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WO2015021592A1 - Method and device for allocating transmission power - Google Patents

Method and device for allocating transmission power Download PDF

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Publication number
WO2015021592A1
WO2015021592A1 PCT/CN2013/081353 CN2013081353W WO2015021592A1 WO 2015021592 A1 WO2015021592 A1 WO 2015021592A1 CN 2013081353 W CN2013081353 W CN 2013081353W WO 2015021592 A1 WO2015021592 A1 WO 2015021592A1
Authority
WO
WIPO (PCT)
Prior art keywords
power
load
cell
transmit power
transmission power
Prior art date
Legal status (The legal status is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the status listed.)
Ceased
Application number
PCT/CN2013/081353
Other languages
French (fr)
Chinese (zh)
Inventor
陈斌
巴万宏
Current Assignee (The listed assignees may be inaccurate. Google has not performed a legal analysis and makes no representation or warranty as to the accuracy of the list.)
Huawei Technologies Co Ltd
Original Assignee
Huawei Technologies Co Ltd
Priority date (The priority date is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the date listed.)
Filing date
Publication date
Application filed by Huawei Technologies Co Ltd filed Critical Huawei Technologies Co Ltd
Priority to PCT/CN2013/081353 priority Critical patent/WO2015021592A1/en
Priority to CN201380001937.4A priority patent/CN103858494B/en
Publication of WO2015021592A1 publication Critical patent/WO2015021592A1/en
Anticipated expiration legal-status Critical
Ceased legal-status Critical Current

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Classifications

    • H—ELECTRICITY
    • H04—ELECTRIC COMMUNICATION TECHNIQUE
    • H04W—WIRELESS COMMUNICATION NETWORKS
    • H04W52/00—Power management, e.g. Transmission Power Control [TPC] or power classes
    • H04W52/04—Transmission power control [TPC]
    • H04W52/06—TPC algorithms
    • H04W52/14—Separate analysis of uplink or downlink
    • H04W52/143—Downlink power control
    • H—ELECTRICITY
    • H04—ELECTRIC COMMUNICATION TECHNIQUE
    • H04W—WIRELESS COMMUNICATION NETWORKS
    • H04W52/00—Power management, e.g. Transmission Power Control [TPC] or power classes
    • H04W52/04—Transmission power control [TPC]
    • H04W52/18—TPC being performed according to specific parameters
    • H04W52/22—TPC being performed according to specific parameters taking into account previous information or commands
    • H04W52/228—TPC being performed according to specific parameters taking into account previous information or commands using past power values or information
    • H—ELECTRICITY
    • H04—ELECTRIC COMMUNICATION TECHNIQUE
    • H04W—WIRELESS COMMUNICATION NETWORKS
    • H04W52/00—Power management, e.g. Transmission Power Control [TPC] or power classes
    • H04W52/04—Transmission power control [TPC]
    • H04W52/30—Transmission power control [TPC] using constraints in the total amount of available transmission power
    • H04W52/34—TPC management, i.e. sharing limited amount of power among users or channels or data types, e.g. cell loading
    • H04W52/343—TPC management, i.e. sharing limited amount of power among users or channels or data types, e.g. cell loading taking into account loading or congestion level
    • H—ELECTRICITY
    • H04—ELECTRIC COMMUNICATION TECHNIQUE
    • H04W—WIRELESS COMMUNICATION NETWORKS
    • H04W52/00—Power management, e.g. Transmission Power Control [TPC] or power classes
    • H04W52/04—Transmission power control [TPC]
    • H04W52/30—Transmission power control [TPC] using constraints in the total amount of available transmission power
    • H04W52/34—TPC management, i.e. sharing limited amount of power among users or channels or data types, e.g. cell loading
    • H04W52/346—TPC management, i.e. sharing limited amount of power among users or channels or data types, e.g. cell loading distributing total power among users or channels

