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WO2012028030A1 - Method for multi-user acknowledgement feedback, and station for feeding back acknowledgment - Google Patents

Method for multi-user acknowledgement feedback, and station for feeding back acknowledgment Download PDF

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Publication number
WO2012028030A1
WO2012028030A1 PCT/CN2011/076722 CN2011076722W WO2012028030A1 WO 2012028030 A1 WO2012028030 A1 WO 2012028030A1 CN 2011076722 W CN2011076722 W CN 2011076722W WO 2012028030 A1 WO2012028030 A1 WO 2012028030A1
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WO
WIPO (PCT)
Prior art keywords
sta
mimo
packet
ack
group
Prior art date
Legal status (The legal status is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the status listed.)
Ceased
Application number
PCT/CN2011/076722
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French (fr)
Chinese (zh)
Inventor
田开波
姜静
李峰
吕开颖
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ZTE Corp
Original Assignee
ZTE Corp
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Filing date
Publication date
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Publication of WO2012028030A1 publication Critical patent/WO2012028030A1/en
Anticipated expiration legal-status Critical
Ceased legal-status Critical Current

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Classifications

    • HELECTRICITY
    • H04ELECTRIC COMMUNICATION TECHNIQUE
    • H04WWIRELESS COMMUNICATION NETWORKS
    • H04W74/00Wireless channel access
    • H04W74/04Scheduled access
    • H04W74/06Scheduled access using polling

