CN116566008A - Battery circuit and power supply method - Google Patents
Battery circuit and power supply method Download PDFInfo
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- CN116566008A CN116566008A CN202310555662.4A CN202310555662A CN116566008A CN 116566008 A CN116566008 A CN 116566008A CN 202310555662 A CN202310555662 A CN 202310555662A CN 116566008 A CN116566008 A CN 116566008A
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- H—ELECTRICITY
- H02—GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
- H02J—CIRCUIT ARRANGEMENTS OR SYSTEMS FOR SUPPLYING OR DISTRIBUTING ELECTRIC POWER; SYSTEMS FOR STORING ELECTRIC ENERGY
- H02J7/00—Circuit arrangements for charging or depolarising batteries or for supplying loads from batteries
- H02J7/00032—Circuit arrangements for charging or depolarising batteries or for supplying loads from batteries characterised by data exchange
- H02J7/00034—Charger exchanging data with an electronic device, i.e. telephone, whose internal battery is under charge
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- H—ELECTRICITY
- H02—GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
- H02J—CIRCUIT ARRANGEMENTS OR SYSTEMS FOR SUPPLYING OR DISTRIBUTING ELECTRIC POWER; SYSTEMS FOR STORING ELECTRIC ENERGY
- H02J7/00—Circuit arrangements for charging or depolarising batteries or for supplying loads from batteries
- H02J7/00032—Circuit arrangements for charging or depolarising batteries or for supplying loads from batteries characterised by data exchange
- H02J7/00036—Charger exchanging data with battery
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- H—ELECTRICITY
- H02—GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
- H02J—CIRCUIT ARRANGEMENTS OR SYSTEMS FOR SUPPLYING OR DISTRIBUTING ELECTRIC POWER; SYSTEMS FOR STORING ELECTRIC ENERGY
- H02J7/00—Circuit arrangements for charging or depolarising batteries or for supplying loads from batteries
- H02J7/0013—Circuit arrangements for charging or depolarising batteries or for supplying loads from batteries acting upon several batteries simultaneously or sequentially
- H02J7/0014—Circuits for equalisation of charge between batteries
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- H—ELECTRICITY
- H02—GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
- H02J—CIRCUIT ARRANGEMENTS OR SYSTEMS FOR SUPPLYING OR DISTRIBUTING ELECTRIC POWER; SYSTEMS FOR STORING ELECTRIC ENERGY
- H02J7/00—Circuit arrangements for charging or depolarising batteries or for supplying loads from batteries
- H02J7/0029—Circuit arrangements for charging or depolarising batteries or for supplying loads from batteries with safety or protection devices or circuits
- H02J7/00302—Overcharge protection
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- H—ELECTRICITY
- H02—GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
- H02J—CIRCUIT ARRANGEMENTS OR SYSTEMS FOR SUPPLYING OR DISTRIBUTING ELECTRIC POWER; SYSTEMS FOR STORING ELECTRIC ENERGY
- H02J7/00—Circuit arrangements for charging or depolarising batteries or for supplying loads from batteries
- H02J7/0029—Circuit arrangements for charging or depolarising batteries or for supplying loads from batteries with safety or protection devices or circuits
- H02J7/00306—Overdischarge protection
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- H—ELECTRICITY
- H02—GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
- H02J—CIRCUIT ARRANGEMENTS OR SYSTEMS FOR SUPPLYING OR DISTRIBUTING ELECTRIC POWER; SYSTEMS FOR STORING ELECTRIC ENERGY
- H02J7/00—Circuit arrangements for charging or depolarising batteries or for supplying loads from batteries
- H02J7/0047—Circuit arrangements for charging or depolarising batteries or for supplying loads from batteries with monitoring or indicating devices or circuits
- H02J7/0048—Detection of remaining charge capacity or state of charge [SOC]
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- H—ELECTRICITY
- H02—GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
- H02J—CIRCUIT ARRANGEMENTS OR SYSTEMS FOR SUPPLYING OR DISTRIBUTING ELECTRIC POWER; SYSTEMS FOR STORING ELECTRIC ENERGY
- H02J7/00—Circuit arrangements for charging or depolarising batteries or for supplying loads from batteries
- H02J7/007—Regulation of charging or discharging current or voltage
- H02J7/00712—Regulation of charging or discharging current or voltage the cycle being controlled or terminated in response to electric parameters
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- H—ELECTRICITY
- H02—GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
- H02J—CIRCUIT ARRANGEMENTS OR SYSTEMS FOR SUPPLYING OR DISTRIBUTING ELECTRIC POWER; SYSTEMS FOR STORING ELECTRIC ENERGY
- H02J2207/00—Indexing scheme relating to details of circuit arrangements for charging or depolarising batteries or for supplying loads from batteries
- H02J2207/20—Charging or discharging characterised by the power electronics converter
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- Y—GENERAL TAGGING OF NEW TECHNOLOGICAL DEVELOPMENTS; GENERAL TAGGING OF CROSS-SECTIONAL TECHNOLOGIES SPANNING OVER SEVERAL SECTIONS OF THE IPC; TECHNICAL SUBJECTS COVERED BY FORMER USPC CROSS-REFERENCE ART COLLECTIONS [XRACs] AND DIGESTS
- Y02—TECHNOLOGIES OR APPLICATIONS FOR MITIGATION OR ADAPTATION AGAINST CLIMATE CHANGE
- Y02E—REDUCTION OF GREENHOUSE GAS [GHG] EMISSIONS, RELATED TO ENERGY GENERATION, TRANSMISSION OR DISTRIBUTION
- Y02E60/00—Enabling technologies; Technologies with a potential or indirect contribution to GHG emissions mitigation
- Y02E60/10—Energy storage using batteries
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- Engineering & Computer Science (AREA)
- Power Engineering (AREA)
- Charge And Discharge Circuits For Batteries Or The Like (AREA)
- Secondary Cells (AREA)
Abstract
Description
技术领域technical field
本申请属于通信技术领域,具体涉及一种电池电路和供电方法。The application belongs to the technical field of communication, and in particular relates to a battery circuit and a power supply method.
背景技术Background technique
电子设备一般包括处理器、存储器、充电模块、电源管理模块、电池、天线、射频模块、音频模块、扬声器、受话器、麦克风、传感器、马达、摄像头、显示屏等。电力的来源为电池或者充电器,锂离子电池的工作电压一般在3.0V~4.5V区间。Electronic devices generally include processors, memory, charging modules, power management modules, batteries, antennas, radio frequency modules, audio modules, speakers, receivers, microphones, sensors, motors, cameras, displays, etc. The source of power is a battery or a charger, and the working voltage of a lithium-ion battery is generally in the range of 3.0V to 4.5V.
但由于电子设备不同模块的设计、制造工艺等不同,供电特性存在较大差异,比如处理器、存储器、传感器、摄像头等工作电压一般在1.8V以下,电池需要通过降压给这些模块供电。而显示屏、高压线性马达、部分音频模块则需要5V及以上的工作电压,电池需要通过降压给这些模块供电。However, due to the different designs and manufacturing processes of different modules of electronic equipment, there are large differences in power supply characteristics. For example, the working voltage of processors, memories, sensors, and cameras is generally below 1.8V, and the battery needs to step down to supply power to these modules. Display screens, high-voltage linear motors, and some audio modules require working voltages of 5V and above, and the battery needs to step down the voltage to supply power to these modules.
在采用两个或多个电池给电子设备供电时,一般采用串联或者并联的方式。多电池串联供电需要各电池的容量相同,避免部分电池存在过充或过放,对堆叠的要求高,且电池到负载的供电链路上要先经过降压再升压的过程,效率损失较大,不利于续航提升。多电池并联供电对于高工作电压的负载则输入和输出电压压差较大,电源的转换效率低。When two or more batteries are used to power electronic equipment, they are generally connected in series or in parallel. Multi-battery power supply in series requires the capacity of each battery to be the same, to avoid overcharging or overdischarging of some batteries, and has high requirements for stacking, and the power supply link from the battery to the load must first go through the process of stepping down and then boosting, resulting in a large loss of efficiency. Large, not conducive to the improvement of battery life. For the load with high working voltage, the voltage difference between the input and output voltage is relatively large when multiple batteries are connected in parallel, and the conversion efficiency of the power supply is low.
发明内容Contents of the invention
本申请实施例的目的是提供一种电池电路和供电方法,能够解决供电效率低的问题。The purpose of the embodiments of the present application is to provide a battery circuit and a power supply method, which can solve the problem of low power supply efficiency.
第一方面,本申请实施例提供了一种电池电路,包括第一电池、第二电池、升降压模块、采集模块和控制模块,所述第一电池的正极端分别与所述第二电池的负极端、第一负载连接,所述第一电池的负极端接地,所述第二电池的正极端与第二负载连接;所述采集模块,用于采集所述第一电池的电压和电流以及所述第二电池的电压和电流;所述控制模块分别与所述采集模块、所述升降压模块连接,所述控制模块基于所述采集模块采集的所述第一电池的电压和电流、所述第二电池的电压和电流向所述升降压模块发送控制信号;所述升降压模块分别与所述第一电池的正极端、所述第二电池的正极端连接,所述升降压模块基于所述控制信号调整向所述第一负载、所述第二负载的供电以使所述第一电池的荷电状态与所述第二电池的荷电状态同步。In the first aspect, the embodiment of the present application provides a battery circuit, including a first battery, a second battery, a buck-boost module, an acquisition module, and a control module, the positive terminal of the first battery is connected to the second battery The negative terminal of the first battery is connected to the first load, the negative terminal of the first battery is connected to the ground, and the positive terminal of the second battery is connected to the second load; the collection module is used to collect the voltage and current of the first battery and the voltage and current of the second battery; the control module is connected to the acquisition module and the buck-boost module respectively, and the control module is based on the voltage and current of the first battery collected by the acquisition module , the voltage and current of the second battery send control signals to the buck-boost module; the buck-boost module is respectively connected to the positive terminal of the first battery and the positive terminal of the second battery, the The buck-boost module adjusts the power supply to the first load and the second load based on the control signal so that the state of charge of the first battery is synchronized with the state of charge of the second battery.