Definitions

  • the present invention relates to the field of wireless communications, and in particular, to a method and apparatus for allocating transmit power. Background technique
  • a conventional antenna forms a beam in a vertical direction, the beam covers a cell, and an Adaptive Antenna System (ASS) can form two beams in a vertical direction, and the two beams can Cover two separate cells.
  • ASS Adaptive Antenna System
  • a fixed transmit power is allocated to the two cells, and the sum of the transmit powers of the two cells is equal to the transmit power of the antenna.
  • the number of users in the cell covered by the antenna is dynamically changed in real time. When one cell accesses more users and congestion occurs, and another cell accesses few users, the access is performed at this time.
  • the transmit power of a cell with a large number of users and congestion is insufficient, and the transmit power of a cell with few users is the remaining, which not only leads to the performance of the cell with more access and the performance of the cell with congestion and the edge throughput. Poor, it also leads to a waste of very few cell resources for the users who access. Summary of the invention
  • an embodiment of the present invention provides a method and apparatus for allocating transmit power.
  • the technical solution is as follows:
  • a method for allocating transmit power is provided, where the method includes:
  • the network side device acquires the first transmit power and the second transmit power, and/or acquires the first load and the second load, where the first transmit power is the transmit power currently used by the first cell, and the second transmit power is The transmit power currently used by the two cells, the first load is the load of the first cell, the second load is the load of the second cell, and the first cell and the second cell are adaptive.
  • the network side device calculates power according to the third transmit power and the first transmit power a difference, the third transmit power is a transmit power allocated by the network side device to the first cell; the network side device decreases the third transmit power by the power difference, and fourth The transmit power increases the power difference, and the fourth transmit power is a transmit power allocated by the network side device to the second cell.
  • the network side device reduces the third transmit power by the power difference, and increases the fourth transmit power by the power Differences, including:
  • the network side device decreases the third transmit power by the power difference and increases the fourth transmit power by the power difference.
  • the method further includes:
  • the network side device calculates the first user connection number according to the first user connection number and the second user connection number. a ratio of the number of connections to the second user, where the number of first users is the number of user connections of the first cell, and the number of connections of the second user is the number of connections of the second cell;
  • the network side device decreases the third transmit power by the power difference and increases the fourth transmit power by the power difference.
  • the network side device includes Base station or centralized controller device.
  • an apparatus for allocating transmit power is provided, the apparatus comprising:
  • An acquiring unit configured to acquire a first transmit power and a second transmit power, and/or obtain a first load and a second load, where the first transmit power is a transmit power currently used by the first cell, and the second transmit power is For the transmit power currently used by the second cell, the first load is the load of the first cell, the second load is the load of the second cell, and the first cell and the second cell are Two cells after vertical splitting of the adaptive antenna system AAS;
  • a first calculating unit configured to: if the first transmit power acquired by the acquiring unit is smaller than a first power threshold and the second transmit power is greater than a second power threshold, or for a first load acquired by the acquiring unit If the second load is greater than the second load threshold, the power difference is calculated according to the third transmit power and the first transmit power, where the third transmit power is the network side. a transmission power allocated by the device to the first cell;
  • an increasing or decreasing unit configured to reduce the third transmit power by a power difference calculated by the first calculating unit, and increase a fourth transmit power by a power difference calculated by the first calculating unit, where the fourth The transmit power is the transmit power allocated by the network side device to the second cell.
  • the increasing or decreasing unit is configured to: if the power difference calculated by the first calculating unit is greater than a minimum power threshold, The three transmit power reduces the power difference calculated by the first calculation unit, and increases the fourth transmit power by the power difference calculated by the first calculation unit.
  • the device further includes:
  • a second calculating unit configured to calculate, according to the first user connection number and the second user connection number, if the first load acquired by the acquiring unit is greater than a third load threshold and the second load is greater than a fourth load threshold a ratio between the number of the first user connections and the number of the second user connections, where the number of first users is the number of user connections in the first cell, and the number of connections in the second user is the second cell Number of user connections;
  • the increasing or decreasing unit is further configured to: if the ratio calculated by the second calculating unit is less than a preset value, reduce the third transmit power by a power difference calculated by the first calculating unit, and The transmit power increases the power difference calculated by the first computing unit.
  • the device includes a base station or Centralize the controller device.
  • an apparatus for allocating transmit power comprising a memory and a processor, the memory for storing a code, the processor for executing the code stored by the memory, performing the one of the A method of allocating transmit power, including:
  • first transmit power and a second transmit power and/or acquiring a first load and a second load, where the first transmit power is a transmit power currently used by the first cell, and the second transmit power is a current current of the second cell
  • the transmit power used, the first load is a load of the first cell, the second load is a load of the second cell, and the first cell and the second cell are an adaptive antenna system AAS Two cells after vertical splitting;
  • first transmit power is less than the first power threshold and the second transmit power is greater than the second a power threshold, or, if the first load is smaller than the first load threshold and the second load is greater than the second load threshold, calculating a power difference according to the third transmit power and the first transmit power, where the third The transmit power is a transmit power allocated by the network side device to the first cell;
  • the processor is configured to reduce the third transmit power by the power difference, and increase the fourth transmit power by the power Differences, including:
  • the processor is further configured to:
  • first load is greater than the third load threshold and the second load is greater than the fourth load threshold, calculating the first user connection number and the second according to the first user connection number and the second user connection number a ratio of the number of user connections, the number of first user connections is the number of user connections of the first cell, and the number of second user connections is the number of user connections of the second cell;
  • the third transmit power is decreased by the power difference, and the fourth transmit power is increased by the power difference.
  • the device includes a base station or Centralize the controller device.
  • FIG. 1 is a flowchart of a method for allocating transmit power according to Embodiment 1 of the present invention
  • FIG. 2 is a flowchart of a method for allocating transmit power according to Embodiment 2 of the present invention
  • FIG. 3 is a flowchart of a method for allocating transmit power according to Embodiment 3 of the present invention.
  • FIG. 4 is a schematic structural diagram of an apparatus for allocating transmit power according to Embodiment 4 of the present invention
  • FIG. 5 is a schematic structural diagram of another apparatus for allocating transmit power according to Embodiment 4 of the present invention
  • FIG. 6 is a schematic diagram of Embodiment 5 of the present invention.
  • An embodiment of the present invention provides a method for allocating transmit power.
  • the method includes: Step 101: A network side device acquires a first transmit power and a second transmit power, and/or acquires a first load and a second load.
  • the first transmit power is the transmit power currently used by the first cell
  • the second transmit power is the transmit power currently used by the second cell, where the first load is the load of the first cell, and the second load is the load of the second cell.
  • the first cell and the second cell are two cells after the vertical splitting of the AAS; optionally, the first cell and the second cell may also be two cells after the AAS horizontal splitting.
  • Step 102 If the first transmit power is less than the first power threshold and the second transmit power is greater than the second power threshold, or the first load is less than the first load threshold and the second load is greater than the second load threshold, step 103 is performed, otherwise , performing step 105;
  • Step 103 The network side device calculates a power difference according to the third transmit power and the first transmit power, where the third transmit power is a transmit power allocated by the network side device to the first cell.
  • Step 104 The network side device reduces the power difference of the third transmit power, and increases the power difference between the fourth transmit power, where the fourth transmit power is the transmit power allocated by the network side device to the second cell.
  • the third transmit power is decreased by the power difference, and the fourth transmit power is increased by the power difference.
  • the third transmit power is decreased by the power difference, and after the fourth transmit power is increased by the power difference, the third transmit power and the fourth transmit power are changed.
  • the third transmit power is reduced by the power difference, and the fourth transmit power is increased by the power difference, which also wastes computational resources. Therefore, the power difference is judged compared to the non-power difference, and the network can be saved.
  • the computing resources of the side device are not limited to the power difference.
  • Step 105 Keep the third transmit power and the fourth transmit power unchanged.
  • the network side device may include a base station or a centralized controller device, and the base station includes an eNodeB of a Long Term Evolution (LTE)/LTE Evolution (LTE-Advanced) system, and a broadband.
  • the NodeB of the code division multiple access (WCDMA) system the centralized controller device includes a base station control device of the LTE/LTE-A system, a radio network controller (RNC) of the WCDMA system, and the like.
  • RNC radio network controller
  • Embodiments of the present invention provide a method for allocating transmit power.
  • the downlink transmit power of the user is implemented by dynamic power control, so the downlink transmit power of the user may be dynamically changed in real time.
  • the embodiment of the present invention may be based on the transmit power currently used by the first cell. And the transmit power currently used by the second cell, and the transmit power allocated to the first cell and the transmit power allocated to the second cell are adjusted.
  • the method includes:
  • Step 201 Obtain a first transmit power that is a transmit power currently used by the first cell, and a second transmit power that is a transmit power currently used by the second cell.
  • Step 202 Determine whether the first transmit power is less than the first power threshold and the second transmit power is greater than the second power threshold, if yes, go to step 203, otherwise, go to step 205;
  • Step 203 Calculate a power difference according to the third transmit power and the first transmit power, where the third transmit power is a transmit power allocated to the first cell.
  • the third transmit power is subtracted from the first transmit power to obtain a power difference.
  • the first cell is allocated one transmit power, that is, the third transmit power
  • the second cell is allocated one transmit power, that is, the fourth transmit power
  • the third transmit power and the fourth transmit power may be equal. It may also be unequal, and only the sum of the third transmit power and the fourth transmit power is equal to the transmit power of the AAS antenna.
  • Step 204 Decrease the third transmit power by a power difference, and increase the fourth transmit power by a power difference, where the fourth transmit power is a transmit power allocated to the second cell.
  • the power difference is compared with a minimum power threshold. If the power difference is greater than the minimum power threshold, the third transmit power is decreased by the power difference, and the fourth transmit power is increased by the power difference.
  • the power difference is less than or equal to the minimum power threshold, no adjustment is made for the third transmit power and the fourth transmit power.
  • the third transmit power is decreased by the power difference, and after the fourth transmit power is increased by the power difference, the third transmit power and the fourth transmit power are changed.
  • the power difference is judged compared to the power difference, the computing resources of the network side device can be saved.
  • Step 205 Keep the third transmit power and the fourth transmit power unchanged.
  • the first load and the second load are further acquired, where the first load is a load of the first cell, and the second load is a load of the second cell, according to the first load and the second load pair.
  • the third transmit power and the fourth transmit power are adjusted.
  • the network side device adjusts the user-level parameters, and then adjusts the transmit power of the Physical Downlink Shared Channel (PDSCH), and
  • PDSCH Physical Downlink Shared Channel
  • SIB System Information Broadcase
  • the transmit power of the PDSCH of the user is adjusted, the transmit power of the adjusted PDSCH is passed.
  • the SIB message is sent to the user equipment corresponding to the user, so that the user equipment corresponding to the user adjusts the power of the demodulated data, so that the user equipment corresponding to the user correctly demodulates the data.
  • the embodiment of the present invention for two cells after the vertical splitting of the AAS, when one cell accesses more users and another cell accesses fewer users, power is adjusted by using two cells, thereby avoiding A cell in which a cell with more users is not used, and a cell with fewer users is accessed.
  • the transmit power remaining the embodiment of the present invention reasonably utilizes the network resources of the two cells, improves the performance and edge throughput of the cells with more users, and improves the performance of the network.
  • Embodiments of the present invention provide a method for allocating transmit power.
  • the downlink transmit power of the user is unchanged.
  • the transmit power and the allocation allocated to the first cell may be adopted by the load of the first cell and the load of the second cell.
  • the transmit power of the second cell is adjusted. Referring to Figure 3, the method includes:
  • Step 301 Acquire a first load, a second load, a first transmit power, and a second transmit power, where the first load is a load of the first cell, the second load is a load of the second cell, and the first transmit power is a first cell The currently used transmit power, the second transmit power is the transmit power currently used by the second cell;
  • Step 302 Determine whether the first load is smaller than the first load threshold and the second load is greater than the second load threshold, and if yes, perform the step 303, otherwise, performing step 305;
  • Step 303 Calculate a power difference according to the third transmit power and the first transmit power, where the third transmit power is a transmit power allocated to the first cell.
  • the third transmit power is subtracted from the first transmit power to obtain a power difference.
  • the first cell is allocated one transmit power, that is, the third transmit power
  • the second cell is allocated one transmit power, that is, the fourth transmit power
  • the third transmit power and the fourth transmit power may be equal or not equal. It suffices that the sum of the third transmit power and the fourth transmit power is equal to the transmit power of the AAS antenna.
  • Step 304 Reduce a third transmit power by a power difference, and increase a fourth transmit power by a power difference, where the fourth transmit power is a transmit power allocated to the second cell.
  • the power difference is compared with a minimum power threshold. If the power difference is greater than the minimum power threshold, the third transmit power is decreased by the power difference, and the fourth transmit power is increased by the power difference.
  • the power difference is less than or equal to the minimum power threshold, no adjustment is made for the third transmit power and the fourth transmit power.
  • the third transmit power is decreased by the power difference, and after the fourth transmit power is increased by the power difference, the third transmit power and the fourth transmit power are changed.
  • Small so that it may not solve the problem that the cell transmission power of the access user is insufficient, and reducing the power difference of the third transmit power and increasing the power difference of the fourth transmit power wastes computing resources, so Judging the power difference is compared to not determining the power difference. To save computing resources of network side devices.
  • the third transmit power and the fourth transmit power may also be adjusted by using the first transmit power and the second transmit power in the embodiment of the present invention.
  • Step 305 If the first load is greater than the third load threshold and the second load is greater than the fourth load threshold, step 306 is performed, otherwise, step 309 is performed;
  • the third load threshold is greater than or equal to the first load threshold, and the fourth load threshold is less than or equal to the second load threshold.
  • Step 306 Calculate a ratio between the first user connection number and the second user connection number according to the first user connection number and the second user connection number, where the first user connection number is the number of user connections of the first cell, and the second user The number of connections is the number of user connections of the second cell;
  • the first user connection number is compared with the second user connection number to obtain a ratio between the first user connection number and the second user connection number.
  • the first user connection number and the second user connection number may be obtained at any time before the step, which is not specifically limited in the embodiment of the present invention.
  • Step 307 If the ratio is less than a preset value, calculate a power difference according to the third transmit power and the first transmit power;
  • the ratio between the number of the first user connections and the number of the second user connections is less than a preset value, the user equipment in the second cell is particularly large, and the user equipment in the first cell is compared to the second cell. There are fewer user devices.
  • Step 308 Decrease the third transmit power by a power difference, and increase the fourth transmit power by a power difference
  • the power difference is compared with a minimum power threshold. If the power difference is greater than the minimum power threshold, the third transmit power is decreased by the power difference, and the fourth transmit power is increased by the power difference.
  • the power difference is less than or equal to the minimum power threshold, no adjustment is made for the third transmit power and the fourth transmit power.
  • Step 309 Keep the third transmit power and the fourth transmit power unchanged.
  • the network side device adjusts the cell level parameter of the first cell, and further adjusts the PDSCH transmit power of the first cell, and provides the user to the first cell.
  • the corresponding user equipment sends an SIB message to enable the first cell to be included.
  • the user equipment corresponding to the user knows that the downlink transmit power is adjusted; and adjusts the cell level parameter of the second cell, and then adjusts the PDSCH transmit power of the second cell, and sends the SIB message to the user equipment corresponding to the user included in the second cell.
  • the user equipment corresponding to the user included in the second cell is made aware that its downlink transmit power is adjusted.
  • the transmit power of the adjusted PDSCH is sent to the SIB message through the SIB message.
  • the user equipment corresponding to the user included in the cell adjusts the power of the demodulated data to the user equipment corresponding to the user included in the cell, so that the user equipment corresponding to the user correctly demodulates the data.
  • An embodiment of the present invention provides an apparatus for allocating transmit power.
  • the apparatus includes: an obtaining unit 401, configured to acquire a first transmit power and a second transmit power, and/or acquire a first load and a second load.
  • the first transmit power is the transmit power currently used by the first cell
  • the second transmit power is the transmit power currently used by the second cell, where the first load is the load of the first cell, and the second load is the load of the second cell,
  • One cell and the second cell are two cells after the vertical splitting of the adaptive antenna system AAS;
  • the first calculating unit 402 is configured to: if the first transmit power acquired by the obtaining unit 401 is smaller than the first power threshold and the second transmit power is greater than the second power threshold, or if the first load acquired by the obtaining unit 401 is smaller than the first The load threshold is used, and the second load is greater than the second load threshold, and the power difference is calculated according to the third transmit power and the first transmit power, where the third transmit power is the transmit power allocated by the network side device to the first cell;
  • the increasing or decreasing unit 403 is configured to reduce the third transmit power by the power difference calculated by the first calculating unit 402, and increase the fourth transmit power by the power difference calculated by the first calculating unit 402, where the fourth transmit power is the network side.
  • the increasing or decreasing unit 403 is configured to: if the power difference calculated by the first calculating unit 402 is greater than The minimum power threshold reduces the third transmit power by the power difference and increases the fourth transmit power by the power difference.
  • the device further includes:
  • the second calculating unit 404 is configured to calculate, according to the first user connection number and the second user connection number, the first user, if the first load acquired by the obtaining unit 401 is greater than the third load threshold and the second load is greater than the fourth load threshold a ratio between the number of connections and the number of connections of the second user, the number of connections of the first user is the number of user connections of the first cell, and the number of connections of the second user is the number of connections of the second cell;
  • the increasing or decreasing unit 403 is further configured to: if the ratio calculated by the second calculating unit 404 is less than a preset value, reduce the third transmitting power by the power difference calculated by the first calculating unit 402, and increase the fourth transmitting power by the first The power difference calculated by the calculation unit 402.
  • the device comprises a base station or a centralized controller device.
  • an embodiment of the present invention provides an apparatus for allocating transmit power.
  • the apparatus includes: a memory 501 and a processor 502.
  • the memory 501 is configured to store code
  • the processor 502 is configured to execute the code stored in the memory 501.
  • first transmit power and a second transmit power and/or acquiring a first load and a second load, where the first transmit power is a transmit power currently used by the first cell, and the second transmit power is a current current of the second cell
  • the transmit power used, the first load is a load of the first cell, the second load is a load of the second cell, and the first cell and the second cell are an adaptive antenna system AAS Two cells after vertical splitting;
  • the first transmit power is less than the first power threshold and the second transmit power is greater than the second power threshold, or the first load is less than the first load threshold and the second load is greater than the second load threshold, Calculating a power difference according to the third transmit power and the first transmit power, where the third transmit power is a transmit power allocated by the network side device to the first cell;
  • the fourth transmit power is a transmit power allocated by the network side device to the second cell.
  • the third transmit power is decreased by the power difference and the fourth transmit power is increased by a power difference.
  • processor 502 is further configured to:
  • first load is greater than the third load threshold and the second load is greater than the fourth load threshold, calculating the first user connection number and the second according to the first user connection number and the second user connection number a ratio of the number of user connections, the number of first user connections is the number of user connections of the first cell, and the number of second user connections is the number of user connections of the second cell;
  • the third transmit power is decreased by the power difference, and the fourth transmit power is increased by a power difference.
  • the device includes a base station or a centralized controller device.