Definitions

  • the present invention relates to a technique for feeding back an acknowledgement message (ACK), and more particularly to a method for multi-user feedback confirmation message, and a site (STA, Station) for feeding back a confirmation message.
  • ACK acknowledgement message
  • STA Site
  • Wireless Local Area Networks is a network system that uses wireless communication technology to interconnect computer devices to form a network that can communicate with each other and share resources.
  • the essential feature of WLAN is that it no longer uses a communication cable to connect the computer to the network, but to connect wirelessly, which makes the construction of the network and the movement of the terminal more flexible.
  • IEEE802.i l is one of the mainstream technologies of wireless LAN. This protocol mainly specifies the physical layer (PHY) and media access control (MAC) layer specifications.
  • the technical problem to be solved by the present invention is to provide a method for multi-user feedback confirmation message, which overcomes the shortcomings of the prior art that the multiple users participating in the MU transmission reply to the acknowledgment message (ACK).
  • the present invention provides a method for multi-user feedback confirmation message, which is used for a site (STA) associated with an access point (AP) in a basic service set (BSS).
  • STA site
  • AP access point
  • BSS basic service set
  • the method includes:
  • the STA After receiving the MU-MIMO data frame, the STA indicates the information indicated by the packet number (Group ID) field and the site data flow information indication (N STS ) field in the physical frame header of the data frame, physics.
  • MAC media access control
  • the packet number indicated by the Group ID field in the MU-MIMO data frame is the same as the packet number of the MU-MIMO packet where the STA itself is located, and the corresponding position in the N STS domain is not zero, the physical frame.
  • the bearer carries the same MAC address as the STA's own MAC address, and the STA replies to the ACK;
  • the corresponding location is the same as the relative location of the STA itself in the MU-MIMO packet.
  • the STA that first responds to the ACK is the STA corresponding to the MAC address carried in the request transmission frame (RTS) of the MU-MIMO transmission; the MU-MIMO data frame carries the bearer The remaining STAs identified by the MAC address reply to the ACK in the order of relative positions in the MU-MIMO packet.
  • RTS request transmission frame
  • the order of the agreement includes a relative position sequence of STAs identified by the MAC address carried in the MU-MIMO data frame payload in the MU-MIMO packet.
  • the STA indicates that the packet number indicated by the Group ID field in the MU-MIMO data frame is different from the packet number of the MU-MIMO packet in which the STA itself is located, and the STA does not reply to the ACK.
  • the packet number indicated by the Group ID field in the MU-MIMO data frame is the same as the packet number of the MU-MIMO packet where the STA itself is located, and the corresponding location indication in the N STS domain is zero, and the STA does not reply.
  • the corresponding location is the same as the relative location of the STA itself in the MU-MIMO packet.
  • the group number and the number indicated by the Group ID field in the MU-MIMO data frame The MU-MIMO packet in which the STA is located has the same packet number, and the corresponding location indication in the N STS domain is not zero. If the MAC carried in the physical frame payload is different from the MAC address of the STA itself, the STA does not reply. ACK;
  • the corresponding location is the same as the relative location of the STA in the MU-MIMO packet.
  • the step of assigning a group number to each MU-MIMO packet includes:
  • Another technical problem to be solved by the present invention is to provide a site (STA) for feeding back a confirmation message, which overcomes the drawbacks of the prior art that the multiple users participating in the MU transmission reply to the acknowledgment message (ACK).
  • STA site
  • ACK acknowledgment message
  • the present invention provides a site (STA) for feeding back a confirmation message, which is applied to reply an acknowledgement message (ACK) to an access point (AP) in a basic service set (BSS), which is combined with another one.
  • STA site
  • ACK acknowledgement message
  • AP access point
  • BSS basic service set
  • the STA includes a receiving module and a feedback module, where:
  • the receiving module is configured to: receive a multi-user-multiple input multiple output (MU-MIMO) data frame; the feedback module is configured to: according to the physical frame header of the MU-MIMO data frame
  • MU-MIMO multi-user-multiple input multiple output
  • the group ID field and site data stream information included in the VHT-SIG-A indicate the information indicated by the (N STS ) field, the media access control (MAC ) address information in the physical frame payload, and the Group ID field.
  • MU-MIMO packet information under the indicated packet number, determining STAs replying to the ACK, and replying to the ACK in an agreed order;
  • the AP performs MU-MIMO grouping on the STAs associated with it, for each
  • the packet information is notified to the STA.
  • the feedback module is configured to reply the ACK in the order of the STAs in the MU-MIMO packet.
  • the feedback module is configured to: carry according to the MU-MIMO data frame load
  • the relative locations of the STAs identified by the MAC address in the MU-MIMO packet sequentially reply to the ACK message.
  • the present invention provides a method for multi-user feedback confirmation message for a basic service set
  • STA site associated with the access point (AP) in (BSS) replies with an acknowledgment message (ACK), which includes:
  • the AP performs a multi-user-multiple input multiple output (MU-MIMO) packet on the STA associated with it, assigns a packet number to each MU-MIMO packet, and separately constructs the packet information, and notifies the STA to the STA;
  • MU-MIMO multi-user-multiple input multiple output
  • the domain and site data flow information indicates information indicated by the (N STS ) field, media access control (MAC ) address information in the payload of the physical frame of the MU-MIMO data frame, and the packet number indicated by the Group ID field
  • the underlying MU-MIMO packet information determines the STAs that need to reply to the ACK and replies to the ACK in an agreed order.
  • the step of determining the STA that needs to reply to the ACK includes: the packet number indicated by the Group ID field is the same as the packet number of the MU-MIMO packet where the STA itself is located, and the corresponding location in the N STS domain is not zero.
  • the payload of the physical frame carries the same MAC address as the MAC address of the STA itself, and the STA needs to reply to the ACK;
  • the corresponding location is the same as the relative location of the STA itself in the MU-MIMO packet.
  • the order of the agreement includes: an order of the STAs in the MU-MIMO packet.
  • the order of the agreement includes: the STA that first responds to the ACK is the STA corresponding to the MAC address carried in the RTS; the remaining STAs identified by the MAC address carried in the MU-MIMO data frame payload are in accordance with the MU. - The relative position in the MIMO packet sequentially replies to the ACK.
  • the order of the agreement includes: a relative position sequence of STAs identified by the MAC address carried in the MU-MIMO data frame payload in the MU-MIMO packet.
  • the step of determining the STA that needs to reply to the ACK includes: the packet number indicated by the Group ID field is different from the packet number of the MU-MIMO packet in which the STA itself is located, and the STA does not need to reply to the ACK.
  • the step of determining the STA that needs to reply to the ACK includes: the packet number indicated by the Group ID field is the same as the packet number of the MU-MIMO packet where the STA itself is located, and the corresponding location indication in the N STS domain is zero, The STA does not need to reply to the ACK; The corresponding location is the same as the relative location of the STA itself in the MU-MIMO packet.
  • the step of determining the STA that needs to reply to the ACK includes: the packet number indicated by the Group ID field is the same as the packet number of the MU-MIMO packet where the STA itself is located, and the corresponding location indication in the N STS domain is not zero. If the MAC carried in the payload of the physical frame is different from the MAC address of the STA itself, the STA does not need to reply to the ACK.
  • the corresponding location is the same as the relative location of the STA in the MU-MIMO packet.
  • the step of assigning a group number to each MU-MIMO packet includes: different MU-MIMO packets have the same or different packet numbers.
  • the present invention provides a site (STA) for feeding back a confirmation message for replying an acknowledgment message (ACK) to two (or two) groups of access points (APs) in a basic service set (BSS).
  • STA site
  • BSS basic service set
  • the packet information is notified to the STA, where the STA includes a first receiving module, a second receiving module, and a feedback module, where:
  • the first receiving module is configured to: receive a request sending frame (RTS) sent by the AP, and group information, and learn, according to the grouping information, a packet number of the MU-MIMO packet where the STA itself is located, and the STA itself is in the MU-MIMO packet. Relative position information;
  • RTS request sending frame
  • the second receiving module is configured to: receive a multi-user-multiple input multiple output (MU-MIMO) data frame;
  • MU-MIMO multi-user-multiple input multiple output
  • the feedback module is configured to: according to the obtained packet number of the MU-MIMO packet in which the STA itself is located, and the relative location information of the STA itself in the MU-MIMO packet, the RTS, the physics of the MU-MIMO data frame
  • the MU-MIMO packet information under the packet number indicated by the Group ID field determines the STAs that need to reply to the ACK, and replies to the ACK in an agreed order.
  • the feedback module is further configured to: reply the ACK in the order of the STAs in the MU-MIMO packet.
  • the feedback module is further configured to: reply the ACK according to the relative position of the STAs identified by the MAC address carried in the MU-MIMO data frame payload in the MU-MIMO packet.
  • the feedback module is configured to determine, in the following manner, the STA that needs to reply to the ACK: the packet number indicated by the Group ID field is the same as the packet number of the MU-MIMO packet where the STA itself is located, and the corresponding in the N STS domain If the location of the physical frame is not the same as the MAC address of the STA itself, the feedback module confirms that the STA needs to reply to the ACK;
  • the corresponding location is the same as the relative location of the STA itself in the MU-MIMO packet.
  • FIG. 1 is a schematic flowchart of a method for multi-user feedback ACK according to Embodiment 1 of the present invention
  • FIG. 2 is a schematic diagram of a composition of a STA for feedback ACK according to Embodiment 2 of the present invention.
  • Embodiment 1 Multi-user feedback ACK method
  • This embodiment is used for a station (STA, Station) associated with an access point (AP, Access Point) in a basic service set (BSS) to reply a confirmation message.
  • STA station
  • AP access point
  • BSS basic service set
  • the embodiment mainly includes the following steps:
  • Step S110 In a BSS, the AP performs all possible MU-MIMO packets on the STAs associated with the STA according to one factor or a combination of several factors, such as channel state information, data traffic, and data service type of each STA. Specify a group ID (Group ID) for each MU-MIM0 packet and construct packet information separately;
  • MU-MIMO packets may also have different packet numbers
  • Step S120 the AP notifies the STA of the group information by using signaling
  • the packet information may be carried in a management frame and sent to the STA.
  • Step SI 30 after receiving the packet information, the STA learns the packet number of the MU-MIMO packet in which it is located, and also obtains relative position information in the MU-MIMO packet.
  • Step S140 after receiving the MU-MIMO data frame, the STA indicates the group number (Group ID) field and the site data flow information indication (N STS ) field included in the physical frame header of the data frame according to the VHT-SIG-A.
  • group ID group number
  • N STS site data flow information indication
  • the STA also receives a request to send (RTS, Request To Send), where the RTS includes the MAC address information of both the sender and the receiver.
  • RTS is a control frame used to protect the transmission of MU-MIMO data frames.
  • the corresponding position indication of the N STS field is not zero.
  • the physical frame payload carries the same MAC address as the STA's own MAC address. After the data detection is completed, the STA needs to reply to the ACK. The corresponding location is the same as the STA itself's relative position in the MU-MIMO packet.
  • the STA that first responds to the ACK is the STA corresponding to the MAC address carried in the RTS of the MU-MIMO transmission, and the STA may be referred to as a primary site.
  • the STA does not need to further parse the data, and does not need to reply to the ACK.
  • the STA does not need to further analyze. Data, there is no need to reply to ACK; the above corresponding position is the same as the relative position of the STA itself in the MU-MIMO packet.
  • the corresponding location indication in the N STS domain is not zero, and the physical frame load is carried.
  • the MAC does not need to reply to the ACK when the MAC address of the STA is different from the STA's own MAC address; the corresponding location is the same as the relative position of the STA in the MU-MIMO packet.
  • Each MU-MIMO packet has a maximum of 4 STAs, and a MU-MIMO packet of less than 4 STAs is still considered to be composed of 4 STAs, and an insufficient portion can be considered to have a virtual STA.
  • the identifier is represented by the MAC address of each STA.
  • Each STA receives the MU-MIMO packet information and detects it, but only STA-1, STA-2,
  • STA-4 and STA-6 will use this MU-MIMO packet information as useful information because there is a STA identifier matching the one in the received information.
  • the four STAs have useful information from this MU-MIMO packet information in two ways:
  • the STA identified by the MAC address carried in the RTS frame has data transmission in the current MU-MIMO transmission, the STA needs to reply the ACK first, and the remaining STAs identified by the MAC address carried in the data frame payload are The relative position of the group in which the packet is located is replied in order.
  • STA-1, STA-2 and STA-6 have one data stream transmission, and STA-4 has no data transmission.
  • the MU-MIMO packet transmission is performed, wherein the MAC address in the MAC address field in the RTS frame payload sent by the AP is the MAC address of the STA-6,
  • the information obtained by STA-1 to resolve the N STS domain includes: 1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the third location in the MU-MIMO packet is zero, that is, the data of the STA that does not include the third location in the MU-MIMO packet is transmitted this time;
  • the number of data streams of the STA at the fourth position in the MU-MIMO packet is 1.
  • STA-1 occupies the fourth position in the MU-MIMO packet.
  • the MAC address in the RTS frame payload is the MAC address of STA-6, and the data of STA-6 is transmitted this time;
  • the number of data streams of the STA in the third location in the MU-MIMO packet is zero, that is, the data of the STA that does not include the third location in the MU-MIMO packet is transmitted this time;
  • the number of data streams of the STA at the fourth position in the MU-MIMO packet is 1.
  • STA-2 occupies the first position in the MU-MIMO packet; according to the received RTS frame, it can be known that the MAC address in the RTS frame payload is the STA-6 MAC address. Address, and this transmission has STA-6 data;
  • the STA-3 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and knows that the frame does not belong to the MU-MIMO packet itself, and does not need to reply to the ACK.
  • STAs that have the same processing as STA3 also have STA5.
  • the number of data streams of the STA in the third location in the MU-MIMO packet is zero, that is, the data of the STA that does not include the third location in the MU-MIMO packet is transmitted this time;
  • the number of data streams of the STA at the fourth position in the MU-MIMO packet is 1.
  • STA-4 occupies the third position in the MU-MIMO packet, so the current transmission does not have its own data, and there is no need to reply to the ACK.
  • the number of data streams of the STA in the third position in the MU-MIMO packet is zero, that is, the current transmission does not include the data of the STA in the third position in the MU-MIMO packet; 4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1.
  • STA-6 occupies the second position in the MU-MIMO packet; according to the received RTS frame, it can be known that the MAC address in the RTS frame payload is its own MAC address;
  • STA-6 replies with ACK first according to the method of this practical application.
  • the first reply ACK STA is STA-6;
  • the second reply ACK STA is STA-2;
  • the STA of the third reply ACK is STA-1.
  • Each MU-MIMO packet has a maximum of 4 STAs, and a MU-MIMO packet of less than 4 STAs is still considered to be composed of 4 STAs, and an insufficient portion can be considered to have a virtual STA.
  • the AP divides the six STAs into multiple MU-MIMO packets according to the channel state information of each STA, and notifies the corresponding STAs to the group information, assuming that the group number is sufficient, and each group number indicates only one MU-MIMO packet.
  • the identifier is represented by the MAC address of each STA.
  • Each STA receives the MU-MIMO packet information and detects it, but only STA-1, STA-2, STA-4, and STA-6 will use this MU-MIMO packet information as useful information because it is received.
  • the information has STA identifiers that match itself.
  • the useful information obtained by the four STAs from the MU-MIMO packet information has two aspects:
  • the STA identified by the MAC address carried in the RTS frame needs to reply to the ACK first. However, if the STA has no data transmission in the current MU-MIMO transmission, the STA does not need to reply to the ACK.
  • the STAs identified by the MAC address carried in the data frame payload reply ACK in the order of the relative positions of the packets.
  • the MU-MIMO data packet transmission is performed, wherein the MAC address in the MAC address field in the RTS frame payload sent by the AP is the MAC address of the STA-6, and is included in the physical frame header of the RTS frame.
  • Group number Group ID 2 information.
  • the information obtained by STA-1 to resolve the N STS domain includes:
  • the number of data streams of the STA in the first location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the second location in the MU-MIMO packet is zero, that is, the current transmission does not include the data of the STA in the second location in the MU-MIMO packet;
  • the number of data streams of the STA in the third position in the MU-MIMO packet is zero, that is, the current transmission does not include the data of the STA in the third position in the MU-MIMO packet; 4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1; further analyzing the MAC address information in the frame payload, and discovering that its own MAC address is included, so the current transmission has its own data; According to the foregoing, STA-1 occupies the fourth position in the MU-MIMO packet. According to the received RTS frame, it can be known that the MAC address in the RTS frame payload is the MAC address of STA-6, and there is no STA in this transmission. -6 data,
  • the number of data streams of the STA in the second location in the MU-MIMO packet is zero, that is, the current transmission does not include the data of the STA in the second location in the MU-MIMO packet;
  • the number of data streams of the STA in the third location in the MU-MIMO packet is zero, that is, the data of the STA that does not include the third location in the MU-MIMO packet is transmitted this time;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;
  • the STA-2 occupies the first position in the MU-MIMO packet.
  • the MAC address in the RTS frame payload is the MAC address of the STA-6, and there is no STA in the current transmission. -6 data;
  • STA-2 replies to the first ACK according to the method of this practical application.
  • the STA-3 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame does not belong to the MU-MIMO packet itself, and does not need to reply to the ACK. STAs that have the same processing as STA3 also have STA5.
  • the information obtained by STA-6 to resolve the N STS domain includes:
  • the number of data streams of the STA in the second location in the MU-MIMO packet is zero, that is, the current transmission does not include the data of the STA in the second location in the MU-MIMO packet;
  • the number of data streams of the STA in the third location in the MU-MIMO packet is zero, that is, the data of the STA that does not include the third location in the MU-MIMO packet is transmitted this time;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;
  • STA-4 occupies the third position in the MU-MIMO packet, and the current transmission does not have its own data, and there is no need to reply to the ACK.
  • the number of data streams of the STA in the second location in the MU-MIMO packet is zero, that is, the current transmission does not include the data of the STA in the second location in the MU-MIMO packet;
  • the number of data streams of the STA in the third location in the MU-MIMO packet is zero, that is, the data of the STA that does not include the third location in the MU-MIMO packet is transmitted this time;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;
  • STA-6 occupies the second position in the MU-MIMO packet, so this transmission does not have its own data; although the MAC address in the RTS frame payload is itself MAC address, but according to the method of this practical application, STA-6 does not need to reply ACK.
  • the first reply ACK STA is STA-2;
  • the second reply ACK STA is STA-1.
  • Each MU-MIMO packet has a maximum of 4 STAs, and a MU-MIMO packet of less than 4 STAs is still considered to be composed of 4 STAs, and an insufficient portion can be considered to have a virtual STA.
  • the AP divides the six STAs into multiple MU-MIMO packets according to the channel state information of each STA, and notifies the corresponding STAs to the group information, assuming that the group number is sufficient, and each group number indicates only one MU-MIMO packet.
  • the identifier is represented by the MAC address of each STA.
  • Each STA receives the MU-MIMO packet information and detects it, but only STA-1, STA-2, STA-4, STA-6 will use this MU-MIMO packet information as useful information, because in the received information. There are STA identifiers that match themselves. The four STAs have useful information from this MU-MIMO packet information in two ways:
  • the relative positional order of the STAs identified by the MAC address carried in the MU-MIMO packet That is, the STAs identified by the MAC addresses carried in the data frame payload reply ACKs in the order of the relative positions of the packets.
  • Both STA-4 and STA-6 have a data stream transmission.
  • the MU-MIMO data packet transmission is performed, wherein the MAC address in the MAC address field in the RTS frame payload sent by the AP is the MAC address of the STA-6, and is included in the physical frame header of the RTS frame.
  • Group number Group ID 2 information.
  • the information obtained by STA-1 to resolve the N STS domain includes:
  • the number of data streams of the STA in the third location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;
  • STA-1 occupies the fourth position in the MU-MIMO packet. . Based on the above information, STA-1 responds with ACK 4 in accordance with the method of this practical application.
  • the number of data streams of the STA in the third location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;
  • STA-2 occupies the first position in the MU-MIMO packet. . Based on the above information, STA-2 replies to the first ACK according to the method of this practical application.
  • the STA-3 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and knows that the frame does not belong to its own MU-MIMO packet, and does not need to reply to the ACK.
  • STAs that have the same processing as STA3 also have STA5.
  • the number of data streams of the STA in the third location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;
  • STA-4 occupies the third position in the MU-MIMO packet. . Based on the above information, STA-4 replies to the third ACK according to the method of the actual application. (5) For STA-6
  • the number of data streams of the STA in the third location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;
  • STA-6 occupies the second position in the MU-MIMO packet. Combining the above information, according to the method of the actual application, the STA-6 replies with the second ACK. The order in which the ACK is finally returned:
  • the first reply ACK STA is STA-2;
  • the second reply ACK STA is STA-6;
  • the third reply ACK STA is STA-4;
  • the fourth reply ACK STA is STA-1.
  • 9 STAs are represented as the first station (STA-1), the second station (STA-2), the third station (STA-3), and the fourth station (STA). -4), fifth station (STA-5), sixth station (STA-6), seventh station (STA-7), eighth station (STA-8), ninth station (STA-9).
  • STA-1 first station
  • STA-2 second station
  • STA-3 third station
  • STA-4 fourth station
  • STA-5 fifth station
  • STA-6 sixth station
  • STA-7 seventh station
  • STA-8 eighth station
  • STA-9 ninth station
  • Each MU-MIMO packet has a maximum of 4 STAs, and a MU-MIMO packet of less than 4 STAs is still considered to be composed of 4 STAs, and an insufficient portion can be considered to have a virtual STA.
  • the AP divides the nine STAs into multiple MU-MIMO packets according to the channel state information of each STA. And all the group information is notified to the STA, assuming that the group number is not enough, each group number can indicate multiple MU-MIMO packets, but there is such a constraint that if the same STA appears in multiple MUs indicated by the same group number In the MIMO packet, then the relative position of this STA in the group among these packets is fixed.
  • the AP issues MU-MIMO packet information, and the MU-MIMO packet information includes the group number.
  • the order in which the packet information is distributed is also in the order written above.
  • the STA identified by the MAC address carried in the RTS frame is this time.
  • the STA needs to reply ACK first, and the remaining STAs identified by the MAC address carried in the data frame payload reply ACK according to the relative position of the group.
  • the MU-MIMO data packet transmission is performed, wherein the MAC address in the MAC address field in the RTS frame payload sent by the AP is the MAC address of the STA-6, and is included in the physical frame header of the RTS frame.
  • Group number Group ID 2 information.
  • the information obtained by STA-1 to resolve the N STS domain includes:
  • the number of data streams of the STA in the third location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1; further analyzing the MAC address information in the frame payload, and discovering that its own MAC address is not included, so this transmission does not have its own data. .
  • STA-1 does not reply to ACK according to the method of this practical application.
  • the number of data streams of the STA in the third location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;
  • the STA-2 occupies the first position in the MU-MIMO packet.
  • the MAC address in the RTS frame payload is the MAC address of the STA-6, and the STA is transmitted this time. -6 data.
  • STA-2 replies ACK 2 in accordance with the method of this practical application.
  • the STA-3 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and knows that the frame does not belong to its own MU-MIMO packet, and does not need to reply to the ACK.
  • STAs that have the same processing as STA3 also have STA5, STA7, and STA8;
  • the number of data streams of the STA in the third location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;
  • STA-4 occupies the third position in the MU-MIMO packet. . Based on the above information, STA-4 replies to the third ACK according to the method of the actual application. (5) For STA-6
  • the number of data streams of the STA in the third location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;
  • STA-6 occupies the second position in the MU-MIMO packet; according to the received RTS frame, it can be known that the MAC address in the RTS frame payload is its own MAC address.
  • the number of data streams of the STA in the third location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;
  • STA-9 occupies the fourth position in the MU-MIMO packet.
  • the MAC address in the RTS frame payload is the MAC address of STA-6, and the data of STA-6 is transmitted this time.
  • the first reply ACK STA is STA-6;
  • the second reply ACK STA is STA-2;
  • the third reply ACK STA is STA-4;
  • the 4th reply ACK STA is STA-9.
  • 9 STAs are represented as the first station (STA-1), the second station (STA-2), the third station (STA-3), and the fourth station (STA). -4), fifth station (STA-5), sixth station (STA-6), seventh station (STA-7), eighth station (STA-8), ninth station (STA-9).
  • STA-1 first station
  • STA-2 second station
  • STA-3 third station
  • STA-4 fourth station
  • STA-5 fifth station
  • STA-6 sixth station
  • STA-7 seventh station
  • STA-8 eighth station
  • STA-9 ninth station
  • Each MU-MIMO packet has a maximum of 4 STAs, and a MU-MIMO packet of less than 4 STAs is still considered to be composed of 4 STAs, and an insufficient portion can be considered to have a virtual STA.
  • the AP divides the nine STAs into multiple MU-MIMO packets according to the channel state information of each STA. And all the group information is notified to the STA, assuming that the group number is not enough, each group number can indicate multiple MU-MIMO packets, but there is such a constraint that if the same STA appears in multiple MUs indicated by the same group number In the MIMO packet, then the relative position of this STA in the group among these packets is fixed.
  • the AP issues MU-MIMO packet information, and the MU-MIMO packet information includes the group number.
  • the order in which the packet information is distributed is also in the order written above.
  • the STAs identified by the MAC addresses carried in the data frame payload reply to the ACK in the order of the relative positions of the packets.
  • the MU-MIMO data packet transmission is performed, wherein the MAC address in the MAC address field in the RTS frame payload sent by the AP is the MAC address of the STA-6, and is included in the physical frame header of the RTS frame.
  • Group number Group ID 2 information.
  • the information obtained by STA-1 to resolve the N STS domain includes:
  • the number of data streams of the STA in the third location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1; Further parsing the MAC address information in the frame load, and discovering that its own MAC address is not included, so this transmission does not have its own data;
  • STA-1 does not reply to ACK according to the method of this practical application.
  • the number of data streams of the STA in the third location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;
  • STA-2 occupies the first position in the MU-MIMO packet. . Based on the above information, STA-2 replies to the first ACK according to the method of this practical application.
  • the STA-3 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and knows that the frame does not belong to its own MU-MIMO packet, and does not need to reply to the ACK.
  • STAs that have the same processing as STA3 also have STA5, STA7, and STA8;
  • the number of data streams of the STA in the second location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the third location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;
  • STA-4 occupies the third position in the MU-MIMO packet. . Based on the above information, STA-4 replies to the third ACK according to the method of the actual application. (5) For STA-6
  • the number of data streams of the STA in the third location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;
  • STA-6 occupies the second position in the MU-MIMO packet. Based on the above information, STA-6 replies to the second ACK according to the method of the present application. (6) For STA-9
  • the information obtained by the STA-9 to parse the N STS domain includes:
  • the number of data streams of the STA in the third location in the MU-MIMO packet is 1;
  • the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1; further analyzing the MAC address information in the frame payload, and discovering that its own MAC address is included, so the current transmission has its own data; According to the foregoing, STA-9 occupies the fourth position in the MU-MIMO packet;
  • the first reply ACK STA is STA-2;
  • the second reply ACK STA is STA-6;
  • the third reply ACK STA is STA-4;
  • the 4th reply ACK STA is STA-9.
  • Embodiment 2 A site for feedback confirmation message (STA)
  • the STA of this embodiment is applied to reply to an access point AP in a BSS, which is associated with one or more other STAs and APs, and mainly includes a first receiving module 210, a second receiving module 220, and a feedback module. 230, where:
  • the first receiving module 210 is configured to: receive the RTS and the packet information sent by the AP, and learn, according to the packet information, the packet number of the MU-MIMO packet in which the STA itself is located and the relative location information of the STA itself in the MU-MIMO packet;
  • the second receiving module 220 is configured to: receive the MU-MIMO data frame;
  • the feedback module 230 is connected to the first receiving module 210 and the second receiving module 220, and is configured to: according to the packet number field and the N STS field included in the VHT-SIG-A in the physical frame header of the MU-MIMO data frame.
  • the AP performs MU-MIMO grouping on the STAs associated with each of the STAs according to the channel state information, the data traffic volume, the data service type, and the like of each STA, and specifies a packet number for each MU-MIMO packet.
  • the packet information is separately constructed, and the packet information is notified to the STA by signaling.
  • the feedback module 230 is configured to reply the ACK message in the order of the STAs in the MU-MIMO packet.
  • the feedback module 230 may be configured to: reply the ACK message in order according to the relative position of the STAs identified by the MAC address carried in the MU-MIMO data frame payload in the MU-MIMO packet.
  • modules or steps of the present invention described above can be implemented by a general-purpose computing device, which can be centralized on a single computing device or distributed over a network of multiple computing devices. Alternatively, they may be implemented by program code executable by the computing device, such that they may be stored in the storage device by the computing device, or they may be fabricated into individual integrated circuit modules, or many of them Modules or steps are made into a single integrated circuit module. Thus, the invention is not limited to any specific combination of hardware and software.
  • the STAs in the MU-MIMO packet can reply ACKs in an orderly manner without additional signaling, and collisions are avoided between each other, and STAs without data transmission in the group need not transmit.
  • ACK also saves signaling overhead. It also guarantees that the services of the primary STAs are given priority and therefore have strong industrial applicability.

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Abstract

The present invention discloses a method for multi-user acknowledgement (ACK) feedback and a station (STA) for feeding back an ACK. The method is used for STAs related to an Access Point (AP) in a Basic Service Set (BSS) to reply with ACKs, and includes: after dividing the STAs related to the AP into Multi-User Multiple Input Multiple Output (MU-MIMO) groups, assigning a group identification (ID) and creating group information for each MU-MIMO group respectively, the AP notifies the STAs of the group information; after receiving a Request To Send (RTS) frame and an MU-MIMO data frame, according to the group information, the RTS, the Group ID domain and the information indicated by the station data flow information indication NSTS domain contained in VHT-SIG-A in the physical frame header of the MU-MIMO data frame, the Media Access Control (MAC) address information in the physical frame load of the MU-MIMO data frame and the MU-MIMO group information with the Group ID indicated by the Group ID domain, the STA determines the STA needing to reply with an ACK, and replies with the ACK in an appointed order.

