CN104270820B - United vertical beam control and power distribution method in the extensive mimo systems of 3D - Google Patents
United vertical beam control and power distribution method in the extensive mimo systems of 3D Download PDFInfo
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- CN104270820B CN104270820B CN201410380297.9A CN201410380297A CN104270820B CN 104270820 B CN104270820 B CN 104270820B CN 201410380297 A CN201410380297 A CN 201410380297A CN 104270820 B CN104270820 B CN 104270820B
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- H—ELECTRICITY
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- H04B7/00—Radio transmission systems, i.e. using radiation field
- H04B7/02—Diversity systems; Multi-antenna system, i.e. transmission or reception using multiple antennas
- H04B7/04—Diversity systems; Multi-antenna system, i.e. transmission or reception using multiple antennas using two or more spaced independent antennas
- H04B7/0413—MIMO systems
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Abstract
本发明公开了一种3D大规模MIMO系统中联合的垂直波束控制及功率分配方法,包括以下步骤:1)根据用户位置分布将每个小区划分为两个垂直扇区并在垂直扇区间复用一组相同的导频序列进行上行信道估计;2)在下行数据传输阶段,首先,基于上行信道估计的结果以及上行用户所属扇区的初始化结果,以最大比传输为下行预编码算法,最大化和速率为目标,联合优化各小区近扇区的3D天线阵列加权矢量wl0、发送功率pl0,以及远扇区的3D天线阵列加权矢量wl1、发送功率pl1;然后,根据优化后每个扇区的波束增益,将用户重新划分到波束增益较大的扇区;重复2)中步骤,直至用户所属扇区情况不变;至此,完成3D大规模MIMO系统中联合的垂直波束控制及功率分配。
The invention discloses a joint vertical beam control and power allocation method in a 3D massive MIMO system, comprising the following steps: 1) dividing each cell into two vertical sectors according to user position distribution and multiplexing between the vertical sectors A group of the same pilot sequence is used for uplink channel estimation; 2) In the downlink data transmission stage, firstly, based on the result of uplink channel estimation and the initialization result of the sector to which the uplink user belongs, the maximum ratio transmission is used as the downlink precoding algorithm to maximize and rate as the target, jointly optimize the 3D antenna array weight vector w l0 and transmit power p l0 of the near sector of each cell, and the 3D antenna array weight vector w l1 and transmit power p l1 of the far sector; then, according to the optimized the beam gain of each sector, and re-divide users into sectors with larger beam gains; repeat the steps in 2) until the situation of the sector to which the user belongs remains unchanged; so far, the joint vertical beam steering and joint vertical beam steering in the 3D massive MIMO system and the 3D massive MIMO system are completed. power distribution.
Description
Claims (1)
- A combined vertical beam control and power allocation method in a 3D massive MIMO system is characterized by comprising the following steps:1) in an uplink channel estimation stage, dividing each cell in a cooperation cluster into two virtual vertical sectors according to user position distribution, and enabling the two vertical sectors to reuse one group of same pilot frequency sequences so as to increase the number of users simultaneously served by each base station, wherein the channel estimation adopts an LS estimation algorithm;2) in the downlink data transmission stage, in the first step, each cell is set according to the distribution of user positionsTwo fixed antenna downward inclination angles, two vertical sectors are formed in each cell, namely a near sector and a far sector, and the sector to which each user belongs is initialized; secondly, based on the result of the uplink channel estimation and the initialization result of the sector to which each cell user belongs, the 3D antenna array weighting vector w of the near sector of each cell is optimized in a combined manner by taking maximum ratio transmission as a downlink precoding algorithm and taking the maximum sum rate as a targetl0And a transmission power pl0And a 3D antenna array weighting vector w for the far sectorl1And a transmission power pl1(ii) a Thirdly, according to the optimized wave beam gain of the near sector and the far sector of the cell where the user is located, the user is divided into the sectors with larger wave beam gain in the