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  • Computer Networks & Wireless Communication (AREA)
  • Signal Processing (AREA)
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Abstract

The present invention relates to the field of wireless communications. Provided in an embodiment of the present invention are a method and device for allocating transmission power, the method comprising: acquiring a first transmission power and a second transmission power, and/or acquiring a first load and a second load; if the first transmission power is less than a first power threshold, and the second transmission power is greater than a second power threshold, or if the first load is less than a first load threshold, and the second load is greater than a second load threshold, then calculating the power difference according to a third transmission power and the first transmission power, the third transmission power being the transmission power allocated to a first cell; reducing the third transmission power by the power difference, and increasing a fourth transmission power by the power difference, the fourth transmission power being the transmission power allocated to a second cell. The present invention reasonably utilizes the network resources of two cells and improves the performance and edge throughput of the cell having more access users, thus improving network performance.

Description

一种分配发射功率的方法和装置 技术领域  Method and device for allocating transmission power

本发明涉及无线通信领域， 特别涉及一种分配发射功率的方法和装置。 背景技术  The present invention relates to the field of wireless communications, and in particular, to a method and apparatus for allocating transmit power. Background technique

在无线通信网络中， 传统的天线在垂直方向上形成一个波束， 该波束覆盖 一个小区， 而自适应天线系统（ Adaptive Antenna System, AAS )在垂直方向 上可以形成两个波束， 该两个波束可以覆盖两个独立的小区。  In a wireless communication network, a conventional antenna forms a beam in a vertical direction, the beam covers a cell, and an Adaptive Antenna System (ASS) can form two beams in a vertical direction, and the two beams can Cover two separate cells.

目前， 在初始化时， 对该两个小区分别分配一个固定的发射功率， 且该两 个小区的发射功率之和等于该天线的发射功率。 由于在实际应用时， 该天线覆 盖的小区内的用户数量是实时动态变化的， 当一个小区接入的用户较多且出现 拥塞， 另一个小区接入的用户极少时， 此时接入的用户较多且出现拥塞的小区 的发射功率不够用， 而接入的用户极少的小区的发射功率剩余， 如此不仅会导 致接入的用户较多且出现拥塞的小区的性能和边缘吞吐量较差，还会导致接入 的用户极少的小区资源的浪费。 发明内容  Currently, at initialization, a fixed transmit power is allocated to the two cells, and the sum of the transmit powers of the two cells is equal to the transmit power of the antenna. In actual application, the number of users in the cell covered by the antenna is dynamically changed in real time. When one cell accesses more users and congestion occurs, and another cell accesses few users, the access is performed at this time. The transmit power of a cell with a large number of users and congestion is insufficient, and the transmit power of a cell with few users is the remaining, which not only leads to the performance of the cell with more access and the performance of the cell with congestion and the edge throughput. Poor, it also leads to a waste of very few cell resources for the users who access. Summary of the invention

为了提高接入的用户较多的小区的性能和边缘吞吐量， 以及提高网络的性 能，本发明实施例提供了一种分配发射功率的方法和装置。所述技术方案如下： 第一方面， 提供了一种分配发射功率的方法， 所述方法包括：  In order to improve the performance and edge throughput of a cell with more users, and to improve the performance of the network, an embodiment of the present invention provides a method and apparatus for allocating transmit power. The technical solution is as follows: In a first aspect, a method for allocating transmit power is provided, where the method includes:

网络侧设备获取第一发射功率和第二发射功率，和 /或获取第一负载和第二 负载， 所述第一发射功率为第一小区当前使用的发射功率， 所述第二发射功率 为第二小区当前使用的发射功率， 所述第一负载为所述第一小区的负载， 所述 第二负载为所述第二小区的负载， 所述第一小区和所述第二小区为自适应天线 系统 AAS垂直劈裂后的两个小区；  The network side device acquires the first transmit power and the second transmit power, and/or acquires the first load and the second load, where the first transmit power is the transmit power currently used by the first cell, and the second transmit power is The transmit power currently used by the two cells, the first load is the load of the first cell, the second load is the load of the second cell, and the first cell and the second cell are adaptive. Two cells in the antenna system AAS after vertical splitting;

如果所述第一发射功率小于第一功率门限且所述第二发射功率大于第二 功率门限， 或者， 所述第一负载小于第一负载门限且所述第二负载大于第二负 载门限， 则所述网络侧设备根据第三发射功率和所述第一发射功率， 计算功率 差值， 所述第三发射功率为所述网络侧设备分配给所述第一小区的发射功率； 所述网络侧设备将所述第三发射功率减小所述功率差值， 并将第四发射功 率增加所述功率差值， 所述第四发射功率为所述网络侧设备分配给所述第二小 区的发射功率。 If the first transmit power is less than the first power threshold and the second transmit power is greater than the second power threshold, or the first load is less than the first load threshold and the second load is greater than the second load threshold, The network side device calculates power according to the third transmit power and the first transmit power a difference, the third transmit power is a transmit power allocated by the network side device to the first cell; the network side device decreases the third transmit power by the power difference, and fourth The transmit power increases the power difference, and the fourth transmit power is a transmit power allocated by the network side device to the second cell.

结合第一方面， 在上述第一方面的第一种可能的实现方式中， 所述网络侧 设备将所述第三发射功率减小所述功率差值， 并将第四发射功率增加所述功率 差值， 包括：  With reference to the first aspect, in a first possible implementation manner of the foregoing first aspect, the network side device reduces the third transmit power by the power difference, and increases the fourth transmit power by the power Differences, including:

如果所述功率差值大于最小功率阈值， 则所述网络侧设备将所述第三发射 功率减小所述功率差值， 并将第四发射功率增加所述功率差值。  And if the power difference is greater than a minimum power threshold, the network side device decreases the third transmit power by the power difference and increases the fourth transmit power by the power difference.

结合第一方面或第一方面的第一种可能的实现方式，在上述第一方面的第 二种可能的实现方式中， 所述方法还包括：  In conjunction with the first aspect or the first possible implementation of the first aspect, in a second possible implementation manner of the foregoing first aspect, the method further includes:

如果所述第一负载大于第三负载门限且所述第二负载大于第四负载门限， 则所述网络侧设备根据第一用户连接数和第二用户连接数，计算所述第一用户 连接数与所述第二用户连接数之间的比值， 所述第一用户连接数为所述第一小 区的用户连接数， 所述第二用户连接数为所述第二小区的用户连接数；  If the first load is greater than the third load threshold and the second load is greater than the fourth load threshold, the network side device calculates the first user connection number according to the first user connection number and the second user connection number. a ratio of the number of connections to the second user, where the number of first users is the number of user connections of the first cell, and the number of connections of the second user is the number of connections of the second cell;

如果所述比值小于预设数值， 则所述网络侧设备将所述第三发射功率减小 所述功率差值， 并将所述第四发射功率增加所述功率差值。  If the ratio is less than a preset value, the network side device decreases the third transmit power by the power difference and increases the fourth transmit power by the power difference.

结合第一方面、第一方面的第一种可能的实现方式或第一方面的第二种可 能的实现方式， 在上述第一方面的第三种可能的实现方式中， 所述网络侧设备 包括基站或集中控制器设备。 第二方面， 提供了一种分配发射功率的装置， 所述装置包括：  With reference to the first aspect, the first possible implementation manner of the first aspect, or the second possible implementation manner of the first aspect, in the third possible implementation manner of the foregoing first aspect, the network side device includes Base station or centralized controller device. In a second aspect, an apparatus for allocating transmit power is provided, the apparatus comprising:

获取单元，用于获取第一发射功率和第二发射功率，和 /或获取第一负载和 第二负载， 所述第一发射功率为第一小区当前使用的发射功率， 所述第二发射 功率为第二小区当前使用的发射功率， 所述第一负载为所述第一小区的负载， 所述第二负载为所述第二小区的负载， 所述第一小区和所述第二小区为自适应 天线系统 AAS垂直劈裂后的两个小区；  An acquiring unit, configured to acquire a first transmit power and a second transmit power, and/or obtain a first load and a second load, where the first transmit power is a transmit power currently used by the first cell, and the second transmit power is For the transmit power currently used by the second cell, the first load is the load of the first cell, the second load is the load of the second cell, and the first cell and the second cell are Two cells after vertical splitting of the adaptive antenna system AAS;

第一计算单元， 用于如果所述获取单元获取的第一发射功率小于第一功率 门限且所述第二发射功率大于第二功率门限， 或者， 用于如果所述获取单元获 取的第一负载小于第一负载门限且所述第二负载大于第二负载门限， 则根据第 三发射功率和所述第一发射功率， 计算功率差值， 所述第三发射功率为网络侧 设备分配给所述第一小区的发射功率； a first calculating unit, configured to: if the first transmit power acquired by the acquiring unit is smaller than a first power threshold and the second transmit power is greater than a second power threshold, or for a first load acquired by the acquiring unit If the second load is greater than the second load threshold, the power difference is calculated according to the third transmit power and the first transmit power, where the third transmit power is the network side. a transmission power allocated by the device to the first cell;

增减单元， 用于将所述第三发射功率减小所述第一计算单元计算的功率差 值， 并将第四发射功率增加所述第一计算单元计算的功率差值， 所述第四发射 功率为所述网络侧设备分配给所述第二小区的发射功率。  And an increasing or decreasing unit, configured to reduce the third transmit power by a power difference calculated by the first calculating unit, and increase a fourth transmit power by a power difference calculated by the first calculating unit, where the fourth The transmit power is the transmit power allocated by the network side device to the second cell.

结合第二方面， 在上述第二方面的第一种可能的实现方式中， 所述增减单 元用于， 如果所述第一计算单元计算的功率差值大于最小功率阈值， 则将所述 第三发射功率减小所述第一计算单元计算的功率差值， 并将第四发射功率增加 所述第一计算单元计算的功率差值。  With reference to the second aspect, in a first possible implementation manner of the foregoing second aspect, the increasing or decreasing unit is configured to: if the power difference calculated by the first calculating unit is greater than a minimum power threshold, The three transmit power reduces the power difference calculated by the first calculation unit, and increases the fourth transmit power by the power difference calculated by the first calculation unit.