Description

多用户反馈确认消息的方法及反馈确认消息的站点  Method for multi-user feedback confirmation message and site for feedback confirmation message

技术领域 Technical field

本发明涉及反馈确认消息 (ACK ) 的技术, 尤其涉及一种多用户反馈确 认消息的方法, 以及一种反馈确认消息的站点 (STA , Station ) 。  The present invention relates to a technique for feeding back an acknowledgement message (ACK), and more particularly to a method for multi-user feedback confirmation message, and a site (STA, Station) for feeding back a confirmation message.

背景技术 Background technique

无线局域网络( WLAN , Wireless Local Area Networks )是应用无线通信 技术将计算机设备互联起来,构成可以互相通信和实现资源共享的网络体系。 无线局域网的本质特点是不再使用通信电缆将计算机与网络连接起来, 而是 通过无线的方式连接,从而使网络的构建和终端的移动更加灵活。 IEEE802.i l 是目前无线局域网的主流技术之一, 此协议主要规定物理层(PHY )和媒体 访问控制 (MAC )层规范。  Wireless Local Area Networks (WLAN) is a network system that uses wireless communication technology to interconnect computer devices to form a network that can communicate with each other and share resources. The essential feature of WLAN is that it no longer uses a communication cable to connect the computer to the network, but to connect wirelessly, which makes the construction of the network and the movement of the terminal more flexible. IEEE802.i l is one of the mainstream technologies of wireless LAN. This protocol mainly specifies the physical layer (PHY) and media access control (MAC) layer specifications.

随着移动通信技术的发展以及人们对无线网络的需求的提高, 物理层技 术规范向着速率越来越高的方向不断发展, 经历了 802.11 到 802.11b再到 802.1 la/g, 然后 802.11η, 最后到 802.11ac的发展历程。 实际的物理技术也从 直接序列扩频技术发展到正交频率复用(OFDM, orthogonal frequency division multiplexing )技术,并且在 IEEE802.1 In中引入了多天线技术,在 IEEE802.1 lac 中引入大带宽和多用户-多输入多输出 (MU-MIMO ) 。  With the development of mobile communication technology and the increasing demand for wireless networks, the physical layer specification has been developing towards higher and higher speeds, going through 802.11 to 802.11b to 802.1 la/g, then 802.11η, and finally To the development of 802.11ac. The actual physical technology has also evolved from direct sequence spread spectrum technology to orthogonal frequency division multiplexing (OFDM) technology, and introduced multi-antenna technology in IEEE802.1 In to introduce large bandwidth in IEEE802.1 lac. And multi-user-multiple input multiple output (MU-MIMO).

但是, 现有技术还未提供参与多用户( MU )传输的多个用户如何回复确 认消息 (ACK ) 的技术方案。  However, the prior art has not provided a technical solution for how multiple users participating in multi-user (MU) transmissions reply to an acknowledgement message (ACK).

发明内容 Summary of the invention

本发明所要解决的技术问题是需要提供一种多用户反馈确认消息的方 法,克服现有技术未提供参与 MU传输的多个用户如何回复确认消息( ACK ) 的技术方案的缺陷。  The technical problem to be solved by the present invention is to provide a method for multi-user feedback confirmation message, which overcomes the shortcomings of the prior art that the multiple users participating in the MU transmission reply to the acknowledgment message (ACK).

为了解决上述技术问题,本发明提供了一种多用户反馈确认消息的方法, 用于一个基本服务集(BSS ) 中与接入点 (AP ) 关联的站点 (STA ) 回复确 认消息( ACK ); AP对与其关联的 STA进行多用户-多输入多输出( MU-MIMO ) 分组, 为每一个 MU-MIMO分组指定分组编号并分别构造分组信息后, 将分 组信息通知给 STA; 该方法包括: In order to solve the above technical problem, the present invention provides a method for multi-user feedback confirmation message, which is used for a site (STA) associated with an access point (AP) in a basic service set (BSS). The acknowledgement message (ACK); the AP performs multi-user-multiple input multiple output (MU-MIMO) packets on the STAs associated with it, assigns a packet number to each MU-MIMO packet, and constructs packet information separately, and notifies the STA of the packet information. ; The method includes:

STA收到 MU-MIMO数据帧后, 根据数据帧的物理帧头中 VHT-SIG-A 所包含的分组编号( Group ID )域和站点数据流信息指示( NSTS )域所指示的 信息, 物理帧负载中的媒体访问控制(MAC )地址信息, 以及 Group ID域所 指示的分组编号下的 MU-MIMO分组信息, 确定回复 ACK的 STA, 并按约 定顺序回复 ACK。 After receiving the MU-MIMO data frame, the STA indicates the information indicated by the packet number (Group ID) field and the site data flow information indication (N STS ) field in the physical frame header of the data frame, physics. The media access control (MAC) address information in the frame payload, and the MU-MIMO packet information under the packet number indicated by the Group ID field, determine the STA that replies to the ACK, and reply the ACK in the agreed order.

其中, 所述 MU-MIMO数据帧中的 Group ID域所指示的分组编号与本 STA自身所在的 MU-MIMO分组的分组编号相同, NSTS域中的相应位置处不 为零, 所述物理帧负载中携带有与本 STA自身的 MAC地址相同的 MAC地 址, 则此 STA回复所述 ACK; The packet number indicated by the Group ID field in the MU-MIMO data frame is the same as the packet number of the MU-MIMO packet where the STA itself is located, and the corresponding position in the N STS domain is not zero, the physical frame. The bearer carries the same MAC address as the STA's own MAC address, and the STA replies to the ACK;

其中,所述相应位置与本 STA自身在 MU-MIMO分组中的相对位置相同。  The corresponding location is the same as the relative location of the STA itself in the MU-MIMO packet.

其中,根据所述约定顺序,首先回复所述 ACK的 STA是此次 MU-MIMO 传输的请求发送帧( RTS )中承载的 MAC地址所对应的 STA;所述 MU-MIMO 数据帧负载中携带的 MAC地址所标识的其余 STA按照在 MU-MIMO分组中 的相对位置顺序回复所述 ACK。 According to the agreed order, the STA that first responds to the ACK is the STA corresponding to the MAC address carried in the request transmission frame (RTS) of the MU-MIMO transmission; the MU-MIMO data frame carries the bearer The remaining STAs identified by the MAC address reply to the ACK in the order of relative positions in the MU-MIMO packet.

其中, 所述约定顺序包括所述 MU-MIMO数据帧负载中携带的 MAC地 址所标识的 STA在 MU-MIMO分组中的相对位置顺序。  The order of the agreement includes a relative position sequence of STAs identified by the MAC address carried in the MU-MIMO data frame payload in the MU-MIMO packet.

其中, 所述 MU-MIMO数据帧中的 Group ID域所指示的分组编号与本 STA 自身所在的 MU-MIMO 分组的分组编号不同, 则此 STA 不回复所述 ACK。  The STA indicates that the packet number indicated by the Group ID field in the MU-MIMO data frame is different from the packet number of the MU-MIMO packet in which the STA itself is located, and the STA does not reply to the ACK.

其中, 所述 MU-MIMO数据帧中的 Group ID域所指示的分组编号与本 STA自身所在的 MU-MIMO分组的分组编号相同, NSTS域中的相应位置指示 为零, 则此 STA不回复所述 ACK; The packet number indicated by the Group ID field in the MU-MIMO data frame is the same as the packet number of the MU-MIMO packet where the STA itself is located, and the corresponding location indication in the N STS domain is zero, and the STA does not reply. The ACK;

其中,所述相应位置与本 STA自身在 MU-MIMO分组中的相对位置相同。 其中, 所述 MU-MIMO数据帧中的 Group ID域所指示的分组编号与本 STA自身所在的 MU-MIMO分组的分组编号相同, NSTS域中的相应位置指示 不为零, 所述物理帧负载中携带的 MAC与本 STA自身的 MAC地址不同, 则此 STA不回复所述 ACK; The corresponding location is the same as the relative location of the STA itself in the MU-MIMO packet. The group number and the number indicated by the Group ID field in the MU-MIMO data frame The MU-MIMO packet in which the STA is located has the same packet number, and the corresponding location indication in the N STS domain is not zero. If the MAC carried in the physical frame payload is different from the MAC address of the STA itself, the STA does not reply. ACK;

其中, 所述相应位置与本 STA在 MU-MIMO分组中的相对位置相同。 其中, 为每一个 MU-MIMO分组指定组编号的步骤, 包括:  The corresponding location is the same as the relative location of the STA in the MU-MIMO packet. The step of assigning a group number to each MU-MIMO packet includes:

本发明所要解决的另一技术问题是需要提供一种反馈确认消息的站点 ( STA ) , 克服现有技术未提供参与 MU传输的多个用户如何回复确认消息 ( ACK ) 的技术方案的缺陷。 Another technical problem to be solved by the present invention is to provide a site (STA) for feeding back a confirmation message, which overcomes the drawbacks of the prior art that the multiple users participating in the MU transmission reply to the acknowledgment message (ACK).

为了解决上述技术问题,本发明提供了一种反馈确认消息的站点( STA ) , 应用于向一个基本服务集(BSS )中的接入点(AP )回复确认消息(ACK ) , 其与其他一个或一个以上的 STA与所述 AP相关联; 所述 STA包括接收模块 以及反馈模块, 其中:  In order to solve the above technical problem, the present invention provides a site (STA) for feeding back a confirmation message, which is applied to reply an acknowledgement message (ACK) to an access point (AP) in a basic service set (BSS), which is combined with another one. Or more than one STA is associated with the AP; the STA includes a receiving module and a feedback module, where:

所述接收模块设置成: 接收多用户-多输入多输出( MU-MIMO )数据帧; 所述反馈模块设置成: 根据所述 MU-MIMO 数据帧的物理帧头中 The receiving module is configured to: receive a multi-user-multiple input multiple output (MU-MIMO) data frame; the feedback module is configured to: according to the physical frame header of the MU-MIMO data frame

VHT-SIG-A所包含的分组编号(Group ID )域和站点数据流信息指示(NSTS ) 域所指示的信息, 物理帧负载中的媒体访问控制 (MAC )地址信息, 以及 Group ID域所指示的分组编号下的 MU-MIMO分组信息, 确定回复 ACK的 STA, 并按约定顺序回复 ACK; The group ID field and site data stream information included in the VHT-SIG-A indicate the information indicated by the (N STS ) field, the media access control (MAC ) address information in the physical frame payload, and the Group ID field. MU-MIMO packet information under the indicated packet number, determining STAs replying to the ACK, and replying to the ACK in an agreed order;

其中, 所述 AP对与其关联的 STA进行 MU-MIMO 分组, 为每一个 The AP performs MU-MIMO grouping on the STAs associated with it, for each

MU-MIMO 分组指定分组编号并分别构造分组信息后, 将分组信息通知给 STA。 After the MU-MIMO packet specifies the packet number and constructs the packet information separately, the packet information is notified to the STA.

其中,所述反馈模块设置成:按 STA在 MU-MIMO分组中的顺序回复所 述 ACK。  The feedback module is configured to reply the ACK in the order of the STAs in the MU-MIMO packet.

其中, 所述反馈模块设置成: 按所述 MU-MIMO数据帧负载中携带的 The feedback module is configured to: carry according to the MU-MIMO data frame load

MAC地址所标识的 STA在 MU-MIMO分组中的相对位置顺序回复所述 ACK 消息。 The relative locations of the STAs identified by the MAC address in the MU-MIMO packet sequentially reply to the ACK message.

本发明提供了一种多用户反馈确认消息的方法, 用于一个基本服务集 ( BSS ) 中与接入点 (AP ) 关联的站点 (STA ) 回复确认消息 (ACK ) , 该 方法包括: The present invention provides a method for multi-user feedback confirmation message for a basic service set The site (STA) associated with the access point (AP) in (BSS) replies with an acknowledgment message (ACK), which includes:

AP对与其关联的 STA进行多用户-多输入多输出 ( MU-MIMO )分组, 为每一个 MU-MIMO分组指定分组编号并分别构造分组信息后, 将所述分组 信息通知给 STA; STA收到请求发送帧 (RTS )和 MU-MIMO数据帧后, 根 据所述分组信息、所述 RTS、所述 MU-MIMO数据帧的物理帧头中 VHT-SIG-A 所包含的分组编号( Group ID )域和站点数据流信息指示(NSTS )域所指示的 信息、 所述 MU-MIMO数据帧的物理帧的负载中的媒体访问控制(MAC )地 址信息以及所述 Group ID域所指示的分组编号下的 MU-MIMO分组信息,确 定需要回复 ACK的 STA, 并按约定顺序回复所述 ACK。 The AP performs a multi-user-multiple input multiple output (MU-MIMO) packet on the STA associated with it, assigns a packet number to each MU-MIMO packet, and separately constructs the packet information, and notifies the STA to the STA; After requesting a transmission frame (RTS) and a MU-MIMO data frame, according to the packet information, the RTS, and a packet number (Group ID) included in the physical frame header of the MU-MIMO data frame, VHT-SIG-A The domain and site data flow information indicates information indicated by the (N STS ) field, media access control (MAC ) address information in the payload of the physical frame of the MU-MIMO data frame, and the packet number indicated by the Group ID field The underlying MU-MIMO packet information determines the STAs that need to reply to the ACK and replies to the ACK in an agreed order.

其中, 确定需要回复 ACK的 STA的步骤包括: 所述 Group ID域所指示 的分组编号与 STA自身所在的 MU-MIMO分组的分组编号相同, 所述 NSTS 域中的相应位置处不为零,所述物理帧的负载中携带有与该 STA自身的 MAC 地址相同的 MAC地址, 则该 STA需要回复所述 ACK; The step of determining the STA that needs to reply to the ACK includes: the packet number indicated by the Group ID field is the same as the packet number of the MU-MIMO packet where the STA itself is located, and the corresponding location in the N STS domain is not zero. The payload of the physical frame carries the same MAC address as the MAC address of the STA itself, and the STA needs to reply to the ACK;

其中,所述相应位置与该 STA自身在 MU-MIMO分组中的相对位置相同。 其中, 所述约定顺序包括: STA在 MU-MIMO分组中的顺序。  The corresponding location is the same as the relative location of the STA itself in the MU-MIMO packet. The order of the agreement includes: an order of the STAs in the MU-MIMO packet.

其中, 所述约定顺序包括: 首先回复所述 ACK的 STA是所述 RTS中承 载的 MAC地址所对应的 STA; 所述 MU-MIMO数据帧负载中携带的 MAC 地址所标识的其余 STA按照在 MU-MIMO分组中的相对位置顺序回复所述 ACK。  The order of the agreement includes: the STA that first responds to the ACK is the STA corresponding to the MAC address carried in the RTS; the remaining STAs identified by the MAC address carried in the MU-MIMO data frame payload are in accordance with the MU. - The relative position in the MIMO packet sequentially replies to the ACK.

其中, 所述约定顺序包括: 所述 MU-MIMO数据帧负载中携带的 MAC 地址所标识的 STA在 MU-MIMO分组中的相对位置顺序。  The order of the agreement includes: a relative position sequence of STAs identified by the MAC address carried in the MU-MIMO data frame payload in the MU-MIMO packet.

其中, 确定需要回复 ACK的 STA的步骤包括: 所述 Group ID域所指示 的分组编号与 STA自身所在的 MU-MIMO分组的分组编号不同, 则该 STA 不需要回复所述 ACK。  The step of determining the STA that needs to reply to the ACK includes: the packet number indicated by the Group ID field is different from the packet number of the MU-MIMO packet in which the STA itself is located, and the STA does not need to reply to the ACK.