cell again; repeating the first step to the third step until the sector condition of the user is unchanged; so far, the combined vertical beam control and power distribution in the 3D large-scale MIMO system is completed;the method specifically comprises the following steps:(1) and (3) uplink channel estimation: dividing each cell into two virtual vertical sectors according to the user position distribution, using one vertical beam to receive the uplink pilot signals sent by all users in the two virtual sectors in each cell, carrying out LS channel estimation, and carrying out LS channel estimation on a near sector user k in a cell l0The LS channel estimation result isThe method comprises the following specific steps:<mrow> <mtable> <mtr> <mtd> <mrow> <msubsup> <mover> <mi>b</mi> <mo>^</mo> </mover> <mrow> <msub> <mi>llk</mi> <mn>0</mn> </msub> </mrow> <mrow> <mi>L</mi> <mi>S</mi> </mrow> </msubsup> <mo>=</mo> <mfrac> <mrow> <msub> <mi>y</mi> <mi>l</mi> </msub> <msubsup> <mi>&Psi;</mi> <mi>k</mi> <mi>H</mi> </msubsup> </mrow> <mrow> <mi>K</mi> <mi>A</mi> <mrow> <mo>(</mo> <msub> <mi>&theta;</mi> <mrow> <mi>D</mi> <mo>,</mo> <mi>l</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>&theta;</mi> <mrow> <msub> <mi>llk</mi> <mn>0</mn> </msub> </mrow> </msub> <mo>)</mo> </mrow> </mrow> </mfrac> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <mo>=</mo> <msub> <mi>b</mi> <mrow> <msub> <mi>llk</mi> <mn>0</mn> </msub> </mrow> </msub> <mo>+</mo> <mfrac> <mrow> <msub> <mi>b</mi> <mrow> <msub> <mi>llk</mi> <mn>1</mn> </msub> </mrow> </msub> <mi>A</mi> <mrow> <mo>(</mo> <msub> <mi>&theta;</mi> <mrow> <mi>D</mi> <mo>,</mo> <mi>l</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>&theta;</mi> <mrow> <msub> <mi>llk</mi> <mn>1</mn> </msub> </mrow> </msub> <mo>)</mo> </mrow> </mrow> <mrow> <mi>A</mi> <mrow> <mo>(</mo> <msub> <mi>&theta;</mi> <mrow> <mi>D</mi> <mo>,</mo> <mi>l</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>&theta;</mi> <mrow> <msub> <mi>llk</mi> <mn>0</mn> </msub> </mrow> </msub> <mo>)</mo> </mrow> </mrow> </mfrac> <mo>+</mo> <munderover> <mo>&Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <mn>1</mn> <mo>,</mo> <mi>j</mi> <mo>&NotEqual;</mo> <mi>l</mi> </mrow> <mi>L</mi> </munderover> <mrow> <mo>(</mo> <mfrac> <mrow> <msub> <mi>b</mi> <mrow> <msub> <mi>ljk</mi> <mn>0</mn> </msub> </mrow> </msub> <mi>A</mi> <mrow> <mo>(</mo> <msub> <mi>&theta;</mi> <mrow> <mi>D</mi> <mo>,</mo> <mi>l</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>&theta;</mi> <mrow> <msub> <mi>ljk</mi> <mn>0</mn> </msub> </mrow> </msub> <mo>)</mo> </mrow> <mo>+</mo> <msub> <mi>b</mi> <mrow> <msub> <mi>ljk</mi> <mn>1</mn> </msub> </mrow> </msub> <mi>A</mi> <mrow> <mo>(</mo> <msub> <mi>&theta;</mi> <mrow> <mi>D</mi> <mo>,</mo> <mi>l</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>&theta;</mi> <mrow> <msub> <mi>llk</mi> <mn>1</mn> </msub> </mrow> </msub> <mo>)</mo> </mrow> </mrow> <mrow> <mi>A</mi> <mrow> <mo>(</mo> <msub> <mi>&theta;</mi> <mrow> <mi>D</mi> <mo>,</mo> <mi>l</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>&theta;</mi> <mrow> <msub> <mi>llk</mi> <mn>0</mn> </msub> </mrow> </msub> <mo>)</mo> </mrow> </mrow> </mfrac> <mo>)</mo> </mrow> <mo>+</mo> <mfrac> <mrow> <msub> <mi>z</mi> <mi>l</mi> </msub> <msubsup> <mi>&Psi;</mi> <mi>k</mi> <mi>H</mi> </msubsup> </mrow> <mrow> <mi>K</mi> <mi>A</mi> <mrow> <mo>(</mo> <msub> <mi>&theta;</mi> <mrow> <mi>D</mi> <mo>,</mo> <mi>l</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>&theta;</mi> <mrow> <msub> <mi>llk</mi> <mn>0</mn> </msub> </mrow> </msub> <mo>)</mo> </mrow> </mrow> </mfrac> </mrow> </mtd> </mtr> </mtable> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>4</mn> <mo>)</mo> </mrow> </mrow>in the formula: y islThe calculation formula of the signal received by the base station l