结合第二方面或第二方面的第一种可能的实现方式，在上述第二方面的第 二种可能的实现方式中， 所述装置还包括：  With reference to the second aspect, or the first possible implementation manner of the second aspect, in the second possible implementation manner of the foregoing second aspect, the device further includes:

第二计算单元， 用于如果所述获取单元获取的第一负载大于第三负载门限 且所述第二负载大于第四负载门限， 则根据第一用户连接数和第二用户连接 数， 计算所述第一用户连接数与所述第二用户连接数之间的比值， 所述第一用 户连接数为所述第一小区的用户连接数， 所述第二用户连接数为所述第二小区 的用户连接数；  a second calculating unit, configured to calculate, according to the first user connection number and the second user connection number, if the first load acquired by the acquiring unit is greater than a third load threshold and the second load is greater than a fourth load threshold a ratio between the number of the first user connections and the number of the second user connections, where the number of first users is the number of user connections in the first cell, and the number of connections in the second user is the second cell Number of user connections;

增减单元， 还用于如果所述第二计算单元计算的比值小于预设数值， 则将 所述第三发射功率减小所述第一计算单元计算的功率差值， 并将所述第四发射 功率增加所述第一计算单元计算的功率差值。  The increasing or decreasing unit is further configured to: if the ratio calculated by the second calculating unit is less than a preset value, reduce the third transmit power by a power difference calculated by the first calculating unit, and The transmit power increases the power difference calculated by the first computing unit.

结合第二方面、第二方面的第一种可能的实现方式或第二方面的第二种可 能的实现方式， 在上述第二方面的第三种可能的实现方式中， 所述装置包括基 站或集中控制器设备。 第三方面， 提供了一种分配发射功率的装置， 所述装置包括存储器和处理 器， 所述存储器用于存储代码， 所述处理器用于执行所述存储器存储的代码， 执行所述的一种分配发射功率的方法， 包括：  With reference to the second aspect, the first possible implementation manner of the second aspect, or the second possible implementation manner of the second aspect, in a third possible implementation manner of the foregoing second aspect, the device includes a base station or Centralize the controller device. In a third aspect, there is provided an apparatus for allocating transmit power, the apparatus comprising a memory and a processor, the memory for storing a code, the processor for executing the code stored by the memory, performing the one of the A method of allocating transmit power, including:

获取第一发射功率和第二发射功率，和 /或获取第一负载和第二负载，所述 第一发射功率为第一小区当前使用的发射功率， 所述第二发射功率为第二小区 当前使用的发射功率， 所述第一负载为所述第一小区的负载， 所述第二负载为 所述第二小区的负载， 所述第一小区和所述第二小区为自适应天线系统 AAS 垂直劈裂后的两个小区；  Obtaining a first transmit power and a second transmit power, and/or acquiring a first load and a second load, where the first transmit power is a transmit power currently used by the first cell, and the second transmit power is a current current of the second cell The transmit power used, the first load is a load of the first cell, the second load is a load of the second cell, and the first cell and the second cell are an adaptive antenna system AAS Two cells after vertical splitting;

如果所述第一发射功率小于第一功率门限且所述第二发射功率大于第二 功率门限， 或者， 所述第一负载小于第一负载门限且所述第二负载大于第二负 载门限， 则根据第三发射功率和所述第一发射功率， 计算功率差值， 所述第三 发射功率为网络侧设备分配给所述第一小区的发射功率； If the first transmit power is less than the first power threshold and the second transmit power is greater than the second a power threshold, or, if the first load is smaller than the first load threshold and the second load is greater than the second load threshold, calculating a power difference according to the third transmit power and the first transmit power, where the third The transmit power is a transmit power allocated by the network side device to the first cell;

将所述第三发射功率减小所述功率差值， 并将第四发射功率增加所述功率 差值， 所述第四发射功率为所述网络侧设备分配给所述第二小区的发射功率。  And reducing the third transmit power to the power difference, and increasing the fourth transmit power by the power difference, where the fourth transmit power is a transmit power allocated by the network side device to the second cell .

结合第三方面， 在上述第三方面的第一种可能的实现方式中， 所述处理器 用于将所述第三发射功率减小所述功率差值， 并将第四发射功率增加所述功率 差值， 包括：  With reference to the third aspect, in a first possible implementation manner of the foregoing third aspect, the processor is configured to reduce the third transmit power by the power difference, and increase the fourth transmit power by the power Differences, including:

如果所述功率差值大于最小功率阈值， 则将所述第三发射功率减小所述功 率差值， 并将第四发射功率增加所述功率差值。  And if the power difference is greater than a minimum power threshold, reducing the third transmit power by the power difference and increasing the fourth transmit power by the power difference.

结合第三方面或第三方面的第一种可能的实现方式，在上述第三方面的第 二种可能的实现方式中， 所述处理器还用于：  In conjunction with the third aspect or the first possible implementation manner of the third aspect, in a second possible implementation manner of the foregoing third aspect, the processor is further configured to:

如果所述第一负载大于第三负载门限且所述第二负载大于第四负载门限， 则根据第一用户连接数和第二用户连接数，计算所述第一用户连接数与所述第 二用户连接数之间的比值， 所述第一用户连接数为所述第一小区的用户连接 数， 所述第二用户连接数为所述第二小区的用户连接数；  If the first load is greater than the third load threshold and the second load is greater than the fourth load threshold, calculating the first user connection number and the second according to the first user connection number and the second user connection number a ratio of the number of user connections, the number of first user connections is the number of user connections of the first cell, and the number of second user connections is the number of user connections of the second cell;

如果所述比值小于预设数值， 则将所述第三发射功率减小所述功率差值， 并将所述第四发射功率增加所述功率差值。  If the ratio is less than a preset value, the third transmit power is decreased by the power difference, and the fourth transmit power is increased by the power difference.

结合第三方面、第三方面的第一种可能的实现方式或第三方面的第二种可 能的实现方式， 在上述第三方面的第三种可能的实现方式中， 所述装置包括基 站或集中控制器设备。  With reference to the third aspect, the first possible implementation manner of the third aspect, or the second possible implementation manner of the third aspect, in a third possible implementation manner of the foregoing third aspect, the device includes a base station or Centralize the controller device.

在本发明实施例中， 对于 AAS垂直劈裂后的两个小区， 当一个小区接入 的用户较多， 另一个小区接入的用户较少时， 通过对两个小区进行功率调整， 从而避免接入的用户较多的小区的发射功率不够用且接入的用户较少的小区 的发射功率剩余， 本发明实施例合理地利用了两个小区的网络资源， 提高了接 入的用户较多的小区的性能和边缘吞吐量， 进而提高了网络的性能。 附图说明  In the embodiment of the present invention, for two cells after the vertical splitting of the AAS, when one cell accesses more users and another cell accesses fewer users, power is adjusted by using two cells, thereby avoiding In the embodiment of the present invention, the network resources of the two cells are used reasonably, and the number of users accessing the network is increased. The performance and edge throughput of the cell improves the performance of the network. DRAWINGS

为了更清楚地说明本发明实施例中的技术方案， 下面将对实施例描述中所 需要使用的附图作筒单地介绍， 显而易见地， 下面描述中的附图仅仅是本发明 的一些实施例，对于本领域普通技术人员来讲，在不付出创造性劳动的前提下， 还可以根据这些附图获得其他的附图。 In order to more clearly illustrate the technical solutions in the embodiments of the present invention, the drawings used in the description of the embodiments will be briefly described below. It is obvious that the drawings in the following description are only some embodiments of the present invention. For those of ordinary skill in the art, without creative efforts, Other drawings can also be obtained from these figures.

图 1是本发明实施例一提供的一种分配发射功率的方法流程图；  1 is a flowchart of a method for allocating transmit power according to Embodiment 1 of the present invention;

图 2是本发明实施例二提供的一种分配发射功率的方法流程图；  2 is a flowchart of a method for allocating transmit power according to Embodiment 2 of the present invention;

图 3是本发明实施例三提供的一种分配发射功率的方法流程图；  3 is a flowchart of a method for allocating transmit power according to Embodiment 3 of the present invention;

图 4是本发明实施例四提供的一种分配发射功率的装置结构示意图； 图 5是本发明实施例四提供的另一种分配发射功率的装置结构示意图； 图 6是本发明实施例五提供的一种分配发射功率的装置结构示意图。 具体实施方式  4 is a schematic structural diagram of an apparatus for allocating transmit power according to Embodiment 4 of the present invention; FIG. 5 is a schematic structural diagram of another apparatus for allocating transmit power according to Embodiment 4 of the present invention; FIG. 6 is a schematic diagram of Embodiment 5 of the present invention. A schematic diagram of a device structure for allocating transmit power. detailed description

为使本发明的目的、 技术方案和优点更加清楚， 下面将结合附图对本发明 实施方式作进一步地详细描述。 实施例一  The embodiments of the present invention will be further described in detail below with reference to the accompanying drawings. Embodiment 1

本发明实施例提供了一种分配发射功率的方法， 参见图 1 , 该方法包括： 步骤 101 : 网络侧设备获取第一发射功率和第二发射功率， 和 /或获取第一 负载和第二负载， 其中， 第一发射功率为第一小区当前使用的发射功率， 第二 发射功率为第二小区当前使用的发射功率， 第一负载为第一小区的负载， 第二 负载为第二小区的负载， 第一小区和第二小区为 AAS垂直劈裂后的两个小区； 可选地， 第一小区和第二小区也可以为 AAS水平劈裂后的两个小区。 步骤 102: 如果第一发射功率小于第一功率门限且第二发射功率大于第二 功率门限， 或者， 第一负载小于第一负载门限且第二负载大于第二负载门限， 则执行步骤 103 , 否则， 执行步骤 105;  An embodiment of the present invention provides a method for allocating transmit power. Referring to FIG. 1, the method includes: Step 101: A network side device acquires a first transmit power and a second transmit power, and/or acquires a first load and a second load. The first transmit power is the transmit power currently used by the first cell, and the second transmit power is the transmit power currently used by the second cell, where the first load is the load of the first cell, and the second load is the load of the second cell. The first cell and the second cell are two cells after the vertical splitting of the AAS; optionally, the first cell and the second cell may also be two cells after the AAS horizontal splitting. Step 102: If the first transmit power is less than the first power threshold and the second transmit power is greater than the second power threshold, or the first load is less than the first load threshold and the second load is greater than the second load threshold, step 103 is performed, otherwise , performing step 105;

步骤 103: 网络侧设备根据第三发射功率和第一发射功率，计算功率差值， 第三发射功率为网络侧设备分配给第一小区的发射功率；  Step 103: The network side device calculates a power difference according to the third transmit power and the first transmit power, where the third transmit power is a transmit power allocated by the network side device to the first cell.

步骤 104: 网络侧设备将第三发射功率减小功率差值， 并将第四发射功率 增加功率差值， 第四发射功率为网络侧设备分配给第二小区的发射功率；  Step 104: The network side device reduces the power difference of the third transmit power, and increases the power difference between the fourth transmit power, where the fourth transmit power is the transmit power allocated by the network side device to the second cell.

可选的， 如果功率差值大于最小功率阈值， 则将第三发射功率减小功率差 值， 并将第四发射功率增加所述功率差值。  Optionally, if the power difference is greater than the minimum power threshold, the third transmit power is decreased by the power difference, and the fourth transmit power is increased by the power difference.