其中, 确定需要回复 ACK的 STA的步骤包括: 所述 Group ID域所指示 的分组编号与 STA自身所在的 MU-MIMO分组的分组编号相同, 所述 NSTS 域中的相应位置指示为零, 则该 STA不需要回复所述 ACK; 其中,所述相应位置与该 STA自身在 MU-MIMO分组中的相对位置相同。 其中, 确定需要回复 ACK的 STA的步骤包括: 所述 Group ID域所指示 的分组编号与 STA自身所在的 MU-MIMO分组的分组编号相同, 所述 NSTS 域中的相应位置指示不为零, 所述物理帧的负载中携带的 MAC与该 STA自 身的 MAC地址不同, 则该 STA不需要回复所述 ACK; The step of determining the STA that needs to reply to the ACK includes: the packet number indicated by the Group ID field is the same as the packet number of the MU-MIMO packet where the STA itself is located, and the corresponding location indication in the N STS domain is zero, The STA does not need to reply to the ACK; The corresponding location is the same as the relative location of the STA itself in the MU-MIMO packet. The step of determining the STA that needs to reply to the ACK includes: the packet number indicated by the Group ID field is the same as the packet number of the MU-MIMO packet where the STA itself is located, and the corresponding location indication in the N STS domain is not zero. If the MAC carried in the payload of the physical frame is different from the MAC address of the STA itself, the STA does not need to reply to the ACK.

其中, 所述相应位置与该 STA在 MU-MIMO分组中的相对位置相同。 其中, 为每一个 MU-MIMO 分组指定组编号的步骤包括: 不同的 MU-MIMO分组具有相同或者不同的分组编号。  The corresponding location is the same as the relative location of the STA in the MU-MIMO packet. Wherein, the step of assigning a group number to each MU-MIMO packet includes: different MU-MIMO packets have the same or different packet numbers.

本发明提供了一种反馈确认消息的站点 (STA ) , 用于向一个基本服务 集(BSS ) 中的接入点 (AP ) 回复确认消息 (ACK ) , 两个或两个以上的所 分组, 为每一个 MU-MIMO分组指定分组编号并分别构造分组信息后, 将所 述分组信息通知给所述 STA, 所述 STA包括第一接收模块、 第二接收模块以 及反馈模块, 其中:  The present invention provides a site (STA) for feeding back a confirmation message for replying an acknowledgment message (ACK) to two (or two) groups of access points (APs) in a basic service set (BSS). After the packet number is specified for each MU-MIMO packet and the packet information is separately configured, the packet information is notified to the STA, where the STA includes a first receiving module, a second receiving module, and a feedback module, where:

所述第一接收模块设置成: 接收 AP发送的请求发送帧( RTS )以及分组 信息,根据所述分组信息获知 STA自身所处的 MU-MIMO分组的分组编号以 及 STA自身在 MU-MIMO分组内的相对位置信息;  The first receiving module is configured to: receive a request sending frame (RTS) sent by the AP, and group information, and learn, according to the grouping information, a packet number of the MU-MIMO packet where the STA itself is located, and the STA itself is in the MU-MIMO packet. Relative position information;

所述第二接收模块设置成: 接收多用户-多输入多输出 ( MU-MIMO )数 据帧;  The second receiving module is configured to: receive a multi-user-multiple input multiple output (MU-MIMO) data frame;

所述反馈模块设置成:根据所获知的 STA自身所处的 MU-MIMO分组的 分组编号以及 STA自身在 MU-MIMO分组内的相对位置信息、所述 RTS、所 述 MU-MIMO数据帧的物理帧头中 VHT-SIG-A所包含的分组编号( Group ID ) 域和站点数据流信息指示 (NSTS )域所指示的信息、 物理帧的负载中的媒体 访问控制 (MAC )地址信息以及所述 Group ID 域所指示的分组编号下的 MU-MIMO分组信息, 确定需要回复 ACK的 STA, 并按约定顺序回复所述 ACK。 The feedback module is configured to: according to the obtained packet number of the MU-MIMO packet in which the STA itself is located, and the relative location information of the STA itself in the MU-MIMO packet, the RTS, the physics of the MU-MIMO data frame The packet number (Group ID) field and the site data stream information indication (N STS ) field included in the VHT-SIG-A in the frame header, the media access control (MAC) address information in the payload of the physical frame, and the location The MU-MIMO packet information under the packet number indicated by the Group ID field determines the STAs that need to reply to the ACK, and replies to the ACK in an agreed order.

其中: 所述反馈模块还设置成:按 STA在 MU-MIMO分组中的顺序回复 所述 ACK。 其中: 所述反馈模块还设置成: 按所述 MU-MIMO数据帧负载中携带的 MAC 地址所标识的 STA在 MU-MIMO 分组中的相对位置顺序回复所述 ACK。 Wherein: the feedback module is further configured to: reply the ACK in the order of the STAs in the MU-MIMO packet. The feedback module is further configured to: reply the ACK according to the relative position of the STAs identified by the MAC address carried in the MU-MIMO data frame payload in the MU-MIMO packet.

其中: 所述反馈模块设置成按照以下方式确定需要回复 ACK的 STA: 所述 Group ID域所指示的分组编号与 STA自身所在的 MU-MIMO分组 的分组编号相同, 所述 NSTS域中的相应位置处不为零, 所述物理帧的负载中 携带有与该 STA自身的 MAC地址相同的 MAC地址, 则所述反馈模块确认 该 STA需要回复所述 ACK; The feedback module is configured to determine, in the following manner, the STA that needs to reply to the ACK: the packet number indicated by the Group ID field is the same as the packet number of the MU-MIMO packet where the STA itself is located, and the corresponding in the N STS domain If the location of the physical frame is not the same as the MAC address of the STA itself, the feedback module confirms that the STA needs to reply to the ACK;

其中,所述相应位置与该 STA自身在 MU-MIMO分组中的相对位置相同。 釆用此发明技术方案,可以保证 MU-MIMO分组中的 STA能够有序有效 的回复 ACK, 而不需要额外的信令通知, 相互间亦会避免碰撞, 同时组内无 数据传输的 STA无需传输 ACK, 也节省了信令开销。 也可以保证首要 STA 的服务获得优先保障。  The corresponding location is the same as the relative location of the STA itself in the MU-MIMO packet. With the technical solution of the invention, it is ensured that the STAs in the MU-MIMO packet can reply ACKs in an orderly manner without additional signaling, and collisions are avoided between each other, and STAs without data transmission in the group need not transmit. ACK also saves signaling overhead. It is also possible to ensure that the services of the primary STAs are given priority protection.

本发明的其它特征和优点将在随后的说明书中阐述, 并且, 部分地从说 明书中变得显而易见, 或者通过实施本发明而了解。 本发明的目的和其他优 点可通过在说明书、权利要求书以及附图中所特别指出的结构来实现和获得。  Other features and advantages of the invention will be set forth in the description which follows, The objectives and other advantages of the invention may be realized and obtained by the structure particularly pointed in the appended claims.

附图概述 BRIEF abstract

附图用来提供对本发明的进一步理解, 并且构成说明书的一部分, 与本 发明的实施例一起用于解释本发明, 并不构成对本发明的限制。 在附图中: 图 1是本发明实施例一的多用户反馈 ACK的方法的流程示意图; 图 2是本发明实施例二的反馈 ACK的 STA的组成示意图。  The drawings are intended to provide a further understanding of the invention, and are intended to be a part of the description of the invention. 1 is a schematic flowchart of a method for multi-user feedback ACK according to Embodiment 1 of the present invention; and FIG. 2 is a schematic diagram of a composition of a STA for feedback ACK according to Embodiment 2 of the present invention.

本发明的较佳实施方式 Preferred embodiment of the invention

以下将结合附图及实施例来详细说明本发明的实施方式, 借此对本发明 如何应用技术手段来解决技术问题, 并达成技术效果的实现过程能充分理解 并据以实施。 均在本发明的保护范围之内。 另外, 在附图的流程图示出的步骤可以在诸如 一组计算机可执行指令的计算机系统中执行, 并且, 虽然在流程图中示出了 逻辑顺序, 但是在某些情况下, 可以以不同于此处的顺序执行所示出或描述 的步骤。 The embodiments of the present invention will be described in detail below with reference to the accompanying drawings and embodiments, in which the present invention can be applied to the technical problems, and the implementation of the technical effects can be fully understood and implemented. All are within the scope of protection of the present invention. Additionally, the steps illustrated in the flowchart of the figures may be performed in a computer system, such as a set of computer-executable instructions, and, although the logical order is illustrated in the flowchart, in some cases, may be different The steps shown or described are performed in the order herein.

实施例一、 多用户反馈 ACK的方法  Embodiment 1 Multi-user feedback ACK method

本实施例用于一个基本服务集(BSS, Basic Service Set )中与接入点( AP, Access Point ) 关联的站点 (STA, Station ) 回复确认消息。 如图 1所示, 本 实施例主要包括如下步骤:  This embodiment is used for a station (STA, Station) associated with an access point (AP, Access Point) in a basic service set (BSS) to reply a confirmation message. As shown in FIG. 1, the embodiment mainly includes the following steps:

步骤 S110, 在一个 BSS中, AP根据每个 STA的信道状态信息、 数据业 务量、 数据业务类型等一个因素或几个因素的组合, 对与其关联的 STA进行 所有可能的 MU-MIMO分组,同时为每一个 MU-MIM0分组指定一个分组编 号 (Group ID )并分别构造分组信息;  Step S110: In a BSS, the AP performs all possible MU-MIMO packets on the STAs associated with the STA according to one factor or a combination of several factors, such as channel state information, data traffic, and data service type of each STA. Specify a group ID (Group ID) for each MU-MIM0 packet and construct packet information separately;

MU-MIMO分组也可以具有不同的分组编号; MU-MIMO packets may also have different packet numbers;

步骤 S120, AP通过信令将分组信息通知给 STA;  Step S120, the AP notifies the STA of the group information by using signaling;

其中, 该分组信息可以携带在管理帧中发送给 STA。  The packet information may be carried in a management frame and sent to the STA.

步骤 SI 30, STA接收到分组信息后,获知自身所处的 MU-MIMO分组的 分组编号, 同时也可以获得自身在 MU-MIMO分组内的相对位置信息;  Step SI 30, after receiving the packet information, the STA learns the packet number of the MU-MIMO packet in which it is located, and also obtains relative position information in the MU-MIMO packet.

步骤 S140, STA收到 MU-MIMO数据帧后, 根据数据帧的物理帧头中 VHT-SIG-A所包含的分组编号( Group ID )域和站点数据流信息指示( NSTS ) 域所指示的信息, 物理帧负载中的媒体访问控制 (MAC )地址信息, 以及 Group ID域所指示的分组编号下的 MU-MIMO分组信息,确定需要回复 ACK 的 STA, 并按约定顺序回复 ACK。 Step S140, after receiving the MU-MIMO data frame, the STA indicates the group number (Group ID) field and the site data flow information indication (N STS ) field included in the physical frame header of the data frame according to the VHT-SIG-A. The information, the media access control (MAC) address information in the physical frame payload, and the MU-MIMO packet information under the packet number indicated by the Group ID field, determine the STAs that need to reply to the ACK, and reply ACKs in the agreed order.

其中, STA还会收到请求发送帧 (RTS, Request To Send ) , 该 RTS中 包含收发双方的 MAC地址信息。 RTS是控制帧, 用来保护 MU-MIMO数据 帧的发送。  The STA also receives a request to send (RTS, Request To Send), where the RTS includes the MAC address information of both the sender and the receiver. The RTS is a control frame used to protect the transmission of MU-MIMO data frames.

其中,若 MU-MIMO数据帧中的 Group ID域所指示的分组编号与本 STA 自身所在的 MU-MIMO分组的分组编号相同, NSTS域相应位置指示不为零, 物理帧负载中携带有与本 STA自身的 MAC地址相同的 MAC地址, 则数据 检测完成后, 此 STA 需要回复 ACK; 上述相应位置与本 STA 自身在 MU-MIMO分组中的相对位置相同。 Wherein, if the group number indicated by the Group ID field in the MU-MIMO data frame is the same as the group number of the MU-MIMO packet in which the STA itself is located, the corresponding position indication of the N STS field is not zero. The physical frame payload carries the same MAC address as the STA's own MAC address. After the data detection is completed, the STA needs to reply to the ACK. The corresponding location is the same as the STA itself's relative position in the MU-MIMO packet.

其中, 按上述约定顺序, 首先回复 ACK的 STA是此次 MU-MIMO传输 的 RTS中所承载的 MAC地址所对应的 STA, 此 STA可以称之为首要站点。 The STA that first responds to the ACK is the STA corresponding to the MAC address carried in the RTS of the MU-MIMO transmission, and the STA may be referred to as a primary site.

其中,若 MU-MIMO数据帧中的 Group ID域所指示的分组编号与本 STA 自身所在的 MU-MIMO分组的分组编号不同,则此 STA无需进一步解析数据, 也无需回复 ACK。  If the packet number indicated by the Group ID field in the MU-MIMO data frame is different from the packet number of the MU-MIMO packet in which the STA itself is located, the STA does not need to further parse the data, and does not need to reply to the ACK.

其中,若 MU-MIMO数据帧中的 Group ID域所指示的分组编号与本 STA 自身所在的 MU-MIMO分组的分组编号相同, NSTS域中的相应位置指示为零, 则此 STA无需进一步解析数据, 也无需回复 ACK; 上述相应位置与本 STA 自身在 MU-MIMO分组中的相对位置相同。 If the packet number indicated by the Group ID field in the MU-MIMO data frame is the same as the packet number of the MU-MIMO packet in which the STA itself is located, and the corresponding location indication in the N STS domain is zero, the STA does not need to further analyze. Data, there is no need to reply to ACK; the above corresponding position is the same as the relative position of the STA itself in the MU-MIMO packet.

其中,若 MU-MIMO数据帧中的 Group ID域所指示的分组编号与本 STA 自身所在的 MU-MIMO分组的分组编号相同, NSTS域中的相应位置指示不为 零, 物理帧负载中携带的 MAC与本 STA自身的 MAC地址不同, 则此 STA 无需回复 ACK; 上述相应位置与本 STA在 MU-MIMO分组中的相对位置相 同。 If the packet number indicated by the Group ID field in the MU-MIMO data frame is the same as the packet number of the MU-MIMO packet where the STA itself is located, the corresponding location indication in the N STS domain is not zero, and the physical frame load is carried. The MAC does not need to reply to the ACK when the MAC address of the STA is different from the STA's own MAC address; the corresponding location is the same as the relative position of the STA in the MU-MIMO packet.

实施例一的实际应用一 Practical application of the first embodiment

网络中有 1个 AP和 6个 STA, 6个 STA分别表示为第一站点(STA-1 ) , 第二站点 (STA-2 ) , 第三站点 (STA-3 ) , 第四站点 (STA-4 ) , 第五站点 ( STA-5 ) , 第六站点 ( STA-6 ) 。 每个 MU-MIMO分组最多有 4个 STA组 成, 不足 4个 STA的 MU-MIMO分组仍然被认为由 4个 STA组成, 不足的 部分可以认为有虚拟的 STA存在。  There are 1 AP and 6 STAs in the network, and 6 STAs are represented as the first station (STA-1), the second station (STA-2), the third station (STA-3), and the fourth station (STA-). 4), the fifth station (STA-5), the sixth station (STA-6). Each MU-MIMO packet has a maximum of 4 STAs, and a MU-MIMO packet of less than 4 STAs is still considered to be composed of 4 STAs, and an insufficient portion can be considered to have a virtual STA.