第二方面,本申请实施例提供了一种供电方法,应用于如上述第一方面所述的电池电路,包括:In the second aspect, the embodiment of the present application provides a power supply method, which is applied to the battery circuit described in the first aspect above, including:
采集所述第一电池的电压、所述第二电池的电压和流经所述第一电池的电流、流经所述第二电池的电流;collecting the voltage of the first battery, the voltage of the second battery, the current flowing through the first battery, and the current flowing through the second battery;
在根据采集的电压和电流确定所述第一电池的荷电状态与所述第二电池的荷电状态不同步的情况下,调整向所述第一负载、所述第二负载的供电以使所述第一电池的荷电状态与所述第二电池的荷电状态同步。When it is determined according to the collected voltage and current that the state of charge of the first battery is not synchronized with the state of charge of the second battery, adjusting the power supply to the first load and the second load so that The state of charge of the first battery is synchronized with the state of charge of the second battery.
第三方面,本申请实施例提供了一种电子设备,包括如上述第一方面所述的电池电路。In a third aspect, an embodiment of the present application provides an electronic device, including the battery circuit described in the first aspect above.
在本申请实施例中,通过将第一电池的正极端分别与第二电池的负极端、第一负载连接,第二电池的正极端与第二负载2连接,并且升降压模块分别与第一电池的正极端、第二电池的正极端连接,升降压模块可以基于第一电池的电压和电流以及所述第二电池的电压和电流调整向第一负载、第二负载的供电,由此通过串联的第一电池和第二电池,可以在提升向高工作电压负载的输入电压至两个电池的电压之和,降低高工作电压负载输入和输出电压压差,极大地提高电源的转换效率,以及向低工作电压负载直接提供一个电池输出的电压,避免电压的升降转换,减少供电效率损失,提升续航能力。此外,基于第一电池、第二电池的电压和电流,由升降压模块调整向第一负载、第二负载的供电,可以使得第一电池和第二电池的荷电状态同步,避免电池存在过充或过放,提高电池寿命。In the embodiment of the present application, by connecting the positive end of the first battery to the negative end of the second battery and the first load respectively, the positive end of the second battery is connected to the second load 2, and the buck-boost module is respectively connected to the first load. The positive terminal of the first battery and the positive terminal of the second battery are connected, and the buck-boost module can adjust the power supply to the first load and the second load based on the voltage and current of the first battery and the voltage and current of the second battery, by By connecting the first battery and the second battery in series, the input voltage to the high operating voltage load can be increased to the sum of the voltages of the two batteries, reducing the voltage difference between the input and output voltage of the high operating voltage load, and greatly improving the conversion of the power supply Efficiency, and directly provide a battery output voltage to the low working voltage load, avoid voltage up-down conversion, reduce power supply efficiency loss, and improve battery life. In addition, based on the voltage and current of the first battery and the second battery, the buck-boost module adjusts the power supply to the first load and the second load, so that the state of charge of the first battery and the second battery can be synchronized, avoiding the existence of batteries Overcharge or overdischarge, improve battery life.
附图说明Description of drawings
图1是本申请实施例的电池电路的结构方框图。FIG. 1 is a structural block diagram of a battery circuit according to an embodiment of the present application.
图2是本申请一个实施例的电池电路的电路示意图。FIG. 2 is a schematic circuit diagram of a battery circuit according to an embodiment of the present application.
图3是本申请实施例的电池电路对应放电状态的电路示意图。FIG. 3 is a schematic circuit diagram of a battery circuit corresponding to a discharge state according to an embodiment of the present application.
图4是本申请实施例的电池电路对应充电状态的电路示意图。FIG. 4 is a schematic circuit diagram of a battery circuit corresponding to a charging state according to an embodiment of the present application.
图5是本申请一个实施例的升降压模块的工作原理示意图。Fig. 5 is a schematic diagram of the working principle of the buck-boost module according to an embodiment of the present application.
图6是本申请一个实施例的升降压模块的工作原理示意图。Fig. 6 is a schematic diagram of the working principle of the buck-boost module according to an embodiment of the present application.
图7是本申请另一个实施例的电池电路的电路示意图。FIG. 7 is a schematic circuit diagram of a battery circuit according to another embodiment of the present application.
图8是本申请另一个实施例的升降压模块的工作原理示意图。FIG. 8 is a schematic diagram of a working principle of a buck-boost module according to another embodiment of the present application.
图9是本申请实施例的供电方法的流程示意图。FIG. 9 is a schematic flowchart of a power supply method according to an embodiment of the present application.
具体实施方式Detailed ways
下面将结合本申请实施例中的附图,对本申请实施例中的技术方案进行清楚地描述,显然,所描述的实施例是本申请一部分实施例,而不是全部的实施例。基于本申请中的实施例,本领域普通技术人员获得的所有其他实施例,都属于本申请保护的范围。The following will clearly describe the technical solutions in the embodiments of the present application with reference to the drawings in the embodiments of the present application. Obviously, the described embodiments are part of the embodiments of the present application, but not all of them. All other embodiments obtained by persons of ordinary skill in the art based on the embodiments in this application belong to the protection scope of this application.
本申请的说明书和权利要求书中的术语“第一”、“第二”等是用于区别类似的对象,而不用于描述特定的顺序或先后次序。应该理解这样使用的数据在适当情况下可以互换,以便本申请的实施例能够以除了在这里图示或描述的那些以外的顺序实施,且“第一”、“第二”等所区分的对象通常为一类,并不限定对象的个数,例如第一对象可以是一个,也可以是多个。此外,说明书以及权利要求中“和/或”表示所连接对象的至少其中之一,字符“/”,一般表示前后关联对象是一种“或”的关系。The terms "first", "second" and the like in the specification and claims of the present application are used to distinguish similar objects, and are not used to describe a specific sequence or sequence. It should be understood that the terms so used are interchangeable under appropriate circumstances such that the embodiments of the application can be practiced in sequences other than those illustrated or described herein, and that references to "first," "second," etc. distinguish Objects are generally of one type, and the number of objects is not limited. For example, there may be one or more first objects. In addition, "and/or" in the specification and claims means at least one of the connected objects, and the character "/" generally means that the related objects are an "or" relationship.
下面结合附图,通过具体的实施例及其应用场景对本申请实施例提供的电池电路和供电方法进行详细地说明。The battery circuit and power supply method provided by the embodiments of the present application will be described in detail below through specific embodiments and application scenarios with reference to the accompanying drawings.
图1是本申请实施例的电池电路的结构方框图,如图1所示,电池电路包括第一电池10、第二电池20、升降压模块30、采集模块40和控制模块50,第一电池10的正极端分别与第二电池20的负极端、第一负载1连接,所述第一电池10的负极端接地,所述第二电池20的正极端与第二负载2连接;所述采集模块40,用于采集所述第一电池10的电压和电流以及所述第二电池20的电压和电流;所述控制模块50分别与所述采集模块40、所述升降压模块30连接,所述控制模块50基于所述采集模块40采集的所述第一电池10的电压和电流、所述第二电池20的电压和电流向所述升降压模块30发送控制信号;所述升降压模块30分别与所述第一电池10的正极端、所述第二电池20的正极端连接,所述升降压模块30基于所述控制信号调整向所述第一负载1、所述第二负载2的供电以使所述第一电池的荷电状态与所述第二电池的荷电状态同步。Fig. 1 is a structural block diagram of the battery circuit of the embodiment of the present application, as shown in Fig. 1, the battery circuit includes a first battery 10, a second battery 20, a buck-boost module 30, an acquisition module 40 and a control module 50, the first battery The positive terminal of 10 is respectively connected with the negative terminal of the second battery 20 and the first load 1, the negative terminal of the first battery 10 is grounded, and the positive terminal of the second battery 20 is connected with the second load 2; The module 40 is used to collect the voltage and current of the first battery 10 and the voltage and current of the second battery 20; the control module 50 is respectively connected with the collection module 40 and the buck-boost module 30, The control module 50 sends a control signal to the buck-boost module 30 based on the voltage and current of the first battery 10 and the voltage and current of the second battery 20 collected by the collection module 40; The voltage module 30 is respectively connected to the positive terminal of the first battery 10 and the positive terminal of the second battery 20. The power supply of the two loads 2 synchronizes the state of charge of the first battery with the state of charge of the second battery.
第一电池10的正极端与第二电池20的负极端连接,第一电池10的负极端通过接地端GND接地,第一电池10的正极端还与第一负载1连接,可以直接输出电压,向第一负载1供电。第二电池20的正极端与第二负载2连接,可将第一电池10和第二电池20输出的电压叠加后向第二负载2供电。The positive terminal of the first battery 10 is connected to the negative terminal of the second battery 20, the negative terminal of the first battery 10 is grounded through the ground terminal GND, the positive terminal of the first battery 10 is also connected to the first load 1, and can directly output voltage, Supply power to the first load 1 . The positive end of the second battery 20 is connected to the second load 2 , and the voltages output by the first battery 10 and the second battery 20 can be superimposed to supply power to the second load 2 .
第一电池10和第二电池20可以是锂电池,锂电池的工作电压范围在3.0V~4.5V区间,由此第一电池10向第一负载1提供的电压可以最高达到4.5V,串联的第一电池10和第二电池向第二负载2提供的电压可以最高达9V。第一负载1为高工作电压负载,第二负载2为低工作电压负载。The first battery 10 and the second battery 20 can be lithium batteries, and the operating voltage range of the lithium batteries is in the range of 3.0V to 4.5V, so the voltage provided by the first battery 10 to the first load 1 can reach up to 4.5V, and the series connection The voltage provided by the first battery 10 and the second battery to the second load 2 can be up to 9V. The first load 1 is a high working voltage load, and the second load 2 is a low working voltage load.
由于第一负载1和第二负载2是基于用户使用的场景来决定的,大小不可控。因此,会存在第一负载1和第二负载2消耗电量不同的情况,如此导致第一电池10和第二电池20的荷电状态(SOC)不同,进而导致某个电池存在过充或过放现象,对电池造成损坏。Since the first load 1 and the second load 2 are determined based on scenarios used by users, their sizes are uncontrollable. Therefore, there will be situations where the power consumption of the first load 1 and the second load 2 are different, so that the state of charge (SOC) of the first battery 10 and the second battery 20 is different, which in turn leads to overcharging or overdischarging of a certain battery phenomenon, causing damage to the battery.