其中， 如果功率差值小于或等于最小功率阈值， 则将第三发射功率减小功 率差值， 以及将第四发射功率增加功率差值之后， 使第三发射功率和第四发射 功率的变化较小，从而可能不会解决接入用户较多的小区发射功率不够用的问 题， 并且将第三发射功率减小功率差值， 以及将第四发射功率增加功率差值还 会浪费计算资源， 所以对功率差值进行判断相比于不对功率差值进行判断， 可 以节省网络侧设备的计算资源。 Wherein, if the power difference is less than or equal to the minimum power threshold, the third transmit power is decreased by the power difference, and after the fourth transmit power is increased by the power difference, the third transmit power and the fourth transmit power are changed. Small, so it may not solve the problem that the transmission power of the cell with more access users is insufficient. The problem is that the third transmit power is reduced by the power difference, and the fourth transmit power is increased by the power difference, which also wastes computational resources. Therefore, the power difference is judged compared to the non-power difference, and the network can be saved. The computing resources of the side device.

步骤 105: 保持第三发射功率和第四发射功率不变。  Step 105: Keep the third transmit power and the fourth transmit power unchanged.

其中，在本发明实施例中，网络侧设备可以包括基站或者集中控制器设备， 基站包括长期演进（ Long Term Evolution, LTE) /LTE的演进（ LTE- Advanced, LTE-A ) 系统的 eNodeB , 宽带码分多址 （Wideband Code Division Multiple Access, WCDMA ) 系统的 NodeB等， 集中控制器设备包括 LTE/LTE-A系统 的基站控制设备， WCDMA系统的无线网络控制器（ Radio Network Controller, RNC )等。  In the embodiment of the present invention, the network side device may include a base station or a centralized controller device, and the base station includes an eNodeB of a Long Term Evolution (LTE)/LTE Evolution (LTE-Advanced) system, and a broadband. The NodeB of the code division multiple access (WCDMA) system, the centralized controller device includes a base station control device of the LTE/LTE-A system, a radio network controller (RNC) of the WCDMA system, and the like.

在本发明实施例中， 对于 AAS垂直劈裂后的两个小区， 当一个小区接入 的用户较多， 另一个小区接入的用户较少时， 通过对两个小区进行功率调整， 从而避免接入的用户较多的小区的发射功率不够用且接入的用户较少的小区 的发射功率剩余， 本发明实施例合理地利用了两个小区的网络资源， 提高了接 入的用户较多的小区的性能和边缘吞吐量， 进而提高了网络的性能。 实施例二  In the embodiment of the present invention, for two cells after the vertical splitting of the AAS, when one cell accesses more users and another cell accesses fewer users, power is adjusted by using two cells, thereby avoiding In the embodiment of the present invention, the network resources of the two cells are used reasonably, and the number of users accessing the network is increased. The performance and edge throughput of the cell improves the performance of the network. Embodiment 2

本发明实施例提供了一种分配发射功率的方法。其中，在本发明实施例中， 用户的下行发射功率是通过动态功率控制实现的， 所以用户的下行发射功率可 能实时动态变化， 优选的， 本发明实施例可以根据第一小区当前使用的发射功 率和第二小区当前使用的发射功率情况， 对分配给第一小区的发射功率和分配 给第二小区的发射功率进行调整。 参见图 2, 该方法包括：  Embodiments of the present invention provide a method for allocating transmit power. In the embodiment of the present invention, the downlink transmit power of the user is implemented by dynamic power control, so the downlink transmit power of the user may be dynamically changed in real time. Preferably, the embodiment of the present invention may be based on the transmit power currently used by the first cell. And the transmit power currently used by the second cell, and the transmit power allocated to the first cell and the transmit power allocated to the second cell are adjusted. Referring to Figure 2, the method includes:

步骤 201: 获取第一发射功率和第二发射功率， 第一发射功率为第一小区 当前使用的发射功率， 第二发射功率为第二小区当前使用的发射功率；  Step 201: Obtain a first transmit power that is a transmit power currently used by the first cell, and a second transmit power that is a transmit power currently used by the second cell.

步骤 202: 判断第一发射功率是否小于第一功率门限且第二发射功率是否 大于第二功率门限， 如果是， 则执行步骤 203, 否则， 执行步骤 205;  Step 202: Determine whether the first transmit power is less than the first power threshold and the second transmit power is greater than the second power threshold, if yes, go to step 203, otherwise, go to step 205;

步骤 203: 根据第三发射功率和第一发射功率， 计算功率差值， 第三发射 功率为分配给第一小区的发射功率；  Step 203: Calculate a power difference according to the third transmit power and the first transmit power, where the third transmit power is a transmit power allocated to the first cell.

具体地， 将第三发射功率减去第一发射功率， 得到功率差值。  Specifically, the third transmit power is subtracted from the first transmit power to obtain a power difference.

其中， 对第一小区分配一个发射功率， 即第三发射功率， 以及对第二小区 分配一个发射功率，即第四发射功率，第三发射功率和第四发射功率可以相等， 也可以不相等， 只需第三发射功率与第四发射功率之和等于 AAS天线的发射 功率即可。 The first cell is allocated one transmit power, that is, the third transmit power, and the second cell is allocated one transmit power, that is, the fourth transmit power, and the third transmit power and the fourth transmit power may be equal. It may also be unequal, and only the sum of the third transmit power and the fourth transmit power is equal to the transmit power of the AAS antenna.

步骤 204: 将第三发射功率减小功率差值， 并将第四发射功率增加功率差 值， 第四发射功率为分配给第二小区的发射功率；  Step 204: Decrease the third transmit power by a power difference, and increase the fourth transmit power by a power difference, where the fourth transmit power is a transmit power allocated to the second cell.

可选地， 将功率差值与最小功率阈值进行比较， 如果功率差值大于最小功 率阈值， 则将第三发射功率减小功率差值， 并将第四发射功率增加功率差值。  Optionally, the power difference is compared with a minimum power threshold. If the power difference is greater than the minimum power threshold, the third transmit power is decreased by the power difference, and the fourth transmit power is increased by the power difference.

进一步地， 如果功率差值小于或等于最小功率阈值， 则对第三发射功率和 第四发射功率不做调整。  Further, if the power difference is less than or equal to the minimum power threshold, no adjustment is made for the third transmit power and the fourth transmit power.

其中， 如果功率差值小于或等于最小功率阈值， 则将第三发射功率减小功 率差值， 以及将第四发射功率增加功率差值之后， 使第三发射功率和第四发射 功率的变化较小，从而可能不会解决接入用户较多的小区发射功率不够用的问 题， 并且将第三发射功率减小功率差值， 以及将第四发射功率增加功率差值还 会浪费计算资源， 所以对功率差值进行判断相比于不对功率差值进行判断， 可 以节省网络侧设备的计算资源。  Wherein, if the power difference is less than or equal to the minimum power threshold, the third transmit power is decreased by the power difference, and after the fourth transmit power is increased by the power difference, the third transmit power and the fourth transmit power are changed. Small, so that it may not solve the problem that the cell transmission power of the access user is insufficient, and reducing the power difference of the third transmit power and increasing the power difference of the fourth transmit power wastes computing resources, so When the power difference is judged compared to the power difference, the computing resources of the network side device can be saved.

步骤 205: 保持第三发射功率和第四发射功率不变。  Step 205: Keep the third transmit power and the fourth transmit power unchanged.

可选地， 在本发明实施例中还可以获取第一负载和第二负载， 第一负载为 第一小区的负载， 第二负载为第二小区的负载， 根据第一负载和第二负载对第 三发射功率和第四发射功率进行调整。  Optionally, in the embodiment of the present invention, the first load and the second load are further acquired, where the first load is a load of the first cell, and the second load is a load of the second cell, according to the first load and the second load pair. The third transmit power and the fourth transmit power are adjusted.

进一步地， 当对第三发射功率和第四发射功率进行调整之后， 网络侧设备 对用户级的参数进行调整， 进而调整物理下行共享信道（Physical Downlink Shared Channel, PDSCH ) 的发射功率， 并向该用户对应的用户设备发送系统 信息广播（ System Information Broadcase , SIB ) 消息， 使该用户对应的用户设 备知道其下行发射功率被调整。  Further, after adjusting the third transmit power and the fourth transmit power, the network side device adjusts the user-level parameters, and then adjusts the transmit power of the Physical Downlink Shared Channel (PDSCH), and The user equipment corresponding to the user sends a System Information Broadcase (SIB) message, so that the user equipment corresponding to the user knows that the downlink transmission power is adjusted.

其中， 由于该用户的 PDSCH的发射功率与该用户对应的用户设备解调数 据的功率之间存在一个偏置， 当该用户的 PDSCH的发射功率被调整时， 将调 整后的 PDSCH的发射功率通过 SIB消息发送给该用户对应的用户设备， 使该 用户对应的用户设备调整解调数据的功率， 进而使该用户对应的用户设备正确 地解调数据。  There is an offset between the transmit power of the PDSCH of the user and the power of the demodulated data of the user equipment corresponding to the user. When the transmit power of the PDSCH of the user is adjusted, the transmit power of the adjusted PDSCH is passed. The SIB message is sent to the user equipment corresponding to the user, so that the user equipment corresponding to the user adjusts the power of the demodulated data, so that the user equipment corresponding to the user correctly demodulates the data.

在本发明实施例中， 对于 AAS垂直劈裂后的两个小区， 当一个小区接入 的用户较多， 另一个小区接入的用户较少时， 通过对两个小区进行功率调整， 从而避免接入的用户较多的小区的发射功率不够用且接入的用户较少的小区 的发射功率剩余， 本发明实施例合理地利用了两个小区的网络资源， 提高了接 入的用户较多的小区的性能和边缘吞吐量， 进而提高了网络的性能。 实施例三 In the embodiment of the present invention, for two cells after the vertical splitting of the AAS, when one cell accesses more users and another cell accesses fewer users, power is adjusted by using two cells, thereby avoiding A cell in which a cell with more users is not used, and a cell with fewer users is accessed. The transmit power remaining, the embodiment of the present invention reasonably utilizes the network resources of the two cells, improves the performance and edge throughput of the cells with more users, and improves the performance of the network. Embodiment 3

本发明实施例提供了一种分配发射功率的方法。其中，在本发明实施例中， 用户的下行发射功率不变， 优选的， 本发明实施例可以通过第一小区的负载、 第二小区的负载情况，对分配给第一小区的发射功率和分配给第二小区的发射 功率进行调整。 参见图 3 , 该方法包括：  Embodiments of the present invention provide a method for allocating transmit power. In the embodiment of the present invention, the downlink transmit power of the user is unchanged. Preferably, in the embodiment of the present invention, the transmit power and the allocation allocated to the first cell may be adopted by the load of the first cell and the load of the second cell. The transmit power of the second cell is adjusted. Referring to Figure 3, the method includes:

步骤 301 : 获取第一负载、 第二负载、 第一发射功率和第二发射功率， 第 一负载为第一小区的负载， 第二负载为第二小区的负载， 第一发射功率为第一 小区当前使用的发射功率， 第二发射功率为第二小区当前使用的发射功率； 步骤 302: 判断第一负载是否小于第一负载门限且第二负载是否大于第二 负载门限， 如果是， 则执行步骤 303 , 否则， 执行步骤 305;  Step 301: Acquire a first load, a second load, a first transmit power, and a second transmit power, where the first load is a load of the first cell, the second load is a load of the second cell, and the first transmit power is a first cell The currently used transmit power, the second transmit power is the transmit power currently used by the second cell; Step 302: Determine whether the first load is smaller than the first load threshold and the second load is greater than the second load threshold, and if yes, perform the step 303, otherwise, performing step 305;

步骤 303: 根据第三发射功率和第一发射功率， 计算功率差值， 第三发射 功率为分配给第一小区的发射功率；  Step 303: Calculate a power difference according to the third transmit power and the first transmit power, where the third transmit power is a transmit power allocated to the first cell.