AP按照各 STA的信道状态信息将这 6个 STA分为多个 MU-MIMO分组, 并将分组信息通知给相应的 STA。 假定组编号足够多, 每一个组编号只指示 一个 MU-MIMO分组, 其中一个分组为 (STA-2, STA-6, STA-4, STA-1 ) , 组编号 Group ID=2。 The AP divides the six STAs into multiple MU-MIMO packets according to the channel state information of each STA, and notifies the corresponding STAs of the packet information. Assuming that the group number is sufficient, each group number indicates only one MU-MIMO packet, and one of the packets is (STA-2, STA-6, STA-4, STA-1). Group number Group ID=2.

AP发布此 MU-MIMO分组信息, 信息包含组编号 Group ID=2 , 以及按 照上面括号内的顺序排列的 4个 STA的标识符, 本实际应用中标识符用各 STA的 MAC地址表示。  The AP issues the MU-MIMO packet information, the information includes the group number Group ID=2, and the identifiers of the four STAs arranged in the order of the parentheses above. In the actual application, the identifier is represented by the MAC address of each STA.

各 STA接收此 MU-MIMO分组信息后都进行检测,但只有 STA- 1 , STA-2 , Each STA receives the MU-MIMO packet information and detects it, but only STA-1, STA-2,

STA-4以及 STA-6会将此 MU-MIMO分组信息作为有用信息, 因为在接收到 的信息中有与本身相匹配的 STA标识符。 这四个 STA从此 MU-MIMO分组 信息中得到的有用信息有两方面: STA-4 and STA-6 will use this MU-MIMO packet information as useful information because there is a STA identifier matching the one in the received information. The four STAs have useful information from this MU-MIMO packet information in two ways:

1 )本身属于组编号 Group ID=2的 MU-MIMO分组;  1) a MU-MIMO packet belonging to the group number Group ID=2;

2 )本身在此 MU-MIMO分组中的相对位置。  2) The relative position of itself in this MU-MIMO packet.

例如, STA-1从此 MU-MIMO分组信息中得到的信息包括: STA-1属于 组编号 Group ID=2的 MU-MIMO分组, 同时 STA-1在此分组中的处于第 4 个位置。  For example, the information obtained by STA-1 from the MU-MIMO packet information includes: STA-1 belongs to the MU-MIMO packet with the group number Group ID=2, and STA-1 is in the fourth position in this packet.

本实际应用中, RTS 帧中携带的 MAC 地址所标识的 STA在本次 MU-MIMO传输中有数据传输, 则此 STA需要首先回复 ACK, 数据帧负载 中携带的 MAC地址所标识的其余 STA按照所在分组的相对位置顺序回复 ACK。  In this application, if the STA identified by the MAC address carried in the RTS frame has data transmission in the current MU-MIMO transmission, the STA needs to reply the ACK first, and the remaining STAs identified by the MAC address carried in the data frame payload are The relative position of the group in which the packet is located is replied in order.

本实际应用的当前 MU-MIMO传输, 在 4个 STA中, STA-1、 STA-2和 STA-6都有一个数据流传输, STA-4没有数据传输。  In the current MU-MIMO transmission of the actual application, among the four STAs, STA-1, STA-2 and STA-6 have one data stream transmission, and STA-4 has no data transmission.

进行 RTS/允许发送帧 ( Clear To Send, CTS ) 交换后, 进行 MU-MIMO 数据包传输,其中在 AP发送的 RTS帧负载中的 MAC地址域中的 MAC地址 为 STA-6的 MAC地址,在 RTS帧的物理帧头中包含组编号 Group ID=2信息。  After the RTS/Clear To Send (CTS) exchange, the MU-MIMO packet transmission is performed, wherein the MAC address in the MAC address field in the RTS frame payload sent by the AP is the MAC address of the STA-6, The physical frame header of the RTS frame contains the group number Group ID=2 information.

釆用本实际应用的方法, 各 STA回复 ACK的判决过程如下:  Using the method of this practical application, the decision process of each STA replying to ACK is as follows:

( 1 )对于 STA-1  (1) for STA-1

STA-1接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-1解析 NSTS域获得的信息包括: 1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;STA-1 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-1 to resolve the N STS domain includes: 1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1; 2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为零, 即本次传 输不包含 MU-MIMO分组中第三个位置的 STA的数据;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is zero, that is, the data of the STA that does not include the third location in the MU-MIMO packet is transmitted this time;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1。  4) The number of data streams of the STA at the fourth position in the MU-MIMO packet is 1.

进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据; 根据前面的内容可知 , STA- 1占据此 MU-MIMO分组内的第四个位置; 根据接收的 RTS帧, 可知 RTS帧负载中的 MAC地址是 STA-6的 MAC 地址, 且本次传输有 STA-6的数据;  Further analyzing the MAC address information in the frame payload and discovering that its own MAC address is included, so the current transmission has its own data; according to the foregoing, STA-1 occupies the fourth position in the MU-MIMO packet. According to the received RTS frame, it can be known that the MAC address in the RTS frame payload is the MAC address of STA-6, and the data of STA-6 is transmitted this time;

综合以上这些信息, 按照本实际应用的方法, 因为相对位置靠前的一个 STA没有数据传输即第三个位置上的 STA没有数据传输,故 STA-1第 3个回 复 ACK。  Combining the above information, according to the method of the present application, since one STA of the relative position has no data transmission, that is, the STA at the third position has no data transmission, STA-1 replies to the third ACK.

( 2 )对于 STA-2  (2) For STA-2

STA-2接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-2解析 NSTS域获得的信息包括: The STA-2 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-2 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为零, 即本次传 输不包含 MU-MIMO分组中第三个位置的 STA的数据;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is zero, that is, the data of the STA that does not include the third location in the MU-MIMO packet is transmitted this time;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1。  4) The number of data streams of the STA at the fourth position in the MU-MIMO packet is 1.

进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据;  Further parsing the MAC address information in the frame payload and discovering that its own MAC address is included, so this transmission has its own data;

根据前面的内容可知, STA-2占据此 MU-MIMO分组内的第一个位置; 根据接收的 RTS帧, 可知 RTS帧负载中的 MAC地址是 STA-6的 MAC 地址, 且本次传输有 STA-6的数据; According to the foregoing, STA-2 occupies the first position in the MU-MIMO packet; according to the received RTS frame, it can be known that the MAC address in the RTS frame payload is the STA-6 MAC address. Address, and this transmission has STA-6 data;

综合以上这些信息, 按照本实际应用的方法, STA-2第 2个回复 ACK。 ( 3 )对于 STA-3及 STA-5  Based on the above information, STA-2 replies ACK 2 in accordance with the method of this practical application. (3) For STA-3 and STA-5

STA-3接收到 MU-MIMO数据帧, 解析 VHT-SIG-A中的 Group ID域, 获知此帧不属于本身所在 MU-MIMO分组, 无需回复 ACK。  The STA-3 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and knows that the frame does not belong to the MU-MIMO packet itself, and does not need to reply to the ACK.

与 STA3有相同处理的 STA还有 STA5。  STAs that have the same processing as STA3 also have STA5.

( 4 )对于 STA-4  (4) For STA-4

STA-4接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-4解析 NSTS域获得的信息包括: The STA-4 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-4 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为零, 即本次传 输不包含 MU-MIMO分组中第三个位置的 STA的数据;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is zero, that is, the data of the STA that does not include the third location in the MU-MIMO packet is transmitted this time;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1。  4) The number of data streams of the STA at the fourth position in the MU-MIMO packet is 1.

根据前面的内容可知, STA-4占据此 MU-MIMO分组内的第三个位置, 故本次传输没有属于自身的数据, 无需回复 ACK。  According to the foregoing, STA-4 occupies the third position in the MU-MIMO packet, so the current transmission does not have its own data, and there is no need to reply to the ACK.

( 5 )对于 STA-6  (5) For STA-6

STA-6接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-6解析 NSTS域获得的信息包括: The STA-6 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-6 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为零, 即本次传 输不包含 MU-MIMO分组中第三个位置的 STA的数据; 4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1。 3) The number of data streams of the STA in the third position in the MU-MIMO packet is zero, that is, the current transmission does not include the data of the STA in the third position in the MU-MIMO packet; 4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1.

进一步解析 MU-MIMO数据帧负载中的 MAC地址信息, 发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据;  Further analyzing the MAC address information in the MU-MIMO data frame payload, and discovering that its own MAC address is included, so the current transmission has its own data;

根据前面的内容可知, STA-6占据此 MU-MIMO分组内的第二个位置; 根据接收的 RTS帧, 可知 RTS帧负载中的 MAC地址是本身的 MAC地 址;  According to the foregoing, STA-6 occupies the second position in the MU-MIMO packet; according to the received RTS frame, it can be known that the MAC address in the RTS frame payload is its own MAC address;

综合以上这些信息, 按照本实际应用的方法, STA-6第 1个回复 ACK。 最终回复 ACK的顺序:  Based on the above information, STA-6 replies with ACK first according to the method of this practical application. The order in which the ACK is finally returned:

第 1个回复 ACK的 STA是 STA-6;  The first reply ACK STA is STA-6;

第 2个回复 ACK的 STA是 STA-2;  The second reply ACK STA is STA-2;

第 3个回复 ACK的 STA是 STA-1。  The STA of the third reply ACK is STA-1.

实施例一的实际应用二 Practical application 2 of the first embodiment

网络中有 1个 AP和 6个 STA, 6个 STA分别表示为第一站点(STA-1 ) , 第二站点 (STA-2 ) , 第三站点 (STA-3 ) , 第四站点 ( STA-4 ) , 第五站点 ( STA-5 ) , 第六站点 ( STA-6 ) 。 每个 MU-MIMO分组最多有 4个 STA组 成, 不足 4个 STA的 MU-MIMO分组仍然被认为由 4个 STA组成, 不足的 部分可以认为有虚拟的 STA存在。  There are 1 AP and 6 STAs in the network, and 6 STAs are represented as the first station (STA-1), the second station (STA-2), the third station (STA-3), and the fourth station (STA-). 4), the fifth station (STA-5), the sixth station (STA-6). Each MU-MIMO packet has a maximum of 4 STAs, and a MU-MIMO packet of less than 4 STAs is still considered to be composed of 4 STAs, and an insufficient portion can be considered to have a virtual STA.

AP按照各 STA的信道状态信息将这 6个 STA分为多个 MU-MIMO分组, 并将分组信息通知给相应的 STA, 假定组编号足够多, 每一个组编号只指示 一个 MU-MIMO分组, 其中一个分组为 (STA-2, STA-6, STA-4, STA-1 ) , 组编号 Group ID=2。  The AP divides the six STAs into multiple MU-MIMO packets according to the channel state information of each STA, and notifies the corresponding STAs to the group information, assuming that the group number is sufficient, and each group number indicates only one MU-MIMO packet. One of the packets is (STA-2, STA-6, STA-4, STA-1), and the group number is Group ID=2.

AP发布此 MU-MIMO分组信息, 信息包含组编号 Group ID=2 , 以及按 照上面括号内的顺序排列的 4个 STA的标识符, 本实际应用中标识符用各 STA的 MAC地址表示。  The AP issues the MU-MIMO packet information, the information includes the group number Group ID=2, and the identifiers of the four STAs arranged in the order of the parentheses above. In the actual application, the identifier is represented by the MAC address of each STA.

各 STA接收此 MU-MIMO分组信息后都进行检测,但只有 STA-1 , STA-2 , STA-4以及 STA-6会将此 MU-MIMO分组信息作为有用信息, 因为在接收到 的信息中有与本身相匹配的 STA标识符, 这四个 STA从此 MU-MIMO分组 信息中得到的有用信息有两方面: Each STA receives the MU-MIMO packet information and detects it, but only STA-1, STA-2, STA-4, and STA-6 will use this MU-MIMO packet information as useful information because it is received. The information has STA identifiers that match itself. The useful information obtained by the four STAs from the MU-MIMO packet information has two aspects:

1 )本身属于组编号 Group ID=2的 MU-MIMO分组;  1) a MU-MIMO packet belonging to the group number Group ID=2;

2 )本身在此 MU-MIMO分组中的相对位置。  2) The relative position of itself in this MU-MIMO packet.

例如, STA-1从此 MU-MIMO分组信息中得到的信息包括: STA-1属于 组编号 Group ID=2的 MU-MIMO分组, 同时 STA-1在此分组中的处于第 4 个位置。  For example, the information obtained by STA-1 from the MU-MIMO packet information includes: STA-1 belongs to the MU-MIMO packet with the group number Group ID=2, and STA-1 is in the fourth position in this packet.

本实际应用中, RTS帧中携带的 MAC地址所标识的 STA需要首先回复 ACK, 但若此 STA在本次 MU-MIMO传输中无数据传输, 则此 STA无需回 复 ACK。数据帧负载中携带的 MAC地址所标识的 STA按照所在分组的相对 位置顺序回复 ACK。  In this application, the STA identified by the MAC address carried in the RTS frame needs to reply to the ACK first. However, if the STA has no data transmission in the current MU-MIMO transmission, the STA does not need to reply to the ACK. The STAs identified by the MAC address carried in the data frame payload reply ACK in the order of the relative positions of the packets.

本实际应用的当前 MU-MIMO传输,在 4个 STA中,只有 STA-1、 STA-2 各有一个数据流传输, STA-4和 STA-6没有数据传输。  In the current MU-MIMO transmission of the actual application, among the four STAs, only STA-1 and STA-2 have one data stream transmission, and STA-4 and STA-6 have no data transmission.

进行 RTS/CTS帧交换后, 进行 MU-MIMO数据包传输, 其中在 AP发送 的 RTS帧负载中的 MAC地址域中的 MAC地址为 STA-6的 MAC地址, 在 RTS帧的物理帧头中包含组编号 Group ID=2信息。  After the RTS/CTS frame exchange is performed, the MU-MIMO data packet transmission is performed, wherein the MAC address in the MAC address field in the RTS frame payload sent by the AP is the MAC address of the STA-6, and is included in the physical frame header of the RTS frame. Group number Group ID=2 information.

釆用本实际应用的方法, 各 STA回复 ACK的判决过程如下:  Using the method of this practical application, the decision process of each STA replying to ACK is as follows:

( 1 )对于 STA-1  (1) for STA-1

STA-1接收到 MU-MIMO数据帧, 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-1解析 NSTS域获得的信息包括: STA-1 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-1 to resolve the N STS domain includes:

1 ) 此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) The number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为零, 即本次传 输不包含 MU-MIMO分组中第二个位置的 STA的数据;  2) The number of data streams of the STA in the second location in the MU-MIMO packet is zero, that is, the current transmission does not include the data of the STA in the second location in the MU-MIMO packet;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为零, 即本次传 输不包含 MU-MIMO分组中第三个位置的 STA的数据; 4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1; 进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据; 根据前面的内容可知 , STA- 1占据此 MU-MIMO分组内的第四个位置; 根据接收的 RTS帧, 可知 RTS帧负载中的 MAC地址是 STA-6的 MAC 地址, 且本次传输没有 STA-6的数据, 3) The number of data streams of the STA in the third position in the MU-MIMO packet is zero, that is, the current transmission does not include the data of the STA in the third position in the MU-MIMO packet; 4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1; further analyzing the MAC address information in the frame payload, and discovering that its own MAC address is included, so the current transmission has its own data; According to the foregoing, STA-1 occupies the fourth position in the MU-MIMO packet. According to the received RTS frame, it can be known that the MAC address in the RTS frame payload is the MAC address of STA-6, and there is no STA in this transmission. -6 data,

综合以上这些信息, 按照本实际应用的方法, STA-1第 2个回复 ACK。  Based on the above information, STA-1 replies with ACK 2 in accordance with the method of this practical application.