采集模块40可分别采集第一电池10的电压和电流以及第二电池20的电压和电流等数据,控制模块50与采集模块40连接,则能够获取采集模块40的采集数据,并据此判断第一电池10和第二电池20的当前荷电状态是否不同。并在荷电状态不同的情况下,向升降压模块30发送控制信号,控制升降压模块30调整第一电池10、第二电池20向第一负载1、第二负载2提供的电压。The collection module 40 can collect data such as the voltage and current of the first battery 10 and the voltage and current of the second battery 20 respectively, and the control module 50 is connected with the collection module 40, so that the collection data of the collection module 40 can be obtained, and the second battery can be judged accordingly. Whether the current states of charge of the first battery 10 and the second battery 20 are different. And when the state of charge is different, send a control signal to the buck-boost module 30 to control the buck-boost module 30 to adjust the voltage provided by the first battery 10 and the second battery 20 to the first load 1 and the second load 2 .
在本申请实施例中,升降压模块30分别与第一电池10的正极端、第二电池20的正极端连接,也即升降压模块30可与第一负载1、第二负载2连接,形成对应的电流路径。In the embodiment of the present application, the buck-boost module 30 is connected to the positive terminal of the first battery 10 and the positive terminal of the second battery 20 respectively, that is, the buck-boost module 30 can be connected to the first load 1 and the second load 2 , forming the corresponding current path.
参考图1,所述升降压模块30的第一端在第一节点A分别与所述第一电池10的正极端、所述第一负载1连接;所述升降压模块30的第二端在第二节点B分别与所述第二电池20的正极端、所述第二负载2连接;所述升降压模块30的第三端与所述控制模块50连接。Referring to FIG. 1 , the first end of the buck-boost module 30 is respectively connected to the positive end of the first battery 10 and the first load 1 at the first node A; the second end of the buck-boost module 30 terminals are respectively connected to the positive terminal of the second battery 20 and the second load 2 at the second node B; the third terminal of the buck-boost module 30 is connected to the control module 50 .
第一电池10除形成接入第一负载1的通路之外,还可与升降压模块30形成接入第二负载2的通路。由此,第一电池10正极端输出的电压可以直接向第一负载1供电,也可以搭配升降压模块30向第一负载1供电,还可以搭配升降压模块30向第二负载2供电。In addition to forming a path for connecting to the first load 1 , the first battery 10 may also form a path for connecting to the second load 2 with the buck-boost module 30 . Thus, the voltage output from the positive terminal of the first battery 10 can directly supply power to the first load 1, or can be used to supply power to the first load 1 with the buck-boost module 30, and can also be used to supply power to the second load 2 with the buck-boost module 30. .
同样地,第二电池20除形成接入第二负载2的通路之外,还可以与升降压模块30形成接入第一负载1的通路。由此,第二负载2可以由第二电池20正极端输出的电压直接供电,也可以搭配升降压模块30向第二负载2供电。Similarly, in addition to forming a path for connecting to the second load 2 , the second battery 20 can also form a path for connecting to the first load 1 with the buck-boost module 30 . Thus, the second load 2 can be directly powered by the voltage output from the positive terminal of the second battery 20 , or can be combined with the buck-boost module 30 to supply power to the second load 2 .
如图1所示,升降压模块30的第三端与控制模块50,用于接收控制模块50发送的控制信号。关于控制模块50如何发送控制信号,使得升降压模块30根据控制信号对应调整向第一负载1、第二负载2供电的工作原理将在下文中展开描述。As shown in FIG. 1 , the third terminal of the buck-boost module 30 and the control module 50 are used to receive the control signal sent by the control module 50 . The working principle of how the control module 50 sends the control signal so that the buck-boost module 30 correspondingly adjusts the power supply to the first load 1 and the second load 2 will be described below.
如上文所述,采集模块40用于采集第一电池10和第二电池20的电压和电流。参考图2,在一个实施例中,采集模块40包括第一采样电阻Rsense1和第一电流采集单元Isns1,第二采样电阻Rsense2和电流采集单元Isns2,以及第一电压采集单元Vsns1和第二电压采集单元Vsns2,所述第一采样电阻Rsense1连接在所述第一电池10的负极端与接地之间,所述第一电流采集单元Isns1通过采集所述第一采样电阻Rsense1两端的电压和所述第一采样电阻Rsense1的阻值,采集流经所述第一电池10的电流;所述第二采样电阻Rsense2连接在所述第二电池20的负极端与所述第一电池10的正极端之间,所述第二电流采集单元Isns2通过采集所述第二采样电阻Rsense2两端的电压和所述第二采样电阻Rsense2的阻值,采集流经所述第二电池20的电流;所述第一电压采集单元Vsns与所述第一电池10的正极端连接,用于采集所述第一电池10的电压;所述第二电压采集单元Vsns2与所述第二电池20的正极端连接,用于采集所述第二电池20的电压;所述控制模块50与所述采集模块40连接,用于根据所述采集模块40采集的电流和电压向所述升降压模块30的第三端发送所述控制信号。As mentioned above, the collection module 40 is used to collect the voltage and current of the first battery 10 and the second battery 20 . With reference to Fig. 2, in one embodiment, acquisition module 40 comprises the first sampling resistance Rsense1 and the first current acquisition unit Isns1, the second sampling resistance Rsense2 and current acquisition unit Isns2, and the first voltage acquisition unit Vsns1 and the second voltage acquisition unit Unit Vsns2, the first sampling resistor Rsense1 is connected between the negative terminal of the first battery 10 and the ground, and the first current acquisition unit Isns1 collects the voltage at both ends of the first sampling resistor Rsense1 and the first The resistance value of a sampling resistor Rsense1 is used to collect the current flowing through the first battery 10; the second sampling resistor Rsense2 is connected between the negative terminal of the second battery 20 and the positive terminal of the first battery 10 , the second current collection unit Isns2 collects the current flowing through the second battery 20 by collecting the voltage across the second sampling resistor Rsense2 and the resistance value of the second sampling resistor Rsense2; the first voltage The collection unit Vsns is connected to the positive terminal of the first battery 10 for collecting the voltage of the first battery 10; the second voltage collection unit Vsns2 is connected to the positive terminal of the second battery 20 for collecting The voltage of the second battery 20; the control module 50 is connected to the collection module 40, and is used to send the voltage to the third terminal of the buck-boost module 30 according to the current and voltage collected by the collection module 40. control signal.
采集模块40包括用于采集电流信号的模块和用于采集电压信号的模块,在图2实施例中,第一采样电阻Rsense1和第一电流采集单元Isns1构成采集流经第一电池10的电流的模块,第一采样电阻Rsense1连接在第一电池10的负极端与接地之间。在其他实施例中,也可以通过MOS管替代采样电阻进行电流采集,本申请不局限于上述具体实施例。The collection module 40 includes a module for collecting current signals and a module for collecting voltage signals. In the embodiment of FIG. module, the first sampling resistor Rsense1 is connected between the negative terminal of the first battery 10 and the ground. In other embodiments, current collection may also be performed by using MOS transistors instead of sampling resistors, and the present application is not limited to the above specific embodiments.
通过第一电流采集单元Isns1连接在第一采样电阻Rsense1的两端采集各端的电压信号,则通过将第一采样电阻Rsense1的两端之间的电压差与第一采样电阻Rsense1的阻值相除,即可得到流经第一采样电阻Rsense1的电流,流经第一采样电阻Rsense1的电流即为流经第一电池10的电流。The first current acquisition unit Isns1 is connected to both ends of the first sampling resistor Rsense1 to collect voltage signals at each end, then by dividing the voltage difference between the two ends of the first sampling resistor Rsense1 by the resistance value of the first sampling resistor Rsense1 , the current flowing through the first sampling resistor Rsense1 can be obtained, and the current flowing through the first sampling resistor Rsense1 is the current flowing through the first battery 10 .
同样地,第二采样电阻Rsense2和第二电流采集单元Isns2构成采集流经第二电池20的电流的模块,第二采样电阻Rsense2连接在第一电池10的正极端与第二电池20的负极端之间。Similarly, the second sampling resistor Rsense2 and the second current acquisition unit Isns2 form a module for collecting the current flowing through the second battery 20, and the second sampling resistor Rsense2 is connected between the positive terminal of the first battery 10 and the negative terminal of the second battery 20 between.
通过第二电流采集单元Isns2连接在第二采样电阻Rsense2的两端采集各端的电压信号,则通过将第二采样电阻Rsense2的两端之间的电压差与第二采样电阻Rsense2的阻值相除,即可得到流经第二采样电阻Rsense2的电流,流经第二采样电阻Rsense2的电流即为流经第二电池20的电流。The voltage signal at each end is collected by connecting the two ends of the second sampling resistor Rsense2 through the second current acquisition unit Isns2, then by dividing the voltage difference between the two ends of the second sampling resistor Rsense2 by the resistance value of the second sampling resistor Rsense2 , the current flowing through the second sampling resistor Rsense2 can be obtained, and the current flowing through the second sampling resistor Rsense2 is the current flowing through the second battery 20 .
在图2实施例中,第一电压采集单元Vsns1连接在第一电池10的正极端,用于采集第一电池10的电压VBAT1,对第一负载1放电供电时,第一节点A处的电压为VBAT1。第二电压采集单元Vsns2连接在第二电池20的正极端,用于采集第二电池20的电压VBAT2,对第二负载2放电供电时,则第二节点B处的电压为VBAT1+VBAT2。In the embodiment of FIG. 2 , the first voltage acquisition unit Vsns1 is connected to the positive terminal of the first battery 10, and is used to acquire the voltage VBAT1 of the first battery 10, and the voltage at the first node A when discharging and supplying power to the first load 1 for VBAT1. The second voltage collection unit Vsns2 is connected to the positive terminal of the second battery 20 for collecting the voltage VBAT2 of the second battery 20. When discharging and supplying power to the second load 2, the voltage at the second node B is VBAT1+VBAT2.
第一负载1的供电由第一电池10输出的电压VBAT1,或者第一电池10输出的电压VBAT1搭配升降压模块30实现,第二负载2的供电由第二电池20输出的电压VBAT1+VBAT2,或者第二电池20输出的电压VBAT1+VBAT2搭配升降压模块30实现。The power supply of the first load 1 is realized by the voltage VBAT1 output by the first battery 10 , or the voltage VBAT1 output by the first battery 10 is combined with the buck-boost module 30 , and the power supply of the second load 2 is realized by the voltage VBAT1+VBAT2 output by the second battery 20 , or the voltage VBAT1+VBAT2 output by the second battery 20 is realized by collaborating with the buck-boost module 30 .