is:<mrow> <mtable> <mtr> <mtd> <mrow> <msub> <mi>y</mi> <mi>l</mi> </msub> <mo>=</mo> <munderover> <mo>&Sigma;</mo> <mrow> <mi>k</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>K</mi> </munderover> <mrow> <mo>(</mo> <msub> <mi>b</mi> <mrow> <msub> <mi>llk</mi> <mn>0</mn> </msub> </mrow> </msub> <mi>A</mi> <mo>(</mo> <mrow> <msub> <mi>&theta;</mi> <mrow> <mi>D</mi> <mo>,</mo> <mi>l</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>&theta;</mi> <mrow> <msub> <mi>llk</mi> <mn>0</mn> </msub> </mrow> </msub> </mrow> <mo>)</mo> <msub> <mi>&Psi;</mi> <mi>k</mi> </msub> <mo>+</mo> <msub> <mi>b</mi> <mrow> <msub> <mi>llk</mi> <mn>1</mn> </msub> </mrow> </msub> <mi>A</mi> <mo>(</mo> <mrow> <msub> <mi>&theta;</mi> <mrow> <mi>D</mi> <mo>,</mo> <mi>l</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>&theta;</mi> <mrow> <msub> <mi>llk</mi> <mn>1</mn> </msub> </mrow> </msub> </mrow> <mo>)</mo> <msub> <mi>&Psi;</mi> <mi>k</mi> </msub> <mo>)</mo> </mrow> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <mo>+</mo> <munderover> <mo>&Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <mn>1</mn> <mo>,</mo> <mi>j</mi> <mo>&NotEqual;</mo> <mi>l</mi> </mrow> <mi>L</mi> </munderover> <munderover> <mo>&Sigma;</mo> <mrow> <mi>k</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>K</mi> </munderover> <mrow> <mo>(</mo> <msub> <mi>b</mi> <mrow> <msub> <mi>ljk</mi> <mn>0</mn> </msub> </mrow> </msub> <mi>A</mi> <mo>(</mo> <mrow> <msub> <mi>&theta;</mi> <mrow> <mi>D</mi> <mo>,</mo> <mi>l</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>&theta;</mi> <mrow> <msub> <mi>llk</mi> <mn>0</mn> </msub> </mrow> </msub> </mrow> <mo>)</mo> <msub> <mi>&Psi;</mi> <mi>k</mi> </msub> <mo>+</mo> <msub> <mi>b</mi> <mrow> <msub> <mi>ljk</mi> <mn>1</mn> </msub> </mrow> </msub> <mi>A</mi> <mo>(</mo> <mrow> <msub> <mi>&theta;</mi> <mrow> <mi>D</mi> <mo>,</mo> <mi>l</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>&theta;</mi> <mrow> <msub> <mi>ljk</mi> <mn>1</mn> </msub> </mrow> </msub> </mrow> <mo>)</mo> <msub> <mi>&Psi;</mi> <mi>k</mi> </msub> <mo>)</mo> </mrow> <mo>+</mo> <msub> <mi>z</mi> <mi>l</mi> </msub> </mrow> </mtd> </mtr> </mtable> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>1</mn> <mo>)</mo> </mrow> </mrow>wherein: k is the total number of users served by each cell, L is the total number of cells in the coordinated cluster, ΨkFor near sector user k0And remote sector user k1The same pilot sequence is transmitted in 1 x tau dimension in uplink,for cell/. near-sector user k0The channel matrix to the base station/,for cell l remote sector user k1The channel matrix to the base station/,for cell j near sector user k0The channel matrix to the base station/,for cell j remote sector user k1Channel matrix to base station l, A (-) is the 3D antenna pattern of the base station, θD,lIs the downtilt angle of the base station i antenna array,for a near sector user k in cell l0Looking at the elevation angle of the base station i,for a remote sector user k in cell l1Looking at the elevation angle of the base station i,for a near sector user k in cell j0Looking at the elevation angle of the base station i,for a remote sector user k in cell j1Elevation angle, z, looking at base station llIs additive white Gaussian noise of base station l, andN0is noise power spectral density, I is unit array;denotes ΨkThe conjugate transpose of (1);(2) downlink vertical beam forming and power distribution joint optimization: for user k in cell l, maximum ratio transmission is carried out based on uplink channel estimation information, and the user and rate R can be obtainedlkThe expression of (1); the optimization target is to maximize the sum rate of all users in the cooperative cluster, and the optimization target is the 3D antenna array weighting vector w of each cell near sectorl0And a transmission power pl0And a 3D antenna array weighting vector w for the far sectorl1And a transmission power pl1I.e. the optimization problem isThe concrete form is as