( 2 )对于 STA-2  (2) For STA-2

STA-2接收到 MU-MIMO数据帧, 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-2解析 NSTS域获得的信息包括: The STA-2 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-2 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为零, 即本次传 输不包含 MU-MIMO分组中第二个位置的 STA的数据;  2) The number of data streams of the STA in the second location in the MU-MIMO packet is zero, that is, the current transmission does not include the data of the STA in the second location in the MU-MIMO packet;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为零, 即本次传 输不包含 MU-MIMO分组中第三个位置的 STA的数据;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is zero, that is, the data of the STA that does not include the third location in the MU-MIMO packet is transmitted this time;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1;  4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;

进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据;  Further parsing the MAC address information in the frame payload and discovering that its own MAC address is included, so this transmission has its own data;

根据前面的内容可知, STA-2占据此 MU-MIMO分组内的第一个位置; 根据接收的 RTS帧, 可知 RTS帧负载中的 MAC地址是 STA-6的 MAC 地址, 且本次传输没有 STA-6的数据;  According to the foregoing, the STA-2 occupies the first position in the MU-MIMO packet. According to the received RTS frame, the MAC address in the RTS frame payload is the MAC address of the STA-6, and there is no STA in the current transmission. -6 data;

综合以上这些信息, 按照本实际应用的方法, STA-2第 1个回复 ACK。  Based on the above information, STA-2 replies to the first ACK according to the method of this practical application.

( 3 )对于 STA-3及 STA-5  (3) For STA-3 and STA-5

STA-3接收到 MU-MIMO数据帧, 解析 VHT-SIG-A中的 Group ID域, 获知此帧不属于本身所 MU-MIMO分组, 无需回复 ACK。 与 STA3有相同处理的 STA还有 STA5。 The STA-3 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame does not belong to the MU-MIMO packet itself, and does not need to reply to the ACK. STAs that have the same processing as STA3 also have STA5.

( 4 )对于 STA-4  (4) For STA-4

STA-4接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-6解析 NSTS域获得的信息包括: The STA-4 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-6 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为零, 即本次传 输不包含 MU-MIMO分组中第二个位置的 STA的数据;  2) The number of data streams of the STA in the second location in the MU-MIMO packet is zero, that is, the current transmission does not include the data of the STA in the second location in the MU-MIMO packet;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为零, 即本次传 输不包含 MU-MIMO分组中第三个位置的 STA的数据;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is zero, that is, the data of the STA that does not include the third location in the MU-MIMO packet is transmitted this time;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1;  4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;

根据前面的内容可知, STA-4占据此 MU-MIMO分组内的第三个位置, 本次传输没有属于自身的数据, 无需回复 ACK。  According to the foregoing, STA-4 occupies the third position in the MU-MIMO packet, and the current transmission does not have its own data, and there is no need to reply to the ACK.

( 5 )对于 STA-6  (5) For STA-6

STA-6接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-6解析 NSTS域获得的信息包括: The STA-6 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-6 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为零, 即本次传 输不包含 MU-MIMO分组中第二个位置的 STA的数据;  2) The number of data streams of the STA in the second location in the MU-MIMO packet is zero, that is, the current transmission does not include the data of the STA in the second location in the MU-MIMO packet;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为零, 即本次传 输不包含 MU-MIMO分组中第三个位置的 STA的数据;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is zero, that is, the data of the STA that does not include the third location in the MU-MIMO packet is transmitted this time;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1;  4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;

根据前面的内容可知, STA-6占据此 MU-MIMO分组内的第二个位置, 所以本次传输没有属于自身的数据; 虽然 RTS帧负载中的 MAC地址是本身 的 MAC地址 , 但按照本实际应用的方法, STA-6无需回复 ACK。 According to the foregoing, STA-6 occupies the second position in the MU-MIMO packet, so this transmission does not have its own data; although the MAC address in the RTS frame payload is itself MAC address, but according to the method of this practical application, STA-6 does not need to reply ACK.

最终回复 ACK的顺序:  The order in which the ACK is finally returned:

第 1个回复 ACK的 STA是 STA-2;  The first reply ACK STA is STA-2;

第 2个回复 ACK的 STA是 STA-1。  The second reply ACK STA is STA-1.

实施例一的实际应用三 Practical application three of the first embodiment

假定网络中有 1 个 AP和 6个 STA, 6个 STA分别表示为第一站点 ( STA-1 ) , 第二站点( STA-2 ) , 第三站点( STA-3 ) , 第四站点( STA-4 ) , 第五站点 (STA-5 ) , 第六站点 (STA-6 ) 。 每个 MU-MIMO分组最多有 4 个 STA组成,不足 4个 STA的 MU-MIMO分组仍然被认为由 4个 STA组成, 不足的部分可以认为有虚拟的 STA存在。  Assume that there are 1 AP and 6 STAs in the network, and 6 STAs are represented as the first station (STA-1), the second station (STA-2), the third station (STA-3), and the fourth station (STA). -4), fifth site (STA-5), sixth site (STA-6). Each MU-MIMO packet has a maximum of 4 STAs, and a MU-MIMO packet of less than 4 STAs is still considered to be composed of 4 STAs, and an insufficient portion can be considered to have a virtual STA.

AP按照各 STA的信道状态信息将这 6个 STA分为多个 MU-MIMO分组, 并将分组信息通知给相应的 STA, 假定组编号足够多, 每一个组编号只指示 一个 MU-MIMO分组, 其中一个分组为 (STA-2, STA-6, STA-4, STA-1 ) , 组编号 Group ID=2。  The AP divides the six STAs into multiple MU-MIMO packets according to the channel state information of each STA, and notifies the corresponding STAs to the group information, assuming that the group number is sufficient, and each group number indicates only one MU-MIMO packet. One of the packets is (STA-2, STA-6, STA-4, STA-1), and the group number is Group ID=2.

AP发布此 MU-MIMO分组信息, 信息包含组编号 Group ID=2 , 以及按 照上面括号内的顺序排列的 4个 STA的标识符, 本实际应用中标识符用各 STA的 MAC地址表示。  The AP issues the MU-MIMO packet information, the information includes the group number Group ID=2, and the identifiers of the four STAs arranged in the order of the parentheses above. In the actual application, the identifier is represented by the MAC address of each STA.

各 STA接收此 MU-MIMO分组信息后都进行检测,但只有 STA-1 , STA-2 , STA-4, STA-6会将此 MU-MIMO分组信息作为有用信息, 因为在接收到的 信息中有与本身相匹配的 STA标识符 , 这四个 STA从此 MU-MIMO分组信 息中得到的有用信息有两方面:  Each STA receives the MU-MIMO packet information and detects it, but only STA-1, STA-2, STA-4, STA-6 will use this MU-MIMO packet information as useful information, because in the received information. There are STA identifiers that match themselves. The four STAs have useful information from this MU-MIMO packet information in two ways:

1 )本身属于组编号 Group ID=2的 MU-MIMO分组;  1) a MU-MIMO packet belonging to the group number Group ID=2;

2 )本身在此 MU-MIMO分组中的相对位置。  2) The relative position of itself in this MU-MIMO packet.

例如, STA-1从此 MU-MIMO分组信息中得到的信息包括: STA-1属于 组编号 Group ID=2的 MU-MIMO分组, 同时 STA-1在此分组中的处于第 4 个位置。 中携带的 MAC地址所标识的 STA在 MU-MIMO分组中的相对位置顺序。也 即, 数据帧负载中携带的 MAC地址所标识的 STA按照所在分组的相对位置 顺序回复 ACK。 For example, the information obtained by the STA-1 from the MU-MIMO packet information includes: STA-1 belongs to the MU-MIMO packet of the group number Group ID=2, and STA-1 is in the fourth position in this packet. The relative positional order of the STAs identified by the MAC address carried in the MU-MIMO packet. That is, the STAs identified by the MAC addresses carried in the data frame payload reply ACKs in the order of the relative positions of the packets.

本实际应用中当前 MU-MIMO传输, 在 4个 STA中, STA-1、 STA-2、 Current MU-MIMO transmission in this application, in 4 STAs, STA-1, STA-2,

STA-4和 STA-6都有一个数据流传输。 Both STA-4 and STA-6 have a data stream transmission.

进行 RTS/CTS帧交换后, 进行 MU-MIMO数据包传输, 其中在 AP发送 的 RTS帧负载中的 MAC地址域中的 MAC地址为 STA-6的 MAC地址, 在 RTS帧的物理帧头中包含组编号 Group ID=2信息。  After the RTS/CTS frame exchange is performed, the MU-MIMO data packet transmission is performed, wherein the MAC address in the MAC address field in the RTS frame payload sent by the AP is the MAC address of the STA-6, and is included in the physical frame header of the RTS frame. Group number Group ID=2 information.

釆用本实际应用的方法, 各 STA回复 ACK的判决过程如下:  Using the method of this practical application, the decision process of each STA replying to ACK is as follows:

( 1 )对于 STA-1  (1) for STA-1

STA-1接收到 MU-MIMO数据帧, 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-1解析 NSTS域获得的信息包括: STA-1 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-1 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为 1;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is 1;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1;  4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;

进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据; 根据前面的内容可知 , STA- 1占据此 MU-MIMO分组内的第四个位置。 综合以上这些信息, 按照本实际应用的方法, STA-1第 4个回复 ACK。 ( 2 )对于 STA-2  Further analyzing the MAC address information in the frame payload and discovering that its own MAC address is included, so the current transmission has its own data; according to the foregoing, STA-1 occupies the fourth position in the MU-MIMO packet. . Based on the above information, STA-1 responds with ACK 4 in accordance with the method of this practical application. (2) For STA-2

STA-2接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-2解析 NSTS域获得的信息包括:The STA-2 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes According to the foregoing, the information obtained by the STA-2 to parse the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1; 1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为 1;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is 1;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1;  4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;

进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据; 根据前面的内容可知, STA-2占据此 MU-MIMO分组内的第一个位置。 综合以上这些信息, 按照本实际应用的方法, STA-2第 1个回复 ACK。  Further analyzing the MAC address information in the frame load and discovering that its own MAC address is included, so the current transmission has its own data; according to the foregoing, STA-2 occupies the first position in the MU-MIMO packet. . Based on the above information, STA-2 replies to the first ACK according to the method of this practical application.

( 3 )对于 STA-3以及 STA-5  (3) For STA-3 and STA-5

STA-3接收到 MU-MIMO数据帧, 解析 VHT-SIG-A中的 Group ID域, 获知此帧不属于本身所 MU-MIMO分组, 无需回复 ACK。  The STA-3 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and knows that the frame does not belong to its own MU-MIMO packet, and does not need to reply to the ACK.

与 STA3有相同处理的 STA还有 STA5。  STAs that have the same processing as STA3 also have STA5.

( 4 )对于 STA-4  (4) For STA-4

STA-4接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-4解析 NSTS域获得的信息包括: The STA-4 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-4 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为 1;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is 1;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1;  4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;

进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据; 根据前面的内容可知 , STA-4占据此 MU-MIMO分组内的第三个位置。 综合以上这些信息, 按照本实际应用的方法, STA-4第 3个回复 ACK。 ( 5 )对于 STA-6 Further analyzing the MAC address information in the frame payload and discovering that its own MAC address is included, so the current transmission has its own data; according to the foregoing, STA-4 occupies the third position in the MU-MIMO packet. . Based on the above information, STA-4 replies to the third ACK according to the method of the actual application. (5) For STA-6

STA-6接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-6解析 NSTS域获得的信息包括: The STA-6 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-6 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为 1;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is 1;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1;  4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;

进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据; 根据前面的内容可知, STA-6占据此 MU-MIMO分组内的第二个位置; 综合以上这些信息, 按照本实际应用的方法, STA-6第 2个回复 ACK。 最终回复 ACK的顺序:  Further analyzing the MAC address information in the frame load and discovering that its own MAC address is included, so the current transmission has its own data; according to the foregoing, STA-6 occupies the second position in the MU-MIMO packet. Combining the above information, according to the method of the actual application, the STA-6 replies with the second ACK. The order in which the ACK is finally returned:

第 1个回复 ACK的 STA是 STA-2;  The first reply ACK STA is STA-2;

第 2个回复 ACK的 STA是 STA-6;  The second reply ACK STA is STA-6;

第 3个回复 ACK的 STA是 STA-4;  The third reply ACK STA is STA-4;

第 4个回复 ACK的 STA是 STA-1。  The fourth reply ACK STA is STA-1.

实施例一的实际应用四 Practical application of the first embodiment

假定网络中有 1 个 AP和 9个 STA, 9个 STA分别表示为第一站点 ( STA-1 ) , 第二站点( STA-2 ) , 第三站点( STA-3 ) , 第四站点( STA-4 ) , 第五站点 (STA-5 ) , 第六站点 (STA-6 ) , 第七站点 (STA-7 ) , 第八站点 ( STA-8 ) , 第九站点 ( STA-9 ) 。 每个 MU-MIMO分组最多有 4个 STA组 成, 不足 4个 STA的 MU-MIMO分组仍然被认为由 4个 STA组成, 不足的 部分可以认为有虚拟的 STA存在。  Assume that there are 1 AP and 9 STAs in the network, and 9 STAs are represented as the first station (STA-1), the second station (STA-2), the third station (STA-3), and the fourth station (STA). -4), fifth station (STA-5), sixth station (STA-6), seventh station (STA-7), eighth station (STA-8), ninth station (STA-9). Each MU-MIMO packet has a maximum of 4 STAs, and a MU-MIMO packet of less than 4 STAs is still considered to be composed of 4 STAs, and an insufficient portion can be considered to have a virtual STA.

AP按照各 STA的信道状态信息将这 9个 STA分为多个 MU-MIMO分组, 并将所有分组信息通知给 STA, 假定组编号不够多, 每一个组编号可以指示 多个 MU-MIMO分组,但有这样一个约束条件,如果同一个 STA出现在同一 个组编号指示的多个 MU-MIMO分组中,那么这个 STA在这些分组中的组内 相对位置是固定的。 The AP divides the nine STAs into multiple MU-MIMO packets according to the channel state information of each STA. And all the group information is notified to the STA, assuming that the group number is not enough, each group number can indicate multiple MU-MIMO packets, but there is such a constraint that if the same STA appears in multiple MUs indicated by the same group number In the MIMO packet, then the relative position of this STA in the group among these packets is fixed.

本实际应用中组编号 Group ID=2指示两个 MU-MIMO分组,二个分组分 另' J为 ( STA-2, STA-6, STA-4, STA-1 ) , ( STA-2, STA-6, STA-4, STA-9 ) 。  In the actual application, the group number Group ID=2 indicates two MU-MIMO packets, and the two sub-components are 'STA-2, STA-6, STA-4, STA-1), (STA-2, STA) -6, STA-4, STA-9).

AP发布 MU-MIMO分组信息,该 MU-MIMO分组信息包含组编号 Group 分组信息发布的顺序也按照上面所写的顺序。  The AP issues MU-MIMO packet information, and the MU-MIMO packet information includes the group number. The order in which the packet information is distributed is also in the order written above.

本实际应用中, RTS 帧中携带的 MAC 地址所标识的 STA在本次 In this application, the STA identified by the MAC address carried in the RTS frame is this time.

MU-MIMO传输中有数据传输, 则此 STA需要首先回复 ACK, 数据帧负载 中携带的 MAC地址所标识的其余 STA按照所在分组的相对位置顺序回复 ACK。 If there is data transmission in the MU-MIMO transmission, the STA needs to reply ACK first, and the remaining STAs identified by the MAC address carried in the data frame payload reply ACK according to the relative position of the group.

本实际应用的当前 MU-MIMO传输, 在 4个 STA中 , STA-9、 STA-6、 STA-4 和 STA-1 都有一个数据流传输, 即本次传输针对的是组编号 Group ID=2下的第二个分组。  In the current MU-MIMO transmission of the actual application, among the four STAs, STA-9, STA-6, STA-4, and STA-1 all have one data stream transmission, that is, the current transmission is for the group number Group ID= The second group under 2.