如上文所述,在电池放电对负载供电时,第一节点A处的电压可以为VBAT1,第二节点B处的电压为VBAT1+VBAT2,第一节点B的电压大于第二节点A的电压,因此将第一节点A连接的第一负载1选择为低工作电压负载,将第二节点B连接的第二负载2选择为高工作电压负载。As mentioned above, when the battery discharges to supply power to the load, the voltage at the first node A can be VBAT1, the voltage at the second node B can be VBAT1+VBAT2, the voltage at the first node B is greater than the voltage at the second node A, Therefore, the first load 1 connected to the first node A is selected as a low operating voltage load, and the second load 2 connected to the second node B is selected as a high operating voltage load.
如此,可以使得对应电路连接关系的第一电池10和第二电池20输出的电压可以落在负载对应的工作电压范围内,不存在高工作电压的第二负载2输入和输出电压压差较大的情况,提升电源的转换效率。也不需要再额外借助其他升压模块或降压模块,避免效率损失较大,有利于提升续航提升。In this way, the voltage output by the first battery 10 and the second battery 20 corresponding to the circuit connection relationship can fall within the operating voltage range corresponding to the load, and there is no second load 2 with a high operating voltage. The input and output voltage difference is large In the case of the power supply, the conversion efficiency of the power supply is improved. There is also no need to use other boost modules or step-down modules to avoid a large loss of efficiency, which is conducive to improving battery life.
如上文所述,由于第一负载1和第二负载2是基于用户使用的场景来决定的,在第一负载1和第二负载2消耗电量不同的情况下,会导致第一电池10的荷电状态和第二电池20的荷电状态不同或不同步,需要在对第一负载1和第二负载2供电的过程中,实时控制第一电池10和第二电池20的荷电状态同步,从而调整向第一负载1、第二负载2的供电。As mentioned above, since the first load 1 and the second load 2 are determined based on the scene used by the user, when the power consumption of the first load 1 and the second load 2 are different, the load of the first battery 10 will be The state of charge of the first battery 10 and the state of charge of the second battery 20 are different or not synchronized. In the process of supplying power to the first load 1 and the second load 2, it is necessary to control the synchronization of the state of charge of the first battery 10 and the second battery 20 in real time. Thus, the power supply to the first load 1 and the second load 2 is adjusted.
对于放电状态和充电状态,第一电池10和第二电池20对应的电流和电压不同,升降压模块30调整向第一负载1、第二负载2的供电方式也是不同的。For the discharge state and the charge state, the current and voltage corresponding to the first battery 10 and the second battery 20 are different, and the ways in which the buck-boost module 30 adjusts the power supply to the first load 1 and the second load 2 are also different.
可选地,所述第一负载1为低工作电压负载,所述第二负载2为高工作电压负载,在所述采集模块40采集的电流为放电电流的情况下,所述控制模块50根据流经所述第一电池10的第一放电电流、流经所述第二电池20的第二放电电流、所述第一电池10的可用最大容量和所述第二电池20的可用最大容量,控制所述升降压模块30调整流经所述升降压模块30的第二端的第一电流,以使所述第一电池10的荷电状态与所述第二电池20的荷电状态同步。Optionally, the first load 1 is a low operating voltage load, and the second load 2 is a high operating voltage load. When the current collected by the acquisition module 40 is a discharge current, the control module 50 according to a first discharge current flowing through the first battery 10 , a second discharge current flowing through the second battery 20 , the maximum available capacity of the first battery 10 and the maximum available capacity of the second battery 20 , controlling the buck-boost module 30 to adjust the first current flowing through the second terminal of the buck-boost module 30, so that the state of charge of the first battery 10 is synchronized with the state of charge of the second battery 20 .
在放电状态下,如图3所示,第二负载2的供电电压通过第一电池10和第二电池20串联之后,提升至VBAT1+VBAT2,可以极大的提高供电效率。In the discharge state, as shown in FIG. 3 , the power supply voltage of the second load 2 is increased to VBAT1+VBAT2 after the first battery 10 and the second battery 20 are connected in series, which can greatly improve the power supply efficiency.
第一电池10的放电电流为I1,第二电池20的放电电流为I2。升降压模块30的第二端为与第二节点B连接的端口,流经升降压模块30的第二端的电流为I4。升降压模块30的第一端为与第一节点A连接的端口,流经升降压模块30的第一端的电流为I3。The discharge current of the first battery 10 is I1, and the discharge current of the second battery 20 is I2. The second terminal of the buck-boost module 30 is a port connected to the second node B, and the current flowing through the second terminal of the buck-boost module 30 is I4. The first terminal of the buck-boost module 30 is a port connected to the first node A, and the current flowing through the first terminal of the buck-boost module 30 is I3.
在升降压模块30工作在降压模式时,对应的输入电流为电流I4,输出电流为电流I3,则对应的输入电压为VBAT1+VBAT2,输出电压为VBAT1,转换效率为η0:When the buck-boost module 30 works in the step-down mode, the corresponding input current is current I4, and the output current is current I3, then the corresponding input voltage is VBAT1+VBAT2, the output voltage is VBAT1, and the conversion efficiency is η0:
输入第一负载1的电流: Current input to first load 1:
输入第二负载2的电流: Current into the second load 2:
I2=I4+Iload2I2=I4+Iload2
在通过第一电池10和第二电池20串联放电对负载供电的同时,还需要控制第一电池10的荷电状态与第二电池20的荷电状态同步。此时,控制模块50可以通过采集模块40采集的第一电池10和第二电池20的电流和电压信息,对升降压模块30进行调控,具体方案如下:While the first battery 10 and the second battery 20 are discharged in series to supply power to the load, it is also necessary to control the state of charge of the first battery 10 to be synchronized with the state of charge of the second battery 20 . At this time, the control module 50 can regulate the buck-boost module 30 through the current and voltage information of the first battery 10 and the second battery 20 collected by the collection module 40, and the specific scheme is as follows:
第一电池10或者第二电池20的荷电状态(SOC)通常可以用函数表示为:SOC=f(Q,OCV,T),其中Q表示电流I与时间t的库伦积分;OCV为开路电压,用于校准和电量纠偏;T代表电池温度。The state of charge (SOC) of the first battery 10 or the second battery 20 can generally be expressed as a function: SOC=f(Q, OCV, T), wherein Q represents the Coulomb integral of the current I and time t; OCV is the open circuit voltage , used for calibration and power correction; T represents the battery temperature.
在开路电压OCV没有达到校准条件和温度T相同的情况下,第一电池10的荷电状态SOC1、第二电池20的荷电状态SOC2基于电流积分进行估算:When the open circuit voltage OCV does not reach the calibration condition and the temperature T is the same, the state of charge SOC1 of the first battery 10 and the state of charge SOC2 of the second battery 20 are estimated based on the current integral:
其中,Qmax1和Qmax2分别表示第一电池10和第二电池20的可用最大容量。Wherein, Qmax1 and Qmax2 represent the available maximum capacity of the first battery 10 and the second battery 20 respectively.
为了保持第一电池10和第二电池20的荷电状态同步,f(Q1)=f(Q2),则在荷电状态同步时VBAT1≈VBAT2,由于输入第一负载1的电流Iload1和输入第二负载2的电流Iload2由用户场景决定,是不可控的,则根据f(Q1)=f(Q2)可以推得:In order to keep the state of charge of the first battery 10 and the second battery 20 synchronized, f(Q1)=f(Q2), then when the state of charge is synchronized, VBAT1≈VBAT2, due to the current Iload1 input to the first load 1 and the input current Iload1 The current Iload2 of the second load 2 is determined by the user scenario and is uncontrollable. According to f(Q1)=f(Q2), it can be deduced as follows:
上述公式中,电流Iload1和电流Iload2与用户场景相关,可以通过I1和I2来表征,而η0为固定值,Qmax1、Qmax2是通过采集模块40获取的已知值,I4为可以通过控制模块50调控的变量,通过调整电流I4可以达成SOC1=SOC2。In the above formula, the current Iload1 and the current Iload2 are related to the user scene and can be represented by I1 and I2, while η0 is a fixed value, Qmax1 and Qmax2 are known values obtained through the acquisition module 40, and I4 is a value that can be adjusted through the control module 50 variable, SOC1=SOC2 can be achieved by adjusting the current I4.
控制模块50可以通过判断采集模块采集的第一电池10的电压VBAT1和第二电池20的电压VBAT1是否相等,来判断当前第一电池10和第二电池20荷电状态是否同步。在|VBAT1-VBAT2|<△V0,即VBAT1和VBAT2的压差在一定的阈值门限△V0以内时,VBAT1≈VBAT2,判断同步;否则,不同步。The control module 50 can judge whether the current state of charge of the first battery 10 and the second battery 20 are synchronized by judging whether the voltage VBAT1 of the first battery 10 collected by the collection module is equal to the voltage VBAT1 of the second battery 20 . When |VBAT1-VBAT2|<△V0, that is, when the voltage difference between VBAT1 and VBAT2 is within a certain threshold △V0, VBAT1≈VBAT2, it is judged to be synchronous; otherwise, it is not synchronous.
在确定第一电池10的荷电状态与第二电池20的荷电状态不同步时,根据采集的第一电池10的电压、第二电池20的电压和流经第一电池10的第一放电电流、流经第二电池20的第二放电电流,确定提供至第一负载1的电流Iload1和提供至第二负载2的电流Iload2。When it is determined that the state of charge of the first battery 10 is not synchronized with the state of charge of the second battery 20 , according to the collected voltage of the first battery 10 , the voltage of the second battery 20 and the first discharge flowing through the first battery 10 The current, the second discharge current flowing through the second battery 20 , determines the current Iload1 supplied to the first load 1 and the current Iload2 supplied to the second load 2 .