follows:<mrow> <mtable> <mtr> <mtd> <mrow> <munder> <mi>max</mi> <mrow> <mo>(</mo> <msub> <mi>w</mi> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>,</mo> <msub> <mi>w</mi> <mrow> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>,</mo> <msub> <mi>P</mi> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>,</mo> <msub> <mi>P</mi> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>)</mo> </mrow> </munder> <munderover> <mo>&Sigma;</mo> <mrow> <mi>l</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>L</mi> </munderover> <mrow> <mo>(</mo> <munderover> <mo>&Sigma;</mo> <mrow> <msub> <mi>k</mi> <mn>0</mn> </msub> <mo>=</mo> <mn>1</mn> </mrow> <msub> <mi>K</mi> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> </munderover> <msub> <mi>R</mi> <mrow> <msub> <mi>lk</mi> <mn>0</mn> </msub> </mrow> </msub> <mo>+</mo> <munderover> <mo>&Sigma;</mo> <mrow> <msub> <mi>k</mi> <mn>1</mn> </msub> <mo>=</mo> <mn>1</mn> </mrow> <msub> <mi>K</mi> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> </munderover> <msub> <mi>R</mi> <mrow> <msub> <mi>lk</mi> <mn>1</mn> </msub> </mrow> </msub> <mo>)</mo> </mrow> </mrow> </mtd> </mtr> <mtr> <mtd> <mtable> <mtr> <mtd> <mrow> <mi>s</mi> <mo>.</mo> <mi>t</mi> <mo>.</mo> </mrow> </mtd> <mtd> <mrow> <msub> <mi>C</mi> <mn>1</mn> </msub> <mo>:</mo> <msubsup> <mi>w</mi> <mrow> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>,</mo> <mi>l</mi> <mn>0</mn> </mrow> <mi>H</mi> </msubsup> <msub> <mi>w</mi> <mrow> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>,</mo> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>=</mo> <msubsup> <mi>w</mi> <mrow> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>,</mo> <mi>l</mi> <mn>1</mn> </mrow> <mi>H</mi> </msubsup> <msub> <mi>w</mi> <mrow> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>,</mo> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>=</mo> <mn>1</mn> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow></mrow> </mtd> <mtd> <mrow> <mi>&rho;</mi> <mo>=</mo> <mfrac> <mrow> <msubsup> <mo>&Integral;</mo> <mrow> <mo>-</mo> <mi>&pi;</mi> </mrow> <mi>&pi;</mi> </msubsup> <mrow> <mo>(</mo> <msubsup> <mi>w</mi> <mrow> <mi>l</mi> <mn>0</mn> </mrow> <mi>H</mi> </msubsup> <mi>B</mi> <mi>r</mi> <mo>(</mo> <mi>&theta;</mi> <mo>)</mo> <mo>)</mo> </mrow> <msup> <mrow> <mo>(</mo> <msubsup> <mi>w</mi> <mrow> <mi>l</mi> <mn>1</mn> </mrow> <mi>H</mi> </msubsup> <mi>B</mi> <mi>r</mi> <mo>(</mo> <mi>&theta;</mi> <mo>)</mo> <mo>)</mo> </mrow> <mo>*</mo> </msup> <mi>p</mi> <mrow> <mo>(</mo> <mi>&theta;</mi> <mo>)</mo> </mrow> <mi>d</mi> <mi>&theta;</mi> </mrow> <mrow> <msubsup> <mo>&Integral;</mo> <mrow> <mo>-</mo> <mi>&pi;</mi> </mrow> <mi>&pi;</mi> </msubsup> <msup> <mrow> <mo>|</mo> <msubsup> <mi>w</mi> <mrow> <mi>l</mi> <mn>0</mn> </mrow> <mi>H</mi> </msubsup> <mi>B</mi> <mi>r</mi> <mrow> <mo>(</mo> <mi>&theta;</mi> <mo>)</mo> </mrow> <mo>|</mo> </mrow> <mn>2</mn> </msup> <mi>p</mi> <mrow> <mo>(</mo> <mi>&theta;</mi> <mo>)</mo> </mrow> <mi>d</mi> <mi>&theta;</mi> <msubsup> <mo>&Integral;</mo> <mrow> <mo>-</mo> <mi>&pi;</mi> </mrow> <mi>&pi;</mi> </msubsup> <msup> <mrow> <mo>|</mo> <msubsup> <mi>w</mi> <mrow> <mi>l</mi> <mn>1</mn> </mrow> <mi>H</mi> </msubsup> <mi>B</mi> <mi>r</mi> <mrow> <mo>(</mo> <mi>&theta;</mi> <mo>)</mo> </mrow> <mo>|</mo> </mrow> <mn>2</mn> </msup> <mi>p</mi> <mrow> <mo>(</mo> <mi>&theta;</mi> <mo>)</mo> </mrow> <mi>d</mi> <mi>&theta;</mi> </mrow> </mfrac> <mo>&le;</mo> <msub> <mi>&rho;</mi> <mi>max</mi> </msub> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow></mrow> </mtd> <mtd> <mrow> <msub> <mi>C</mi> <mn>2</mn> </msub> <mo>:</mo> <msub> <mi>p</mi> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>+</mo> <msub> <mi>p</mi> <mrow> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>&le;</mo> <mi>P</mi> </mrow> </mtd> </mtr> </mtable> </mtd> </mtr> </mtable> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>8</mn> <mo>)</mo> </mrow> </mrow>in the formula:andmean elevation angles of users in the near sector and the far sector of the cell l are respectively represented;the optimization problem includes two constraints: c1The premise that the correlation between the antenna beams of two sectors in each cell is smaller than a threshold value is shown, and the transmission power of the base station is kept unchanged after the weighting vector w is adjusted;C2means that the total power of two sectors per cell is less than the total power P of the base station;Br(θ)∈CM×1is the directional diagram of the base station antenna array, and M is the number of base station antennas;p (θ) represents a probability density function of the user distribution;ρ represents the correlation coefficient between two sector antenna beams per cell;indicates that the antenna has a downtilt angle ofThe antenna array weight vector for the near sector of cell i,to representThe conjugate transpose of (1);indicates that the antenna has a downtilt angle ofThe antenna array weight vector for the far sector of cell/,to representThe conjugate transpose of (1);pl0indicating the base station service power, p, of the near sector of the celll1Represents the base station service power of the remote sector of the cell l;wherein:for a near sector user k in cell l0The sum of the rates of (a) and (b),for a remote sector user k in cell l1L is the total number of cells in the cooperative cluster, Kl0Is the total number of users, K, in the celll1The total number of users of the remote sector in the cell l;in order to reduce inter-cell interference and meet total power constraints, the constraint condition of the optimization problem is set to be that the correlation of the beam between sectors is smaller than a threshold rhomaxAnd the total transmitting power of the two sectors does not exceed P;(3) in order to reduce the complexity of solving the optimization problem, iterative solution is carried out by using a particle swarm algorithm;the first step is as follows: initializing 3D antenna array weighting vectors w for each cell near sectorl0And a transmission power pl0And a 3D antenna array weighting vector w for the far sectorl1And a transmission power pl1Setting a 3D antenna array weighting vector w of each cell near sectorl0Has an update speed vw,l0And a transmission power pl0Has an update speed vp,l0Setting a 3D antenna array weighting vector w of each cell remote sectorl1Has an update speed vw,l1And a transmission power pl1Has an update speed vp,l1;The second step is that: setting the total sum rate of the system as a utility function, and continuously updating the 3D antenna array weighting vector w of each cell near sector by taking the maximum utility function as a targetl0And a transmission power pl0And a 3D antenna array weighting vector w for the far sectorl1And a transmission power pl1;The third step: if the maximum iteration times are reached or the difference value of the utility functions of two adjacent iterations is smaller than a preset constant delta, stopping the iteration process, wherein the constant delta is smaller than 0.01;according to the iterated 3D antenna array weighting vector w of each cell near sectorl0And 3D antenna array weight vector w for each cell remote sectorl1Array antenna gains of a serving near sector and a far sector are respectively calculated, wherein the near sector array antenna gain of a user i in a cell l at a base station l is A (theta)D,l0,θlli),θD,l0Down tilt angle, theta, of the near sector antenna for celllliThe pitch angle from user i in cell l to base station l, and the array antenna gain of user i in cell l in the far sector of base station l is A (theta)D,l1,θlli),θD,l1The downtilt angle of the remote sector antenna of the serving cell l;wherein a 3D antenna array weighting vector w for each cell near sector is initializedl0And its update speed vw,l0The calculation formula is as follows:<mrow> <mfenced open = "{" close = ""> <mtable> <mtr> <mtd> <mrow> <msubsup> <mi>v</mi> <msub> <mi>w</mi> <mrow> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>,</mo> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mi>j</mi> </msubsup> <mrow> <mo>(</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>=</mo> <mrow> <mo>(</mo> <mfrac> <mi>&epsiv;</mi> <mn>2</mn> </mfrac> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mi>cos</mi> <mo>&lsqb;</mo> <mfrac> <mrow> <mn>2</mn> <mi>&pi;</mi> <mi>d</mi> </mrow> <mi>&lambda;</mi> </mfrac> <mrow> <mo>(</mo> <mi>m</mi> <mi> </mi> <mi>sin</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>+</mo> <mi>n</mi> <mi> </mi> <mi>cos</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>)</mo> </mrow> <mo>&rsqb;</mo> <mo>-</mo> <mrow> <mo>(</mo> <mfrac> <mi>&epsiv;</mi> <mn>2</mn> </mfrac> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mi>j</mi> <mi> </mi> <mi>sin</