the above method embodiments.

在一些实施例中,所公开的方法可以实施为以机器可读格式被编码在计算机可读存储介质上的或者被编码在其它非瞬时性介质或者制品上的计算机程序指令。In some embodiments, the disclosed methods may be implemented as computer program instructions encoded in a machine-readable format on a computer-readable storage medium or on other non-transitory media or articles of manufacture.

图13示意性地示出本发明实施例提供的计算机程序产品的概念性局部视图,所述计算机程序产品包括用于在计算设备上执行计算机进程的计算机程序。13 schematically shows a conceptual partial view of a computer program product provided by an embodiment of the present invention, the computer program product including a computer program for executing a computer process on a computing device.

在一个实施例中,计算机程序产品是使用信号承载介质410来提供的。所述信号承载介质410可以包括一个或多个程序指令,其当被一个或多个处理器运行时可以提供以上针对图4描述的功能或者部分功能。因此,例如,参考图4中所示的实施例,S11-S13的一个或多个特征可以由与信号承载介质410相关联的一个或多个指令来承担。此外,图13中的程序指令也描述示例指令。In one embodiment, the computer program product is provided using signal bearing medium 410 . The signal bearing medium 410 may include one or more program instructions that, when executed by one or more processors, may provide the functions, or portions thereof, described above with respect to FIG. 4 . Thus, for example, with reference to the embodiment shown in FIG. 4 , one or more features of S11 - S13 may be undertaken by one or more instructions associated with the signal bearing medium 410 . Additionally, the program instructions in Figure 13 also describe example instructions.

在一些示例中,信号承载介质410可以包含计算机可读介质411,诸如但不限于,硬盘驱动器、紧密盘(CD)、数字视频光盘(DVD)、数字磁带、存储器、只读存储记忆体(read-only memory,ROM)或随机存储记忆体(random access memory,RAM)等等。In some examples, the signal bearing medium 410 may include a computer readable medium 411 such as, but not limited to, a hard drive, a compact disc (CD), a digital video disc (DVD), a digital tape, a memory, a read only memory (read only memory) -only memory, ROM) or random access memory (random access memory, RAM), etc.

在一些实施方式中,信号承载介质410可以包含计算机可记录介质412,诸如但不限于,存储器、读/写(R/W)CD、R/W DVD、等等。In some implementations, the signal bearing medium 410 may include a computer recordable medium 412 such as, but not limited to, memory, read/write (R/W) CDs, R/W DVDs, and the like.

在一些实施方式中,信号承载介质410可以包含通信介质413,诸如但不限于,数字和/或模拟通信介质(例如,光纤电缆、波导、有线通信链路、无线通信链路、等等)。In some embodiments, signal bearing medium 410 may include communication medium 413 such as, but not limited to, digital and/or analog communication media (eg, fiber optic cables, waveguides, wired communication links, wireless communication links, etc.).

信号承载介质410可以由无线形式的通信介质413(例如,遵守IEEE802.41标准或者其它传输协议的无线通信介质)来传达。一个或多个程序指令可以是,例如,计算机可执行指令或者逻辑实施指令。The signal bearing medium 410 may be conveyed by a wireless form of communication medium 413 (eg, a wireless communication medium conforming to the IEEE 802.41 standard or other transmission protocol). The one or more program instructions may be, for example, computer-executable instructions or logic-implemented instructions.

在一些示例中,诸如针对图4描述的写数据装置可以被配置为,响应于通过计算机可读介质411、计算机可记录介质412、和/或通信介质413中的一个或多个程序指令,提供各种操作、功能、或者动作。In some examples, a data writing device such as that described with respect to FIG. 4 may be configured to provide, in response to one or more program instructions through computer readable medium 411 , computer recordable medium 412 , and/or communication medium 413 , Various operations, functions, or actions.

通过以上的实施方式的描述,所属领域的技术人员可以清楚地了解到,为描述的方便和简洁,仅以上述各功能模块的划分进行举例说明,实际应用中,可以根据需要而将上述功能分配由不同的功能模块完成,即将装置的内部结构划分成不同的功能模块,以完成以上描述的全部或者部分功能。From the description of the above embodiments, those skilled in the art can clearly understand that for the convenience and brevity of the description, only the division of the above functional modules is used as an example for illustration. In practical applications, the above functions can be allocated as required. It is completed by different functional modules, that is, the internal structure of the device is divided into different functional modules, so as to complete all or part of the functions described above.