根据电流Iload1和电流Iload2、第一电池10的可用最大容量和第二电池20的可用最大容量等参数,结合上述公式(2)调整流经升降压模块30的第二端的电流I4大小,由此调整向第一负载1、第二负载2的供电,直至检测到|VBAT1-VBAT2|<△V0,即第一电池10的荷电状态与第二电池20的荷电状态同步时停止调整。According to parameters such as current Iload1 and current Iload2, the available maximum capacity of the first battery 10 and the available maximum capacity of the second battery 20, the size of the current I4 flowing through the second end of the buck-boost module 30 is adjusted in combination with the above formula (2), and the current I4 is adjusted by The power supply to the first load 1 and the second load 2 is adjusted until it is detected that |VBAT1-VBAT2|
当控制模块50检测到第二电池20的荷电状态下降快于第一电池10,即第二负载2较大时,升降压模块30工作在降压模式,如图3所示升降压模块30工作在降压模式下,电流I4的电流方向为正向,通过控制升降压模块30降低电流I4进行补偿;如果第二负载2很大,升降压模块30可以工作在升压模式,升降压模块30工作在升压模式下,电流I4为反向,第一电池10经过升降压模块30反向升压给第二负载2供电,降低第二电池20的电量消耗,同时增加第一电池10的电量消耗来进行补偿,使得第一电池10的荷电状态与第二电池20同步。When the control module 50 detects that the state of charge of the second battery 20 drops faster than the first battery 10, that is, when the second load 2 is relatively large, the buck-boost module 30 works in a buck mode, as shown in FIG. 3 The module 30 works in the step-down mode, and the current direction of the current I4 is positive, and the buck-boost module 30 is controlled to reduce the current I4 to compensate; if the second load 2 is very large, the buck-boost module 30 can work in the boost mode , the buck-boost module 30 works in the boost mode, the current I4 is reversed, and the first battery 10 is reversely boosted by the buck-boost module 30 to supply power to the second load 2, reducing the power consumption of the second battery 20, and at the same time The power consumption of the first battery 10 is increased to compensate, so that the state of charge of the first battery 10 is synchronized with that of the second battery 20 .
当第二电池20的荷电状态下降慢于第一电池10,即第二负载2较小时,通过控制升降压模块30增加电流I4进行补偿。增加第二电池20的电量消耗,同时降低第一电池10的电量消耗来进行补偿,使得第二电池20的荷电状态与第一电池10同步。When the state of charge of the second battery 20 drops slower than that of the first battery 10 , that is, when the second load 2 is small, the buck-boost module 30 is controlled to increase the current I4 to compensate. The power consumption of the second battery 20 is increased while the power consumption of the first battery 10 is decreased to compensate, so that the state of charge of the second battery 20 is synchronized with that of the first battery 10 .
在另一个实施例中,所述第一负载1为低工作电压负载,所述第二负载2为高工作电压负载,在所述采集模块40采集的电流为充电电流的情况下,所述控制模块50根据流经所述第一电池10的第一充电电流、流经所述第二电池20的第二充电电流、所述第一电池10的可用最大容量和所述第二电池20的可用最大容量,控制所述升降压模块30调整流经所述升降压模块30的第二端的第二电流,以使所述第一电池10的荷电状态SOC与所述第二电池20的荷电状态SOC同步。In another embodiment, the first load 1 is a low operating voltage load, and the second load 2 is a high operating voltage load. When the current collected by the acquisition module 40 is a charging current, the control The module 50 is based on the first charging current flowing through the first battery 10 , the second charging current flowing through the second battery 20 , the available maximum capacity of the first battery 10 and the available capacity of the second battery 20 maximum capacity, controlling the buck-boost module 30 to adjust the second current flowing through the second terminal of the buck-boost module 30, so that the state of charge SOC of the first battery 10 is the same as that of the second battery 20 State of charge SOC synchronization.
在充电状态下,控制模块50可以通过判断采集模块40采集的第一电池10的电压VBAT1和第二电池20的电压VBAT1是否相等,来判断当前第一电池10和第二电池20荷电状态是否同步。在|VBAT1-VBAT2|<△V0,即VBAT1和VBAT2的压差在一定的阈值门限△V0以内时,判断同步;否则,不同步。In the charging state, the control module 50 can determine whether the current state of charge of the first battery 10 and the second battery 20 is equal by judging whether the voltage VBAT1 of the first battery 10 collected by the collection module 40 is equal to the voltage VBAT1 of the second battery 20 Synchronize. When |VBAT1-VBAT2|<△V0, that is, when the voltage difference between VBAT1 and VBAT2 is within a certain threshold △V0, it is judged to be synchronous; otherwise, it is not synchronous.
在确定第一电池10的荷电状态与第二电池20的荷电状态不同步时,根据采集的第一电池10的电压、第二电池20的电压和流经第一电池10的第一放电电流、流经第二电池20的第二放电电流,确定提供至第一负载1的电流Iload1和提供至第二负载2的电流Iload2。When it is determined that the state of charge of the first battery 10 is not synchronized with the state of charge of the second battery 20 , according to the collected voltage of the first battery 10 , the voltage of the second battery 20 and the first discharge flowing through the first battery 10 The current, the second discharge current flowing through the second battery 20 , determines the current Iload1 supplied to the first load 1 and the current Iload2 supplied to the second load 2 .
升降压转换模块30工作在升压模式,升降压模块30的第一端输入电流为,升降压模块30的第二端输出电流,同时为第二电池20充电和为第二负载2供电。The buck-boost conversion module 30 works in the boost mode, the input current of the first terminal of the buck-boost module 30 is , and the output current of the second terminal of the buck-boost module 30 is for charging the second battery 20 and for the second load 2 at the same time. powered by.
根据电流Iload1和电流Iload2、第一电池10的可用最大容量和第二电池20的可用最大容量等参数,结合上述公式(2)调整流经升降压模块30的第二端的电流I4大小,由此调整向第一负载1、第二负载2的供电,直至检测到|VBAT1-VBAT2|<△V0,即第一电池10的荷电状态与第二电池20的荷电状态同步时停止调整。According to parameters such as current Iload1 and current Iload2, the available maximum capacity of the first battery 10 and the available maximum capacity of the second battery 20, the size of the current I4 flowing through the second end of the buck-boost module 30 is adjusted in combination with the above formula (2), and the current I4 is adjusted by The power supply to the first load 1 and the second load 2 is adjusted until it is detected that |VBAT1-VBAT2|
当控制模块50检测到第二电池20的荷电状态上涨快于第一电池10,即给第二电池20充电的充电电流较大时,通过控制升降压模块30降低流经升降压模块30的第二端的输出电流进行补偿。升降压模块30甚至可以停止工作,在第二端输出的电流为0,确保第二电池20与第一电池10的荷电状态上涨同步。When the control module 50 detects that the state of charge of the second battery 20 rises faster than that of the first battery 10, that is, when the charging current for charging the second battery 20 is relatively large, it controls the buck-boost module 30 to reduce the voltage flowing through the buck-boost module. The output current of the second terminal of 30 is compensated. The buck-boost module 30 can even stop working, and the output current at the second terminal is 0, so as to ensure that the state of charge of the second battery 20 and the first battery 10 increase synchronously.
当第二电池20的荷电状态下降慢于第一电池10,即第二负载2较小时,通过控制升降压模块30增加第二端的输出电流进行补偿。由此,增加对第二电池20的充电,同时降低对第一电池10的充电来进行补偿,使得第二电池20的荷电状态与第一电池10同步。When the state of charge of the second battery 20 drops slower than that of the first battery 10 , that is, when the second load 2 is small, the buck-boost module 30 is controlled to increase the output current of the second terminal to compensate. Thus, the charging of the second battery 20 is increased while the charging of the first battery 10 is decreased to compensate, so that the state of charge of the second battery 20 is synchronized with that of the first battery 10 .
在一个实施例中,电池电路还包括充电模块,所述充电模块的第一端接入外部电源,所述充电模块的第二端连接所述第一负载1,所述充电模块的第三端在所述第一节点A分别与所述第一电池10的正极端、所述升降压模块30的第一端连接,所述充电模块的第四端与所述控制模块50连接;所述控制模块50还用于根据所述采集模块40采集的电流和电压控制所述充电模块60为所述第一电池10充电和通过所述升降压模块30为所述第二电池20充电。In one embodiment, the battery circuit further includes a charging module, the first end of the charging module is connected to an external power supply, the second end of the charging module is connected to the first load 1, and the third end of the charging module The first node A is respectively connected to the positive terminal of the first battery 10 and the first terminal of the buck-boost module 30, and the fourth terminal of the charging module is connected to the control module 50; the The control module 50 is also used to control the charging module 60 to charge the first battery 10 and charge the second battery 20 through the buck-boost module 30 according to the current and voltage collected by the collection module 40 .
如图2所示,充电模块60的一端与充电器70连接,充电模块60的第二端连接第一负载1,充电模块60的第三端连接第一电池10的正极端和升降压模块30的第一端。As shown in Figure 2, one end of the charging module 60 is connected to the charger 70, the second end of the charging module 60 is connected to the first load 1, and the third end of the charging module 60 is connected to the positive terminal of the first battery 10 and the buck-boost module 30 on the first end.
所述充电模块具备路径管理功能,放电状态下所述第一电池通过所述充电模块的路径管理给所述第一负载供电;以及充电状态下,所述充电模块将所述外部电源的能量转化后分别给所述第一电池、所述第二电池和所述第一负载供电。The charging module has a path management function. In a discharging state, the first battery supplies power to the first load through the path management of the charging module; and in a charging state, the charging module converts the energy of the external power supply into Then supply power to the first battery, the second battery and the first load respectively.
充电模块60负责给第一电池10充电,并且与升降压模块30搭配实现给第二电池20充电。同时,充电模块60具备路径管理功能。放电时,第一电池10通过充电模块60的路径管理给第一负载1供电;充电时,充电器70的能量经过充电模块60转化,在给第一电池10和第二电池20充电的同时,给第一负载1供电。The charging module 60 is responsible for charging the first battery 10 , and cooperates with the buck-boost module 30 to charge the second battery 20 . Meanwhile, the charging module 60 has a path management function. When discharging, the first battery 10 supplies power to the first load 1 through the path management of the charging module 60; when charging, the energy of the charger 70 is converted by the charging module 60, while charging the first battery 10 and the second battery 20, Supply power to the first load 1 .
在放电状态下,如图4所示,用户连接充电器70进行充电时,经过充电模块60转化之后,充电电流在第一节点A位置处分成两个方向分别对第一电池10和第二电池20进行充电,其中电流Ichg0直接给第一电池10充电,电流Ichg3经过升降压模块30转化之后,同时给第二电池20和第一电池10充电,此时升降压模块30工作在升压模式。In the discharging state, as shown in FIG. 4 , when the user connects the charger 70 to charge, after being converted by the charging module 60, the charging current is divided into two directions at the first node A to respectively charge the first battery 10 and the second battery. 20 for charging, wherein the current Ichg0 directly charges the first battery 10, and the current Ichg3 is converted by the buck-boost module 30 to charge the second battery 20 and the first battery 10 at the same time. At this time, the buck-boost module 30 works in the boost model.
充电模块60输出的总电流为Ichg,充电模块60具备路径管理功能,所以第一负载1可由充电模块60直接提供电流Iload1,第一电池10的充电电流为Ichg1=Ichg0+Ichg2,第二电池20的充电电流为Ichg2,升降压模块30工作在升压模式时,升降压模块30对应第二节点B处的第二端输出的电流为Ichg4,如图4所示升降压模块30工作在升压模式下,电流Ichg4为反向,同时以电流Ichg2为第二电池20充电以及向第二负载2提供电流Iload2。升降压模块30对应第一节点A处的第一端输入的电流为Ichg3,升降压模块30的第二端对应的输出电压为VBAT1+VBAT2,升降压模块30的的第一端对应的输入电压为VBAT1,转换效率为η1:The total current output by the charging module 60 is Ichg, and the charging module 60 has a path management function, so the first load 1 can be directly provided with a current Iload1 by the charging module 60, the charging current of the first battery 10 is Ichg1=Ichg0+Ichg2, and the second battery 20 The charging current of the buck-boost module 30 is Ichg2. When the buck-boost module 30 works in the boost mode, the current output by the buck-boost module 30 corresponding to the second terminal at the second node B is Ichg4. The buck-boost module 30 works as shown in FIG. 4 In the boost mode, the current Ichg4 is reversed, while the current Ichg2 is used to charge the second battery 20 and provide the second load 2 with the current Iload2. The buck-boost module 30 corresponds to the current input by the first terminal at the first node A as Ichg3, the output voltage corresponding to the second terminal of the buck-boost module 30 is VBAT1+VBAT2, and the first terminal of the buck-boost module 30 corresponds to The input voltage is VBAT1, and the conversion efficiency is η1:
Ichg2=Ichg4-Iload2Ichg2=Ichg4-Iload2
在开路电压OCV没有达到校准条件和温度T相同的情况下,第一电池10和第二电池20的荷电状态基于电流积分进行估算:In the case that the open circuit voltage OCV does not reach the calibration condition and the temperature T is the same, the state of charge of the first battery 10 and the second battery 20 is estimated based on the current integral:
为了保持第一电池10和第二电池20的荷电状态同步,f(Q1)=f(Q2),在荷电状态相同时VBAT1≈VBAT2,由于输入第一负载1的电流Iload1和输入第二负载2的电流Iload2由用户场景决定,是不可控的,则根据f(Q1)=f(Q2)可以推得:In order to keep the state of charge of the first battery 10 and the second battery 20 synchronized, f(Q1)=f(Q2), when the state of charge is the same, VBAT1≈VBAT2, due to the current Iload1 input to the first load 1 and the current Iload1 input to the second The current Iload2 of load 2 is determined by the user scenario and is uncontrollable. According to f(Q1)=f(Q2), it can be deduced as follows:
上述公式中,电流Iload2与用户场景相关,而η1为固定值,Qmax1、Qmax2和电流Ichg1是通过采集模块40获取的已知值,Ichag4为可以通过控制模块50调控的变量,因此通过调整电流Ichg4可以达成SOC1=SOC2。In the above formula, the current Iload2 is related to the user scene, and η1 is a fixed value, Qmax1, Qmax2 and current Ichg1 are known values obtained through the acquisition module 40, and Ichag4 is a variable that can be regulated by the control module 50, so by adjusting the current Ichg4 SOC1=SOC2 can be achieved.
控制模块50可以通过判断采集模块采集的第一电池10的电压VBAT1和第二电池20的电压VBAT1是否相等,来判断当前第一电池10和第二电池20荷电状态是否同步。在|VBAT1-VBAT2|<△V0,即VBAT1和VBAT2的压差在一定的阈值门限△V0以内时,判断同步;否则,不同步。The control module 50 can judge whether the current state of charge of the first battery 10 and the second battery 20 are synchronized by judging whether the voltage VBAT1 of the first battery 10 collected by the collection module is equal to the voltage VBAT1 of the second battery 20 . When |VBAT1-VBAT2|<△V0, that is, when the voltage difference between VBAT1 and VBAT2 is within a certain threshold △V0, it is judged to be synchronous; otherwise, it is not synchronous.
在确定第一电池10的荷电状态与第二电池20的荷电状态不同步时,根据采集的第一电池10的电压VBAT1、第二电池20的电压VBAT2和流经第一电池10的第一充电电流Ichg1、流经第二电池20的第二充电电流Ichg2,确定提供至第二负载2的电流Iload2。When it is determined that the state of charge of the first battery 10 is not synchronized with the state of charge of the second battery 20 , according to the collected voltage VBAT1 of the first battery 10 , the voltage VBAT2 of the second battery 20 and the first battery 10 flowing through the first battery 10 A charging current Ichg1 and a second charging current Ichg2 flowing through the second battery 20 determine the current Iload2 provided to the second load 2 .
根据第一充电电流Ichg1、电流Iload2、第一电池10的可用最大容量Qmax1和第二电池20的可用最大容量Qmax2参数,结合上述公式(3)调整流经升降压模块30的第二端的电流Ichg4大小,由此调整向第一负载1、第二负载2的供电,直至检测到|VBAT1-VBAT2|<△V0,即第一电池10的荷电状态与第二电池20的荷电状态同步时停止调整。According to the parameters of the first charging current Ichg1, the current Iload2, the available maximum capacity Qmax1 of the first battery 10, and the available maximum capacity Qmax2 of the second battery 20, the current flowing through the second terminal of the buck-boost module 30 is adjusted in combination with the above formula (3). Ichg4, thereby adjusting the power supply to the first load 1 and the second load 2 until |VBAT1-VBAT2|<△V0 is detected, that is, the state of charge of the first battery 10 is synchronized with the state of charge of the second battery 20 stop the adjustment.
当控制模块50检测到第二电池20的荷电状态上涨快于第一电池10,即第二电池20的充电电流lchg2较大时,通过控制升降压模块30降低电流Ichg4进行补偿,确保第二电池20与第一电池10的荷电状态上涨同步。When the control module 50 detects that the state of charge of the second battery 20 rises faster than that of the first battery 10, that is, when the charging current lchg2 of the second battery 20 is relatively large, it compensates by controlling the buck-boost module 30 to reduce the current Ichg4 to ensure that the second battery 20 The state of charge of the second battery 20 rises synchronously with that of the first battery 10 .
当控制模块50检测到第二电池20的荷电状态上涨慢于第一电池10,即第二负载2较小时,通过控制升降压模块30增加电流Ichg4进行补偿,确保第二电池20与第一电池10的荷电状态上涨同步。When the control module 50 detects that the state of charge of the second battery 20 rises slower than that of the first battery 10, that is, when the second load 2 is small, it compensates by controlling the buck-boost module 30 to increase the current Ichg4 to ensure that the second battery 20 is compatible with the first battery 10. The state of charge of a battery 10 rises synchronously.
在一个实施例中,如图2至图4所示,升降压模块包括第一晶体管Q1、第二晶体管Q2、驱动单元32和电感L,所述第一晶体管Q1的栅极与所述驱动单元32连接,所述第一晶体管Q1的源极在所述第二节点B分别与所述第二电池的正极端、所述第二负载连接连接,所述第一晶体管Q1的漏极与所述第二晶体管Q2连接;所述第二晶体管Q2的栅极与所述驱动单元连接,所述第二晶体管Q2的源极与所述第一晶体管Q1的漏极连接,所述第二晶体管Q2的漏极接地;所述电感L的第一端连接在所述第一晶体管Q1的漏极与所述第二晶体管Q2的源极之间,所述电感L的第二端在所述第一节点分别与所述第一电池的正极端、所述第一负载连接。In one embodiment, as shown in FIG. 2 to FIG. 4 , the buck-boost module includes a first transistor Q1, a second transistor Q2, a drive unit 32 and an inductor L, and the gate of the first transistor Q1 is connected to the drive unit 32, the source of the first transistor Q1 is respectively connected to the positive terminal of the second battery and the second load at the second node B, and the drain of the first transistor Q1 is connected to the The second transistor Q2 is connected; the gate of the second transistor Q2 is connected to the driving unit, the source of the second transistor Q2 is connected to the drain of the first transistor Q1, and the second transistor Q2 The drain of the inductor L is grounded; the first end of the inductor L is connected between the drain of the first transistor Q1 and the source of the second transistor Q2, and the second end of the inductor L is connected between the first transistor Q1 and the source of the second transistor Q2. The nodes are respectively connected to the positive terminal of the first battery and the first load.
对于上述实施例的放电状态,当控制模块50检测到第二电池20的荷电状态下降快于第一电池10,控制模块50通过控制图2至图4实施例的升降压模块30降低电流I4进行补偿,具体原理如下:For the discharge state of the above embodiment, when the control module 50 detects that the state of charge of the second battery 20 drops faster than that of the first battery 10, the control module 50 reduces the current by controlling the buck-boost module 30 of the embodiment shown in FIG. 2 to FIG. 4 I4 compensates, the specific principle is as follows:
定义第一晶体管Q1和第二晶体管Q2导通为高电平、关闭为低电平,定义降压时的电感L上流经的电流IL为正向,则第一晶体管Q1、第二晶体管Q2与电感电流IL的控制波形如图5所示,当处于降压模式下,如果第二负载2逐渐变大,控制模块50通过向驱动单元32发送对应的控制信号,以逐步降低第一晶体管Q1的导通时间ton,降低电流I4;当电流I4足够小,电感电流IL出现过零时,进入图5所示的降压轻载模式;当第二负载2足够大,升降压模块30进入升压模式,电感电流IL反向。It is defined that the first transistor Q1 and the second transistor Q2 are turned on as a high level, and that they are turned off as a low level, and that the current IL flowing through the inductor L during step-down is defined as positive, then the first transistor Q1, the second transistor Q2 and The control waveform of the inductor current IL is shown in FIG. 5 . When in the step-down mode, if the second load 2 gradually becomes larger, the control module 50 sends a corresponding control signal to the driving unit 32 to gradually reduce the voltage of the first transistor Q1. The on-time ton reduces the current I4; when the current I4 is small enough and the inductor current IL crosses zero, it enters the step-down light load mode shown in FIG. 5; when the second load 2 is large enough, the buck-boost module 30 enters voltage mode, the inductor current IL reverses.