mi> <mo>&lsqb;</mo> <mfrac> <mrow> <mn>2</mn> <mi>&pi;</mi> <mi>d</mi> </mrow> <mi>&lambda;</mi> </mfrac> <mrow> <mo>(</mo> <mi>m</mi> <mi> </mi> <mi>sin</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>+</mo> <mi>n</mi> <mi> </mi> <mi>cos</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>)</mo> </mrow> <mo>&rsqb;</mo> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <msubsup> <mi>w</mi> <msub> <mi>w</mi> <mrow> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>,</mo> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mi>j</mi> </msubsup> <mrow> <mo>(</mo> <mn>0</mn> <mo>)</mo> </mrow> <mo>=</mo> <mi>cos</mi> <mo>&lsqb;</mo> <mfrac> <mrow> <mn>2</mn> <mi>&pi;</mi> <mi>d</mi> </mrow> <mi>&lambda;</mi> </mfrac> <mrow> <mo>(</mo> <mi>m</mi> <mi> </mi> <mi>sin</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>+</mo> <mi>n</mi> <mi> </mi> <mi>cos</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>)</mo> </mrow> <mo>&rsqb;</mo> <mo>-</mo> <mi>j</mi> <mi> </mi> <mi>sin</mi> <mo>&lsqb;</mo> <mfrac> <mrow> <mn>2</mn> <mi>&pi;</mi> <mi>d</mi> </mrow> <mi>&lambda;</mi> </mfrac> <mrow> <mo>(</mo> <mi>m</mi> <mi> </mi> <mi>sin</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>+</mo> <mi>n</mi> <mi> </mi> <mi>cos</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mo>)</mo> </mrow> <mo>&rsqb;</mo> </mrow> </mtd> </mtr> </mtable> </mfenced> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>10</mn> <mo>)</mo> </mrow> </mrow>in the formula: e to U (0,1), d is the spacing of two antenna elements, and d ═ dy=dz,dyAnd dzRespectively representing the horizontal spacing and the vertical spacing of the antennas;m and n represent the mth row and nth column antenna element of the planar antenna array;is (N-1) NVThe update speed at time 1 of the j-th particle of + m elements,is (N-1) NVInitial position at time 0 of j-th particle of + m elements, NvRepresenting the number of vertical antennas of the antenna array;λ represents the wavelength of the user transmit beam;initializing the transmit power p of the near sector of each celll0The calculation formula is as follows:<mrow> <mfenced open = "{" close = ""> <mtable> <mtr> <mtd> <mrow> <msubsup> <mi>v</mi> <msub> <mi>P</mi> <mrow> <mi>l</mi> <mn>0</mn> </mrow> </msub> <mi>j</mi> </msubsup> <mrow> <mo>(</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>=</mo> <mi>P</mi> <mo>&times;</mo> <mi>&epsiv;</mi> <mo>-</mo> <mfrac> <mi>P</mi> <mn>2</mn> </mfrac> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <msubsup> <mi>P</mi> <mrow> <mi>l</mi> <mn>0</mn> </mrow> <mi>j</mi> </msubsup> <mrow> <mo>(</mo> <mn>0</mn> <mo>)</mo> </mrow> <mo>=</mo> <mfrac> <mi>P</mi> <mn>2</mn> </mfrac> </mrow> </mtd> </mtr> </mtable> </mfenced> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>9</mn> <mo>)</mo> </mrow> </mrow>in the formula:is Pl0The update rate at time 1 of the jth particle,is Pl0Initial position at time 0 of the jth particle;initializing 3D antenna array weighting vectors w for each cell remote sectorl1And an update speed vw,l1The calculation formula is as follows:<mrow> <mfenced open = "{" close = ""> <mtable> <mtr> <mtd> <mrow> <msubsup> <mi>v</mi> <msub> <mi>w</mi> <mrow> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>,</mo> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mi>j</mi> </msubsup> <mrow> <mo>(</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>=</mo> <mrow> <mo>(</mo> <mfrac> <mi>&epsiv;</mi> <mn>2</mn> </mfrac> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mi>cos</mi> <mo>&lsqb;</mo> <mfrac> <mrow> <mn>2</mn> <mi>&pi;</mi> <mi>d</mi> </mrow> <mi>&lambda;</mi> </mfrac> <mrow> <mo>(</mo> <mi>m</mi> <mi> </mi> <mi>sin</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>+</mo> <mi>n</mi> <mi> </mi> <mi>cos</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>)</mo> </mrow> <mo>&rsqb;</mo> <mo>-</mo> <mrow> <mo>(</mo> <mfrac> <mi>&epsiv;</mi> <mn>2</mn> </mfrac> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mi>j</mi> <mi> </mi> <mi>sin</mi> <mo>&lsqb;</mo> <mfrac> <mrow> <mn>2</mn> <mi>&pi;</mi> <mi>d</mi> </mrow> <mi>&lambda;</mi> </mfrac> <mrow> <mo>(</mo> <mi>m</mi> <mi> </