在本发明所提供的几个实施例中,应该理解到,所揭露的装置和方法,可以通过其它的方式实现。例如,以上所描述的装置实施例仅仅是示意性的,例如,所述模块或单元的划分,仅仅为一种逻辑功能划分,实际实现时可以有另外的划分方式,例如多个单元或组件可以结合或者可以集成到另一个装置,或一些特征可以忽略,或不执行。另一点,所显示或讨论的相互之间的耦合或直接耦合或通信连接可以是通过一些接口,装置或单元的间接耦合或通信连接,可以是电性,机械或其它的形式。In the several embodiments provided by the present invention, it should be understood that the disclosed apparatus and method may be implemented in other manners. For example, the device embodiments described above are only illustrative. For example, the division of the modules or units is only a logical function division. In actual implementation, there may be other division methods. For example, multiple units or components may be Incorporation may either be integrated into another device, or some features may be omitted, or not implemented. On the other hand, the shown or discussed mutual coupling or direct coupling or communication connection may be through some interfaces, indirect coupling or communication connection of devices or units, and may be in electrical, mechanical or other forms.

所述作为分离部件说明的单元可以是或者也可以不是物理上分开的,作为单元显示的部件可以是一个物理单元或多个物理单元,即可以位于一个地方,或者也可以分布到多个不同地方。可以根据实际的需要选择其中的部分或者全部单元来实现本实施例方案的目的。The units described as separate components may or may not be physically separated, and the components shown as units may be one physical unit or multiple physical units, that is, they may be located in one place, or may be distributed to multiple different places . Some or all of the units may be selected according to actual needs to achieve the purpose of the solution in this embodiment.

另外,在本发明各个实施例中的各功能单元可以集成在一个处理单元中,也可以是各个单元单独物理存在,也可以两个或两个以上单元集成在一个单元中。上述集成的单元既可以采用硬件的形式实现,也可以采用软件功能单元的形式实现。In addition, each functional unit in each embodiment of the present invention may be integrated into one processing unit, or each unit may exist physically alone, or two or more units may be integrated into one unit. The above-mentioned integrated units may be implemented in the form of hardware, or may be implemented in the form of software functional units.

所述集成的单元如果以软件功能单元的形式实现并作为独立的产品销售或使用时,可以存储在一个可读取存储介质中。基于这样的理解,本发明实施例的技术方案本质上或者说对现有技术做出贡献的部分或者该技术方案的全部或部分可以以软件产品的形式体现出来,该软件产品存储在一个存储介质中,包括若干指令用以使得一个设备(可以是单片机,芯片等)或处理器(processor)执行本发明各个实施例所述方法的全部或部分步骤。而前述的存储介质包括:U盘、移动硬盘、ROM、RAM、磁碟或者光盘等各种可以存储程序代码的介质。If the integrated unit is implemented in the form of a software functional unit and sold or used as an independent product, it may be stored in a readable storage medium. Based on such understanding, the technical solutions of the embodiments of the present invention are essentially or contribute to the prior art, or all or part of the technical solutions may be embodied in the form of software products, and the software products are stored in a storage medium Among them, several instructions are included to cause a device (which may be a single-chip microcomputer, a chip, etc.) or a processor (processor) to execute all or part of the steps of the methods described in the various embodiments of the present invention. The aforementioned storage medium includes: a U disk, a removable hard disk, a ROM, a RAM, a magnetic disk, or an optical disk and other mediums that can store program codes.

以上所述,仅为本发明的具体实施方式,但本发明的保护范围并不局限于此,任何在本发明揭露的技术范围内的变化或替换,都应涵盖在本发明的保护范围之内。因此,本发明的保护范围应以所述权利要求的保护范围为准。The above are only specific embodiments of the present invention, but the protection scope of the present invention is not limited thereto, and any changes or substitutions within the technical scope disclosed by the present invention should be covered within the protection scope of the present invention. . Therefore, the protection scope of the present invention should be based on the protection scope of the claims.

Claims (14)