对于上述实施例的放电状态,当第二电池20的荷电状态下降慢于第一电池10,即第二负载2较小时,控制模块50通过控制升降压模块30增加电流I4进行补偿,具体原理如下:For the discharge state of the above embodiment, when the state of charge of the second battery 20 drops slower than that of the first battery 10, that is, when the second load 2 is small, the control module 50 compensates by controlling the buck-boost module 30 to increase the current I4, specifically The principle is as follows:
此时升降压模块30工作在降压模式,定义第一晶体管Q1和第二晶体管Q2导通为高电平、关闭为低电平,定义降压时电感L上流经的电流IL为正向,则控制模块50通过向驱动单元32发送对应的控制信号,得到第一晶体管Q1和第二晶体管Q2与电感电流IL的控制波形如图6所示,第一晶体管Q1导通时间ton内输入给电感充电,第一晶体管Q1关闭时间toff内电感放电,则电流I3约为电感电流IL的平均值。脉宽调制(PWM)的开关周期T=ton+toff,通过调整ton的时间长短,即可控制电流I3和电流I4的大小,实现对第一电池10和第二电池20电量平衡的调控。At this time, the buck-boost module 30 works in the step-down mode, and the first transistor Q1 and the second transistor Q2 are defined as high level when they are turned on and low level when they are turned off, and the current IL flowing through the inductor L during step-down is defined as positive , then the control module 50 sends the corresponding control signal to the driving unit 32 to obtain the control waveforms of the first transistor Q1 and the second transistor Q2 and the inductor current IL as shown in FIG. The inductor is charged, and the inductor is discharged within the off time toff of the first transistor Q1, so the current I3 is approximately the average value of the inductor current IL. The pulse width modulation (PWM) switching period T=ton+toff, by adjusting the time length of ton, the magnitude of the current I3 and the current I4 can be controlled, and the balance of the first battery 10 and the second battery 20 can be adjusted.
对于对于上述实施例的充电状态,控制模块50控制升降压模块30进行对应升压或降压的工作原理可以参考上述放电状态的工作原理,这里不再赘述。For the charging state of the above embodiment, the working principle of the control module 50 controlling the buck-boost module 30 to boost or buck the voltage can refer to the working principle of the above-mentioned discharging state, which will not be repeated here.
在另一个实施例中,如图7所示,升降压模块包括第三晶体管Q3、第四晶体管Q4、第五晶体管Q5、第六晶体管Q6、驱动单元32和电容Cfly,所述第三晶体管的栅极与所述驱动单元连接,所述第三晶体管的源极在所述第二节点分别与所述第二电池的正极端、所述第二负载连接连接,所述第三晶体管的漏极与所述第四晶体管连接;所述第四晶体管的栅极与所述驱动单元连接,所述第四晶体管的源极与所述第三晶体管的漏极连接,所述第四晶体管的漏极与所述第五晶体管连接;所述第五晶体管的栅极与所述驱动单元连接,所述第五晶体管的源极与所述第四晶体管的漏极连接,所述第五晶体管的漏极与所述第六晶体管连接;所述第六晶体管的栅极与所述驱动单元连接,所述第六晶体管的源极与所述第五晶体管的漏极连接,所述第六晶体管的漏极接地;所述电容Cfly的第一端连接在所述第三晶体管的漏极与所述第四晶体管的源极之间,所述电容Cfly的第二端连接在所述第五晶体管的漏极与所述第六晶体管的源极之间;所述第四晶体管的漏极或所述第五晶体管的源极还在所述第一节点分别与所述第一电池的正极端、所述第一负载连接。In another embodiment, as shown in FIG. 7, the buck-boost module includes a third transistor Q3, a fourth transistor Q4, a fifth transistor Q5, a sixth transistor Q6, a driving unit 32, and a capacitor Cfly. The third transistor The gate of the third transistor is connected to the drive unit, the source of the third transistor is respectively connected to the positive terminal of the second battery and the second load at the second node, and the drain of the third transistor The pole is connected to the fourth transistor; the gate of the fourth transistor is connected to the drive unit, the source of the fourth transistor is connected to the drain of the third transistor, and the drain of the fourth transistor The pole is connected to the fifth transistor; the gate of the fifth transistor is connected to the drive unit, the source of the fifth transistor is connected to the drain of the fourth transistor, and the drain of the fifth transistor The pole is connected to the sixth transistor; the gate of the sixth transistor is connected to the drive unit, the source of the sixth transistor is connected to the drain of the fifth transistor, and the drain of the sixth transistor grounded; the first end of the capacitor Cfly is connected between the drain of the third transistor and the source of the fourth transistor, and the second end of the capacitor Cfly is connected to the drain of the fifth transistor pole and the source of the sixth transistor; the drain of the fourth transistor or the source of the fifth transistor is also connected to the positive terminal of the first battery, the positive terminal of the first battery, and the first node respectively. first load connection.
该实施例的升降压模块的控制原理如下:如图8所示,在充放电过程中,当第二电池20的电量比第一电池10高时,即VBAT2>VBAT1,此时控制模块50控制驱动单元32工作在降压模式,输入电压为VBAT1+VBAT2,输出电压为VBAT1,周期t1内第三晶体管Q3和第五晶体管Q5导通,电容Cfly充电;周期t2内,电容Cfly给VBAT1释放能量。The control principle of the buck-boost module of this embodiment is as follows: as shown in FIG. 8 , during the charging and discharging process, when the power of the second battery 20 is higher than that of the first battery 10, that is, VBAT2>VBAT1, the control module 50 The driving unit 32 is controlled to work in the step-down mode, the input voltage is VBAT1+VBAT2, the output voltage is VBAT1, the third transistor Q3 and the fifth transistor Q5 are turned on in the period t1, and the capacitor Cfly is charged; in the period t2, the capacitor Cfly is released to VBAT1 energy.
当第一电池10的电量比第二电池20高时,即VBAT1>VBAT2,此时控制模块50控制驱动单元32工作在升压模式,输入电压为VBAT1,输出电压为VBAT1+VBAT2,周期t1内第四晶体管Q4和第六晶体管Q6导通,电容Cfly充电;周期t2内,电容Cfly给VBAT1+VBAT2释放能量。When the power of the first battery 10 is higher than that of the second battery 20, that is, VBAT1>VBAT2, the control module 50 controls the driving unit 32 to work in the boost mode, the input voltage is VBAT1, and the output voltage is VBAT1+VBAT2, within the period t1 The fourth transistor Q4 and the sixth transistor Q6 are turned on, and the capacitor Cfly is charged; in the period t2, the capacitor Cfly releases energy to VBAT1+VBAT2 .
上述实施例的升降压模块30既可以实现降压,也可以实现升压。The buck-boost module 30 in the above-mentioned embodiment can realize both step-down and step-up.
在本申请实施例中,所述第一电池10的容量与所述第二电池20的容量不同。In the embodiment of the present application, the capacity of the first battery 10 is different from that of the second battery 20 .
例如第一电池10的容量为Cap1,第二电池20的容量为Cap2,则Cap1和Cap2可以根据高工作电压的第二负载2的功耗占比进行初步设计,比如通过在一定数量的用户样本下,统计用户每一天使用场景的平均功耗分布占比,第二负载2占比约23%,则第二负载2的功耗P2和低工作电压的第一负载1的功耗P1的大致占比为:For example, the capacity of the first battery 10 is Cap1, and the capacity of the second battery 20 is Cap2, then Cap1 and Cap2 can be preliminarily designed according to the power consumption ratio of the second load 2 with high operating voltage, for example, through a certain number of user samples Next, calculate the average power consumption distribution of the user's daily usage scenarios, and the second load 2 accounts for about 23%, then the power consumption P2 of the second load 2 and the power consumption P1 of the first load 1 with low operating voltage are approximately The proportion is:
通过升降压模块30的调控,可以使两个第一电池10和第二电池20的荷电状态接近同步,即VBAT1≈VBAT2。Through the regulation of the buck-boost module 30 , the states of charge of the two first batteries 10 and the second battery 20 can be nearly synchronized, that is, VBAT1 ≈ VBAT2 .
则第一电池10和第二电池20的容量比值可以按照如下公式进行大致设计:Then the capacity ratio of the first battery 10 and the second battery 20 can be roughly designed according to the following formula:
假如电子设备的电池容量为5000mAh,则可以按照第一电池的容量Cap1=652mAh、第二电池的容量Cap2=4348mAh进行设计。以上仅为粗略估算的方法,实际可以根据负载功耗情况和升降压模块的控制能力进行调整。If the battery capacity of the electronic device is 5000mAh, it can be designed according to the capacity Cap1 of the first battery = 652mAh and the capacity of the second battery Cap2 = 4348mAh. The above is only a rough estimation method, and it can be adjusted according to the load power consumption and the control capability of the buck-boost module.
使用容量不一样的电池可以实现串联充电,提高充电速度,且降低堆叠的难度。The use of batteries with different capacities can realize series charging, increase the charging speed, and reduce the difficulty of stacking.
在其他实施例中,第一电池和第二电池的容量也可以一样,相同容量的电池可以解决串联充电过程中因为老化速度等导致的电量均衡问题。In other embodiments, the capacity of the first battery and the second battery can also be the same, and batteries with the same capacity can solve the problem of power balance caused by aging speed and the like during the series charging process.
