8000 Not possible to do BFS on a graph of City · Issue #182 · dominikbraun/graph · GitHub
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Not possible to do BFS on a graph of City #182

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@riberr

Hi,

This example is not possible:

type City struct {
    Name string
}

cityHash := func(c City) string {
    return c.Name
}

g := graph.New(cityHash)

//...

f := func(c City) bool {
    return c.Name == "London"
}

graph.DFS(g, "Paris", f)

Warning: "Cannot use 'f' (type func(c City) bool) as the type func(string) bool"

Am I missing something? Because the docs says this should be possible.

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  1. GeorgeMac commented on Nov 12, 2024

    @GeorgeMac

    @riberr The DFS visit function takes K (the generic type for the hash, as opposed to the contained vertex type).
    So you would need to do the following to start at Paris and descend until London:

    f := func(name string) bool {
        return name == "London"
    }
    
    graph.DFS(g, "Paris", f)
    
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