mi> <mi>sin</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>+</mo> <mi>n</mi> <mi> </mi> <mi>cos</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>)</mo> </mrow> <mo>&rsqb;</mo> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <msubsup> <mi>w</mi> <msub> <mi>w</mi> <mrow> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>,</mo> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mi>j</mi> </msubsup> <mrow> <mo>(</mo> <mn>0</mn> <mo>)</mo> </mrow> <mo>=</mo> <mi>cos</mi> <mo>&lsqb;</mo> <mfrac> <mrow> <mn>2</mn> <mi>&pi;</mi> <mi>d</mi> </mrow> <mi>&lambda;</mi> </mfrac> <mrow> <mo>(</mo> <mi>m</mi> <mi> </mi> <mi>sin</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>+</mo> <mi>n</mi> <mi> </mi> <mi>cos</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>)</mo> </mrow> <mo>&rsqb;</mo> <mo>-</mo> <mi>j</mi> <mi> </mi> <mi>sin</mi> <mo>&lsqb;</mo> <mfrac> <mrow> <mn>2</mn> <mi>&pi;</mi> <mi>d</mi> </mrow> <mi>&lambda;</mi> </mfrac> <mrow> <mo>(</mo> <mi>m</mi> <mi> </mi> <mi>sin</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>+</mo> <mi>n</mi> <mi> </mi> <mi>cos</mi> <msub> <mover> <mi>&theta;</mi> <mo>&OverBar;</mo> </mover> <mrow> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>)</mo> </mrow> <mo>&rsqb;</mo> </mrow> </mtd> </mtr> </mtable> </mfenced> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>11</mn> <mo>)</mo> </mrow> </mrow>in the formula:is (N-1) NVUpdate speed at time 1 of the jth particle of + m elements;is (N-1) NVAn initial position at time 0 of a jth particle of + m elements;the formula for the iteratively updated for each particle at time τ is as follows:<mrow> <mtable> <mtr> <mtd> <mrow> <msup> <mi>v</mi> <mi>j</mi> </msup> <mrow> <mo>(</mo> <mi>&tau;</mi> <mo>)</mo> </mrow> <mo>=</mo> <msup> <mi>av</mi> <mi>j</mi> </msup> <mrow> <mo>(</mo> <mi>&tau;</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>+</mo> <msub> <mi>c</mi> <mn>1</mn> </msub> <msub> <mi>r</mi> <mn>1</mn> </msub> <mo>&lsqb;</mo> <msup> <mi>p</mi> <mi>j</mi> </msup> <mrow> <mo>(</mo> <mi>&tau;</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>-</mo> <msup> <mi>x</mi> <mi>j</mi> </msup> <mrow> <mo>(</mo> <mi>&tau;</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>&rsqb;</mo> <mo>+</mo> <msub> <mi>c</mi> <mn>2</mn> </msub> <msub> <mi>r</mi> <mn>2</mn> </msub> <mo>&lsqb;</mo> <msup> <mi>p</mi> <mi>g</mi> </msup> <mrow> <mo>(</mo> <mi>&tau;</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>-</mo> <msup> <mi>x</mi> <mi>j</mi> </msup> <mrow> <mo>(</mo> <mi>&tau;</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>&rsqb;</mo> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <msup> <mi>x</mi> <mi>j</mi> </msup> <mrow> <mo>(</mo> <mi>&tau;</mi> <mo>)</mo> </mrow> <mo>=</mo> <msup> <mi>x</mi> <mi>j</mi> </msup> <mrow> <mo>(</mo> <mi>&tau;</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>+</mo> <msup> <mi>v</mi> <mi>j</mi> </msup> <mrow> <mo>(</mo> <mi>&tau;</mi> <mo>)</mo> </mrow> </mrow> </mtd> </mtr> </mtable> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>12</mn> <mo>)</mo> </mrow> </mrow>wherein: v. ofj(τ) update speed, x, of jth particle time τj(τ) the position of the jth particle time τ, c1, c2 being normal numbers, called the learning factor; r1 and r2 are [0, 1 ]]A is an inertial weight factor; p is a radical ofj(τ -1) is the local optimum, p, for the jth particle time τ -1g(τ -1) is the global optimum of all particles at time τ -1;(4) the sector to which the user belongs is re-divided according to the beam gain of the user in each sector, and the adjustment process is as follows:if A (theta)D,l0,θlli)≥A(θD,l1,θlli) If the user is a near sector user;if A (theta)D,l0,θlli)<A(θD,l1,θlli) If the user is a remote sector user;wherein,in the formula:is an antenna array with a downward inclination angle thetaD,l0Then, the weighting vector of the cell l near sector antenna array; b isr(θlli)∈CM×1Is the directional pattern of the base station antenna array, Br(θlli) (N-1) NV+ m elements being Br,m,n(θlli) Representing the m-th row and n-th column of antenna elementsGain, expressed