具体地， 将第三发射功率减去第一发射功率， 得到功率差值。  Specifically, the third transmit power is subtracted from the first transmit power to obtain a power difference.

其中， 对第一小区分配一个发射功率， 即第三发射功率， 以及对第二小区 分配一个发射功率，即第四发射功率，第三发射功率和第四发射功率可以相等， 也可以不相等， 只需第三发射功率与第四发射功率之和等于 AAS天线的发射 功率即可。  The first cell is allocated one transmit power, that is, the third transmit power, and the second cell is allocated one transmit power, that is, the fourth transmit power, and the third transmit power and the fourth transmit power may be equal or not equal. It suffices that the sum of the third transmit power and the fourth transmit power is equal to the transmit power of the AAS antenna.

步骤 304: 将第三发射功率减小功率差值， 并将第四发射功率增加功率差 值， 第四发射功率为分配给第二小区的发射功率；  Step 304: Reduce a third transmit power by a power difference, and increase a fourth transmit power by a power difference, where the fourth transmit power is a transmit power allocated to the second cell.

可选地， 将功率差值与最小功率阈值进行比较， 如果功率差值大于最小功 率阈值， 则将第三发射功率减小功率差值， 并将第四发射功率增加功率差值。  Optionally, the power difference is compared with a minimum power threshold. If the power difference is greater than the minimum power threshold, the third transmit power is decreased by the power difference, and the fourth transmit power is increased by the power difference.

进一步地， 如果功率差值小于或等于最小功率阈值， 则对第三发射功率和 第四发射功率不做调整。  Further, if the power difference is less than or equal to the minimum power threshold, no adjustment is made for the third transmit power and the fourth transmit power.

其中， 如果功率差值小于或等于最小功率阈值， 则将第三发射功率减小功 率差值， 以及将第四发射功率增加功率差值之后， 使第三发射功率和第四发射 功率的变化较小，从而可能不会解决接入用户较多的小区发射功率不够用的问 题， 并且将第三发射功率减小功率差值， 以及将第四发射功率增加功率差值还 会浪费计算资源， 所以对功率差值进行判断相比于不对功率差值进行判断， 可 以节省网络侧设备的计算资源。 Wherein, if the power difference is less than or equal to the minimum power threshold, the third transmit power is decreased by the power difference, and after the fourth transmit power is increased by the power difference, the third transmit power and the fourth transmit power are changed. Small, so that it may not solve the problem that the cell transmission power of the access user is insufficient, and reducing the power difference of the third transmit power and increasing the power difference of the fourth transmit power wastes computing resources, so Judging the power difference is compared to not determining the power difference. To save computing resources of network side devices.

可选地，在本发明实施例中还可以通过第一发射功率和第二发射功率对第 三发射功率和第四发射功率进行调整。  Optionally, the third transmit power and the fourth transmit power may also be adjusted by using the first transmit power and the second transmit power in the embodiment of the present invention.

步骤 305:如果第一负载大于第三负载门限且第二负载大于第四负载门限， 则执行步骤 306, 否则， 执行步骤 309;  Step 305: If the first load is greater than the third load threshold and the second load is greater than the fourth load threshold, step 306 is performed, otherwise, step 309 is performed;

优选地， 第三负载门限大于或等于第一负载门限， 第四负载门限小于或等 于第二负载门限。  Preferably, the third load threshold is greater than or equal to the first load threshold, and the fourth load threshold is less than or equal to the second load threshold.

步骤 306: 根据第一用户连接数和第二用户连接数， 计算第一用户连接数 和第二用户连接数之间的比值， 第一用户连接数为第一小区的用户连接数， 第 二用户连接数为第二小区的用户连接数；  Step 306: Calculate a ratio between the first user connection number and the second user connection number according to the first user connection number and the second user connection number, where the first user connection number is the number of user connections of the first cell, and the second user The number of connections is the number of user connections of the second cell;

具体地， 将第一用户连接数与第二用户连接数进行比值运算， 得到第一用 户连接数和第二用户连接数之间的比值。  Specifically, the first user connection number is compared with the second user connection number to obtain a ratio between the first user connection number and the second user connection number.

其中， 第一用户连接数和第二用户连接数可以在该步骤之前任意时刻获 取， 在本发明实施例中对此不做具体限定。  The first user connection number and the second user connection number may be obtained at any time before the step, which is not specifically limited in the embodiment of the present invention.

步骤 307: 如果该比值小于预设数值， 则根据第三发射功率和第一发射功 率， 计算功率差值；  Step 307: If the ratio is less than a preset value, calculate a power difference according to the third transmit power and the first transmit power;

其中， 当第一用户连接数与第二用户连接数之间的比值小于预设数值时， 则说明第二小区中的用户设备特别多， 第一小区中的用户设备相比第二小区中 的用户设备少艮多。  When the ratio between the number of the first user connections and the number of the second user connections is less than a preset value, the user equipment in the second cell is particularly large, and the user equipment in the first cell is compared to the second cell. There are fewer user devices.

进一步地， 当第一用户连接数与第二用户连接数之间的比值大于或等于预 设数值时， 则对第三发射功率和第四发射功率不做调整。  Further, when the ratio between the first user connection number and the second user connection number is greater than or equal to a preset value, no adjustment is made for the third transmission power and the fourth transmission power.

步骤 308: 将第三发射功率减小功率差值， 并将第四发射功率增加功率差 值；  Step 308: Decrease the third transmit power by a power difference, and increase the fourth transmit power by a power difference;

可选地， 将功率差值与最小功率阈值进行比较， 如果功率差值大于最小功 率阈值， 则将第三发射功率减小功率差值， 并将第四发射功率增加功率差值。  Optionally, the power difference is compared with a minimum power threshold. If the power difference is greater than the minimum power threshold, the third transmit power is decreased by the power difference, and the fourth transmit power is increased by the power difference.

进一步地， 如果功率差值小于或等于最小功率阈值， 则对第三发射功率和 第四发射功率不做调整。  Further, if the power difference is less than or equal to the minimum power threshold, no adjustment is made for the third transmit power and the fourth transmit power.

步骤 309: 保持第三发射功率和第四发射功率不变。  Step 309: Keep the third transmit power and the fourth transmit power unchanged.

进一步地， 当对第三发射功率和第四发射功率进行调整之后， 网络侧设备 对第一小区的小区级参数进行调整， 进而调整第一小区的 PDSCH发射功率， 并向第一小区包括的用户对应的用户设备发送 SIB消息，使第一小区包括的用 户对应的用户设备知道其下行发射功率被调整； 以及对第二小区的小区级参数 进行调整， 进而调整第二小区的 PDSCH发射功率， 并向第二小区包括的用户 对应的用户设备发送 SIB消息，使第二小区包括的用户对应的用户设备知道其 下行发射功率被调整。 Further, after adjusting the third transmit power and the fourth transmit power, the network side device adjusts the cell level parameter of the first cell, and further adjusts the PDSCH transmit power of the first cell, and provides the user to the first cell. The corresponding user equipment sends an SIB message to enable the first cell to be included. The user equipment corresponding to the user knows that the downlink transmit power is adjusted; and adjusts the cell level parameter of the second cell, and then adjusts the PDSCH transmit power of the second cell, and sends the SIB message to the user equipment corresponding to the user included in the second cell. The user equipment corresponding to the user included in the second cell is made aware that its downlink transmit power is adjusted.

其中， 由于小区的 PDSCH发射功率与该用户对应的用户设备解调数据的 功率之间存在一个偏置， 当调整小区的 PDSCH 的发射功率时， 将调整后的 PDSCH的发射功率通过 SIB消息发送给该小区包括的用户对应的用户设备， 使该小区包括的用户对应的用户设备调整解调数据的功率， 进而使该用户对应 的用户设备正确地解调数据。  When there is an offset between the PDSCH transmit power of the cell and the power of the demodulated data of the user equipment corresponding to the user, when the transmit power of the PDSCH of the cell is adjusted, the transmit power of the adjusted PDSCH is sent to the SIB message through the SIB message. The user equipment corresponding to the user included in the cell adjusts the power of the demodulated data to the user equipment corresponding to the user included in the cell, so that the user equipment corresponding to the user correctly demodulates the data.

在本发明实施例中， 对于 AAS垂直劈裂后的两个小区， 当一个小区接入 的用户较多， 另一个小区接入的用户较少时， 通过对两个小区进行功率调整， 从而避免接入的用户较多的小区的发射功率不够用且接入的用户较少的小区 的发射功率剩余， 本发明实施例合理地利用了两个小区的网络资源， 提高了接 入的用户较多的小区的性能和边缘吞吐量， 进而提高了网络的性能。 实施例四  In the embodiment of the present invention, for two cells after the vertical splitting of the AAS, when one cell accesses more users and another cell accesses fewer users, power is adjusted by using two cells, thereby avoiding In the embodiment of the present invention, the network resources of the two cells are used reasonably, and the number of users accessing the network is increased. The performance and edge throughput of the cell improves the performance of the network. Embodiment 4

本发明实施例提供了一种分配发射功率的装置， 参见图 4, 该装置包括： 获取单元 401 , 用于获取第一发射功率和第二发射功率， 和 /或获取第一负 载和第二负载， 第一发射功率为第一小区当前使用的发射功率， 第二发射功率 为第二小区当前使用的发射功率， 第一负载为第一小区的负载， 第二负载为第 二小区的负载， 第一小区和第二小区为自适应天线系统 AAS垂直劈裂后的两 个小区；  An embodiment of the present invention provides an apparatus for allocating transmit power. Referring to FIG. 4, the apparatus includes: an obtaining unit 401, configured to acquire a first transmit power and a second transmit power, and/or acquire a first load and a second load. The first transmit power is the transmit power currently used by the first cell, and the second transmit power is the transmit power currently used by the second cell, where the first load is the load of the first cell, and the second load is the load of the second cell, One cell and the second cell are two cells after the vertical splitting of the adaptive antenna system AAS;

第一计算单元 402, 用于如果获取单元 401获取的第一发射功率小于第一 功率门限且第二发射功率大于第二功率门限， 或者， 用于如果获取单元 401获 取的第一负载小于第一负载门限且第二负载大于第二负载门限， 则根据第三发 射功率和第一发射功率， 计算功率差值， 第三发射功率为网络侧设备分配给第 一小区的发射功率；  The first calculating unit 402 is configured to: if the first transmit power acquired by the obtaining unit 401 is smaller than the first power threshold and the second transmit power is greater than the second power threshold, or if the first load acquired by the obtaining unit 401 is smaller than the first The load threshold is used, and the second load is greater than the second load threshold, and the power difference is calculated according to the third transmit power and the first transmit power, where the third transmit power is the transmit power allocated by the network side device to the first cell;

增减单元 403 , 用于将第三发射功率减小第一计算单元 402计算的功率差 值， 并将第四发射功率增加第一计算单元 402计算的功率差值， 第四发射功率 为网络侧设备分配给第二小区的发射功率。  The increasing or decreasing unit 403 is configured to reduce the third transmit power by the power difference calculated by the first calculating unit 402, and increase the fourth transmit power by the power difference calculated by the first calculating unit 402, where the fourth transmit power is the network side. The transmission power allocated by the device to the second cell.