在本申请实施例中,通过将第一电池的正极端分别与第二电池的负极端、第一负载连接,第二电池的正极端与第二负载2连接,并且升降压模块分别与第一电池的正极端、第二电池的正极端连接,升降压模块可以基于第一电池的电压和电流以及所述第二电池的电压和电流调整向第一负载、第二负载的供电,由此通过串联的第一电池和第二电池,可以在提升向高工作电压负载的输入电压至两个电池的电压之和,降低高工作电压负载输入和输出电压压差,极大地提高电源的转换效率,以及向低工作电压负载直接提供一个电池输出的电压,避免电压的升降转换,减少供电效率损失,提升续航能力。此外,基于第一电池、第二电池的电压和电流,由升降压模块调整向第一负载、第二负载的供电,可以使得第一电池和第二电池的荷电状态同步,避免电池存在过充或过放,提高电池寿命。In the embodiment of the present application, by connecting the positive end of the first battery to the negative end of the second battery and the first load respectively, the positive end of the second battery is connected to the second load 2, and the buck-boost module is respectively connected to the first load. The positive terminal of the first battery and the positive terminal of the second battery are connected, and the buck-boost module can adjust the power supply to the first load and the second load based on the voltage and current of the first battery and the voltage and current of the second battery, by By connecting the first battery and the second battery in series, the input voltage to the high operating voltage load can be increased to the sum of the voltages of the two batteries, reducing the voltage difference between the input and output voltage of the high operating voltage load, and greatly improving the conversion of the power supply Efficiency, and directly provide a battery output voltage to the low working voltage load, avoid voltage up-down conversion, reduce power supply efficiency loss, and improve battery life. In addition, based on the voltage and current of the first battery and the second battery, the buck-boost module adjusts the power supply to the first load and the second load, so that the state of charge of the first battery and the second battery can be synchronized, avoiding the existence of batteries Overcharge or overdischarge, improve battery life.
如图9所示,本申请实施例还提供了一种供电方法,应用于如上述图1至图8任一实施例所述的电池电路,该方法包括:As shown in FIG. 9, the embodiment of the present application also provides a power supply method, which is applied to the battery circuit described in any one of the above-mentioned embodiments in FIG. 1 to FIG. 8, and the method includes:
步骤102,采集第一电池的电压、第二电池的电压和流经第一电池的电流、流经第二电池的电流;Step 102, collecting the voltage of the first battery, the voltage of the second battery, the current flowing through the first battery, and the current flowing through the second battery;
步骤104,在根据采集的电压和电流确定第一电池的荷电状态与第二电池的荷电状态不同步的情况下,调整向第一负载、第二负载的供电以使第一电池的荷电状态与第二电池的荷电状态同步。Step 104, when it is determined according to the collected voltage and current that the state of charge of the first battery is not synchronized with the state of charge of the second battery, adjust the power supply to the first load and the second load so that the charge of the first battery The state of charge is synchronized with the state of charge of the second battery.
步骤102可以由电池电路的采集模块执行,且能达到相同的技术效果,为避免重复,这里不再赘述。Step 102 can be performed by the acquisition module of the battery circuit, and can achieve the same technical effect, so in order to avoid repetition, details are not repeated here.
在步骤104中,可选地,在所述电流为所述第一电池、所述第二电池放电状态下采集的电流的情况下,调整向所述第一负载、所述第二负载的供电,包括:根据采集的所述第一电池的电压和所述第二电池的电压,确定所述第一电池的荷电状态与所述第二电池的荷电状态是否同步;若否,根据采集的所述第一电池的电压、所述第二电池的电压和流经所述第一电池的第一放电电流、流经所述第二电池的第二放电电流,确定提供至所述第一负载的第一供电电流和提供至所述第二负载的第二供电电流;根据所述第一供电电流、所述第二供电电流、所述第一电池的可用最大容量和所述第二电池的可用最大容量,调整流经所述升降压模块的第二端的第二电流大小以调整向所述第一负载、所述第二负载的供电,直至所述第一电池的荷电状态与所述第二电池的荷电状态同步。In step 104, optionally, when the current is the current collected in the discharge state of the first battery and the second battery, adjust the power supply to the first load and the second load , comprising: according to the collected voltage of the first battery and the voltage of the second battery, determining whether the state of charge of the first battery is synchronized with the state of charge of the second battery; if not, according to the collected The voltage of the first battery, the voltage of the second battery, the first discharge current flowing through the first battery, and the second discharge current flowing through the second battery are determined to be supplied to the first The first supply current of the load and the second supply current provided to the second load; according to the first supply current, the second supply current, the available maximum capacity of the first battery and the second battery the available maximum capacity, adjust the magnitude of the second current flowing through the second terminal of the buck-boost module to adjust the power supply to the first load and the second load, until the state of charge of the first battery is equal to The states of charge of the second batteries are synchronized.
在步骤104中,可选地,在所述电流为所述第一电池、所述第二电池充电状态下采集的电流的情况下,调整向所述第一负载、所述第二负载的供电,包括:根据采集的所述第一电池的电压和所述第二电池的电压,确定所述第一电池的荷电状态与所述第二电池的荷电状态是否同步;若否,根据采集的所述第一电池的电压、所述第二电池的电压和流经所述第一电池的第一充电电流、流经所述第二电池的第二充电电流,确定提供至所述第二负载的第三供电电流;根据所述第一充电电流、所述第三供电电流、所述第一电池的可用最大容量和所述第二电池的可用最大容量,调整流经所述升降压模块的第二端的第二电流大小以调整向所述第一负载、所述第二负载的供电,直至所述第一电池的荷电状态与所述第二电池的荷电状态同步。In step 104, optionally, in the case that the current is the current collected in the charging state of the first battery and the second battery, adjust the power supply to the first load and the second load , comprising: according to the collected voltage of the first battery and the voltage of the second battery, determining whether the state of charge of the first battery is synchronized with the state of charge of the second battery; if not, according to the collected The voltage of the first battery, the voltage of the second battery, the first charging current flowing through the first battery, and the second charging current flowing through the second battery are determined to be provided to the second The third power supply current of the load; according to the first charging current, the third power supply current, the available maximum capacity of the first battery and the available maximum capacity of the second battery, adjust the voltage flowing through the buck-boost The magnitude of the second current at the second terminal of the module is used to adjust the power supply to the first load and the second load until the state of charge of the first battery is synchronized with the state of charge of the second battery.
步骤104中的步骤可以由电池电路的控制模块、升降压模块对应执行,且能达到相同的技术效果,为避免重复,这里不再赘述。The steps in step 104 can be executed correspondingly by the control module of the battery circuit and the buck-boost module, and can achieve the same technical effect. To avoid repetition, details are not repeated here.
此外,本申请实施例还提供了一种电子设备,包括如上述图1至图8任一实施例所述的电池电路。In addition, an embodiment of the present application also provides an electronic device, including the battery circuit as described in any one of the embodiments in FIG. 1 to FIG. 8 above.
需要说明的是,在本文中,术语“包括”、“包含”或者其任何其他变体意在涵盖非排他性的包含,从而使得包括一系列要素的过程、方法、物品或者装置不仅包括那些要素,而且还包括没有明确列出的其他要素,或者是还包括为这种过程、方法、物品或者装置所固有的要素。在没有更多限制的情况下,由语句“包括一个……”限定的要素,并不排除在包括该要素的过程、方法、物品或者装置中还存在另外的相同要素。此外,需要指出的是,本申请实施方式中的方法和装置的范围不限按示出或讨论的顺序来执行功能,还可包括根据所涉及的功能按基本同时的方式或按相反的顺序来执行功能,例如,可以按不同于所描述的次序来执行所描述的方法,并且还可以添加、省去、或组合各种步骤。另外,参照某些示例所描述的特征可在其他示例中被组合。It should be noted that, in this document, the term "comprising", "comprising" or any other variation thereof is intended to cover a non-exclusive inclusion such that a process, method, article or apparatus comprising a set of elements includes not only those elements, It also includes other elements not expressly listed, or elements inherent in the process, method, article, or device. Without further limitations, an element defined by the phrase "comprising a ..." does not preclude the presence of additional identical elements in the process, method, article, or apparatus comprising that element. In addition, it should be pointed out that the scope of the methods and devices in the embodiments of the present application is not limited to performing functions in the order shown or discussed, and may also include performing functions in a substantially simultaneous manner or in reverse order according to the functions involved. Functions are performed, for example, the described methods may be performed in an order different from that described, and various steps may also be added, omitted, or combined. Additionally, features described with reference to certain examples may be combined in other examples.
通过以上的实施方式的描述,本领域的技术人员可以清楚地了解到上述实施例方法可借助软件加必需的通用硬件平台的方式来实现,当然也可以通过硬件,但很多情况下前者是更佳的实施方式。基于这样的理解,本申请的技术方案本质上或者说对现有技术做出贡献的部分可以以计算机软件产品的形式体现出来,该计算机软件产品存储在一个存储介质(如ROM/RAM、磁碟、光盘)中,包括若干指令用以使得一台终端(可以是手机,计算机,服务器,或者网络设备等)执行本申请各个实施例所述的方法。Through the description of the above embodiments, those skilled in the art can clearly understand that the methods of the above embodiments can be implemented by means of software plus a necessary general-purpose hardware platform, and of course also by hardware, but in many cases the former is better implementation. Based on such an understanding, the technical solution of the present application can be embodied in the form of computer software products, which are stored in a storage medium (such as ROM/RAM, magnetic disk, etc.) , optical disc), including several instructions to enable a terminal (which may be a mobile phone, computer, server, or network device, etc.) to execute the methods described in various embodiments of the present application.
上面结合附图对本申请的实施例进行了描述,但是本申请并不局限于上述的具体实施方式,上述的具体实施方式仅仅是示意性的,而不是限制性的,本领域的普通技术人员在本申请的启示下,在不脱离本申请宗旨和权利要求所保护的范围情况下,还可做出很多形式,均属于本申请的保护之内。The embodiments of the present application have been described above in conjunction with the accompanying drawings, but the present application is not limited to the above-mentioned specific implementations. The above-mentioned specific implementations are only illustrative and not restrictive. Those of ordinary skill in the art will Under the inspiration of this application, without departing from the purpose of this application and the scope of protection of the claims, many forms can also be made, all of which belong to the protection of this application.
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| WO2025039505A1 (en) * | 2023-08-23 | 2025-02-27 | 荣耀终端股份有限公司 | Power supply circuit and method, and chip and electronic device |
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| WO2025039505A1 (en) * | 2023-08-23 | 2025-02-27 | 荣耀终端股份有限公司 | Power supply circuit and method, and chip and electronic device |
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