numpy.choose#
- numpy.choose(a, choices, out=None, mode='raise')[source]#
- Construct an array from an index array and a list of arrays to choose from. - First of all, if confused or uncertain, definitely look at the Examples - in its full generality, this function is less simple than it might seem from the following code description: - np.choose(a,c) == np.array([c[a[I]][I] for I in np.ndindex(a.shape)]) - But this omits some subtleties. Here is a fully general summary: - Given an “index” array (a) of integers and a sequence of - narrays (choices), a and each choice array are first broadcast, as necessary, to arrays of a common shape; calling these Ba and Bchoices[i], i = 0,…,n-1 we have that, necessarily,- Ba.shape == Bchoices[i].shapefor each- i. Then, a new array with shape- Ba.shapeis created as follows:- if - mode='raise'(the default), then, first of all, each element of- a(and thus- Ba) must be in the range- [0, n-1]; now, suppose that- i(in that range) is the value at the- (j0, j1, ..., jm)position in- Ba- then the value at the same position in the new array is the value in- Bchoices[i]at that same position;
- if - mode='wrap', values in a (and thus Ba) may be any (signed) integer; modular arithmetic is used to map integers outside the range [0, n-1] back into that range; and then the new array is constructed as above;
- if - mode='clip', values in a (and thus- Ba) may be any (signed) integer; negative integers are mapped to 0; values greater than- n-1are mapped to- n-1; and then the new array is constructed as above.
 - Parameters:
- aint array
- This array must contain integers in - [0, n-1], where- nis the number of choices, unless- mode=wrapor- mode=clip, in which cases any integers are permissible.
- choicessequence of arrays
- Choice arrays. a and all of the choices must be broadcastable to the same shape. If choices is itself an array (not recommended), then its outermost dimension (i.e., the one corresponding to - choices.shape[0]) is taken as defining the “sequence”.
- outarray, optional
- If provided, the result will be inserted into this array. It should be of the appropriate shape and dtype. Note that out is always buffered if - mode='raise'; use other modes for better performance.
- mode{‘raise’ (default), ‘wrap’, ‘clip’}, optional
- Specifies how indices outside - [0, n-1]will be treated:- ‘raise’ : an exception is raised 
- ‘wrap’ : value becomes value mod - n
- ‘clip’ : values < 0 are mapped to 0, values > n-1 are mapped to n-1 
 
 
- Returns:
- merged_arrayarray
- The merged result. 
 
- Raises:
- ValueError: shape mismatch
- If a and each choice array are not all broadcastable to the same shape. 
 
 - See also - ndarray.choose
- equivalent method 
- numpy.take_along_axis
- Preferable if choices is an array 
 - Notes - To reduce the chance of misinterpretation, even though the following “abuse” is nominally supported, choices should neither be, nor be thought of as, a single array, i.e., the outermost sequence-like container should be either a list or a tuple. - Examples - >>> import numpy as np >>> choices = [[0, 1, 2, 3], [10, 11, 12, 13], ... [20, 21, 22, 23], [30, 31, 32, 33]] >>> np.choose([2, 3, 1, 0], choices ... # the first element of the result will be the first element of the ... # third (2+1) "array" in choices, namely, 20; the second element ... # will be the second element of the fourth (3+1) choice array, i.e., ... # 31, etc. ... ) array([20, 31, 12, 3]) >>> np.choose([2, 4, 1, 0], choices, mode='clip') # 4 goes to 3 (4-1) array([20, 31, 12, 3]) >>> # because there are 4 choice arrays >>> np.choose([2, 4, 1, 0], choices, mode='wrap') # 4 goes to (4 mod 4) array([20, 1, 12, 3]) >>> # i.e., 0 - A couple examples illustrating how choose broadcasts: - >>> a = [[1, 0, 1], [0, 1, 0], [1, 0, 1]] >>> choices = [-10, 10] >>> np.choose(a, choices) array([[ 10, -10, 10], [-10, 10, -10], [ 10, -10, 10]]) - >>> # With thanks to Anne Archibald >>> a = np.array([0, 1]).reshape((2,1,1)) >>> c1 = np.array([1, 2, 3]).reshape((1,3,1)) >>> c2 = np.array([-1, -2, -3, -4, -5]).reshape((1,1,5)) >>> np.choose(a, (c1, c2)) # result is 2x3x5, res[0,:,:]=c1, res[1,:,:]=c2 array([[[ 1, 1, 1, 1, 1], [ 2, 2, 2, 2, 2], [ 3, 3, 3, 3, 3]], [[-1, -2, -3, -4, -5], [-1, -2, -3, -4, -5], [-1, -2, -3, -4, -5]]])