可选地， 增减单元 403, 用于如果第一计算单元 402计算的功率差值大于 最小功率阈值， 则将第三发射功率减小功率差值， 并将第四发射功率增加功率 差值。 Optionally, the increasing or decreasing unit 403 is configured to: if the power difference calculated by the first calculating unit 402 is greater than The minimum power threshold reduces the third transmit power by the power difference and increases the fourth transmit power by the power difference.

进一步地， 参见图 5 , 该装置还包括：  Further, referring to FIG. 5, the device further includes:

第二计算单元 404, 用于如果获取单元 401获取的第一负载大于第三负载 门限且第二负载大于第四负载门限， 则根据第一用户连接数和第二用户连接 数， 计算第一用户连接数与第二用户连接数之间的比值， 第一用户连接数为第 一小区的用户连接数， 第二用户连接数为第二小区的用户连接数；  The second calculating unit 404 is configured to calculate, according to the first user connection number and the second user connection number, the first user, if the first load acquired by the obtaining unit 401 is greater than the third load threshold and the second load is greater than the fourth load threshold a ratio between the number of connections and the number of connections of the second user, the number of connections of the first user is the number of user connections of the first cell, and the number of connections of the second user is the number of connections of the second cell;

增减单元 403 , 还用于如果第二计算单元 404计算的比值小于预设数值， 则将第三发射功率减小第一计算单元 402计算的功率差值， 并将第四发射功率 增加第一计算单元 402计算的功率差值。  The increasing or decreasing unit 403 is further configured to: if the ratio calculated by the second calculating unit 404 is less than a preset value, reduce the third transmitting power by the power difference calculated by the first calculating unit 402, and increase the fourth transmitting power by the first The power difference calculated by the calculation unit 402.

其中， 该装置包括基站或集中控制器设备。  Wherein, the device comprises a base station or a centralized controller device.

在本发明实施例中， 对于 AAS垂直劈裂后的两个小区， 当一个小区接入 的用户较多， 另一个小区接入的用户较少时， 通过对两个小区进行功率调整， 从而避免接入的用户较多的小区的发射功率不够用且接入的用户较少的小区 的发射功率剩余， 本发明实施例合理地利用了两个小区的网络资源， 提高了接 入的用户较多的小区的性能和边缘吞吐量， 进而提高了网络的性能。 实施例五  In the embodiment of the present invention, for two cells after the vertical splitting of the AAS, when one cell accesses more users and another cell accesses fewer users, power is adjusted by using two cells, thereby avoiding In the embodiment of the present invention, the network resources of the two cells are used reasonably, and the number of users accessing the network is increased. The performance and edge throughput of the cell improves the performance of the network. Embodiment 5

参见图 6, 本发明实施例提供了一种分配发射功率的装置， 该装置包括： 存储器 501和处理器 502, 存储器 501用于存储代码， 处理器 502用于执 行存储器 501存储的代码， 执行如下分配发射功率的方法：  Referring to FIG. 6, an embodiment of the present invention provides an apparatus for allocating transmit power. The apparatus includes: a memory 501 and a processor 502. The memory 501 is configured to store code, and the processor 502 is configured to execute the code stored in the memory 501. Method of allocating transmit power:

获取第一发射功率和第二发射功率，和 /或获取第一负载和第二负载，所述 第一发射功率为第一小区当前使用的发射功率， 所述第二发射功率为第二小区 当前使用的发射功率， 所述第一负载为所述第一小区的负载， 所述第二负载为 所述第二小区的负载， 所述第一小区和所述第二小区为自适应天线系统 AAS 垂直劈裂后的两个小区；  Obtaining a first transmit power and a second transmit power, and/or acquiring a first load and a second load, where the first transmit power is a transmit power currently used by the first cell, and the second transmit power is a current current of the second cell The transmit power used, the first load is a load of the first cell, the second load is a load of the second cell, and the first cell and the second cell are an adaptive antenna system AAS Two cells after vertical splitting;

如果所述第一发射功率小于第一功率门限且所述第二发射功率大于第二 功率门限， 或者， 所述第一负载小于第一负载门限且所述第二负载大于第二负 载门限， 则根据第三发射功率和所述第一发射功率， 计算功率差值， 所述第三 发射功率为网络侧设备分配给所述第一小区的发射功率；  If the first transmit power is less than the first power threshold and the second transmit power is greater than the second power threshold, or the first load is less than the first load threshold and the second load is greater than the second load threshold, Calculating a power difference according to the third transmit power and the first transmit power, where the third transmit power is a transmit power allocated by the network side device to the first cell;

将所述第三发射功率减小所述功率差值， 并将第四发射功率增加功率差 值， 所述第四发射功率为所述网络侧设备分配给所述第二小区的发射功率。 可选地： Reducing the third transmit power by the power difference and increasing the fourth transmit power by a power difference The fourth transmit power is a transmit power allocated by the network side device to the second cell. Optionally:

如果所述功率差值大于最小功率阈值， 则将所述第三发射功率减小所述功 率差值， 并将第四发射功率增加功率差值。  If the power difference is greater than a minimum power threshold, the third transmit power is decreased by the power difference and the fourth transmit power is increased by a power difference.

进一步地， 处理器 502还用于：  Further, the processor 502 is further configured to:

如果所述第一负载大于第三负载门限且所述第二负载大于第四负载门限， 则根据第一用户连接数和第二用户连接数，计算所述第一用户连接数与所述第 二用户连接数之间的比值， 所述第一用户连接数为所述第一小区的用户连接 数， 所述第二用户连接数为所述第二小区的用户连接数；  If the first load is greater than the third load threshold and the second load is greater than the fourth load threshold, calculating the first user connection number and the second according to the first user connection number and the second user connection number a ratio of the number of user connections, the number of first user connections is the number of user connections of the first cell, and the number of second user connections is the number of user connections of the second cell;

如果所述比值小于预设数值， 则将所述第三发射功率减小所述功率差值， 并将所述第四发射功率增加功率差值。  If the ratio is less than a preset value, the third transmit power is decreased by the power difference, and the fourth transmit power is increased by a power difference.

其中， 所述装置包括基站或集中控制器设备。  The device includes a base station or a centralized controller device.

在本发明实施例中， 对于 AAS垂直劈裂后的两个小区， 当一个小区接入 的用户较多， 另一个小区接入的用户较少时， 通过对两个小区进行功率调整， 从而避免接入的用户较多的小区的发射功率不够用且接入的用户较少的小区 的发射功率剩余， 本发明实施例合理地利用了两个小区的网络资源， 提高了接 入的用户较多的小区的性能和边缘吞吐量， 进而提高了网络的性能。 本领域普通技术人员可以理解实现上述实施例的全部或部分步骤可以通 过硬件来完成， 也可以通过程序来指令相关的硬件完成， 所述的程序可以存储 于一种计算机可读存储介质中， 上述提到的存储介质可以是只读存储器， 磁盘 或光盘等。 以上所述仅为本发明的较佳实施例， 并不用以限制本发明， 凡在本发明的 精神和原则之内， 所作的任何修改、 等同替换、 改进等， 均应包含在本发明的 保护范围之内。  In the embodiment of the present invention, for two cells after the vertical splitting of the AAS, when one cell accesses more users and another cell accesses fewer users, power is adjusted by using two cells, thereby avoiding In the embodiment of the present invention, the network resources of the two cells are used reasonably, and the number of users accessing the network is increased. The performance and edge throughput of the cell improves the performance of the network. A person skilled in the art may understand that all or part of the steps of implementing the above embodiments may be completed by hardware, or may be instructed by a program to execute related hardware, and the program may be stored in a computer readable storage medium. The storage medium mentioned may be a read only memory, a magnetic disk or an optical disk or the like. The above is only the preferred embodiment of the present invention, and is not intended to limit the present invention. Any modifications, equivalent substitutions, improvements, etc., which are within the spirit and scope of the present invention, should be included in the protection of the present invention. Within the scope.