进行 RTS/CTS帧交换后, 进行 MU-MIMO数据包传输, 其中在 AP发送 的 RTS帧负载中的 MAC地址域中的 MAC地址为 STA-6的 MAC地址, 在 RTS帧的物理帧头中包含组编号 Group ID=2信息。  After the RTS/CTS frame exchange is performed, the MU-MIMO data packet transmission is performed, wherein the MAC address in the MAC address field in the RTS frame payload sent by the AP is the MAC address of the STA-6, and is included in the physical frame header of the RTS frame. Group number Group ID=2 information.

釆用本实际应用的方法, 各 STA回复 ACK的判决过程如下:  Using the method of this practical application, the decision process of each STA replying to ACK is as follows:

( 1 )对于 STA-1  (1) for STA-1

STA-1接收到 MU-MIMO数据帧, 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-1解析 NSTS域获得的信息包括: STA-1 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-1 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为 1; 4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1; 进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址不包含在 内, 所以本次传输没有属于自身的数据。 3) the number of data streams of the STA in the third location in the MU-MIMO packet is 1; 4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1; further analyzing the MAC address information in the frame payload, and discovering that its own MAC address is not included, so this transmission does not have its own data. .

综合以上这些信息, 按照本实际应用的方法, STA-1不回复 ACK。  Based on the above information, STA-1 does not reply to ACK according to the method of this practical application.

( 2 )对于 STA-2  (2) For STA-2

STA-2接收到 MU-MIMO数据帧, 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-2解析 NSTS域获得的信息包括: The STA-2 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-2 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为 1;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is 1;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1;  4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;

进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据;  Further parsing the MAC address information in the frame payload and discovering that its own MAC address is included, so this transmission has its own data;

根据前面的内容可知, STA-2占据此 MU-MIMO分组内的第一个位置; 根据接收的 RTS帧, 可知 RTS帧负载中的 MAC地址是 STA-6的 MAC 地址, 且本次传输有 STA-6的数据。  According to the foregoing, the STA-2 occupies the first position in the MU-MIMO packet. According to the received RTS frame, the MAC address in the RTS frame payload is the MAC address of the STA-6, and the STA is transmitted this time. -6 data.

综合以上这些信息, 按照本实际应用的方法, STA-2第 2个回复 ACK。  Based on the above information, STA-2 replies ACK 2 in accordance with the method of this practical application.

( 3 )对于 STA-3、 STA5、 STA7以及 STA8  (3) For STA-3, STA5, STA7 and STA8

STA-3接收到 MU-MIMO数据帧, 解析 VHT-SIG-A中的 Group ID域, 获知此帧不属于本身所 MU-MIMO分组, 无需回复 ACK。  The STA-3 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and knows that the frame does not belong to its own MU-MIMO packet, and does not need to reply to the ACK.

与 STA3有相同处理的 STA还有 STA5、 STA7和 STA8;  STAs that have the same processing as STA3 also have STA5, STA7, and STA8;

( 4 )对于 STA-4  (4) For STA-4

STA-4接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-4解析 NSTS域获得的信息包括:The STA-4 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number Group ID=2, and analyzes According to the foregoing, the information obtained by the STA-4 to parse the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1; 1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为 1;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is 1;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1;  4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;

进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据; 根据前面的内容可知, STA-4占据此 MU-MIMO分组内的第三个位置。 综合以上这些信息, 按照本实际应用的方法, STA-4第 3个回复 ACK。 ( 5 )对于 STA-6  Further analyzing the MAC address information in the frame payload and discovering that its own MAC address is included, so the current transmission has its own data; according to the foregoing, STA-4 occupies the third position in the MU-MIMO packet. . Based on the above information, STA-4 replies to the third ACK according to the method of the actual application. (5) For STA-6

STA-6接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-6解析 NSTS域获得的信息包括: The STA-6 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-6 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为 1;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is 1;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1;  4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;

进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据;  Further parsing the MAC address information in the frame payload and discovering that its own MAC address is included, so this transmission has its own data;

根据前面的内容可知, STA-6占据此 MU-MIMO分组内的第二个位置; 根据接收的 RTS帧, 可知 RTS帧负载中的 MAC地址是本身的 MAC地 址。  According to the foregoing, STA-6 occupies the second position in the MU-MIMO packet; according to the received RTS frame, it can be known that the MAC address in the RTS frame payload is its own MAC address.

综合以上这些信息, 按照本实际应用的方法, STA-6第 1个回复 ACK。 ( 6 )对于 STA-9  Based on the above information, STA-6 replies with ACK first according to the method of this practical application. (6) For STA-9

STA-9接收到 MU-MIMO数据帧, 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-9解析 NSTS域获得的信息包括: The STA-9 receives the MU-MIMO data frame and parses the Group ID field in the VHT-SIG-A. It is known that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and the data is obtained. According to the foregoing, the information obtained by the STA-9 to parse the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为 1;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is 1;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1;  4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;

进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据; 根据前面的内容可知, STA-9占据此 MU-MIMO分组内的第四个位置; 根据接收的 RTS帧, 可知 RTS帧负载中的 MAC地址是 STA-6的 MAC 地址, 且本次传输有 STA-6的数据。  Further analyzing the MAC address information in the frame load and discovering that its own MAC address is included, so the current transmission has its own data; according to the foregoing, STA-9 occupies the fourth position in the MU-MIMO packet. According to the received RTS frame, it can be known that the MAC address in the RTS frame payload is the MAC address of STA-6, and the data of STA-6 is transmitted this time.

综合以上这些信息, 按照本实际应用的方法, STA-9第 4个回复 ACK。 最终回复 ACK的顺序:  Based on the above information, STA-9 replies with ACK according to the method of this practical application. The order in which the ACK is finally returned:

第 1个回复 ACK的 STA是 STA-6;  The first reply ACK STA is STA-6;

第 2个回复 ACK的 STA是 STA-2;  The second reply ACK STA is STA-2;

第 3个回复 ACK的 STA是 STA-4;  The third reply ACK STA is STA-4;

第 4个回复 ACK的 STA是 STA-9。  The 4th reply ACK STA is STA-9.

实施例一的实际应用五 Practical application of the first embodiment

假定网络中有 1 个 AP和 9个 STA, 9个 STA分别表示为第一站点 ( STA-1 ) , 第二站点( STA-2 ) , 第三站点( STA-3 ) , 第四站点( STA-4 ) , 第五站点 (STA-5 ) , 第六站点 (STA-6 ) , 第七站点 (STA-7 ) , 第八站点 ( STA-8 ) , 第九站点 ( STA-9 ) 。 每个 MU-MIMO分组最多有 4个 STA组 成, 不足 4个 STA的 MU-MIMO分组仍然被认为由 4个 STA组成, 不足的 部分可以认为有虚拟的 STA存在。  Assume that there are 1 AP and 9 STAs in the network, and 9 STAs are represented as the first station (STA-1), the second station (STA-2), the third station (STA-3), and the fourth station (STA). -4), fifth station (STA-5), sixth station (STA-6), seventh station (STA-7), eighth station (STA-8), ninth station (STA-9). Each MU-MIMO packet has a maximum of 4 STAs, and a MU-MIMO packet of less than 4 STAs is still considered to be composed of 4 STAs, and an insufficient portion can be considered to have a virtual STA.

AP按照各 STA的信道状态信息将这 9个 STA分为多个 MU-MIMO分组, 并将所有分组信息通知给 STA, 假定组编号不够多, 每一个组编号可以指示 多个 MU-MIMO分组,但有这样一个约束条件,如果同一个 STA出现在同一 个组编号指示的多个 MU-MIMO分组中,那么这个 STA在这些分组中的组内 相对位置是固定的。 The AP divides the nine STAs into multiple MU-MIMO packets according to the channel state information of each STA. And all the group information is notified to the STA, assuming that the group number is not enough, each group number can indicate multiple MU-MIMO packets, but there is such a constraint that if the same STA appears in multiple MUs indicated by the same group number In the MIMO packet, then the relative position of this STA in the group among these packets is fixed.

本实际应用中组编号 Group ID=2指示两个 MU-MIMO分组,二个分组分 另' J为 ( STA-2, STA-6, STA-4, STA-1 ) , ( STA-2, STA-6, STA-4, STA-9 ) 。  In the actual application, the group number Group ID=2 indicates two MU-MIMO packets, and the two sub-components are 'STA-2, STA-6, STA-4, STA-1), (STA-2, STA) -6, STA-4, STA-9).

AP发布 MU-MIMO分组信息,该 MU-MIMO分组信息包含组编号 Group 分组信息发布的顺序也按照上面所写的顺序。  The AP issues MU-MIMO packet information, and the MU-MIMO packet information includes the group number. The order in which the packet information is distributed is also in the order written above.

本实际应用中, 数据帧负载中携带的 MAC地址所标识的 STA按照所在 分组的相对位置顺序回复 ACK。  In the actual application, the STAs identified by the MAC addresses carried in the data frame payload reply to the ACK in the order of the relative positions of the packets.

本实际应用的当前 MU-MIMO传输, 在 4个 STA中 , STA-9、 STA-6、 STA-4 和 STA-1 都有一个数据流传输, 即本次传输针对的是组编号 Group ID=2下的第二个分组。  In the current MU-MIMO transmission of the actual application, among the four STAs, STA-9, STA-6, STA-4, and STA-1 all have one data stream transmission, that is, the current transmission is for the group number Group ID= The second group under 2.

进行 RTS/CTS帧交换后, 进行 MU-MIMO数据包传输, 其中在 AP发送 的 RTS帧负载中的 MAC地址域中的 MAC地址为 STA-6的 MAC地址, 在 RTS帧的物理帧头中包含组编号 Group ID=2信息。  After the RTS/CTS frame exchange is performed, the MU-MIMO data packet transmission is performed, wherein the MAC address in the MAC address field in the RTS frame payload sent by the AP is the MAC address of the STA-6, and is included in the physical frame header of the RTS frame. Group number Group ID=2 information.

釆用本实际应用的方法, 各 STA回复 ACK的判决过程如下:  Using the method of this practical application, the decision process of each STA replying to ACK is as follows:

( 1 )对于 STA-1  (1) for STA-1

STA-1接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-1解析 NSTS域获得的信息包括: STA-1 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-1 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为 1;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is 1;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1; 进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址不包含在 内, 所以本次传输没有属于自身的数据; 4) the number of data streams of the STA in the fourth position in the MU-MIMO packet is 1; Further parsing the MAC address information in the frame load, and discovering that its own MAC address is not included, so this transmission does not have its own data;

综合以上这些信息, 按照本实际应用的方法, STA-1不回复 ACK。  Based on the above information, STA-1 does not reply to ACK according to the method of this practical application.

( 2 )对于 STA-2  (2) For STA-2

STA-2接收到 MU-MIMO数据帧, 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-2解析 NSTS域获得的信息包括: The STA-2 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-2 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为 1;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is 1;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1;  4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;

进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据; 根据前面的内容可知 , STA-2占据此 MU-MIMO分组内的第一个位置。 综合以上这些信息, 按照本实际应用的方法, STA-2第 1个回复 ACK。 ( 3 )对于 STA-3、 STA5、 STA7以及 STA8  Further analyzing the MAC address information in the frame load and discovering that its own MAC address is included, so the current transmission has its own data; according to the foregoing, STA-2 occupies the first position in the MU-MIMO packet. . Based on the above information, STA-2 replies to the first ACK according to the method of this practical application. (3) For STA-3, STA5, STA7 and STA8

STA-3接收到 MU-MIMO数据帧, 解析 VHT-SIG-A中的 Group ID域, 获知此帧不属于本身所 MU-MIMO分组, 无需回复 ACK。  The STA-3 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and knows that the frame does not belong to its own MU-MIMO packet, and does not need to reply to the ACK.

与 STA3有相同处理的 STA还有 STA5、 STA7和 STA8;  STAs that have the same processing as STA3 also have STA5, STA7, and STA8;

( 4 )对于 STA-4  (4) For STA-4

STA-4接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-4解析 NSTS域获得的信息包括: The STA-4 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-4 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1; 3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为 1;2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1; 3) the number of data streams of the STA in the third location in the MU-MIMO packet is 1;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1; 4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;

进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据; 根据前面的内容可知, STA-4占据此 MU-MIMO分组内的第三个位置。 综合以上这些信息, 按照本实际应用的方法, STA-4第 3个回复 ACK。 ( 5 )对于 STA-6  Further analyzing the MAC address information in the frame payload and discovering that its own MAC address is included, so the current transmission has its own data; according to the foregoing, STA-4 occupies the third position in the MU-MIMO packet. . Based on the above information, STA-4 replies to the third ACK according to the method of the actual application. (5) For STA-6

STA-6接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-6解析 NSTS域获得的信息包括: The STA-6 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes the data. According to the foregoing, The information obtained by STA-6 to resolve the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为 1;  3) The number of data streams of the STA in the third location in the MU-MIMO packet is 1;

4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1;  4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1;

进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据;  Further parsing the MAC address information in the frame payload and discovering that its own MAC address is included, so this transmission has its own data;

根据前面的内容可知, STA-6占据此 MU-MIMO分组内的第二个位置; 综合以上这些信息, 按照本实际应用的方法, STA-6第 2个回复 ACK。 ( 6 )对于 STA-9  According to the foregoing, STA-6 occupies the second position in the MU-MIMO packet. Based on the above information, STA-6 replies to the second ACK according to the method of the present application. (6) For STA-9

STA-9接收到 MU-MIMO数据帧 , 解析 VHT-SIG-A中的 Group ID域, 获知此帧属于本身所在组编号 Group ID=2 的 MU-MIMO 分组, 解析 据, 根据前面的内容可知, STA-9解析 NSTS域获得的信息包括: The STA-9 receives the MU-MIMO data frame, parses the Group ID field in the VHT-SIG-A, and learns that the frame belongs to the MU-MIMO packet whose group number is Group ID=2, and analyzes the data. According to the foregoing, The information obtained by the STA-9 to parse the N STS domain includes:

1 )此 MU-MIMO分组内第一个位置的 STA的数据流数为 1;  1) the number of data streams of the STA in the first location in the MU-MIMO packet is 1;

2 )此 MU-MIMO分组内第二个位置的 STA的数据流数为 1;  2) the number of data streams of the STA in the second location in the MU-MIMO packet is 1;

3 )此 MU-MIMO分组内第三个位置的 STA的数据流数为 1; 4 )此 MU-MIMO分组内第四个位置的 STA的数据流数为 1; 进一步解析帧负载中的 MAC地址信息,发现自身的 MAC地址包含在内, 所以本次传输有属于自身的数据; 根据前面的内容可知, STA-9 占据此 MU-MIMO分组内的第四个位置; 3) the number of data streams of the STA in the third location in the MU-MIMO packet is 1; 4) The number of data streams of the STA in the fourth position in the MU-MIMO packet is 1; further analyzing the MAC address information in the frame payload, and discovering that its own MAC address is included, so the current transmission has its own data; According to the foregoing, STA-9 occupies the fourth position in the MU-MIMO packet;

综合以上这些信息, 按照本实际应用的方法, STA-9第 4个回复 ACK。 最终回复 ACK的顺序:  Based on the above information, STA-9 replies with ACK according to the method of this practical application. The order in which the ACK is finally returned:

第 1个回复 ACK的 STA是 STA-2;  The first reply ACK STA is STA-2;

第 2个回复 ACK的 STA是 STA-6;  The second reply ACK STA is STA-6;

第 3个回复 ACK的 STA是 STA-4;  The third reply ACK STA is STA-4;

第 4个回复 ACK的 STA是 STA-9。  The 4th reply ACK STA is STA-9.