1. A user access method is applied to access network equipment, the access network equipment provides support for public network service and private network service of an operator through a path of carrier wave, and is characterized by comprising the following steps:
acquiring network data of a target service of each operator in N operators in current unit time; the target service comprises K private network services, the network data at least comprises RRC connection number and number transmission connection number, N is an integer greater than or equal to 2, and K is an integer greater than or equal to 1;
when the RRC connection number of the kth private network service of the nth operator is determined to be larger than a first threshold value and/or the data transmission connection number of the kth private network service is determined to be larger than a second threshold value, determining the bandwidth demand of the kth private network service in the current unit time according to the network data of the N operators; wherein N belongs to [1, N ], N is an integer, K belongs to [1, K ], and K is an integer;
and when the residual bandwidth of the nth operator is determined to be larger than the bandwidth demand, allowing the new user of the kth private network service to access the core network equipment corresponding to the kth private network service in the current unit time.
2. The user access method of claim 1, wherein the target service further comprises a public network service;
the user access method further comprises the following steps:
and when the RRC connection number of the public network service of the nth operator is determined to be larger than a third threshold value and/or the data transmission connection number of the public network service of the nth operator is determined to be larger than a fourth threshold value, forbidding a new user of the public network service of the nth operator to access the core network equipment corresponding to the public network service of the nth operator in the current unit time.
3. The user access method of claim 1, further comprising:
determining that the residual bandwidth of the nth operator is less than or equal to the bandwidth demand and when an operator with residual bandwidth greater than the bandwidth demand exists in the operators except the nth operator, allocating resources from any operator with residual bandwidth greater than the bandwidth demand among the operators except the nth operator;
and allocating the allocated resources to the nth operator, and allowing the new user of the kth private network service to access the core network equipment corresponding to the kth private network service in the current unit time.
4. The user access method of claim 1, further comprising:
and when determining that the residual bandwidth of the nth operator is less than or equal to the bandwidth demand and no operator with the residual bandwidth greater than the bandwidth demand exists in the operators except the nth operator, forbidding a new user of the kth private network service to access the core network equipment corresponding to the kth private network service in the current unit time.
5. The user access method of claim 1, wherein the target service further comprises a public network service;
determining the bandwidth demand of the kth private network service in the current unit time according to the network data of the N operators, including:
determining the bandwidth demand of the kth private network service of the nth operator in the current unit time according to a bandwidth demand formula and the network data of the target service of each operator in the N operators in the current unit time; wherein the bandwidth demand formula satisfies:
Figure FDA0002611117510000021
wherein ,
Figure FDA0002611117510000022
indicating bandwidth demand, RCCPrAddRepresents the RRC connection number of the kth private network service in the current unit time,
Figure FDA0002611117510000023
represents the RRC connection number, sigma RCC, of the kth private network service in the current unit timePURepresents the sum of RRC connection numbers of all public network services of the access network equipment in the current unit time, sigma RCCPrRepresents the sum of the RRC connection numbers of all the private network services of the access network equipment in the current unit time,
Figure FDA0002611117510000024
the sum of the number of RRC connections which represents the number of all public network services of the access network equipment in the current unit time,
Figure FDA0002611117510000025
and the sum of the number of the RRC connections which represent the number of all private network services of the access network equipment in the current unit time is transmitted, and w represents the total bandwidth of the access network equipment.
6. The user access method of claim 1, wherein the network data further comprises a remaining bandwidth;
when it is determined that the remaining bandwidth of the nth operator is greater than the bandwidth requirement, before a new user of the kth private network service is allowed to access the core network device corresponding to the kth private network service in the current unit time, the user access method further includes:
determining the bandwidth used by the nth operator in the current unit time according to a bandwidth formula and the network data of the target service of each operator in the N operators in the current unit time; wherein the bandwidth formula satisfies:
Figure FDA0002611117510000031
wherein ,RCCPURepresents the RRC connection number of the public network service of the nth operator in the current unit time, sigma RCCPrRepresents the sum of the RRC connections per unit time of all private network services of the nth operator,
Figure FDA0002611117510000032
the number of the RRC connections with data transmission of the kth private network carrier of the nth operator in the current unit time is represented,
Figure FDA0002611117510000033
sum of all the transmitted RRC connection numbers of the n-th operator's private network services in the current unit time, sigma RCCPURepresents the sum of RRC connection numbers of all public network services of the access network equipment in the current unit time, sigma RCCPrRepresents the sum of the RRC connection numbers of all the private network services of the access network equipment in the current unit time,
Figure FDA0002611117510000034
the sum of the number of RRC connections which represents the number of all public network services of the access network equipment in the current unit time,
Figure FDA0002611117510000035
the sum of the number of RRC connections which represent the number of all private network services of the access network equipment in the current unit time is transmitted, and w represents the total bandwidth of the access network equipment;
and determining the residual bandwidth of the nth operator according to the rated bandwidth of the nth operator and the bandwidth used by the nth operator in the current unit time.
7. An access network device, which provides support for public network service and private network service of an operator through a path of carrier, comprising:
the system comprises an acquisition unit, a processing unit and a processing unit, wherein the acquisition unit is used for acquiring network data of a target service of each operator in N operators in current unit time; the target service comprises K private network services, the network data at least comprises RRC connection number and number transmission connection number, N is an integer greater than or equal to 2, and K is an integer greater than or equal to 1;