as<mrow> <msub> <mi>B</mi> <mrow> <mi>r</mi> <mo>,</mo> <mi>m</mi> <mo>,</mo> <mi>n</mi> </mrow> </msub> <mrow> <mo>(</mo> <msub> <mi>&theta;</mi> <mrow> <mi>l</mi> <mi>l</mi> <mi>i</mi> </mrow> </msub> <mo>)</mo> </mrow> <mo>=</mo> <msub> <mi>G</mi> <mi>v</mi> </msub> <mrow> <mo>(</mo> <msub> <mi>&theta;</mi> <mrow> <mi>l</mi> <mi>l</mi> <mi>i</mi> </mrow> </msub> <mo>)</mo> </mrow> <msup> <mi>e</mi> <mrow> <mi>j</mi> <mfrac> <mrow> <mn>2</mn> <mi>&pi;</mi> </mrow> <mi>&lambda;</mi> </mfrac> <msub> <mi>md</mi> <mi>z</mi> </msub> <mi>c</mi> <mi>o</mi> <mi>s</mi> <mrow> <mo>(</mo> <msub> <mi>&theta;</mi> <mrow> <mi>l</mi> <mi>l</mi> <mi>i</mi> </mrow> </msub> <mo>-</mo> <msub> <mi>&theta;</mi> <mi>D</mi> </msub> <mo>)</mo> </mrow> <mo>+</mo> <mi>j</mi> <mfrac> <mrow> <mn>2</mn> <mi>&pi;</mi> </mrow> <mi>&lambda;</mi> </mfrac> <msub> <mi>nd</mi> <mi>y</mi> </msub> <mi>s</mi> <mi>i</mi> <mi>n</mi> <mrow> <mo>(</mo> <msub> <mi>&theta;</mi> <mrow> <mi>l</mi> <mi>l</mi> <mi>i</mi> </mrow> </msub> <mo>-</mo> <msub> <mi>&theta;</mi> <mi>D</mi> </msub> <mo>)</mo> </mrow> </mrow> </msup> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>3</mn> <mo>)</mo> </mrow> </mrow>In the formula:for vertical patterns of individual antenna elements, theta3dBRepresenting the half-power angle, thetaDRepresenting the downtilt angle, theta, of the antenna arraylliFor the pitch angle, d, of users i in cell l to base station lyAnd dzRepresenting antenna horizontal and vertical spacing;<mrow> <mi>A</mi> <mrow> <mo>(</mo> <msub> <mi>&theta;</mi> <mrow> <mi>D</mi> <mo>,</mo> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mo>,</mo> <msub> <mi>&theta;</mi> <mrow> <mi>l</mi> <mi>l</mi> <mi>i</mi> </mrow> </msub> <mo>)</mo> </mrow> <mo>=</mo> <msubsup> <mi>w</mi> <msub> <mi>&theta;</mi> <mrow> <mi>D</mi> <mo>,</mo> <mi>l</mi> <mn>1</mn> </mrow> </msub> <mi>H</mi> </msubsup> <msub> <mi>B</mi> <mi>r</mi> </msub> <mrow> <mo>(</mo> <msub> <mi>&theta;</mi> <mrow> <mi>l</mi> <mi>l</mi> <mi>i</mi> </mrow> </msub> <mo>)</mo> </mrow> </mrow>in the formula:is an antenna array with a downward inclination angle thetaD,l1Weight vector of time-of-flight far-sector antenna array;Repeating the steps (2) to (4), and stopping if the sector condition of the user does not change to obtain the final 3D antenna array weighting vector w of the near sector of each celll0And a transmission power pl0And a 3D antenna array weighting vector w for the far sectorl1And a transmission power pl1。
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| CN104796373B (en) * | 2015-04-16 | 2018-02-27 | 西安交通大学 | A kind of pilot frequency transmitting method of ofdm system |
| CN104852758B (en) * | 2015-05-15 | 2017-10-24 | 北京理工大学 | Vertical beam shaping method and device under three-dimensional extensive aerial network |
| WO2017028059A1 (en) * | 2015-08-14 | 2017-02-23 | 华为技术有限公司 | Space division multiplexing processing method |
| CN105049166B (en) * | 2015-08-17 | 2017-11-28 | 清华大学 | Pilot allocation method based on user geographic location information in large-scale antenna cells |
| CN105375959B (en) * | 2015-10-14 | 2018-06-26 | 西安交通大学 | Based on the matched distributed disturbance coordination method of beam shape in 3D-MIMO systems |
| WO2017118099A1 (en) * | 2016-01-04 | 2017-07-13 | 中兴通讯股份有限公司 | Method and apparatus for allocating uplink pilot and jointly optimizing received beamforming vectors |
| CN107332597B (en) * | 2017-06-05 | 2021-05-28 | 惠州Tcl移动通信有限公司 | Wireless transmission method and device based on 3D MIMO |
| WO2018228707A1 (en) * | 2017-06-16 | 2018-12-20 | Fraunhofer-Gesellschaft zur Förderung der angewandten Forschung e.V. | Transmitter, receiver, wireless communication network and methods for operating the same |
| CN110113083B (en) * | 2019-05-09 | 2021-06-25 | 西安电子科技大学 | A Channel Estimation Method Based on User Partitioning in 3D Massive MIMO |
| CN110086591B (en) * | 2019-05-14 | 2021-10-22 | 鹰潭泰尔物联网研究中心 | Pilot pollution suppression method in large-scale antenna system |
| CN111257879B (en) * | 2020-02-14 | 2022-08-05 | 南京航空航天大学 | Method for solving millimeter wave MIMO radar target splitting based on two norms |
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