实施例二、 一种反馈确认消息的站点 (STA ) Embodiment 2: A site for feedback confirmation message (STA)

本实施例的 STA应用于向一个 BSS中的接入点 AP回复 ACK,其与其他 一个或一个以上的 STA与 AP相关联, 其主要包括第一接收模块 210、 第二 接收模块 220以及反馈模块 230, 其中:  The STA of this embodiment is applied to reply to an access point AP in a BSS, which is associated with one or more other STAs and APs, and mainly includes a first receiving module 210, a second receiving module 220, and a feedback module. 230, where:

第一接收模块 210设置成: 接收 AP发送的 RTS以及分组信息, 根据分 组信息获知 STA 自身所处的 MU-MIMO分组的分组编号以及 STA 自身在 MU-MIMO分组内的相对位置信息;  The first receiving module 210 is configured to: receive the RTS and the packet information sent by the AP, and learn, according to the packet information, the packet number of the MU-MIMO packet in which the STA itself is located and the relative location information of the STA itself in the MU-MIMO packet;

第二接收模块 220设置成: 接收 MU-MIMO数据帧;  The second receiving module 220 is configured to: receive the MU-MIMO data frame;

反馈模块 230, 与第一接收模块 210及第二接收模块 220相连, 其设置 成: 根据 MU-MIMO数据帧的物理帧头中 VHT-SIG-A所包含的分组编号域 和 NSTS域所指示的信息, 物理帧负载中的 MAC地址信息, 以及 Group ID域 所指示的分组编号下的 MU-MIMO分组信息, 确定需要回复 ACK的 STA, 并按约定顺序回复 ACK消息; The feedback module 230 is connected to the first receiving module 210 and the second receiving module 220, and is configured to: according to the packet number field and the N STS field included in the VHT-SIG-A in the physical frame header of the MU-MIMO data frame. The information, the MAC address information in the physical frame payload, and the MU-MIMO packet information under the packet number indicated by the Group ID field, determine the STA that needs to reply to the ACK, and reply the ACK message in the agreed order;

其中, AP根据每个 STA的信道状态信息、 数据业务量、 数据业务类型 等一者或几者的组合, 对与其关联的 STA进行 MU-MIMO分组, 为每一个 MU-MIMO分组指定分组编号并分别构造分组信息, 通过信令将分组信息通 知给 STA。 上述反馈模块 230设置成:按 STA在 MU-MIMO分组中的顺序回复所述 ACK消息。 The AP performs MU-MIMO grouping on the STAs associated with each of the STAs according to the channel state information, the data traffic volume, the data service type, and the like of each STA, and specifies a packet number for each MU-MIMO packet. The packet information is separately constructed, and the packet information is notified to the STA by signaling. The feedback module 230 is configured to reply the ACK message in the order of the STAs in the MU-MIMO packet.

上述反馈模块 230可以设置成: 按所述 MU-MIMO数据帧负载中携带的 MAC地址所标识的 STA在 MU-MIMO分组中的相对位置顺序回复所述 ACK 消息。  The feedback module 230 may be configured to: reply the ACK message in order according to the relative position of the STAs identified by the MAC address carried in the MU-MIMO data frame payload in the MU-MIMO packet.

本领域的技术人员应该明白, 上述的本发明的各模块或各步骤可以用通 用的计算装置来实现, 它们可以集中在单个的计算装置上, 或者分布在多个 计算装置所组成的网络上, 可选地, 它们可以用计算装置可执行的程序代码 来实现, 从而, 可以将它们存储在存储装置中由计算装置来执行, 或者将它 们分别制作成各个集成电路模块, 或者将它们中的多个模块或步骤制作成单 个集成电路模块来实现。 这样, 本发明不限制于任何特定的硬件和软件结合。 It will be apparent to those skilled in the art that the various modules or steps of the present invention described above can be implemented by a general-purpose computing device, which can be centralized on a single computing device or distributed over a network of multiple computing devices. Alternatively, they may be implemented by program code executable by the computing device, such that they may be stored in the storage device by the computing device, or they may be fabricated into individual integrated circuit modules, or many of them Modules or steps are made into a single integrated circuit module. Thus, the invention is not limited to any specific combination of hardware and software.

虽然本发明所揭露的实施方式如上, 但所述的内容只是为了便于理解本 发明而釆用的实施方式, 并非用以限定本发明。 任何本发明所属技术领域内 的技术人员, 在不脱离本发明所揭露的精神和范围的前提下, 可以在实施的 形式上及细节上作任何的修改与变化, 但本发明的专利保护范围, 仍须以所 附的权利要求书所界定的范围为准。  While the embodiments of the present invention have been described above, the described embodiments are merely for the purpose of understanding the invention and are not intended to limit the invention. Any modification and variation of the form and details of the invention may be made by those skilled in the art without departing from the spirit and scope of the invention. It is still subject to the scope defined by the appended claims.

工业实用性 Industrial applicability

釆用此发明技术方案,可以保证 MU-MIMO分组中的 STA能够有序有效 的回复 ACK, 而不需要额外的信令通知, 相互间亦会避免碰撞, 同时组内无 数据传输的 STA无需传输 ACK, 也节省了信令开销。 也可以保证首要 STA 的服务获得优先保障, 因此具有极强的工业实用性。  With the technical solution of the invention, it is ensured that the STAs in the MU-MIMO packet can reply ACKs in an orderly manner without additional signaling, and collisions are avoided between each other, and STAs without data transmission in the group need not transmit. ACK also saves signaling overhead. It also guarantees that the services of the primary STAs are given priority and therefore have strong industrial applicability.

Claims

权 利 要 求 书 Claim 1、 一种多用户反馈确认消息的方法, 用于一个基本服务集(BSS ) 中与 接入点 (AP ) 关联的站点 (STA ) 回复确认消息 (ACK ) , 该方法包括:A method for multi-user feedback confirmation message, used for a site (STA) reply confirmation message (ACK) associated with an access point (AP) in a basic service set (BSS), the method comprising: AP对与其关联的 STA进行多用户-多输入多输出 ( MU-MIMO )分组, 为每一个 MU-MIMO分组指定分组编号并分别构造分组信息后, 将所述分组 信息通知给 STA; STA收到请求发送帧 (RTS )和 MU-MIMO数据帧后, 根 据所述分组信息、所述 RTS、所述 MU-MIMO数据帧的物理帧头中 VHT-SIG-A 所包含的分组编号( Group ID )域和站点数据流信息指示(NSTS )域所指示的 信息、 所述 MU-MIMO数据帧的物理帧的负载中的媒体访问控制(MAC )地 址信息以及所述 Group ID域所指示的分组编号下的 MU-MIMO分组信息,确 定需要回复 ACK的 STA, 并按约定顺序回复所述 ACK。 The AP performs a multi-user-multiple input multiple output (MU-MIMO) packet on the STA associated with it, assigns a packet number to each MU-MIMO packet, and separately constructs the packet information, and notifies the STA to the STA; After requesting a transmission frame (RTS) and a MU-MIMO data frame, according to the packet information, the RTS, and a packet number (Group ID) included in the physical frame header of the MU-MIMO data frame, VHT-SIG-A The domain and site data flow information indicates information indicated by the (N STS ) field, media access control (MAC ) address information in the payload of the physical frame of the MU-MIMO data frame, and the packet number indicated by the Group ID field The underlying MU-MIMO packet information determines the STAs that need to reply to the ACK and replies to the ACK in an agreed order. 2、 根据权利要求 1所述的方法, 其中, 确定需要回复 ACK的 STA的步 骤包括: 所述 Group ID域所指示的分组编号与 STA自身所在的 MU-MIMO 分组的分组编号相同, 所述 NSTS域中的相应位置处不为零, 所述物理帧的负 载中携带有与该 STA自身的 MAC地址相同的 MAC地址, 则该 STA需要回 复所述 ACK; 2. The method according to claim 1, wherein the step of determining the STA that needs to reply to the ACK comprises: the packet number indicated by the Group ID field is the same as the packet number of the MU-MIMO packet in which the STA itself is located, the N The corresponding location in the STS domain is not zero, and the payload of the physical frame carries the same MAC address as the STA's own MAC address, and the STA needs to reply to the ACK; 其中,所述相应位置与该 STA自身在 MU-MIMO分组中的相对位置相同。  The corresponding location is the same as the relative location of the STA itself in the MU-MIMO packet. 3、 根据权利要求 1 所述的方法, 其中, 所述约定顺序包括: STA在 MU-MIMO分组中的顺序。 3. The method according to claim 1, wherein the order of appointment comprises: an order of STAs in a MU-MIMO packet. 4、 根据权利要求 3所述的方法, 其中, 所述约定顺序包括: 首先回复所 述 ACK 的 STA是所述 RTS 中承载的 MAC 地址所对应的 STA; 所述 MU-MIMO 数据帧负载中携带的 MAC 地址所标识的其余 STA按照在 MU-MIMO分组中的相对位置顺序回复所述 ACK。  The method according to claim 3, wherein the order of the agreement comprises: first, the STA that replies to the ACK is an STA corresponding to the MAC address carried in the RTS; and the MU-MIMO data frame carries The remaining STAs identified by the MAC address reply to the ACK in the order of relative positions in the MU-MIMO packet. 5、根据权利要求 3所述的方法,其中,所述约定顺序包括:所述 MU-MIMO 数据帧负载中携带的 MAC地址所标识的 STA在 MU-MIMO分组中的相对位 置顺序。 The method according to claim 3, wherein the order of appointment comprises: a relative position order of STAs identified by the MAC address carried in the MU-MIMO data frame payload in the MU-MIMO packet. 6、 根据权利要求 1所述的方法, 其中, 确定需要回复 ACK的 STA的步 骤包括: 所述 Group ID域所指示的分组编号与 STA自身所在的 MU-MIMO 分组的分组编号不同, 则该 STA不需要回复所述 ACK。 The method according to claim 1, wherein the step of determining the STA that needs to reply to the ACK comprises: the packet number indicated by the Group ID field is different from the packet number of the MU-MIMO packet in which the STA itself is located, and the STA is There is no need to reply to the ACK. 7、 根据权利要求 1所述的方法, 其中, 确定需要回复 ACK的 STA的步 骤包括: 所述 Group ID域所指示的分组编号与 STA自身所在的 MU-MIMO 分组的分组编号相同, 所述 NSTS域中的相应位置指示为零, 则该 STA不需要 回复所述 ACK; 7. The method according to claim 1, wherein the step of determining the STA that needs to reply to the ACK comprises: the packet number indicated by the Group ID field is the same as the packet number of the MU-MIMO packet in which the STA itself is located, the N The corresponding location indication in the STS field is zero, then the STA does not need to reply to the ACK; 其中,所述相应位置与该 STA自身在 MU-MIMO分组中的相对位置相同。  The corresponding location is the same as the relative location of the STA itself in the MU-MIMO packet. 8、 根据权利要求 1所述的方法, 其中, 确定需要回复 ACK的 STA的步 骤包括: 所述 Group ID域所指示的分组编号与 STA自身所在的 MU-MIMO 分组的分组编号相同, 所述 NSTS域中的相应位置指示不为零, 所述物理帧的 负载中携带的 MAC与该 STA自身的 MAC地址不同, 则该 STA不需要回复 所述 ACK; 8. The method according to claim 1, wherein the step of determining the STA that needs to reply to the ACK comprises: the packet number indicated by the Group ID field is the same as the packet number of the MU-MIMO packet in which the STA itself is located, the N The corresponding location indication in the STS domain is not zero, and the MAC carried in the payload of the physical frame is different from the MAC address of the STA itself, and the STA does not need to reply to the ACK; 其中, 所述相应位置与该 STA在 MU-MIMO分组中的相对位置相同。  The corresponding location is the same as the relative location of the STA in the MU-MIMO packet. 9、 根据权利要求 1所述的方法, 其中, 为每一个 MU-MIMO分组指定 9. The method of claim 1, wherein: specifying for each MU-MIMO packet 10、 一种反馈确认消息的站点 (STA ) , 用于向一个基本服务集(BSS ) 中的接入点( AP )回复确认消息( ACK ) , 两个或两个以上的所述 STA与所 一个 MU-MIMO分组指定分组编号并分别构造分组信息后, 将所述分组信息 通知给所述 STA,所述 STA包括第一接收模块、第二接收模块以及反馈模块, 其中: 10. A station (STA) for feeding back a confirmation message, for replying an acknowledgement message (ACK) to an access point (AP) in a basic service set (BSS), two or more of the STAs and the STAs After the MU-MIMO packet specifies the packet number and constructs the packet information, the packet information is notified to the STA, where the STA includes a first receiving module, a second receiving module, and a feedback module, where: 所述第一接收模块设置成: 接收 AP发送的请求发送帧(RTS )以及分组 信息,根据所述分组信息获知 STA自身所处的 MU-MIMO分组的分组编号以 及 STA自身在 MU-MIMO分组内的相对位置信息;  The first receiving module is configured to: receive a request sending frame (RTS) sent by the AP, and group information, and learn, according to the grouping information, a packet number of the MU-MIMO packet where the STA itself is located, and the STA itself is in the MU-MIMO packet. Relative position information; 所述第二接收模块设置成: 接收多用户-多输入多输出 ( MU-MIMO )数 据帧; 所述反馈模块设置成:根据所获知的 STA自身所处的 MU-MIMO分组的 分组编号以及 STA自身在 MU-MIMO分组内的相对位置信息、所述 RTS、所 述 MU-MIMO数据帧的物理帧头中 VHT-SIG-A所包含的分组编号( Group ID ) 域和站点数据流信息指示 (NSTS )域所指示的信息、 物理帧的负载中的媒体 访问控制 (MAC )地址信息以及所述 Group ID 域所指示的分组编号下的 MU-MIMO分组信息, 确定需要回复 ACK的 STA, 并按约定顺序回复所述 ACK。 The second receiving module is configured to: receive a multi-user-multiple input multiple output (MU-MIMO) data frame; The feedback module is configured to: according to the obtained packet number of the MU-MIMO packet in which the STA itself is located, and the relative location information of the STA itself in the MU-MIMO packet, the RTS, the physics of the MU-MIMO data frame The packet number (Group ID) field and the site data stream information indication (N STS ) field included in the VHT-SIG-A in the frame header, the media access control (MAC) address information in the payload of the physical frame, and the location The MU-MIMO packet information under the packet number indicated by the Group ID field determines the STAs that need to reply to the ACK, and replies to the ACK in an agreed order. 11、 根据权利要求 10所述的站点, 其中: 11. The station of claim 10, wherein: 所述反馈模块还设置成: 按 STA在 MU-MIMO分组中的顺序回复所述 ACK。  The feedback module is further configured to: reply the ACK in the order of the STAs in the MU-MIMO packet. 12、 根据权利要求 10所述的站点, 其中: 12. The station of claim 10, wherein: 所述反馈模块还设置成: 按所述 MU-MIMO数据帧负载中携带的 MAC 地址所标识的 STA在 MU-MIMO分组中的相对位置顺序回复所述 ACK。  The feedback module is further configured to: reply the ACK in the order of the relative positions of the STAs identified by the MAC address carried in the MU-MIMO data frame payload in the MU-MIMO packet. 13、 根据权利要求 10-12 中任一项所述的站点, 其中: 所述反馈模块设 置成按照以下方式确定需要回复 ACK的 STA:  The station according to any one of claims 10-12, wherein: the feedback module is configured to determine a STA that needs to reply to an ACK in the following manner: 所述 Group ID域所指示的分组编号与 STA自身所在的 MU-MIMO分组 的分组编号相同, 所述 NSTS域中的相应位置处不为零, 所述物理帧的负载中 携带有与该 STA自身的 MAC地址相同的 MAC地址, 则所述反馈模块确认 该 STA需要回复所述 ACK; The packet number indicated by the group ID field is the same as the packet number of the MU-MIMO packet in which the STA itself is located, and the corresponding location in the N STS domain is not zero, and the load of the physical frame carries the STA. If the MAC address of the MAC address is the same, the feedback module confirms that the STA needs to reply to the ACK. 其中,所述相应位置与该 STA自身在 MU-MIMO分组中的相对位置相同。  The corresponding location is the same as the relative location of the STA itself in the MU-MIMO packet.
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