a processing unit, configured to determine that the RRC connection number of the kth private network service of the nth operator acquired by the acquisition unit is greater than a first threshold, and/or when the data transfer connection number of the kth private network service acquired by the acquisition unit is greater than a second threshold, determine a bandwidth demand of the kth private network service in the current unit time according to the network data of the N operators acquired by the acquisition unit; wherein N belongs to [1, N ], N is an integer, K belongs to [1, K ], and K is an integer;
the processing unit is further configured to allow a new user of the kth private network service to access core network equipment corresponding to the kth private network service in the current unit time when it is determined that the remaining bandwidth of the nth operator is greater than the bandwidth demand.
8. The access network device of claim 7, wherein the target traffic further comprises public network traffic;
the processing unit is further configured to prohibit, in the current unit time, a new user of the public network service of the nth operator from accessing the core network device corresponding to the public network service of the nth operator when it is determined that the RRC connection number of the public network service of the nth operator acquired by the acquiring unit is greater than a third threshold and/or the data transfer connection number of the public network service of the nth operator acquired by the acquiring unit is greater than a fourth threshold.
9. The access network device according to claim 7, wherein the processing unit is further configured to determine that the remaining bandwidth of the nth operator acquired by the acquiring unit is less than or equal to the bandwidth requirement amount, and when there is an operator whose remaining bandwidth is greater than the bandwidth requirement amount among the operators other than the nth operator, allocate a resource from any operator whose remaining bandwidth is greater than the bandwidth requirement amount among the operators other than the nth operator;
the processing unit is further configured to allocate the allocated resources to the nth operator, and allow the new user of the kth private network service to access the core network device corresponding to the kth private network service in the current unit time.
10. The access network device of claim 7, wherein the processing unit is further configured to determine that the remaining bandwidth of the nth operator acquired by the acquiring unit is less than or equal to the bandwidth demand, and when an operator with a remaining bandwidth greater than the bandwidth demand does not exist in the operators except the nth operator, prohibit a new user of the kth private network service from accessing the core network device corresponding to the kth private network service in a current unit time.
11. The access network device of claim 7, wherein the target traffic further comprises public network traffic;
the processing unit is specifically configured to determine a bandwidth demand of a kth private network service of the nth operator in a current unit time according to a bandwidth demand formula and the network data, acquired by the acquiring unit, of the target service of each operator in the N operators in the current unit time; wherein the bandwidth demand formula satisfies:
Figure FDA0002611117510000041
wherein ,
Figure FDA0002611117510000042
indicating bandwidth demand, RCCPrAddRepresents the RRC connection number of the kth private network service in the current unit time,
Figure FDA0002611117510000043
represents the RRC connection number, sigma RCC, with data transmission of the kth private network service in the current unit timePURepresents the sum of RRC connection numbers of all public network services of the access network equipment in the current unit time, sigma RCCPrRepresents the sum of the RRC connection numbers of all the private network services of the access network equipment in the current unit time,
Figure FDA0002611117510000051
the sum of the number of RRC connections which represents the number of all public network services of the access network equipment in the current unit time,
Figure FDA0002611117510000052
and the sum of the number of the RRC connections which represent the number of all private network services of the access network equipment in the current unit time is transmitted, and w represents the total bandwidth of the access network equipment.
12. The access network device of claim 7, wherein the network data further comprises a remaining bandwidth;
the processing unit is specifically configured to determine, according to a bandwidth formula and the network data of the target service of each operator in the N operators, acquired by the acquiring unit, in the current unit time, a bandwidth used by the nth operator in the current unit time; wherein the bandwidth formula satisfies:
Figure FDA0002611117510000053
wherein ,RCCPURepresents the RRC connection number of the public network service of the nth operator in the current unit time, sigma RCCPrRepresents the sum of the RRC connections per unit time of all private network services of the nth operator,
Figure FDA0002611117510000054
the number of the RRC connections with data transmission of the kth private network carrier of the nth operator in the current unit time is represented,
Figure FDA0002611117510000055
sum of all the transmitted RRC connection numbers of the n-th operator's private network services in the current unit time, sigma RCCPURepresents the sum of RRC connection numbers of all public network services of the access network equipment in the current unit time, sigma RCCPrRepresents the sum of the RRC connection numbers of all the private network services of the access network equipment in the current unit time,
Figure FDA0002611117510000056
the sum of the number of RRC connections which represents the number of all public network services of the access network equipment in the current unit time,
Figure FDA0002611117510000057
the sum of the number of RRC connections which represent the number of all private network services of the access network equipment in the current unit time is transmitted, and w represents the total bandwidth of the access network equipment;
the processing unit is specifically configured to determine the remaining bandwidth of the nth operator according to the rated bandwidth of the nth operator and the bandwidth used by the nth operator in the current unit time.
13. A computer-readable storage medium comprising instructions which, when executed on a computer, cause the computer to perform the user access method of any of claims 1-6.
14. An access network device, comprising: communication interface, processor, memory, bus;
the memory is used for storing computer execution instructions, and the processor is connected with the memory through the bus;
the processor executes the computer-executable instructions stored by the memory when the access network device is operating to cause the access network device to perform the user access method of any of claims 1-6 above.
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