Claims

权 利 要 求 书 claims 1、 一种分配发射功率的方法， 其特征在于， 所述方法包括： 1. A method for allocating transmission power, characterized in that the method includes: 网络侧设备获取第一发射功率和第二发射功率， 和 /或获取第一负载和第二 负载， 所述第一发射功率为第一小区当前使用的发射功率， 所述第二发射功率 为第二小区当前使用的发射功率， 所述第一负载为所述第一小区的负载， 所述 第二负载为所述第二小区的负载， 所述第一小区和所述第二小区为自适应天线 系统 AAS垂直劈裂后的两个小区； The network side device obtains the first transmit power and the second transmit power, and/or obtains the first load and the second load, where the first transmit power is the transmit power currently used by the first cell, and the second transmit power is the transmit power currently used by the first cell. The transmit power currently used by the two cells, the first load is the load of the first cell, the second load is the load of the second cell, the first cell and the second cell are adaptive Two cells after vertical splitting of the antenna system AAS; 如果所述第一发射功率小于第一功率门限且所述第二发射功率大于第二功 率门限， 或者， 所述第一负载小于第一负载门限且所述第二负载大于第二负载 门限， 则所述网络侧设备根据第三发射功率和所述第一发射功率， 计算功率差 值， 所述第三发射功率为所述网络侧设备分配给所述第一小区的发射功率； 所述网络侧设备将所述第三发射功率减小所述功率差值， 并将第四发射功 率增加所述功率差值， 所述第四发射功率为所述网络侧设备分配给所述第二小 区的发射功率。 If the first transmit power is less than the first power threshold and the second transmit power is greater than the second power threshold, or, the first load is less than the first load threshold and the second load is greater than the second load threshold, then The network side device calculates a power difference based on the third transmission power and the first transmission power, where the third transmission power is the transmission power allocated by the network side device to the first cell; the network side The device reduces the third transmission power by the power difference, and increases the fourth transmission power by the power difference. The fourth transmission power is the transmission allocated by the network side device to the second cell. power. 2、 如权利要求 1所述的方法， 其特征在于， 所述网络侧设备将所述第三发 射功率减小所述功率差值， 并将第四发射功率增加所述功率差值， 包括： 2. The method of claim 1, wherein the network side device reduces the third transmission power by the power difference, and increases the fourth transmission power by the power difference, including: 如果所述功率差值大于最小功率阈值， 则所述网络侧设备将所述第三发射 功率减小所述功率差值， 并将第四发射功率增加所述功率差值。 If the power difference is greater than the minimum power threshold, the network side device reduces the third transmission power by the power difference, and increases the fourth transmission power by the power difference. 3、 如权利要求 1或 2所述的方法， 其特征在于， 所述方法还包括： 如果所述第一负载大于第三负载门限且所述第二负载大于第四负载门限， 则所述网络侧设备根据第一用户连接数和第二用户连接数， 计算所述第一用户 连接数与所述第二用户连接数之间的比值， 所述第一用户连接数为所述第一小 区的用户连接数， 所述第二用户连接数为所述第二小区的用户连接数； 3. The method of claim 1 or 2, wherein the method further includes: if the first load is greater than a third load threshold and the second load is greater than a fourth load threshold, then the network The side device calculates a ratio between the first user connection number and the second user connection number based on the first user connection number and the second user connection number, where the first user connection number is the number of the first user connection. The number of user connections, the second number of user connections is the number of user connections of the second cell; 如果所述比值小于预设数值， 则所述网络侧设备将所述第三发射功率减小 所述功率差值， 并将所述第四发射功率增加所述功率差值。 If the ratio is less than the preset value, the network side device reduces the third transmission power by the power difference, and increases the fourth transmission power by the power difference. 4、 如权利要求 1-3任一所述的方法， 其特征在于， 所述网络侧设备包括基 站或集中控制器设备。 4. The method according to any one of claims 1 to 3, characterized in that the network side device includes a base station or a centralized controller device. 5、 一种分配发射功率的装置， 其特征在于， 所述装置包括： 5. A device for allocating transmission power, characterized in that the device includes: 获取单元， 用于获取第一发射功率和第二发射功率， 和 /或获取第一负载和 第二负载， 所述第一发射功率为第一小区当前使用的发射功率， 所述第二发射 功率为第二小区当前使用的发射功率， 所述第一负载为所述第一小区的负载， 所述第二负载为所述第二小区的负载， 所述第一小区和所述第二小区为自适应 天线系统 AAS垂直劈裂后的两个小区； An acquisition unit, configured to acquire the first transmit power and the second transmit power, and/or acquire the first load and the second load, where the first transmit power is the transmit power currently used by the first cell, and the second transmit power is the transmit power currently used by the second cell, the first load is the load of the first cell, the second load is the load of the second cell, the first cell and the second cell are Two cells after vertical splitting of adaptive antenna system AAS; 第一计算单元， 用于如果所述获取单元获取的第一发射功率小于第一功率 门限且所述第二发射功率大于第二功率门限， 或者， 用于如果所述获取单元获 取的第一负载小于第一负载门限且所述第二负载大于第二负载门限， 则根据第 三发射功率和所述第一发射功率， 计算功率差值， 所述第三发射功率为网络侧 设备分配给所述第一小区的发射功率； The first calculation unit is used if the first transmission power obtained by the acquisition unit is less than the first power threshold and the second transmission power is greater than the second power threshold, or, used if the first load obtained by the acquisition unit is less than the first load threshold and the second load is greater than the second load threshold, then calculate the power difference according to the third transmit power and the first transmit power, and the third transmit power is allocated to the network side device. The transmit power of the first cell; 增减单元， 用于将所述第三发射功率减小所述第一计算单元计算的功率差 值， 并将第四发射功率增加所述第一计算单元计算的功率差值， 所述第四发射 功率为所述网络侧设备分配给所述第二小区的发射功率。 an increase and decrease unit, configured to reduce the third transmission power by the power difference calculated by the first calculation unit, and increase the fourth transmission power by the power difference calculated by the first calculation unit, the fourth The transmission power is the transmission power allocated by the network side device to the second cell. 6、 如权利要求 1所述的装置， 其特征在于， 所述增减单元用于， 6. The device according to claim 1, characterized in that, the increasing and decreasing unit is used to, 如果所述第一计算单元计算的功率差值大于最小功率阈值， 则将所述第三 发射功率减小所述第一计算单元计算的功率差值， 并将第四发射功率增加所述 第一计算单元计算的功率差值。 If the power difference calculated by the first calculation unit is greater than the minimum power threshold, the third transmission power is reduced by the power difference calculated by the first calculation unit, and the fourth transmission power is increased by the first The power difference calculated by the calculation unit. 7、 如权利要求 5或 6所述的装置， 其特征在于， 所述装置还包括： 第二计算单元， 用于如果所述获取单元获取的第一负载大于第三负载门限 且所述第二负载大于第四负载门限， 则根据第一用户连接数和第二用户连接数， 计算所述第一用户连接数与所述第二用户连接数之间的比值， 所述第一用户连 接数为所述第一小区的用户连接数， 所述第二用户连接数为所述第二小区的用 户连接数； 7. The device according to claim 5 or 6, characterized in that the device further includes: a second calculation unit, configured to: if the first load acquired by the acquisition unit is greater than a third load threshold and the second If the load is greater than the fourth load threshold, then according to the first user connection number and the second user connection number, calculate the ratio between the first user connection number and the second user connection number, and the first user connection number is The number of user connections in the first cell, and the number of second user connections is the number of user connections in the second cell; 增减单元， 还用于如果所述第二计算单元计算的比值小于预设数值， 则将 所述第三发射功率减小所述第一计算单元计算的功率差值， 并将所述第四发射 功率增加所述第一计算单元计算的功率差值。 The increase and decrease unit is also configured to reduce the third transmit power by the power difference calculated by the first calculation unit if the ratio calculated by the second calculation unit is less than a preset value, and reduce the fourth transmit power by the power difference calculated by the first calculation unit. The transmission power is increased by the power difference calculated by the first calculation unit. 8、 如权利要求 5-7任一所述的装置， 其特征在于， 所述装置包括基站或集 中控制器设备。 8. The device according to any one of claims 5 to 7, characterized in that the device includes a base station or a centralized controller device. 9、一种分配发射功率的装置， 其特征在于， 所述装置包括存储器和处理器， 所述存储器用于存储代码， 所述处理器用于执行所述存储器存储的代码， 执行 分配发射功率的方法， 包括： 9. A device for allocating transmission power, characterized in that the device includes a memory and a processor, the memory is used to store codes, the processor is used to execute the code stored in the memory, and execute the method of allocating transmission power. , include: 获取第一发射功率和第二发射功率， 和 /或获取第一负载和第二负载， 所述 第一发射功率为第一小区当前使用的发射功率， 所述第二发射功率为第二小区 当前使用的发射功率， 所述第一负载为所述第一小区的负载， 所述第二负载为 所述第二小区的负载， 所述第一小区和所述第二小区为自适应天线系统 AAS垂 直劈裂后的两个小区； Obtain the first transmit power and the second transmit power, and/or obtain the first load and the second load, the first transmit power is the transmit power currently used by the first cell, and the second transmit power is the current transmit power of the second cell. The transmit power used, the first load is the load of the first cell, the second load is the load of the second cell, the first cell and the second cell are adaptive antenna systems AAS Two plots after vertical splitting; 如果所述第一发射功率小于第一功率门限且所述第二发射功率大于第二功 率门限， 或者， 所述第一负载小于第一负载门限且所述第二负载大于第二负载 门限， 则根据第三发射功率和所述第一发射功率， 计算功率差值， 所述第三发 射功率为网络侧设备分配给所述第一小区的发射功率； If the first transmit power is less than the first power threshold and the second transmit power is greater than the second power threshold, or, the first load is less than the first load threshold and the second load is greater than the second load threshold, then Calculate the power difference according to the third transmission power and the first transmission power, where the third transmission power is the transmission power allocated to the first cell by the network side device; 将所述第三发射功率减小所述功率差值， 并将第四发射功率增加所述功率 差值， 所述第四发射功率为所述网络侧设备分配给所述第二小区的发射功率。 The third transmission power is reduced by the power difference, and the fourth transmission power is increased by the power difference. The fourth transmission power is the transmission power allocated by the network side device to the second cell. . 10、 如权利要求 9所述的装置， 其特征在于， 所述处理器用于将所述第三 发射功率减小所述功率差值， 并将第四发射功率增加所述功率差值， 包括： 用于如果所述功率差值大于最小功率阈值， 则将所述第三发射功率减小所 述功率差值， 并将第四发射功率增加所述功率差值。 10. The device of claim 9, wherein the processor is configured to reduce the third transmission power by the power difference and increase the fourth transmission power by the power difference, including: It is used to reduce the third transmission power by the power difference value and increase the fourth transmission power by the power difference value if the power difference value is greater than the minimum power threshold value. 11、 如权利要求 9或 10所述的装置， 其特征在于， 所述处理器还用于： 如果所述第一负载大于第三负载门限且所述第二负载大于第四负载门限， 则根据第一用户连接数和第二用户连接数， 计算所述第一用户连接数与所述第 二用户连接数之间的比值， 所述第一用户连接数为所述第一小区的用户连接数， 所述第二用户连接数为所述第二小区的用户连接数； 11. The apparatus according to claim 9 or 10, wherein the processor is further configured to: if the first load is greater than a third load threshold and the second load is greater than a fourth load threshold, then according to The first user connection number and the second user connection number are calculated as the ratio between the first user connection number and the second user connection number, where the first user connection number is the user connection number of the first cell. , the second user connection number is the user connection number of the second cell; 如果所述比值小于预设数值， 则将所述第三发射功率减小所述功率差值， 并将所述第四发射功率增加所述功率差值。 If the ratio is less than the preset value, the third transmission power is reduced by the power difference, and the fourth transmission power is increased by the power difference. 12、 如权利要求 9-11任一所述的装置， 其特征在于， 所述装置包括基站或 集中控制器设备。 12. The device according to any one of claims 9-11, characterized in that the device includes a base station or a centralized controller device.
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Citations (4)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
CN101102606A (en) * 2007-07-20 2008-01-09 中兴通讯股份有限公司 An Indoor Distributed System and Implementation Method Supporting Real-time Network Optimization
CN101742552A (en) * 2008-11-11 2010-06-16 华为技术有限公司 Method, system and equipment for packet switch domain service redirection
CN101808396A (en) * 2010-03-24 2010-08-18 华为技术有限公司 Power sharing method and base station
US20110320826A1 (en) * 2010-06-23 2011-12-29 International Business Machines Corporation Sharing Power Between Two Or More Power Sharing Servers

Family Cites Families (3)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
CN101742522B (en) * 2008-11-04 2013-05-08 鼎桥通信技术有限公司 Carrier power sharing method in multi-carrier cell
CN101720123B (en) * 2009-12-02 2012-10-17 华为技术有限公司 Channel power offset setting method, device, and base station
EP2600664B1 (en) * 2011-11-30 2015-01-07 ST-Ericsson SA Method of communication in a cellular network between a base station and a user equipment

Patent Citations (4)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
CN101102606A (en) * 2007-07-20 2008-01-09 中兴通讯股份有限公司 An Indoor Distributed System and Implementation Method Supporting Real-time Network Optimization
CN101742552A (en) * 2008-11-11 2010-06-16 华为技术有限公司 Method, system and equipment for packet switch domain service redirection
CN101808396A (en) * 2010-03-24 2010-08-18 华为技术有限公司 Power sharing method and base station
US20110320826A1 (en) * 2010-06-23 2011-12-29 International Business Machines Corporation Sharing Power Between Two Or More Power Sharing Servers

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